1) Active Filters, Part I 2) Active Filters, Part IIece.tamu.edu/~kentesar/ELEN457/ELEN457_4.pdf ·...
Transcript of 1) Active Filters, Part I 2) Active Filters, Part IIece.tamu.edu/~kentesar/ELEN457/ELEN457_4.pdf ·...
Kamran Entesari, ELEN 457 Texas A & M University
Section 3
1) Active Filters, Part I
2) Active Filters, Part II
Kamran Entesari, ELEN 457 Texas A & M University
Active Filters
1 ) The transfer function
Common frequency response:
1. Low pass 2. High pass 3. Band pass 4. Band reject 5. All pass
Practical filters: Approximation of the brick-wall magnitude filters
Active filters: no inductance implementation, providing gain, excellent for belowMHz applications such as audio and instrumentation applications
H (s) : The circuit transfer function
Roots: They are characteristic frequencies. They can be real or complex (conjugatePairs)
Kamran Entesari, ELEN 457 Texas A & M University
Active Filters
H (s) and stability:
An stable system has a bounded input to any bounded output. The response of aL.T.I system to an impulse input ( h(t) ) is determined by the poles of the circuit(Natural Response).
RLC circuits are always stable. If circuit contains dependent circuits such as op ampsIts pole may split into right half of the complex plane (RHP) and we have an unstableCircuit.
H (s) and frequency response:
The complex response; xo (t), consists of transient and steady-state responses.If all poles of the system are in LHP, the transient response dies, leaving the steadyState component.
Kamran Entesari, ELEN 457 Texas A & M University
Active Filters
2 ) First order active filters
Differentiator
H (s) =Vo / Vi = - (RC)s,
H (jω) = - j . (ω / ω0) , ω0 = 1 / (RC)
Miller integrator (inverting)
H (s) =Vo / Vi = - 1 / (RC)s,
H (jω) =[ (- 1) / j . (ω / ω0)] , ω0 = 1 / (RC)
Deboo integrator (non-inverting)
H (s) =Vo / Vi = 1 / (RC)s,
We use the Howland current pump circuit
Kamran Entesari, ELEN 457 Texas A & M University
Active Filters
Low-pass filter with gain
H (s) = ( - R2 / R1) . ( 1 / (R2Cs + 1)),
H (jω) = H0 / ( 1 + j . (ω / ω0)) , ω0 = 1 / (R2C)
High-pass filter with gain
Crude approximation of the brick-wall filter
H (s) = ( - R2 / R1) . ((R1Cs) / (R1Cs + 1))
H (jω) = H0 . ( j . (ω / ω0)) / ( 1 + j . (ω / ω0))
ω0 = 1 / (R1C)
Kamran Entesari, ELEN 457 Texas A & M University
Active Filters
Phase shifter
H (s) = (- RCs + 1) / (RCs + 1)
H (jω) = ( 1 - j . (ω / ω0)) / ( 1 + j . (ω / ω0))
ω0 = 1 / (RC)
Band-pass filter (wide band)
H (s) = ( - R2 / R1) . [(R1C1s) / ((R1C1s + 1) . (R2Cs + 1))]
H (jω) = H0 . ( j . (ω / ωL)) / [( 1 + j . (ω / ωL)) . ( 1 + j . (ω .ωH))]
ωL = 1 / (R1C1) , ωH = 1 / (R2C2)
Good for audio applications
Kamran Entesari, ELEN 457 Texas A & M University
Active Filters
3 ) Standard second order response (Biquadratic function)
• Q is a measure of filter selectivity• In practice; 0.5 < Q < 100
• Besides the pole – pair , the high passresponse has a double zero at ω = 0
Kamran Entesari, ELEN 457 Texas A & M University
Active Filters
• The band pass response (pole pairs + one zero at origin +one zero at infinity)
• The notch response (pole pairs + zero pairs at imaginary axis)
HN = HLP + HHP = 1 - HBP
• The all pass response ( 2 poles + 2 zeroes )
HAP = HLP – HBP +HHP = 1 – 2 . HBP
Kamran Entesari, ELEN 457 Texas A & M University
Active Filters
4 ) Single op amp second order active filters
KRC or Sallen-Key filters
The second order passive low pass filter has an asymptotic Slope of 40 dB / dec at high frequencies. , but does not have Sufficient flexibility to control the magnitude of the filterAround ω = ω0
• We use positive feedback to bolster the magnitude of the filter response around ω0
Kamran Entesari, ELEN 457 Texas A & M University
Active Filters
Low-pass KRC filter
• K and Q (or BW) are dependent to component ratios• ω0 is dependent to component products
Equal component KRC circuit: R1 = R2 = R, C1 = C2 = C
Design Equations: RC = 1/ ω0 , K = 3 – (1/Q)
Unity gain KRC circuit: K =1, R1 = mR, R2 = R, C1 =nC, C2 = C
Design Equations: ω0 = 1 / [(mn)1/2. RC] , Q = (mn)1/2 / (m+1)
Kamran Entesari, ELEN 457 Texas A & M University
Active Filters
High-pass KRC filter
• At high frequencies, the equal component design becomes too sensitive to the tolerance of the K when K =2. A slight mismatch, causing intolerable departure ofQ from the desired value and filter oscillation.
• KRC filter are used for Qs below 10
Again, two specific designs are equal componentAnd unity gain design.
Kamran Entesari, ELEN 457 Texas A & M University
Active Filters
Band-pass KRC filter
Typical design approach for Q > 0.4: R1 = R2 = R4 = R, C3 = C5 = C
Kamran Entesari, ELEN 457 Texas A & M University
Active Filters
Band-reject KRC filter
Twin T-network provides alternative pathsthrough which vi can reach the amplifier’s Input:
Low-freq. path: R – RHigh-freq. path: C – C
At intermediate frequencies the two paths provideOpposing phase angles, indicating a tendencyFor signals to cancel each other.
Design Equations: RC = 1/ ω0 , K = 4 – (1/Q)
Kamran Entesari, ELEN 457 Texas A & M University
Active Filters
Multiple feedback filters:
• For LP filter: Y1 and Y3 must be conductance and Y5 must be capacitor
• For BP filter: Y1 or Y3 must be capacitors
• For HP filter: Y1, Y3 and either Y4 or Y5 must be capacitors as
Low-pass filter
Kamran Entesari, ELEN 457 Texas A & M University
Active Filters
Band-pass filter
High-pass filter
Kamran Entesari, ELEN 457 Texas A & M University
Active Filters
4 ) State Variable and Biquad filters
Second order filters using one op amp use near minimum components.
Drawbacks: Wide component spreads, Awkward tuning capabilities. High sensitivityTo component variation, particularly to gain, limit these filters to Q < 10.
State Variable and Biqaud filters are less sensitive to passive component variables Easier to tune, and do not require extravagant component spreads. They provide More than one filter response, simultaneously.
State Variable (KHN) filters:
• Two integrators and a summing amplifier to provide the second – order low pass, band pass and high pass responses
• By using a forth op amp, we can synthesize the notch response or the all pass response
Kamran Entesari, ELEN 457 Texas A & M University
Active Filters
Inverting SV filter:
Typical design approach : R5 = R4 = R3, R6 =R7 = R, C1 = C2 = C
Kamran Entesari, ELEN 457 Texas A & M University
Active Filters
Non- inverting SV filter:
• The BP response is generated by integrating HP response and the LP response isGenerated by integrating the BP response
• The SV filters can easily yield dependable Q’s in the range of hundreds
Kamran Entesari, ELEN 457 Texas A & M University
Active Filters
The Biquad (Tow-Thomas) filter with notch response:
Three cases:
1) R4 = ∞ , ωz = ω0, H0N = -(R5 / R4)2) Switch Left: ωz > ω0, H0N = - (R5ωz
2)/(R2ω02)
3) Switch Right; ωz , ω0, H0N =- (R5 / R2)
We will use the low – and high –pass notches to synthesize a class of higher order filters known as elliptic filters