8. NIV 112 Data Sheet

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Chem 112 Equations Constants, Conversions And Equations For Use During Exams And Quizzes Equations Data Sheet CHEM 112 – SPRING 2015 54 Conversions Constants 1J = kg m 2 s 2 = C V c = 2.99792458 × 10 8 m s 1 R = 0.08206 L atm mol 1 K 1 1A = C s 1 h = 6.63 × 10 34 J s R = 8.314 J mol 1 K 1 1g = 6.02 × 10 23 amu F = 96,485 C mol 1 0 1 n = 1.0086649 amu N A = 6.022 × 10 23 mol 1 1 1 p = 1.0072765 amu K W = 1× 10 14 at 25 o C Equations k = Ae E a RT Rate = kN ΔG = ΔH T ΔS = nFE ln k = E a RT + ln A ln N t N 0 = 0.693t t 12 = kt ΔG o = 2.303 RT log K = RT ln K ln A = ln A 0 kt E= hν = hc λ ΔG = ΔG o + RT ln Q ln k 1 k 2 = E a R 1 T 2 1 T 1 E = mc 2 ΔG = ΔG o + 2.303 RT log Q t 12 = ln2 k = 0.693 k K a × K b = K W = H + OH E o = 0.0592 n log K at 25 o C ( ) 1 A = 1 A 0 + kt pH = pK a + log X HX E = E o 0.0592 n log Q at 25 o C ( ) K p =K c RT ( ) Δn pK W = pH + pOH = pK a + pK b Molecular Orbital Theory Diagrams Crystal Field Theory Diagram Color Wheel with Wavelength Ranges

Transcript of 8. NIV 112 Data Sheet

Page 1: 8. NIV 112 Data Sheet

Chem 112 Equations Constants, Conversions And Equations For Use During Exams And Quizzes

Equations Data Sheet CHEM 112 – SPRING 2015 54  

 

Conversions     Constants  1J = kg ⋅m2 ⋅s−2 = C ⋅V     c = 2.99792458 ×108 m ⋅s−1     R = 0.08206 L ⋅atm ⋅mol−1 ⋅K−1  

1A = C ⋅s−1     h = 6.63 ×10−34 J ⋅s     R = 8.314 J ⋅mol−1 ⋅K−1  

1g = 6.02×1023 amu     F = 96,485 C ⋅mol−1     01 n = 1.0086649 amu  

    NA = 6.022×1023 mol−1     11 p = 1.0072765 amu  

    KW = 1×10−14 at 25 oC      Equations  

k = Ae−EaRT

⎝⎜⎞

⎠⎟

  Rate = kN   ΔG = ΔH −TΔS = −nFE  

ln k =

−Ea

RT+ ln A  

ln

Nt

N0

= −0.693tt1 2

= −kt   ΔGo = −2.303 RT log K = −RT ln K  

ln A⎡⎣ ⎤⎦ = ln A⎡⎣ ⎤⎦0

− kt   E=hν = hcλ   ΔG = ΔGo +RT ln Q  

ln

k1

k2

=Ea

R1

T2

− 1T1

⎝⎜⎞

⎠⎟   E = mc2   ΔG = ΔGo + 2.303 RT log Q  

t1 2 = ln2

k= 0.693

k  

Ka ×Kb = KW = H+⎡⎣ ⎤⎦ OH−⎡⎣ ⎤⎦  

Eo = 0.0592

nlog K at 25 oC( )  

1A⎡⎣ ⎤⎦

= 1A⎡⎣ ⎤⎦0

+ kt   pH = pKa + log

X−⎡⎣ ⎤⎦HX⎡⎣ ⎤⎦

  E = Eo − 0.0592

nlog Q at 25 oC( )  

Kp = Kc RT( )Δn

  pKW = pH+pOH = pKa +pKb

   

Molecular  Orbital  Theory  Diagrams   Crystal  Field  Theory  Diagram                                                 Color  Wheel  with  Wavelength  Ranges                                                                      

   

Page 2: 8. NIV 112 Data Sheet

Chem 112 Equations Constants, Conversions And Equations For Use During Exams And Quizzes

Standard Reduction Potentials CHEM 112 – SPRING 2015 55

Standard  Reduction  Potentials  in  Water  at  25°C    Half  Reaction   E°1/2(V)  F2 g( ) + 2 e− → 2F− aq( ) + 2.87

H2O2 aq( ) + 2H+ aq( ) + 2 e− → 2H2O ℓ( ) + 1.776  Au+ aq( ) + e− → Au s( ) + 1.69  PbO2 s( ) + 4 H+ aq( ) + SO4

2− aq( ) + 2 e− → PbSO4 s( ) + 2H2O ℓ( ) + 1.685  Cl2 g( ) + 2 e− → 2 Cl− aq( ) + 1.359  O2 g( ) + 4 H+ aq( ) + 4 e− → 2H2O ℓ( ) + 1.23  ClO4

− aq( ) + 2H+ aq( ) + 2 e− → ClO3− aq( ) + H2O ℓ( ) + 1.23  

Pt2+ aq( ) + 2 e− → Pt s( ) + 1.20  2 IO3 aq( ) + 12H+ aq( ) + 10 e− → I2 s( ) + 6H2O ℓ( ) + 1.195  Br2 ℓ( ) + 2 e− → 2Br − aq( ) + 1.065  NO3

− aq( ) + 4 H+ aq( ) + 3 e− →NO g( ) + 2H2O ℓ( ) + 0.96  Ag+ aq( ) + e− → Ag s( ) + 0.799  Fe3+ aq( ) + e− → Fe2+ aq( ) + 0.771  O2 g( ) + 2H+ aq( ) + 2 e− →H2O2 aq( ) + 0.68  I2 s( ) + 2 e− → 2 I− aq( ) + 0.536  I3− aq( ) + 2 e− → 3 I− aq( ) + 0.53  Cu+ aq( ) + e− → Cu s( ) + 0.521  Cu2+ aq( ) + 2 e− → Cu s( ) + 0.337  Sn4+ aq( ) + 2 e− → Sn2+ aq( ) + 0.154  Cu2+ aq( ) + e− → Cu+ aq( ) + 0.153  2H+ aq( ) + 2 e− →H2 g( ) + 0.00  Pb2+ aq( ) + 2 e− → Pb s( ) − 0.126  Sn2+ aq( ) + 2 e− → Sn s( ) − 0.136  Co2+ aq( ) + 2 e− → Co s( ) − 0.277  Ni2+ aq( ) + 2 e− →Ni s( ) − 0.28  Cd2+ aq( ) + 2 e− → Cd s( ) − 0.403  Fe2+ aq( ) + 2 e− → Fe s( ) − 0.440  Cr3+ aq( ) + 3 e− → Cr s( ) − 0.74  Zn2+ aq( ) + 2 e− → Zn s( ) − 0.763  2H2O ℓ( ) + 2 e− →H2 g( ) + 2 OH− aq( ) − 0.83  SO4

2− aq( ) + H2O ℓ( ) + 2 e− → SO32− aq( ) + 2 OH− aq( ) − 0.93  

Mn2+ aq( ) + 2 e− →Mn s( ) −1.18  Al3+ aq( ) + 3 e− → Al s( ) −1.66  Mg2+ aq( ) + 2 e− →Mg s( ) − 2.37  Na+ aq( ) + e− →Na s( ) − 2.71  Ca2+ aq( ) + 2 e− → Ca s( ) − 2.87  Li+ aq( ) + e− → Li s( ) − 3.05