6002 L1 Oei12 Gaps Annotated

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    6.002xCIRCUITS ANDELECTRONICS

    Introduction and

    Lumped Circuit Abstrac

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    6.002x is Exciting!

    Whatsbehind this?

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    and this

    Chip photo of Intels 22nm multicore processor codenamed Iv

    PhotographcourtesyofIntelCorp

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    nPrerequisitesnAP level course on electricity and magnetism; e.g., MITs 8.02 (chMIT OpenCourseware)

    nIt is also useful to have a basic knowledge of solving simple diffenTextbook Agarwal and Lang (A&L)

    Underlined readings (in course-at-a-glance handout) are very imporas they stress intuition

    nWeekly homeworks and labs must be completed by the deadline indicaassignmentnAssessments

    ADMINISTRIVIA

    Homeworks 15%Labs 15%1 Midterm 30%Final exam 40%

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    What is engineering?

    What is 6.002x about?

    Purposeful use of science

    Gainful employment of Maxwells equat

    From electrons to digital gates and op

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    Simpleamplif

    ierabstraction

    Instructionsetabstraction

    Pentium,

    MIPS

    Filters

    Operational

    amplifierabst

    r.

    -+"

    Digitalabstraction

    Programminglanguages

    J

    C

    M

    l b

    P h

    Combination

    allogic

    f

    Lumpedcircuitabstraction

    6.002x

    Natureasobs

    ervedinexperim

    ents

    Physicslawsorabstractions

    lM

    axwells

    lO

    hms

    V=RI

    abstract

    ionfor

    tablesof

    data

    Clockeddigi

    talabstraction

    Analog

    subsystems

    Modulators,

    oscillators

    +

    R

    C

    L

    M

    S

    V

    6.0

    04,

    6.8

    46

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    Consider

    V

    Suppose we wish to answer this question:

    What is the current through the bulb?

    The Bigfrom p

    to E

    Lumped Element Abstraction

    Reading: Skim through Chapter 1 o

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    Apply Maxwells

    Faradays

    Continuity

    Others

    t

    BE

    =

    tJ

    =

    0

    E

    =

    lll

    tdlE

    B

    =

    t

    qdSJ

    =

    0

    qdSE =

    lll

    We could do it the Hard Way

    Integral fDifferential form

    V

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    Instead, there is an Easy WayFirst, let us build some insight:

    Analogy

    I ask you: What is the acceleration?

    You quickly ask me: What is the mass?

    I tell you:

    You respond:

    Done!!!

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    Instead, there is an Easy Way

    In doing so, you ignoredl the objects shapel its temperaturel its colorl point of force applicationl

    Point-mass discretization

    F

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    The Easy WayConsider the filament of the light bulb.

    We do not care aboutl how current flows inside the filamentl its temperature, shape, orientation, etc.

    A

    B

    We can replace the bulb with adiscrete resistor

    for the purpose of calculating the current.

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    The Easy Way

    Replace the bulb with adiscrete resistor

    for the purpose of calculating the current.

    A

    B

    Th E W

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    The Easy Way

    R represents the only property of interest!

    Like with point-mass:

    replace objects with their mass m to find a =

    In EECS, we dothe easy way

    A

    B

    A

    B

    R

    I

    +

    V

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    R

    VI =

    V-I Relationship

    R represents the only property of interest!

    andR

    VI =

    relates element VandIR

    called element v-i relationship

    A

    B

    R

    I

    +

    V

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    R is a lumped element abstraction for th

    L d El

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    Lumped circuit element

    described by itsvi

    relaPower consumed by elem

    Lumped Elements

    +

    -

    Voltage source

    +""Viv

    i

    v

    +

    -

    Resistor

    i

    v

    i

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    Lumped element exampleswhose behavior is completelycaptured by their VI relation

    Demoonly for thesorts of

    questions weas EEs wouldlike to ask!

    Exploding resistor democant predict that!

    Pickle democant predict light, smell

    Demo

    N t f t th h

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    Not so fast, though A

    B

    Although we will take the easy way using lumped afor the rest of this course, we must make sure (at

    the first time) that our abstraction is reasonable.

    are defined for the element

    V IIn this case, ensuring that

    It b d fi d

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    A

    B

    I

    +

    I must be defined.

    V

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    I

    I into = I out of

    True only when in the filament!0=

    tq

    Imust be defined. True when

    BAII = only if 0=

    t

    q

    Were engineers! So lets make it true!

    So, are w

    I

    AS

    BS

    I

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    V

    defined whenABV 0=

    t

    B

    outside elementsdlEVABAB

    =

    seeA&L

    AppendixA.1

    Must also bedefined.

    So lets assume this too!

    So

    Also, signal speeds of interest should be way lower than spe

    A

    B

    I

    +

    V

    W l t th EECS Pl

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    Welcome to the EECS PlaygroThe world

    The EECS playgroundOur self imposed constraints in this playground

    0=

    t

    B Outside

    0=

    t

    q Inside elements

    Bulb, wire, battery

    Whergoodthings

    happe

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    Connecting using ideal wires lumped elementsthat obey LMD to form an assembly results

    the lumped circuit abstraction

    Lumped Matter Discipline (LMD)

    0=

    t

    B outside

    0=

    t

    qinside elementsbulb, wire, battery

    Or self imposed constraints:

    More inChapter 1

    of A & L

    So what does LMD buy us?

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    Replace the differential equations with simple algelumped circuit abstraction (LCA).

    What can we say about voltages in a loop under the lumped ma

    +""

    1R

    2R

    3R

    a

    b

    c

    V

    So, what does LMD buy us?

    For example:

    Reading: Chapter 2.1 2.2.2 of A&L

    What can we say about voltages in a loop un

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    What can we say about voltages in a loop un

    Kirchhoffs Voltage Law (KVL):

    The sum of the voltages in a loop is 0.

    Remembertrue everyour EECS

    +""1

    R

    2R

    a

    b

    c

    V

    Wh b ?

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    What can we say about currents?

    +""V

    What can we say about currents?

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    What can we say about currents?ca

    I

    Kirchhoffs Current Law (KCL):The sum of the currents into a node is 0.

    simply conservation of charge

    KVL d KCL S

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    KVL:

    KCL:

    KVL and KCL Summary

    Summary L d M tt Di i li LMD

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    Remember, our EECS playground

    0=

    t

    B

    0=

    t

    q

    Outside eleme

    Inside element

    Allows us to create the lumped circuit ab

    wires resistors

    Summary Lumped Matter Discipline LMD:Constraints we impose on ourselves toanalysis

    Also, signals speeds of interest should lower than speed of light

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    Lumped circuit element+

    -

    v

    i

    power consumed by element =vi

    Summary

    Summary

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    KVL:

    loop

    KCL:

    node

    0=j j

    0=j ji

    ReviewSummary

    Maxwells equations simplify to algebraic KVLKCL under LMD.

    This is amazi