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### Transcript of 5-6 Direct Variation Lesson Quiz Lesson Quiz Lesson Presentation Lesson Presentation Warm Up Warm Up

• Slide 1
• 5-6 Direct Variation Lesson Quiz Lesson Quiz Lesson Presentation Lesson Presentation Warm Up Warm Up
• Slide 2
• 5-6 Direct Variation Warm Up Solve for y. 1. 3 + y = 2x 2. 6x = 3y Write an equation that describes the relationship. 3. y = 2xy = 2x 3 4. 5. y = 3x 9 0.5 Solve for x.
• Slide 3
• 5-6 Direct Variation MA.912.A.3.12 Graph a linear equationin two variables Also MA.912.A.2.1, MA.912.A.2.13. Sunshine State Standards
• Slide 4
• 5-6 Direct Variation Identify, write, and graph direct variation. Objective
• Slide 5
• 5-6 Direct Variation Vocabulary direct variation constant of variation
• Slide 6
• 5-6 Direct Variation A recipe for paella calls for 1 cup of rice to make 5 servings. In other words, a chef needs 1 cup of rice for every 5 servings. The equation y = 5x describes this relationship. In this relationship, the number of servings varies directly with the number of cups of rice.
• Slide 7
• 5-6 Direct Variation A direct variation is a special type of linear relationship that can be written in the form y = kx, where k is a nonzero constant called the constant of variation.
• Slide 8
• 5-6 Direct Variation Additional Example 1A: Identifying Direct Variations from Equations Tell whether the equation represents a direct variation. If so, identify the constant of variation. y = 3x This equation represents a direct variation because it is in the form of y = kx. The constant of variation is 3.
• Slide 9
• 5-6 Direct Variation 3x + y = 8 Solve the equation for y. Since 3x is added to y, subtract 3x from both sides. 3x y = 3x + 8 This equation is not a direct variation because it cannot be written in the form y = kx. Additional Example 1B: Identifying Direct Variations from Equations Tell whether the equation represents a direct variation. If so, identify the constant of variation.
• Slide 10
• 5-6 Direct Variation 4x + 3y = 0 Solve the equation for y. Since 4x is added to 3y, add 4x to both sides. +4x +4x 3y = 4x This equation represents a direct variation because it is in the form of y = kx. The constant of variation is. Since y is multiplied by 3, divide both sides by 3. Additional Example 1C: Identifying Direct Variations from Equations Tell whether the equation represents a direct variation. If so, identify the constant of variation.
• Slide 11
• 5-6 Direct Variation Check It Out! Example 1a 3y = 4x + 1 This equation is not a direct variation because it is not written in the form y = kx. Tell whether the equation represents a direct variation. If so, identify the constant of variation.
• Slide 12
• 5-6 Direct Variation Check It Out! Example 1c y + 3x = 0 Solve the equation for y. Since 3x is added to y, subtract 3x from both sides. 3x 3x y = 3x This equation represents a direct variation because it is in the form of y = kx. The constant of variation is 3. Tell whether the equation represents a direct variation. If so, identify the constant of variation.
• Slide 13
• 5-6 Direct Variation What happens if you solve y = kx for k? y = kx So, in a direct variation, the ratio is equal to the constant of variation. Another way to identify a direct variation is to check whether is the same for each ordered pair (except where x = 0). Divide both sides by x (x 0).
• Slide 14
• 5-6 Direct Variation Additional Example 2A: Identifying Direct Variations from Ordered Pairs Tell whether the relationship is a direct variation. Explain. Method 1 Write an equation. y = 3x This is direct variation because it can be written as y = kx, where k = 3. Each y-value is 3 times the corresponding x-value.
• Slide 15
• 5-6 Direct Variation Additional Example 2A Continued Tell whether the relationship is a direct variation. Explain. Method 2 Find for each ordered pair. This is a direct variation because is the same for each ordered pair.
• Slide 16
• 5-6 Direct Variation Method 1 Write an equation. y = x 3 Each y-value is 3 less than the corresponding x-value. This is not a direct variation because it cannot be written as y = kx. Additional Example 2B: Identifying Direct Variations from Ordered Pairs Tell whether the relationship is a direct variation. Explain.
• Slide 17
• 5-6 Direct Variation Method 2 Find for each ordered pair. This is not direct variation because is the not the same for all ordered pairs. Additional Example 2B Continued Tell whether the relationship is a direct variation. Explain.
• Slide 18
• 5-6 Direct Variation Tell whether the relationship is a direct variation. Explain. Check It Out! Example 2b Method 1 Write an equation. y = 4x Each y-value is 4 times the corresponding x-value. This is a direct variation because it can be written as y = kx, where k = 4.
• Slide 19
• 5-6 Direct Variation Tell whether the relationship is a direct variation. Explain. Check It Out! Example 2c Method 2 Find for each ordered pair. This is not direct variation because is the not the same for all ordered pairs.
• Slide 20
• 5-6 Direct Variation If you know one ordered pair that satisfies a direct variation, you can write the equation. You can also find other ordered pairs that satisfy the direct variation.
• Slide 21
• 5-6 Direct Variation Additional Example 3: Writing and Solving Direct Variation Equations The value of y varies directly with x, and y = 3, when x = 9. Find y when x = 21. Method 1 Find the value of k and then write the equation. y = kx Write the equation for a direct variation. 3 = k(9) Substitute 3 for y and 9 for x. Solve for k. Since k is multiplied by 9, divide both sides by 9. The equation is y = x. When x = 21, y = (21) = 7.
• Slide 22
• 5-6 Direct Variation The value of y varies directly with x, and y = 3 when x = 9. Find y when x = 21. Method 2 Use a proportion. 9y = 63 y = 7 In a direct variation is the same for all values of x and y. Use cross products. Since y is multiplied by 9 divide both sides by 9. Additional Example 3 Continued
• Slide 23
• 5-6 Direct Variation Check It Out! Example 3 The value of y varies directly with x, and y = 4.5 when x = 0.5. Find y when x = 10. Method 1 Find the value of k and then write the equation. y = kx Write the equation for a direct variation. 4.5 = k(0.5) Substitute 4.5 for y and 0.5 for x. Solve for k. Since k is multiplied by 0.5, divide both sides by 0.5. The equation is y = 9x. When x = 10, y = 9(10) = 90. 9 = k
• Slide 24
• 5-6 Direct Variation Check It Out! Example 3 Continued Method 2 Use a proportion. 0.5y = 45 y = 90 In a direct variation is the same for all values of x and y. Use cross products. Since y is multiplied by 0.5 divide both sides by 0.5. The value of y varies directly with x, and y = 4.5 when x = 0.5. Find y when x = 10.
• Slide 25
• 5-6 Direct Variation Check It Out! Example 4 The perimeter y of a square varies directly with its side length x. Write a direct variation equation for this relationship. Then graph. Step 1 Write a direct variation equation. perimeter = 4 sides times length y =4 x
• Slide 26
• 5-6 Direct Variation Check It Out! Example 4 Continued Step 2 Choose values of x and generate ordered pairs. x y = 4x(x, y) 0 y = 4(0) = 0(0, 0)(0, 0) 1 y = 4(1) = 4(1, 4)(1, 4) 2 y = 4(2) = 8(2, 8)(2, 8) The perimeter y of a square varies directly with its side length x. Write a direct variation equation for this relationship. Then graph.
• Slide 27
• 5-6 Direct Variation Step 3 Graph the points and connect. Check It Out! Example 4 Continued The perimeter y of a square varies directly with its side length x. Write a direct variation equation for this relationship. Then graph.
• Slide 28
• 5-6 Direct Variation Standard Lesson Quiz Lesson Quizzes Lesson Quiz for Student Response Systems
• Slide 29
• 5-6 Direct Variation Lesson Quiz: Part I Tell whether each equation represents a direct variation. If so, identify the constant of variation. 1. 2y = 6x yes; 3 2. 3x = 4y 7 no Tell whether the relationship is a direct variation. Explain. 3.
• Slide 30
• 5-6 Direct Variation Lesson Quiz: Part II 4. The value of y varies directly with x, and y = 8 when x = 20. Find y when x = 4. 1.6 5. Apples cost \$0.80 per pound. Write a direct variation equation to describe the cost y of x pounds of apples. Then graph. 2 4 6 y = 0.8x
• Slide 31
• 5-6 Direct Variation Lesson Quiz for Student Response Systems 1. Identify the equation that represents direct variation and its constant of variation. A. 4y = 12x; 3 B. 4x = 3y 8; 2 C. 4y = 5x + 3; 5 D. 3y = 5x + 11; 3
• Slide 32
• 5-6 Direct Variation Lesson Quiz for Student Response Systems 2. Identify the equation that does not represent direct variation. A. 6x = 8y 14 B. 6y = 12x C. 18x = 3y D. 4y = 12x
• Slide 33
• 5-6 Direct Variation Lesson Quiz for Student Response Systems 3. Identify the relationship that represents a direct variation. x 42840 y 15710 x 151923 y 5811 x 642 y 579 x 248 y 102040 A. B. C. D.
• Slide 34
• 5-6 Direct Variation Lesson Quiz for Student Response Systems 4. Identify the relationship that does not represent a direct variation. x 579 y 123 x 612