Advance Microprocessor Key

8/9/2019 Advance Microprocessor Key

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A19

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74LS138

3 to 8 Decoder

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ez

Memorandum of Instruction Solution of Numerical Problems

Name of Examination:

B.E.

emester: 6

th

ranch:

AEI, El , EEE, ET T

Subject:

Advanced Microprocessor Interfacing

ubject Code:

328613 (28)

2.

b)

Step

I:

Address decoding table:

Memory

H ex

A dd

ress

Binary address

IC

A

l 9 A 18

A

17 A 16 A 1 5

A

14 A 1 3

A l2 A ll A

10

A9

A8

A7 A6

A5

A4

A3

A2 Al

A0

2114

0

0 0 0 0

0

0 0

0 0 0

0 0

0

0

S RA M

1

007FE

0

1

1 1

1 1 1

1 1 1

2114

0 0 8 0 0

0

0 0

0 0 0

0 0 0

0

SRAM-3

00FFE

0

1

1 1 1

1 1 1

1 1

Step II: Design of CS (Chip Select):

Step Ill: Connection of memory IC 2114 with microprocessor 8086 in minimum mode

1


2/12

IL:4 SRAM

Ere:

-

E V E N H A N K

1K x

SRA

o a d -

O D D B A N E

NB CX

3


4/12

Again it can be modified as

[ A X + A X * 2 1 ] + [DX + DX 2 2

]+ [BP * 2

1 ] --> CX

M O V B X , A X

S A L A X , 1

A D D B X , A X

A D D B X , D X

MOV CL, 02h

S A L D X , CL

A D D B X , D X

S A L B P , 1

A D D B X , B P

M O V C X , B X

HLT

4.

a)

There is no direct instruction to set or reset the trap flag. Trap flag can be set or

reset by using tack instruction.

To set the trap flag

D1 5

4,

D8 D7

D8 D7

.:

DO

1

D 8 D 7

8 hiSB S

M O V A X ,

0100h

015

P US H A X

D1 5

P OP F

8 LSB S

D O

D O

A X

SS: SP

FLAG REG.

To reset the trap flag

4 8 MSB S

8 LSB S

MOV AX, 0000h

P U S H A X

P OP F

0

A X

D 8

15 7

O

SS: SP

D 8

15

7

O

0

FL A G R E G.

D1 5

D8 D7

T F

D O

4


5/12

(b)

31

16 15

0

EAX

Ali

A L

AX

EBX

BH BL BX

ECX

CH CL

CX

E D X

D H

D L

D X

ESP

BP

ESI

S I

EN D I

ESP

SP

31

1 6 1 5

0

EIP

IP

EFLA G S F L AG S

15

S E G M E N T

REGISTERS

CS

S S

DS

ES

F S

G S

(c)

The

given

value

in

DS is 1007h

Expressing this value in the binary form, we get

13:P=01301000000000111

By comparing this value with the format of segment register in the protected mode, we

get

1 5

13- bit Descriptor number

TI I

PL

16 bit

Segment register

Since the last two significant bits are used to define the RPL and are both 1, so

RPL = 11 (3)

The next bit i.e. bit 2 is indicates table index, TI = 1 so the segment descriptor is in the

local descriptor table (LDT)

5


6/12

The most significant 13 bits are used to select any one descriptor from the total 8192

(8K) descriptors

(0001000000000)

2

=

x 2 2

+ 0 x 2

1 1

+ 0 x 2 1 + 1 x 2

9

+ 0 x 2

8 +

x 2

= (512)

1 0

Each descriptor is of 8 bytes; therefore the address of the 512 th descriptor is

Address of the segment descriptor = Base address + (512 x 8)

512 x 8 = 4096

=1000h

Therefore,

Address of the segment descriptor =

10000000h + 1000h

=

10001000h

(d)

Applications

41

(User softw are)

Application

Services

(OS extensions)

System

Services

PL= 0

111.

1 0

Restricted access

Task C

Task I3

PL (Privilege level)

6

Task A

Unre tricted

L oc

access


7/12

C O N T R O L W O R D

S T A TU S W O R D

5.

b)

CONTROL UNIT

NUMERIC EXECUTION UNIT

I= ORENS

I

US

EXPONENT

M O D U L E

P R O G R A B L M A B L

SNIFFER

F U N C T I O N

BUS

INTERFACE

- 16 w -

68,

64,

ARITRMAT1C

M O D U L E

TEMPORARY

REGISTERS

DATA 14..40

DATA

B U F F E R

N E C I N S T RU C T IO N

M I C R O C O D E

CONTROL UNIT

16

O P E R A N D S

Q U E U E

16

A D D R E S S IN G &

B U S T R A CK I N G

EXCEPTION

P O I N T E R S

T

A

G

R

E

S

T

E

R

--REGISTER STACK ---

M I

0 BITS

S T A T U S

A DDRES S

c )

15

RC

PC IEM

PM

UM

OM 71 4

DM

IM

C

NVALID OPERATION MASK.

DENORMALIZ ED OPEARND MASK

ZERO DIVIDE MASK

OVERFLOW MASK

UNDERFLOW MASK

PRECISION ERROR MASK

INTERRUP T MASK ( .1 INTERRUP TS ARE MASK ED)

PRECISION CONTROL

ROUNDING CONTROL

INFINITY CON TROL

R E S E R V E D

7


8/12

(d)

Area of a circle is A= fl

* R

2

Program:

MOV AX, 3000h

M O V D S , A X

Initialize data segment

MOV SI, 0200h

Initialize source index

MOV DI,

0300h

Initialize destination

index

MOV CX, 000Ah

/

count for 10 values

REPEA T:

LD [S I]

Load

1

s t

value of radius

to ST [Stack top ST (0)]

FS T S T (1)

Store value

of ST

to

ST (1)

F M U L

Multiply ST (0) * ST (1)

= [ST (0)] 2

4 ST (0)

FLD PI

Load

n to ST

F M U L

Multiply ST (0)

*

ST

(1) 4 ST (0)

FST [DI]

Save area in memory loc.

INC SI

Point to the next source

Index for next radius

INC DI

L O O P R E P E A T

H L T / I N T 3

8


9/12

6. b)

RESET

V

Transfer ICWI to Master and

all Slave (Port 0)

Transfer ICW 2 to Master and

all Slave (Port 1)


all Slave (Port I)


all Slave (Port 1)

8259 is Initialize and R eady

to Receive Interrupts

9


10/12

BCD

O P E R A T I O N

0

1

H E X A D E C I M A L

C O U N T

B C D C O U N T

P P M - M O D E

M 2 Ml

MO M O D E

0

0 0

M O D E 0

0

0

I

M O D E 1

X 0

M O D E 2

X

1

M O D E 3

1

0 0

M O D E 4

1 1

M O D E 5

S C - S E L E C T C O U N T E R

SCI

S C O

O P E R A T I O N

0

0

S E L E C T CO U N T E R 0

0

S E L E C T C O U N T E R 1

1

0 S E L E C T C O U N T E R 2

1

I L L E G A L

( 8254 REA D BA CK

C O M M A N D )

RL

-

R E A D / L O A D

R L 1

R L O

O P E R A T I O N

0

o

La t c h Cou n te r f o r " R EA D O N F LY "

Opeartion

0

Read/Load LSB only

1

0

Read/Load MSB ony

1

Read/L oad L SB f i r st then M SB

D T

/R=0

I

D 7

6

5 D4 D3

2 D o

Sc I S C O R L 1

R L 0

M 2 MI MO

BCD

(d)

7. b)

C L K

T2

3

4

(8284)

B H E / S 7 &

S7* S to S3

A191S6

A l

t s

A L E

D15

D

i2

S

O

D I R D C / I O R C

DT /II 7\

D EN

R E A D Y

= I

(8284)

S2

$ U

inactive

2

S p A c t ive

1 0


11/12

A18 A19

M

0

To cs

o

17

A16

A 1 5

(c)

Total memory = 32K word = 64K bytes

IC available = 16K bytes

Hence number of RAM IC required = 64K x 8/16K x 8 = 4 IC s

So,

Even bank = 2 IC s of 16K x 8 RAM

Odd bank = 2 IC s of 16K x 8 RAM

Step I: Address decoding table for

even

bank:

Mown

ex

Addles

Binary address

IC

A 19

A 1 8

A17 A16

A

15

A

14

A

13

A

l2 A11 A

10

A9 A g

A7

A 6

A 5

A 4

A 3

A2 A

l AO

16Kx8

0 0 0 0 0 0

0

0 0

0 0

0

0 0

RAM -- C.

0 7 F F E

0

1

1

1

1

1

1

1

1

16Kx8

0 8 0 0 0

0

0

0

0

0 0

0

0

0

RAM--@

OFFFE

0

1

1 1

1

1 1

1 1

To D e code r

CF

JC 2000h

CF =1 then branches

to the

address 2000h

JMP 3000h

CF =

0 then branches to the address 3000h

12

Advance Microprocessor Key

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