Undamped Free Vibration

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Transcript of Undamped Free Vibration

INTRODUCTION• If the external force is removed after giving the initial

displacement to the system, such vibrations are known as free vibrations, if there is no external resistance(damping) to the vibrations then such vibrations are known as Undamped free vibrations.

• When frequency of external exciting force is equal to natural frequency of vibrating body, the amplitude of vibration becomes excessively large. Such state is known as Resonance.

• Resonance is dangerous and it may lead to the failure of part.• Free vibration means that no time varying external forces act on

the system. • The pendulum will continue to oscillate with the same time

period and amplitude for any length of time.

• The natural frequency of any body or a system depend upon the geometrical parameters and mass property of the body.

• It is independent of the forces acting on the body or a system.

• There are various method to obtain the equation of a vibrating systems, which can be used to find the natural frequency of the given vibratory system.

1. Equilibrium Method(D’Alemberts’s Principle)2. Energy Method3. Reyleigh’s Method

INTRODUCTION

GENERAL EQUATION

• The simplest mechanical vibration equation occurs when γ = 0, F(t) = 0. This is the undamped free vibration. The motion equation is

mu″ + ku = 0.• The characteristic equation is mr² + k = 0. Its

solutions arer = + √(K/m)i or - √(K/m)i

GENERAL EQUATION

• The general solution is then U(t) = C1 cos ω˳ t + C2 sin ω˳ tWhere ω˳ = √(K/m) is known as natural

frequency of system.• frequency at which the system tends to oscillate

in the absence of any damping. A motion of this type is called simple harmonic motion. It is a perpetual, sinusoidal, motion.

GENERAL EQUATION

Example of Simple harmonic Motion

NATURAL FREQUENCY OF UMDAMPE FREE VIBRATION BY EQUILIBRIUM METHOD

• A body or structure which is not in static equilibrium due to acceleration it possesses can be brought to static equilibrium by introducing the inertia force on it.

• The inertia force is equal to the mass times the acceleration direction is opposite to that of acceleration.

• The principle is used for developing the equation of motion for vibrating system which is further used to find the natural frequency of the vibrating system.

 

NATURAL FREQUENCY OF UMDAMPED FREE VIBRATION BY EQUILIBRIUM METHOD

• The gravitational force must be equal to zero. mg=kδ ------- (1)

The force acting on the mass are : 1. inertia force : mẍ (upwards) 2. spring force : K(x+δ) (upwards) 3. gravitational force : mg

NATURAL FREQUENCY OF UMDAMPED FREE VIBRATION BY EQUILIBRIUM METHOD

• We know that the fundamental equation of SHM ẍ + ω²x = 0 -------

(3)• Comparing equation 2 & 3 , ω² = K̲ rad/s -------(4) m

• According to D’Alembert’s principle , mẍ + K(x+δ) – mg = 0 mẍ + Kδ +Kx – mg = 0 mẍ + Kx = 0 ẍ + K̲ x = 0 ------ (2) m

• The natural frequency f of vibration is , f = ω /2∏ or f = ½∏ √(K/m) Hz

----- (5)• also from eq. (1), mg = Kδ → K/m = g/δ ------ (6)• substituting eq (5) in eq (2) , we get f = ½∏ √(g/δ) H ------ (7)• the time period t is , t = 1/f = 1/ (1/2∏)(√(K/m)) or

t = 2∏ √(m/K) s. ------ (8)

NATURAL FREQUENCY OF UMDAMPED FREE VIBRATION BY ENERGY METHOD

• According to lao of conservation of energy , the energy can neither be created nor be destroyed, it can be converted from one form to another form.

• In free undamped vibrations, no energy is transferred to the system or from the system.

• Therefore the total mechanical energy i.e. the sum of kinetic energy and potential energy remains constant.

• Kinetic energy is due to motion of the body or system.

• Potential energy consist of two partsI. Gravitational Potential Energy : Due to

position of body or system with respect to equilibrium or mean position.

II. Strain Energy : Due to elastic deformation of body or system

NATURAL FREQUENCY OF UMDAMPED FREE VIBRATION BY ENERGY METHOD

• At mean position, the kinetic energy is maximum and potential energy is zero; whereas at extreme positions. The kinetic energy is zero and potential energy is maximum.

• E = K.E + P.E = Constant_______(9)

NATURAL FREQUENCY OF UMDAMPED FREE VIBRATION BY ENERGY METHOD

E = ½MV² + ½Kx ² ______(10)E = ½M ẍ² + ½Kx ² ______(11)

NATURAL FREQUENCY OF UMDAMPED FREE VIBRATION BY ENERGY METHOD

(dE/dt) = ½M.2ẍ.ẋ + ½K.2x.ẋ _______(12)0 = ½.2ẋ(M ẍ + K ẋ) _______(13) M ẍ + K ẋ = 0 _______(14)• We know that the fundamental equation of SHM ẍ + ω²x = 0 _______(15)

ẍ + (k/m) ẋ = 0 _______(16)• Comparing equation 2 & 3 ,

ω n = √(K/M) _______(17)f = ½∏ √(K/m) Hz  

 

NATURAL FREQUENCY OF UMDAMPED FREE VIBRATION BY ENERGY METHOD

M ẍ + K ẋ = 0 _______(18)

ẍ + (k/m) ẋ = 0 _______(19)• We know that the fundamental equation of SHM ẍ + ω²x = 0 _______(20)• By comparing above Equation with equation of

natural frequency ωn = √(K/M) _______(21)

NATURAL FREQUENCY OF UMDAMPED FREE VIBRATION BY ENERGY METHOD

f = ½∏ √(K/m) Hz _______(22)• The (natural) period of the oscillation is given by

T = 2∏/ ωn (seconds).

NATURAL FREQUENCY OF UMDAMPED FREE VIBRATION BY ENERGY METHOD

• This is extension of energy method.• According to principle of conservation of energy,(Total Energy)mean position = (Total Energy)extreme position

(K.E + P.E)1 = (K.E + P.E)2

(K.E)1+ (P.E)1 = (K.E) 2 + (P.E)2 • At Position 1 P.E is zero and K.E is Maximum.• At position 2 K.E is zero and P.E is Maximum

NATURAL FREQUENCY OF UMDAMPED FREE VIBRATION BY RAYLEIGH METHOD

• But at mean position K.E is maximum and at extreme position P.E. is maximum.

(K.E)MAX = (P.E)MAX

• Therefore, According to Lord Reyleigh’s, the maximum energy is at mean position is equal to maximum potential energy which is at extreme position.

NATURAL FREQUENCY OF UMDAMPED FREE VIBRATION BY RAYLEIGH METHOD

(P.E)max = (K.E) max

P.E = ½Kx ² ; x=Xsin(ωn t) _______(23)

(P.E)max = ½KX² ; ωn t = 90°_______(24)

NATURAL FREQUENCY OF UMDAMPED FREE VIBRATION BY RAYLEIGH METHOD

NATURAL FREQUENCY OF UMDAMPED FREE VIBRATION BY RAYLEIGH METHOD

  K.E = ½M ẋ ² ; ẋ = X ωn Cos(ωn t) _______(25)(K.E) max = ½M ωn² X² _______(26)(P.E)max = (K.E)max

_______(27)

½KX² = ½M ωn² X² _______(28)- By simulating the above equation we get next equation,

NATURAL FREQUENCY OF UMDAMPED FREE VIBRATION BY RAYLEIGH METHOD

ωn = √(K/M) _______(29)

f = ½∏ √(K/m) Hz• The (natural) period of the oscillation is given

by T = 2∏/ ωn (seconds).

• Due to gravitation force ‘mg’, the cantilever beam is deflected by ‘δ’.

• At Equilibrium position mg = Kδ.• Let the system is subjected to one time external

force due to which it will displaced by ‘x’ from equilibrium position.

Undamped Free Transverse Vibration

Undamped Free Transverse Vibration

• Forces acting on mass beyond mean position are,

1. Inertia Force, mẍ (upward) _________(30)2. Resisting Force, Kx (upward)

• According to D’amberte’s principle,Ʃ(Inertia Force + External Force) = 0

mẍ + Kx = 0ẍ + (K/M)x = 0 _____(31)

Undamped Free Transverse Vibration

• Comparing Eq. 31 with Eq. of S.H.M., ωn² = (K/M) rad/s ωn = √(K/M) rad/s or f = ½∏ √(K/m)

Hz • From Eq. 30,

(K/M) = (g/ δ)• Substituting above values,

Fn = (0.4985/ √ δ) Hz

Undamped Free Transverse Vibration

• Consider a disc having mass moment of inertia ‘I’ suspended on shaft with negligible mass, as shown in fig.

• If the disc is given a angular displacement about a axis of shaft, it oscillates about that axis, such vibrations are known as Torsional vibrations.

Undamped Free Transverse Vibration

Undamped Free Torsional Vibration

• For angular displacement of disc ‘Ɵ’ in clockwise direction, the torques acting on the disc are:

• According to D’amberte’s principle,Ʃ(Inertia Force + External Force) = 0I Ɵˊˊ + Kt. Ɵ = 0Ɵˊˊ + (Kt/I).Ɵ = 0 _______(32)

Undamped Free Transverse Vibration

• The fundamental Eq. of S.H.M. Ɵˊˊ + ωn Ɵ = 0 _____(33)

• By Comparison of above Eq. 32 & 33

ωn = √(Kt/I) rad/s _____(34)

f = ½∏ √(Kt/I) Hz ______(35)

Undamped Free Torsional Vibration

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