Averages….. In table form. We will start with discrete data i.e. the data can only take certain...

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Averages….. In table form

Transcript of Averages….. In table form. We will start with discrete data i.e. the data can only take certain...

Averages…..

In table form

We will start with discrete data

i.e. the data can only take certain values e.g. shoe size

Number of children in a car

No. of children in car Frequency (or No. of cars)

0 3

1 9

2 5

3 2

4 1

The mode means …….

most common

The mode is …….

1 child per car

The range is the

Highest number of children – smallest number (per car)

So the range =

4 – 0 = 4

It is NOT …..

9 – 1 = 8

median

Put in size order

(Already done in our table)

Find the middle value

We have 20 pieces of data

To find the position of the data value we need….

• Add 1 onto the number of data values 21

• Half this 10½

• We need to look halfway between the 10th and 11th pieces of data 1 and 1

• So the median is ……….

1

Now for the trickiest bit….

The mean

We need to find the total number of children in the cars

And then divide by the total number of cars

Add a column to your table

No. of children

Frequency

(No. of cars)

Group total

0 3 0 x 3 = 0

1 9 1 x 9 = 9

2 5 2 x 5 = 10

3 2 3 x 2 = 6

4 1 4 x 1 = 4

TOTAL 20 29

Mean number of children per car ……

Total No. of children ÷ total frequency

Mean = 29 ÷ 20 = ……..

1.45 children per car

One for you then……

No. of rings per student Frequency

0 73

1 15

2 7

3 4

4 1

Mode (most common) = …

0 rings

Range = …….

4 rings – 0 rings = 4

Median ……

• 100 pieces of data

• Do the ‘add one and half business’ which leaves us looking for the 50½ value (in between the 50th and 51st values)

• 50th value is ‘0’ and 51st value is also ‘0’

• So median is 0

Mean ……

New column on table

Like this ……

No. of rings Frequency Group Total

0 73 0 x 73 = 0

1 15 1 x 15 = 15

2 7 2 x 7 = 14

3 4 3 x 4 = 12

4 1 4 x 1 = 4

TOTAL 100 45

Mean = 45 ÷ 100 = ……

0.45

Here’s another one ……

No. of fingers Frequency

8 1

9 2

10 46

11 0

12 1

Mode = …….

10

Range = ……

12 – 8 = 4

Median

• 50 data values so do the ‘add 1 and half’ thing – we want the 25th and 26th values

• Median is 10

Mean

No. of fingers Frequency Group total

8 1 8 x 1 = 8

9 2 9 x 2 = 18

10 46 10 x 46 = 460

11 0 11 x 0 = 0

12 1 12 x 1 = 12

TOTAL 50 498

Mean =

498 ÷ 50 = 9.96