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- J-M Rey - EUCARD Meeting - UNIGE 08/06/2010 1

Task 4HTS material

characterization &dipole insert conceptual

designMélanie Bruchon, Maria Durante, Thibault

Lécrevisse, Jean-Marc Gheller, Olivier Louchart, Jean-Michel Rey

CEA/IRFU/SACM

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HTS characterization

Superpower

AMSC

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HTS characterizationSuperpower (with insulation)

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HTS characterizationSuperpower (without insulation)

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HTS characterizationAMSC

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- J-M Rey - EUCARD Meeting - UNIGE 08/06/2010 6

HTS characterizationWhat next ?

Cooling influence: what happens if we remove insulation?

Quench propagation: next study using compact solenoids. MPZ and MQE determination versus temperature.

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Dipole design

20 mm beam tube

3 double pancakes

2 flat one

1 with bent end, each pancake symetrical / mid plane (only one tooling needed)

External winding diameter: 98 mm

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Dipole designInner bore diameter: 20 mm

254 A/mm² needed to reach 6T

Peak field 6,1T

Fx = 47,8 kdaNFy = 78,5 kdaN

No Nb3Sn contribution

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Dipole designConductor extrapolation

Using Superpower SCS 4050 @ 20 T and 10 K extrapolation: 520 A for a 4 mm wide.

Assuming 2 12 mm wide ribbons and 60% efficiency on one of them the critical current may be 2496 A.

Assuming 12 mm wide conductor of 0,4 mm thickness corresponding to 0,2 mm conductor + 0,1 mm tin + 0,1 mm kapton insulation the critical current density is 520 A/mm².

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Dipole designConductor length needed

With a straight length of 500 mmBlock 1: 69 mBlock 2: 105 mBlock 3: 142 mOnly block 3 needs « flare dance » end.

Or 1260 m of 12 mm wide ribbons needed (or 202 k$)

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We may be able to discuss this number!

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Dipole design

Junctions

Main conductor: SC face to face

Mid point and end connections: SC back to back

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Thank you for your attention

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Which HTS will fit?

Bi2212

YBCO

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Bi 2212

Assume we can make a Rutherford cable using a round wire with 25% SC material

Ic @ 4.2K & 20T = 82A

Winding with 20% insulation

No cabling degradation

Good head treatment

Je = 130 A/mm²

We may expect B = 2.72T

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YBCO

Using AMSC 344 Cu (made for magnets)4.55 x 0.22 = 1 mm²Ic @ 4.2K & 10T = 325AIc @ 4.2K & 15T = 245AExtrapolation : Ic @ 4.2K & 20T = 165AWinding with 20% insulationNo winding degradation

Je = 130 A/mm²We may expect B = 2.72T

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Measured values

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YBCO

Using AMSC 344 S (with stainless steel, not made for magnets)

1.41 mm²Ic @ 4.2K & 15T = 580AExtrapolation : Ic @ 4.2K & 20T = 500AWinding with 20% insulationNo winding degradation

Je = 285 A/mm²We may expect B = 5.96T

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Measured value

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YBCOUsing Super Power SCS 4050i

(with kapton insulation)

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Unit Ribbon Insulated

Width mm 4 4.2

Thickness mm 0.1 0.3

Cross section mm² 0.4

SC cross section mm² 0.004

Cu Cross section mm² 0.016

SC / Non SC ratio % 1%

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YBCO ribbon characterization

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Results (with 0.1 µV/cm criterion) :

Je = 275 A/mm² @ 20K & 13T

We may reach what we need !

(287 A/mm² @ 4.2K & 18T)

Worrying concern: this tape blew up after 8 critical current measurement under 15T at 4.2K and 30K

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YBCO ribbon characterization

Test “as purchased”

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Test after “damaging quench”

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YBCO ribbon characterization•Some measurements problems :

To much heat power generated in the sample-current leads junctions : Uneasy to regulate the température.

The problem is corrected but we haven’t done the tests again yet.

•It’s very difficult to limit the heat generation next to the sample when high current (> 500A) flows through the sample over long period of time (> 20s).

A new measurement setup is needed for high current under low field

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A rough mechanical approach - Forces Blo

c 4

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1040 tonnes

50 tonnes

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A rough mechanical approach - Stresses

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Stress 270 MPa20 mm

Mid plane Stress 17 MPa

Interbloc Stress 9 MPa

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Bloc 4

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StructureWhy should we keep the insert in a

circular bore?

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Winding

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How to use ribons for the mid plane pancake ?

Can we assemble ribbons to increase Ic ?

Can we mix Bi2212 and YBCO in the same insert ?

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Winding

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Winding developments can be inspired from the INNOVAC project (Danish Technical Institute/Danfysik/ Siemens)

From an IOP presentation by Nikolaj Zangenberg, Danish Technological Institute

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ProtectionBloc 4

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Can we allow HTS to quench ?HTS material degradation often observed after

quench

Where could we have copper ?The need of high current density does not

leave place for stabilizer

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It may be wise to add a contribution of the HTS fringe field on the Nb3Sn

winding.

A sub task with T3 and T4 people for the interface definition is strongly

needed !

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