Answers to Tutorial

download Answers to Tutorial

of 4

Transcript of Answers to Tutorial

  • 8/8/2019 Answers to Tutorial

    1/4

    Tutorial: Basic Information on Ionising Radiation

    1. What is meant by radioactivity?

    Ans: Is a spontaneous disintegration in the nucleus of an unstable atom to

    form a nuclide of different Z by emission of radiation from the nucleus

    2. What are the old and S.I. units for measuring an activity of a radionuclide?, andhow are they correlated ?

    Ans: Old Unit: Curie (Ci) S.I. Unit: Becquerel (Bq)

    I Ci = 3.7 x 1010

    Bq

    3. Determine the atomic mass (A), atomic number (Z), no. of protons (#P), neutrons

    (#N) of the radionuclides in the following table. Based on the completedinformation in the box, complete the symbol for each species.

    NUCLIDES Z #P #N A

    13C

    6

    6 6 7 13

    ?Cl

    ?

    17 17 18 35

    ?Fe

    ?

    26 26 30 56

    ?H

    ?

    1 1 2 3

    ?Te

    ?

    52 52 76 128

    ?Sn

    ?

    50 50 70 120

  • 8/8/2019 Answers to Tutorial

    2/4

    4. Calculate the activity of Co-60 in kCi and TBq after 5 years, if the current activityis 100 kCi. Given the T = 5.27 years.

    A(t) = A0 e-l t

    =

    l = ln 2/ T = 0.693 / 5.27

    = 0.1317

    l t = 0.1317 x 5 = 0.6584A(t) = 100 x e

    -0.6584

    A(t) = 100 x 0.517679

    A(t) = 51.77 kCi

    Since 1 Ci = 10-3

    kCi = 3.7 x 1010

    Bq = 3.7 x 10-2

    TBq

    A(t) = 51.77 kCi x 3.7 x 10-2

    TBq / 10-3

    kCi

    A(t) = 1,920 TBq

    5. Complete the following radioactivity decay schemes

    a. 60Co 60Ni +0e

    27 28 -1

    b.137

    Cs137

    Ba +0e

    55 56 -1

    c.90

    Sr90

    Y +0

    e90

    Zr +0

    e38 39 -1 40 -1

    d.85

    Kr85

    Rb +0e

    36 36 -1

    e.226

    Ra222

    Rn +4He

    88 86 2

    6. What is meant by half-life? Give one example.

    Ans: Is the time required for an activity of a radionuclide to reduce by half.

    T1/2 of Cs-137 is 30 years C-14 (5736y) H-3(12.33y) Co-60(5.27y) Ir-192(73.83d) U-238(4.47x10-9

    y) Th-232(14x10-9

    y)

    7. A company bought a gamma projector using Iridium-192 having activity of 50 Ci.The source need to be changed once the activity reached 5 Ci.

    a. Determine the time (in days) this change will take place. Given T =

    73.83 days,

  • 8/8/2019 Answers to Tutorial

    3/4

    A(t) = A0 e-l t

    Ao = 50 Ci

    A(t) = 5 Ci

    T = 73.83 d

    t = ? d

    T Aot = - ln - = 73.83/ 0.693 x (ln (50/5)) = 106.54 x ln 10 = 245.31d

    0.693 A(t)

    b. Suppose you want to change the source once in 5 years, what would be theactivity of the source to procure?

    A(t) = A0 e

    -l t

    => Ao = A(t) el t

    Ao = ? Ci

    A(t) = 5 Ci

    T = 73.83 d

    t = 5 y = 5x 365 d = 1825 d

    Ao = 5 x e0.693 x 1825 / 73.83

    = 5 x e17.13

    = 5 x 27,508,345.79 Ci = 137.5 x 106

    Ci = 137.5 MCi

    8. What are the old and S.I. units for absorbed dose, equivalent dose and effectivedose?, and how are they correlated ?

    Parameters Old Unit S.I. Unit Correlation

    Absorbed dose (D) rem Gray (Gy) 100 rem = 1Gy

    Equivalent dose (H) rad Sievert (Sv) 100 rad = 1Sv

    Effective dose (E) rad Sievert (Sv) 100 rad = 1Sv

    9. Calculate the dose equivalent and effective dose of a radiation worker whose lungand skin have been subjected to a total 20 Gy of alpha radiation from a uranium

    source.

    Ans: Absorbed Dose (D) = 20 Gy

    WR (alpha) = 20

    WT (lung) = 0.12

    WT (skin) = 0.01

  • 8/8/2019 Answers to Tutorial

    4/4

    H = D x WR =20 x20 = 400 Sv

    E (lung) = H x WT (lung) = 400 x 0.12 = 4.80Sv

    E (skin) = H x WT (skin) = 400 x 0.01 = 0.04 Sv

    10. What are the sources of natural and man-made ionizing radiation? What is theaverage annual dose of ionizing radiation received by members of the public?

    Ans: Sources of radiation

    Natural radiation in the environment (Cosmic, terrestrial ) Medical exposure

    Occupational exposure Artificial radioactivity in the environment

    products Medical X ray (0.1 mSv per chest x ray), nuclear medicine (diagnostic

    and therapeutic) [0.3 mSv/y] Nuclear weapon test - radioactive fall-out (.006 mSv/y)

    Nuclear power (0.008 mSv/y to the public), industries (process control,QC)

    Consumer products: smoke detectors, luminous watches, gas mantles,TV. [very low]

    (Source: UNSCEAR, 2.7 mSv total)

    48 %9%

    11 %

    0%

    17 %15%

    Radon

    Internal

    Medical

    Others

    Gamma

    C osmic