Air stability problem
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Transcript of Air stability problem
Air stability problem
Surface air = 35oCtemp @ 4000m = -10oC
Dewpoint = +10oC
questions
• Is the air stable?• What’s the temp of the environmental air at
3500m?• What is the temp of the lifted air at 3500m?• Why are the DAR and PAR different (6.5oC and
10oC / 1000m)?
Why is PAR different from DAR
• PAR pseudo-adiabatic lapse rate (wet air, 6.5oC/100m)
• DAR = dry adiabatic lapse rate (10oC/1000m)
• They are different because the cooling rates are different for dry and wet air. The wet air condenses and releases heat.
Figure the Environmental Lapse Rate
• ELR =change in temp / change in altitude * 1000
• (35oC - -10oC) / 4000m *1000 =45oC / 4000m =11.25oC/1000m
• ELR > 10oC/1000m unstable, so this is unstable
Temp of air parcel air at 3500m
• Figure Lifting condensation level (LCL):(Temp at surface – dewpoint) / 10oC * 1000 m(35oC - 10oC) / 10oC * 1000m = 2500meters
• Temp at 2500m is 10oC, the same as the dewpoint
• We know the wet adiabatic lapse rate = 6.5oC/1000m
• 2500m + 1000m = 3500m10oC (dewpoint at 2500m) - 6.5oC = 3.5o
Temp of environmental air at 3500m • We know the environmental lapse rate = 11.25oC/1000m (calculated earlier)
• At 4000m, we’re given the temp = -10oC4000m – 3500m = 500m (i.e. ½ of 1000m)-10oC + ½(11.25oC/1000m) -10oC + 5.625oC= -4.375oC
• Note the environmental air is colder than the air parcel, which means the parcel is still rising and the system is unstable
• Alternate calculation going upwards:surface temp = 35oC3500m = 3.5 * 1000m35oC –11.25oC – 11.25oC – 11.25oC – 5.625oC = -4.375oC