1 Section 3.3 Principle of Inclusion and Exclusion.
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Transcript of 1 Section 3.3 Principle of Inclusion and Exclusion.
1
Section 3.3 Principle of
Inclusion and Exclusion
2
( 2 more counting principles )
Principle of Inclusion and Exclusion Given finite sets A1, A2, …An, n 2, then
|A1A2 … An| =
nji
ji
n
ii AAA
11
||||
...||1
nkji
kji AAA
+ (-1)n+1| A1A2 … An |
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A-B AB B-AS: universal set
A-B, AB, B-A are mutually disjoint sets. i.e. xA-B, then xB,
and therefore x B-A, x AB.
|AB| = |A| + |B| - |AB||A-B| = |A| - |AB||B-A| = |B| - |AB|
e.g. |AB| can be computed in several ways depends on the information given.
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e.g. In a group of 42 tourists, everyone speaks English or French; there are 35 English speakers and 18 French speakers. How many speak both English & French?
42
English French
35 18
?
|AB| = |A| + |B| - |AB|
|AB| = 11
42 35 18
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e.g. What if we have 3 sets:
|ABC| = |A| + |B| + |C| - |A B| - |A C| - |B C| + |A B C|
L.H.S. = |A (B C)| = |A| + |B C|-|A (B C)|
= |A| + |B| + |C| - |B C| - |(A B) (A C)| = |A| + |B| + |C| - |B C| - |A B| - |A C| + |ABC|
= R.H.S.(can also be seen from the picture)
A
B C
I
I I
II IIIII
II
For |A| + |B| + |C|:I: counted 1 timeII: counted 2 timesIII: counted 3 times
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eg: a survey of 150 college students reveals that:
83 own Cars,
97 own Bikes,
28 own Motorcycles,53 own a car and a bike,14 own a car and a motorcycle,7 own a bike and a motorcycle,2 own all three.
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a. How many own a bike and nothing else?
|B – (C M)|= |B| - |B (C M)|= |B| - |(B C) (B M)|= |B| - (|B C| + |B M| - |B C M|)= 97 – (53 + 7 – 2)= 39
C 83
B 97M 28
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b. How many students do not own any of the three?
150 - |C B M|= 150 – (83+97+28-53-14-7+2)= 150 – 136 = 14
The general formula can be derived on P.1
15018
12
9
51
5
2
39
C
B M
14
9
Pigeonhole Principle:
If more than k items are placed into k bins, then at least one bin contains more than one item.e.g. How many people must be in a room to guarantee that two people have last names that begin with the same letter?
there are 26 letters(or bins). If there are 27 people, then at least 2 people will have last names beginning with the same letter.
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e.g. The population of city x is about 35,000. If each resident has three initials, is it true that there must be at least 2 individuals with the same initials?
Yes, 26 26 26 = 17,576 < 35,000
Why?Pigeonhole principle & Multiplication rule
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eg: How many numbers less than 1 million contain the digit 2?987234 398173 × 222333
106 - 96
(including 0) (without digit 2)
eg: How many bit strings have length 3, 4, or 5? 101 1110 00110 100001×
23 + 24 + 25
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eg: Quality control in a factory pulls 40 parts with paint, packaging, or electronics defects from an assembly line. Of these,
28 had a paint defect, 17 had a packaging defect, 13 had an electronics defect, 6 had both paint and packaging
defects, 7 had both packaging and electronics defects,
and 10 had both paint and electronics defects.
Did any part have all three types of defect?
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Yes, x = 5
40 parts w/paint, packaging, or electronics defects:40 = 28 + 17 + 13 – 6 – 7 – 10 + x
x = 5Paint
Packaging electronics
28
1713
14
eg: In a group of 25 people, must there be at least 3 who were born in the same month?
25 people, since there are only 12 months(bins)
more than 24 items means that at least one bin has more than 2 items.
Yes
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e.g. How many numbers must be selected from the set {2, 4, 6, 8, 10, 12, 14, 16, 18, 20} in order to guarantee that at least one pair adds up to 22?
Find all pairs add to 22: (2, 20)(4, 18)(6, 16) 5 bins(8, 14)(10, 12)
6 numbers selected, at least 2 of them will be from the same pair, which gives 22.