410File 3 Area Coordinates Blackboard
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Transcript of 410File 3 Area Coordinates Blackboard
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ITCM 410 - Construction Surveying
File #2Topographic
SurveyingArea Computation
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Area Units
Units :
ft2, mi 2, m 2, km 21 acre = 43,560 ft 2
640 acres = 1 mi2
10,000 m 2 = 1 hectare = 2.47 Acres
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Area Field Measurement
Division into simple figures(triangles, rectangles)
Offset from a straight lineDouble Meridian Distance(DMD)
Coordinates
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Area by Division Into Triangles
A track can be divided into simplegeometric figures.
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Area of a Triangle(when sides are known)
where: a , b , and c are sides of the triangle s = ( a +b +c )
Another formula for area of a triangle isArea = ab sin C
where: C = angle included between side a and b.
))()(( c sb sa s s Area
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Area by Division Into Triangles
The area of a parcel is the sum of theareas of all triangles. The choice ofwhich equation to use will depend onavailable equipment. If an EDM isaccessible, lengths of triangle sides arereadily measured and first equation is
best. If 2 nd equation is used, bothangles and distances must bemeasured.
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Area By Offsets
Irregular tracts can be reduced to series oftrapezoids by right-angle offsets from
points at regular intervals along measuredstraight line.
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Area By Offsets
where: b is the length of a common interval between offsets and h are the offset
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Area By Offsets
Area = 50[(0 + 5.2 + 8.7 + 9.2 + 4.9 + 10.4+ 5.2 + 12.2 + 2.8)/2]= 2860 ft 2
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Area By Offset for a Tract With
Curved Boundary
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Area - Curved Boundary
For irregular curved boundaries, the spacingof offsets along the reference line should beselected so that connecting straight lines ona curved boundary at offset pointsaccurately define the curves.
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Area - Curved Boundary
Area= [60(7.2+11.9)+80(11.9+14.4)+100(14.4+6.0)+30(6.0+6.1)+105
(6.1+11. 8)+60(11.8+12.4)]= 4,492 ft
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Area Map Measurement
Division of AreaCoordinate Squares
PlanimeterComputer software
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Area Map Measurement
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Area by Coordinates
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Example
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Area by Coordinates
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Area by Coordinates
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Area by Coordinates
Sum the productsof diagonal termsupward to theright:
(1,371.35 734.98) +(691.17 908.98) +(100.00 239.96) +
(208.89 100.00) +(1,169.72 857.00) =
= 2,683,510
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Area by Coordinates
Sum the productof diagonal termsdownward to theright:
(857.00 691.17) +(734.98 100.00) +(908.98 208.89) +
(239.96 1,169.7) +(100.00 1,371.35) =
= 1,273,529
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Area by Coordinates
Determine the double area by taking thedifference between the two sums:
2,683,510 - 1,273,529 = 1,409,981 Divide the double area by 2:Area = 1,409,981 2 = 704,991 ft
Divide by 43,560 ft/ac:Area = 704,991/43,560=16.18 acres
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Area by Coordinates Method
Deg Min Sec Latitude Departure Latitude Departure Northing Easting A 5000.00 5000.00
126 56 10 S 53 o 04' E 323.626 -194.4744 258.6758 -194.4647 258.6601B 4805.54 5258.66
178 20 30 S 1 o 40' E 101.517 -101.4740 2.9378 -101.4710 2.9329C 4704.06 5261.59
15 33 30 N 15 o 33' E 360.178 346.9803 96.6067 346.9911 96.5892D 5051.06 5358.18
284 35 40 N 75 o 25' W 305.123 76.8834 -295.2773 76.8925 -295.2921E 5127.95 5062.89
206 10 20 S 26 o 10' W 142.570 -127.9522 -62.8832 -127.9479 -62.8902 A 5000.00 5000.00
Error = -0.03681 0.05981 0.00000 0.00000Perimeter= 1233.01 Rel. Acc. = Area, ft 2 = 68148.1
Linear Misclosure = 0.07023 17,557 Area, ac. = 1.564127,995,984 128,132,280
136,296
Pt. Length, ft.
Surveying Traverse Computations
Azimuth Unadjusted Adjusted CoordinatesBearing
Spreadsheet created by Dr. Charles Patrick,Professor
Adjusted Coordinates
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Latitude Departure Northing Easting5000.00 5000.00-194.4647 258.6601
4805.54 5258.66-101.4710 2.9329
4704.06 5261.59346.9911 96.5892
5051.06 5358.18
76.8925 -295.29215127.95 5062.89
-127.9479 -62.89025000.00 5000.00
0.00000 0.00000 Area, ft 2 = 68148.1
Area, ac. = 1.564127,995,984 128,132,280
136,296
Adjusted Coordinates
eet created by Dr. Charles Patrick,Professor
A
B
C
D
E
A
Line
Pt.