(Aademi Sssio : 2017 - 2018) BENGALURU, KARNATAKA JEE (Main + Advanced… · T T : FULL SYLLABUS T...

READ THE INSTRUCTIONS CAREFULLY

GENERAL :

1. This sealed booklet is your Question Paper. Do not break the seal till you are toldto do so.

2. Use the Optical Response sheet (ORS) provided separately for answering the questions.

3. Blank spaces are provided within this booklet for rough work.

4. Write your name, form number and sign in the space provided on the back cover of thisbooklet.

5. After breaking the seal of the booklet, verify that the booklet contains 28 pages and thatall the 18 questions in each subject and along with the options are legible. If not, contactthe invigilator for replacement of the booklet.

6. You are allowed to take away the Question Paper at the end of the examination.

OPTICAL RESPONSE SHEET :

7. The ORS will be collected by the invigilator at the end of the examination.

8. Do not tamper with or mutilate the ORS. Do not use the ORS for rough work.

9. Write your name, form number and sign with pen in the space provided for this purpose onthe ORS. Do not write any of these details anywhere else on the ORS. Darken theappropriate bubble under each digit of your form number.

DARKENING THE BUBBLES ON THE ORS :

10. Use a BLACK BALL POINT PEN to darken the bubbles on the ORS.

11. Darken the bubble COMPLETELY.

12. The correct way of darkening a bubble is as :

13. The ORS is machine-gradable. Ensure that the bubbles are darkened in the correctway.

14. Darken the bubbles ONLY IF you are sure of the answer. There is NO WAY to eraseor "un-darken" a darkened bubble.

15. Take g = 10 m/s2 unless otherwise stated.

PAPER – 1

Test Type : FULL SYLLABUS Test Pattern : JEE-AdvancedTEST DATE : 22 - 04 - 2018

CLASSROOM CONTACT PROGRAMME(Academic Session : 2017 - 2018)

Please see the last page of this booklet for rest of the instructions

Time : 3 Hours Maximum Marks : 201

ENG

LISH

)1001CJA102117097)Paper Code

(1001CJA102117097)

SCORE(ADVANCED)JEE (Main + Advanced) : LEADER & ENTHUSIAST COURSE

BENGALURU, KARNATAKA

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Target : JEE (Main + Advanced) 2018/22-04-2018/Paper-1

1001CJA102117097

Space for Rough Work

SOME USEFUL CONSTANTSAtomic No. H = 1, B = 5, C = 6, N = 7, O = 8, F = 9, Al = 13, P = 15, S = 16,

Cl = 17, Br = 35, Xe = 54, Ce = 58,Atomic masses : H = 1, Li = 7, B = 11, C = 12, N = 14, O = 16, F = 19, Na = 23, Mg = 24,

Al = 27, P = 31, S = 32, Cl = 35.5, Ca=40, Fe = 56, Br = 80, I = 127,Xe = 131, Ba=137, Ce = 140,

· Boltzmann constant k = 1.38 × 10–23 JK–1

· Coulomb's law constant pe9

0

1 = 9×104

· Universal gravitational constant G = 6.67259 × 10–11 N–m2 kg–2· Speed of light in vacuum c = 3 × 108 ms–1· Stefan–Boltzmann constant s = 5.67 × 10–8 Wm–2–K–4· Wien's displacement law constant b = 2.89 × 10–3 m–K· Permeability of vacuum µ0 = 4p × 10–7 NA–2

· Permittivity of vacuum Î0 = 20

1cm

· Planck constant h = 6.63 × 10–34 J–s


Leader & Enthusiast Course/Score(Advanced)/22-04-2018/Paper-1

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PART-1 : MATHEMATICSSECTION–I(i) : (Maximum Marks : 15)

This section contains FIVE questions. Each question has FOUR options (A), (B), (C) and (D). ONLY ONE of these four options

is correct. For each question, darken the bubble corresponding to the correct option in the ORS. For each question, marks will be awarded in one of the following categories :

Full Marks : +3 If only the bubble corresponding to the correct option is darkened.Zero Marks : 0 If none of the bubbles is darkened.Negative Marks : –1 In all other cases

1. - -+ + + +æ öç ÷+ +ç ÷+

æ öç ÷+ç ÷ç ÷è øè ø

ò1 2 1 2

3tan x x ln x tan x x ln x(2x 2x 1)2e e dx

1xx

is equal to

(A) - + + +1 2

3tan x x ln xx e C

3 (B) - + + +

1 22

tan x x ln xx e C2

(C) - + + +1 3tan x x lnxxe C (D) - + +1 22 tan x xx e C(where C is constant of integration)

2. The number of solution(s) of the equation 0 2021

2 2

tdx1(x x ) x t t xx

0e xe dx

¥

æ ö+ +ç ÷ -è ø

ò= ò is

(A) 0 (B) 2 (C) 4 (D) 6


BEWARE OF NEGATIVE MARKINGHAVE CONTROL ¾® HAVE PATIENCE ¾® HAVE CONFIDENCE Þ 100% SUCCESS

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3. If the solution of the differential equation +æ ö+- = +ç ÷+è ø

3

2x4 2

x 12 2

dy x 3xy (4x 3)edx (x 1)

is in the form

y = f(x) (where f(0) = 1), then f(1) + f(–1) is

(A) 2 e (B) 3 e (C) 4 e (D) 6 e

4. If a is the value of ( )( )( ) ( )( )

( )

-- -

-®

+ + -101

110 101 1tan x

1 10x 0

1 tan x e tan x 1lim

etan x and the range of the function

( )( ) ( )( )

-

- -

=+ +

21

22 21 1

2 tan xf(x)

3 tan x 2 tan x 3 is (a, b), then the value of

21 ab

æ öp+ +ç ÷aè ø

is

(A) p + p +4 215 36

2 (B) 222

27p

+ (C) p + p +4 215 40

2 (D) 2272

2p

+

5. If - =+

z 2019 1z 2019

and - + + - -z 3 4i z 5 20i is minimum, then the value of -q®+ q+ + q

2

10

sin(9z 30)limtan (z z 2 )

is

(A) 195

2 (B) 195

4 (C) -

1952 (D)

-195

3



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SECTION–I(ii) : (Maximum Marks : 32) This section contains EIGHT questions. Each question has FOUR options (A), (B), (C) and (D). ONE OR MORE THAN ONE of

these four option(s) is (are) correct. For each question, darken the bubble(s) corresponding to all the correct option(s) in the

ORS For each question, marks will be awarded in one of the following categories :

Full Marks : +4 If only the bubble(s) corresponding to all the correct option(s) is (are)darkened.

Partial Marks : +1 For darkening a bubble corresponding to each correct option,Provided NO incorrect option is darkened.

Zero Marks : 0 If none of the bubbles is darkened.Negative Marks : –2 In all other cases.

for example, if (A), (C) and (D) are all the correct options for a question, darkening all thesethree will result in +4 marks; darkening only (A) and (D) will result in +2 marks; anddarkening (A) and (B) will result in –2 marks, as a wrong option is also darkened

6. Let f : [0, 1] ® R be defined as f(x) = h(x) + 9x – 4, where h(x) is some integrable function.

If 1 1

0 0

1f (x)dx x f (x)dx2

= =ò ò , then the possible value(s) of 1 2 2

0((f (x)) (x x)h '(x))dx+ -ò can be

(A) 52 (B)

32 (C) 1 (D) 2

7. If z1, z2 are two non-zero complex numbers such that - = +2 2 2

1 2 1 219z 31z 19z 31z then

(A) ampæ ö p

= ±ç ÷è ø

2

1

zz 2 (B)

2

1

zz is purely real

(C) 21

zz is purely imaginary (D) ( )+ = q + q

2 21 2 2 1 3z z z z log sin cos


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8. Consider the planes P1, P2 and points A(2, 5, 1) and B(1, 3, 0) whereP1: x + y + z = 3

P2 : 2x + y – z = 4then identify the correct statement(s)

(A) distance between line AB and points common to P1, P2 is equal to 1

5 3 units

(B) projection of segment AB on P1 is equal to 6

3 units

(C) projection of segment AB on P1 is equal to 2 2

(D) area enclosed by locus of all points on P1 which are at a distance of 3 units from B is equal

to p26

3 sq. units

9. Identify the correct statement(s). Number of straight lines passing through (1, –4) and whichcan make an area of(A) 6 sq. units with coordinate axes is 2

(B) 10 sq. units with coordinate axes is 4(C) 8 sq. units with coordinate axes is 3(D) 9 sq. units with coordinate axes is 3

10. Let (1 – x + x4)10 = a0 + a1x + a2x2 + a3x3 + ..... + a40x40 then choose the correct option(s).

(A) a0 + a2 + a4 + ..... a40 = +103 1

2 (B) a0 = a40 = 1

(C) a1 = a39 (D) a39 = 0



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11. Let =20 digits

x 111...1114243 , =20 digits

y 444...4414243 , =10 digits

z 777...7714243 , =10 digits

w 999...9914243 then choose the correct option(s).

(A) - =249x 9z 7

14w 9 (B) -

=249x 9z 2

14w 9

(C) 9y = 4w2 + 8w (D) +æ ö = +ç ÷+è ø

1016 x y 10 15 z w

12. Words are formed using all the letters of the word 'JEEADVANCED'.Let 'a' denotes the number of words in which all the vowels are together.

'b' denotes the number of words in which vowels as well as consonants are separated.'c' denotes the number of words which begin and ends in vowels.Which of the following is(are) correct?

(A) c > a > b (B) c > b > a (C) a + b + c = 460 6 (D) a + c = 91b

13. A parabola whose focus is S(6, 8) is touching the co-ordinate axes, then which of thefollowing statement(s) is/are correct ?(A) The equation of circle whose diameter is the portion of the tangent at the vertex of

the parabola between the co-ordinate axis is x2 + y2 – 6x – 8y = 0.

(B) If P and Q are the ends of a focal chord of the parabola, then 1 1 5

SP SQ 24+ = .

(C) Equation of the latus rectum is 4x + 3y = 48

(D) If P and Q are the ends of a focal chord of the parabola, then 1 1 1

SP SQ 5+ =

SECTION –II : Matrix-Match Type & SECTION –III : Integer Value Correct TypeNo question will be asked in section II and III


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SECTION–IV : (Maximum Marks : 20) This section contains FIVE questions. The answer to each question is a SINGLE DIGIT INTEGER ranging from 0 to 9, both

inclusive. For each question, darken the bubble corresponding to the correct integer in the ORS. For each question, marks will be awarded in one of the following categories :


1. If f(x) = x10000 – x5000 + x1000 + x100 + x50 + x10 + 1 then number of rational roots of f(x) = 0 isequal to

2. If a´b = b´ g + a + bˆ ˆ ˆˆ ˆ ˆ ; then the sum of possible value(s) of

é ùa b b gê úê úa g a ´bê úa ´ g + a + g +ê úê úê úë û

ˆ ˆˆ ˆ· ·ˆˆ ˆ ˆ·

ˆ ˆ ˆ ˆ 1 is

(where [· ] denotes greatest integer function)3. Let f : R ® R be defined as f(x) = x2 – 4x + 2a and h : R ® R be defined as h(x) = -x 2 . If the

equation f(x) = h(x) has four distinct real roots and the range of ‘ a ’ is (a, b) then the value of(10a – 8b) is



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4. If ®¥

+ +=

+ +

44 n x

4 nn

(1 cos x ) ef(x) lim1 (1 cosx )

where x4 Î [0, 2p] then the total number of points of discontinuity

of f(x) is

5. If the range of real-valued function - -= + + -1 1f(x) cos (2x) 2 1 cos (2x) is é ù+ë ûa, b 1

(where a and b are positive integers) then (a + b) is equal to


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PART-2 : PHYSICSSECTION–I(i) : (Maximum Marks : 15)

This section contains FIVE questions. Each question has FOUR options (A), (B), (C) and (D). ONLY ONE of these four options is

correct. For each question, darken the bubble corresponding to the correct option in the ORS. For each question, marks will be awarded in one of the following categories :


1. A spring-loaded toy gun is used to shoot a ball of mass M straight up in the air. The ball is notattached to the spring. The ball is pushed down onto the spring so that the spring iscompressed a distance S below its unstretched point. After release, the ball reaches a maximumheight 3S, measured from the unstretched position of the spring (see diagram). The springconstant of the spring is :-

Mass =M

Spring compressedMass released from rest

SSpring unstretched

3S

Maximum Height

(A) Mg/S (B) 2Mg/S (C) 4Mg/S (D) 8Mg/S



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2. An object of mass m is attached to an ideal spring of spring constant k and moves on a frictionlesshorizontal surface. The mass is at X = 0 (where the spring is unstretched) and it has an initialvelocity of V0 in the positive X direction as shown. The average velocity of object between t = 0and t = T/3, where T is the time period of oscillation of the mass on the spring is.

mk

Spring uncompressed

V0

X = 0

(A) 03V 2sin2 3

pp

(B) 03V sin2 4

pp

(C) 0V 2sin2 3

pp

(D) 0V sin2 3

pp

3. The index of refraction of glass can be increased by diffusing impurity. It is then possible tomake a lens of constant thickness. Given a disk of radius ‘a’ and thickness ‘d’ (a >>d),Find the radial variation of index of refraction m(r) which will produce a lens of focal length F.(At r = 0, m = m0 and F >> a)

(A) 2

0r

r2Fdm

m = (B) 2

r 0r

2Fdm = m - (C)

2

r 0r

2Fdm = m + (D)

2

r 0rFd

m = m +


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4. A non uniform ball of mass M and radius R, rolls from rest down a ramp and onto a circular loopof radius r. The ball is initially at height h above the bottom of loop. At the bottom of loop thenormal force on ball is twice its weight. Moment of inertia of ball is given by I = bMR2 . Find b(Assume h >> R and r >> R)

h r

(A) hR (B)

2hr (C)

2h 1r

- (D) 2h 1r

+

5. A small car is moving along a straight level highway at a speed of 3v. The car hits from behinda large truck moving in the same direction at speed v. After the collision, the car is stuck ontothe truck. During the collision, which vehicle experiences the greater average forces(magnitude) ?(A) The car(B) The truck(C) The forces are equal(D) Impossible to determine without information about the masses



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6. A metal sphere of radius a is surrounded by a concentric metal sphere of inner radius b (b>a).The space between the spheres is filled with a material whose electrical coductivity s varieswith the electric field strength E, according to the law s = KE, where K is aconstant. A potential difference V is maintained between two spheres. Choose correct statement(s)

(A) Electric field at a distance r from centre (a < r < b) is given by 1 IEr 4 K

=p

, where I is

current between spheres

(B) Electric field at a distance r from centre (a < r < b) is given by 21 IE

4 Kr=

p, where I is

current between spheres

(C) Current I between spheres is given by 2

2

e

4 KVIbloga

p=

æ öæ öç ÷ç ÷

è øè ø

(D) Current I between spheres is given by 24 KVI

ba

p=

æ öç ÷è ø


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7. Consider a black sphere of radius R at temperature T which radiates to distant black surroundingat zero kelvin. The temperature of black sphere always remains T. Now surround the spherewith a nearby heat shield in the form of a thin black shell whose temperature is determined byradiative equilibrium. Now choose correct statement(s)(A) The heat shield reduces the total power loss to surrounding by system to half of initial

value.(B) There is no change in power loss to surrounding by the system.

(C) At equilibrium temperature of thin black shell is 1 /4T

(2)(D) At equilibrium temperature of thin black shell is T

8. A uniform rubber band having natural length 2pa is having stiffness K. Mass of rubber band isM. Now it is placed on a frictionless cone (vertical axis) with semi vertical angle a as shown indiagram. In equilibrium position.

a

(A) Tension is ring is T = cotMg2

ap

(B) Tension is ring is T = tanMg

2a

p

(C) In equilibrium final radius of rubber band is r = a + 2Mg cot

4 Ka

p

(D) In equilibrium final radius of rubber band is r = a + 2Mg tan

4 Ka

p



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9. A conducting spherical shell of inner radius a and outer radius b is made up of a material ofresistivity r and negligible dielectric activity. At time t = 0, material of shell is electricallyneutral and a charge q0 is some how located at the centre of shell (i.e. at time = 0, there are noinduced charges, they will appear afterward).Choose correct statement(s) :(A) When –Qt charge is induced at inner surface at time t, then electric field in the material of

shell is 0 t20

q – QE =4 rpÎ where r is distance of point under consideration from centre of shell.

(B) Current through shell at this moment (discussed in option A) is 00

q – QI =Î r

(C) At time t we can write t0 t 0

dQ dtq – Q

=Î r

(D) At time t, value of Qt is given by 0t–

t 0Q = q (1 – e )Î r

10. If you were to blow smoke into the space between the plane of S1 & S2 where S1 & S2 arepinhole of standard YDSE and the viewing screen of figure, the smoke would show

S1

S2

Q

yr1

r2q q

P

O

L

d

d

Viewing screen

(A) No evidence of interference between the barrier and the screen(B) Evidence of interference everywhere between the barrier and the screen.(C) Maxima are localised and located on hyperboloids.(D) Maxima are non-localised and located on hyperbolic planes.


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11. In a series RLC A.C. circuit, power factor remains same when capacitor is replaced by anothercapacitor having half of the capacitance of initial one keeping other parameters same. Choosecorrect option(s) (R is resistance, L is inductance, C is initial capacitance)

(A) Value of angular frequency of source is 1.5LC

w =

(B) Value of angular frequency of source is 1

LCw =

(C) There is no effect on rms value of current in the circuit(D) Average power dissipated in the circuit remains unchaned .

12. A glass is filled to a height h0. Volume of liquid is V0 and density is r . A straw with uniformcross-sectional area ‘A’ is used to drink liquid by creating a pressure at top Ptop that is lessthan atmospheric pressure. Work done by the person in order to drink all the liquid in glasswith constant velocity u (of liquid) is -

h0

h

(A) 200h 1W V g h u2 2

é ùæ ö= r - +ê úç ÷è øë û

(B) ( ) 20 0 1W V g h h u2é ù= r - +ê úë û

(C) 20 01W V u V gh2

= r + r (D) 20 01W V u gh2

= r + r



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13. A particle having charge Q and mass M = 2m is tied to two identical particels, each having massm and charge q. The particles are connected with ideal strings of equal length l. The system isheld at rest on a smooth horizontal surface (with string taut) in a position where string make anangle of 60° between them. From this position the system is released :

60°

M,Q

ll

m,q m,q

(A) The amplitude of oscillation of M is 34l

(B) Maximum speed acquired by M is 0

q 14 mpÎ l

(C) When all the particles are in straight line speed of each particle is same.

(D) Tension in string when particles are in straight line is ( )20

qT 4Q 5q16

= +pÎ l



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1. Consider the diagram, a probe of mass m is projected with a velocity of 0GMv4R

= in tangential

direction. The probe has a rocket which fires to put it into a circular orbit at that height.Assume that, at all times, the probe is at the same distance from the planet and that thereare no forces acting on the probe other than the planet’s gravity and the rocket. The work done

by the rocket on probe is found to be GMm3nR . Find n

RM

2R

mv0

2. A charged particle sits at the centre of a circular region containing a magnetic field, Br

. Thefield B B(r)=

r r depends only on radial position r, and is perpendicular to the plane of circle.

The total magnetic flux through the circle is zero. The particle is given a kick so that it leaves

the circular region, then at the instant it leaves, its velocity makes an angle n 4p

´ with outward

radial direction. Find n.Space for Rough Work


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3. The masses of both the wedge and the solid cylinder shown in the figure are m, the radius of thecylinder is R. The wedge can slide without friction on the ground. The minimum value of thecoefficient of static friction between the wedge and the cylinder, if the cylinder rolls withoutslipping along the wedge and the angle of elevation of the wedge is a = 30º, is found to be

12 n

m = . Find n

Rm

ma

4. Fundamental frequency of a stretched sonometer wire is f0. When its tension is increased by96% and length decreased by 35%, its fundamental frequency becomes h1 f0. When its tension isdecreased by 36% and its length is increased by 30%, its fundamental frequency becomes

h2 f0. The value of 1

2

hh is found to be

7n . Find n.

5. In surveying, sometimes a value can be found for an inaccessible length l (such as the height of

a tall tree) by measuring other three lengths l1, l2, l3 in terms of which 1 2

3=l l

ll

. Suppose we

perform such an experiment and obtain the following results (in feet) l1 = 200 ± 2,l2 =5.5 ± 0.1, l3 = 10.0 ± 0.4. If in this experiment value of l is expressed as l = 110 ± x, find valueof x (in feet)


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PART-3 : CHEMISTRYSECTION–I(i) : (Maximum Marks : 15)

This section contains FIVE questions. Each question has FOUR options (A), (B), (C) and (D). ONLY ONE of these four options

is correct. For each question, darken the bubble corresponding to the correct option in the ORS. For each question, marks will be awarded in one of the following categories :


1. In a galvanic cell if salt bridge is replaced by inert platinum sheet, the cell will

(A) not work further : as positive and negative charges will accumulate on respective sides.(B) not work further : as platinum performs poorly as salt bridge.(C) Work as previous : as platinum will perform as salt bridge.

(D) Produce less potential : as platinum performs poorly as salt bridge.2. The molar volume of liquid benzene (density = 0.87 g ml–1) increases by a factor of 2610 as it

vaporizes at 27ºC and that of liquid toluene (density = 0.85g ml–1) increases by a factor of 6800at 27ºC. A solution of benzene and toulene at 27ºC has vapour pressure of 51.1 torr. Assumingvapour to behave as ideal gas incorrect statement among the following (approx)[Given : R = 0.08 litre-atm/K-mole](A) Vapour pressure of pure liquid benzene at 27ºC is 77.95 torr.

(B) Vapour pressure of pure liquid toluene at 27ºC is 24.25 torr.(C) Mole fraction of Toluene in liquid phase is 0.50.(D) Mole fraction of benzene in vapour phase is 0.50.

3. p- bond order between hetero atoms is maximum in:(A) NaN3 (B) N2O (C) Ca(CN2) (D) KO2



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4. Which of the following molecule on alkaline hydrolysis produces a compound which can showIodoform test ?

(A) Cl

(B) ClCl (C)

Cl Cl

(D) Cl

Cl

5. Which of the following statement is INCORRECT about given compound ?

N

N|H

(II)

(I)

(III)N

N–H(IV)

(A) Compound can not give electrophilic aromatic substitution(B) Nitrogen labelled as (IV) is more basic than (II) but lesser basic than that of (I)

(C) Given compound is having aromatic character.(D) Basic strength of Nitrogen (III) > Nitrogen (IV)


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6. Check correct statement(s) :

(A) Formation of micelles take place only below a particular temperature called Kraft temperature.(B) For soaps, critical micelle concentration is 10–4 M to 10–3M.

(C) As2O3 + H2S ¾¾¾¾¾¾®double

decomposition As2S3(sol) + 3H2O

(D) For tyndall effect, refractive indices of dispersed phase and dispersion medium differ greatlyin magnitude.

7. Check correct statement(s) :

(A) Number of atoms in hexagonal prismatic unit cell is 6.(B) In monoclinic unit cell , two types of lattice arrangements are possible.(C) Due to frenkel defect, dielectric constant of solid increases.

(D) If NaCl is doped with 10–2 mole % of SrCl2, then cation vacancies in one mole of NaClare 6.022 × 1019.



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8. Ortho and para hydrogen do NOT differ in:

(A) Degree of freedom (B) Dipole moment(C) Electron spin (D) Molar mass

9. Select the CORRECT statement about co-ordination isomer(s) of [Co(NH3)6] [Cr(CN)6] whichexhibit stereoisomerism?(A) It is/are optically inactive.(B) Compound contains unpaired electrons.

(C) One of the central metal ion has fully filled t2g orbital.(D) It can exhibit linkage isomerism

10. Only one metal in the form of precipitate or solution can be separated from the mixture of HgS,CuS, PbS, Sb2S3 by using :(A) yellow ammonium sulphide (B) dil. HNO3(C) dil. HCl (D) Hot water

11. Which of the following statement(s) is/are correct about Nylon ?(A) Nylon-66 is a homopolymer of hexamethylene diamine and adipic acid.

(B) Nylon-2-Nylon-6 is alternating polyamide copolymer of glycine and aminocaproic acid.(C) Nylon-6 is produced by prolonged heating of caprolactum.(D) Nylon-6 on further polymerization gives Nylon-66


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12. Consider following reactions

(i) Ni/H (excess)2

200ºC Product(s)

(ii) CH – CH – COOH3OH

D Product(s)

Select INCORRECT statemement(s) :(A) One of the product formed in reaction (ii) is having centre of symmetry.

(B) Products formed in both reactions are unsaturated.(C) Reaction (i) can also be carried out using N2H4/EtoNa(D) Reaction (ii) leads to the formation of lactides.

13. Which of the following reaction(s) will yield benzoic acid as major product ?

(A) Ph – CN +¾¾¾®3H O (B) PhMgBr +

¾¾¾®¾¾¾®2 32

CO H OEt O

(C) Ph – CO – O – CO – Ph 2H OHÅ¾¾¾® (D) Ph – COOCH3 +

¾¾¾¾®¾¾¾®32

MeMgBr H OEt O




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1. A catalyst lowers activation energy of certain reaction from 69.8 kJ mol–1 to 20.0 kJ mol–1.

If rate of reaction increases by factor ex at 27ºC, other things being equal , then find x5

æ öç ÷è ø

.

[Given: R = 8.3 J/K-mole]

2. An ideal gas having initial pressure P, Volume ‘V’ and temperature ‘T’ is allowed to expand

reversible adiabatically until its volume becomes 5.66V while its temperature falls to T2 . How

many degree of freedom do the gas molecule have for this process.[Use log 5.66 = 0.7528 and log 2 = 0.3010][Vibrational degree of freedom is inactive]


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1001CJA102117097


3. A transition metal of 3d-series exhibit its highest oxidation state in its amphoteric oxide as wellas in fluoride.The group number of this element in long form of periodic table = x.Number of valence electrons in it = yThe value of |x – y| is ......

4. How many species are coloured, paramagnetic and act as oxidiser among given ?CsO2 , PbO2, NO2, KO3, NO, F2, Mn+3Aq. , O3 , XeF2

5. 2-Methylpentane on monochlorination produces ‘x’ isomers. Product mixture on fractionaldistillation gives ‘y’ fractions. Then (x – y) is



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Que. Marks Marks Marks Marks section+3 0 –1

I(i) Single If only the bubble If none In allcorrect option 5 corresponding to — of the other 15

the correct option bubbles is casesis darkened darkened

+4 +1 0 –2One or more If only the bubble(s)For darkening a bubble If none In all

I(ii) correct 8 corresponding corresponding to each of the other 32option(s) to all the correct correct option, provided bubbles is casesoption(s) is(are) NO incorrect option darkened

darkened darkened+4 0 –1

Single digit If only the bubble If none In all IV Integer 5 corresponding — of the other 20

(0-9) to correct answer bubbles is casesis darkened darkened

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(Aademi Sssio : 2017 - 2018) BENGALURU, KARNATAKA JEE (Main + Advanced… · T T : FULL SYLLABUS T...

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