Task 4 HTS material characterization & dipole insert conceptual design
description
Transcript of Task 4 HTS material characterization & dipole insert conceptual design
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Task 4HTS material
characterization &dipole insert conceptual
designMélanie Bruchon, Maria Durante, Thibault
Lécrevisse, Jean-Marc Gheller, Olivier Louchart, Jean-Michel Rey
CEA/IRFU/SACM
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HTS characterization
Superpower
AMSC
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HTS characterizationSuperpower (with insulation)
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HTS characterizationSuperpower (without insulation)
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HTS characterizationAMSC
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HTS characterizationWhat next ?
Cooling influence: what happens if we remove insulation?
Quench propagation: next study using compact solenoids. MPZ and MQE determination versus temperature.
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Dipole design
20 mm beam tube
3 double pancakes
2 flat one
1 with bent end, each pancake symetrical / mid plane (only one tooling needed)
External winding diameter: 98 mm
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Dipole designInner bore diameter: 20 mm
254 A/mm² needed to reach 6T
Peak field 6,1T
Fx = 47,8 kdaNFy = 78,5 kdaN
No Nb3Sn contribution
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Dipole designConductor extrapolation
Using Superpower SCS 4050 @ 20 T and 10 K extrapolation: 520 A for a 4 mm wide.
Assuming 2 12 mm wide ribbons and 60% efficiency on one of them the critical current may be 2496 A.
Assuming 12 mm wide conductor of 0,4 mm thickness corresponding to 0,2 mm conductor + 0,1 mm tin + 0,1 mm kapton insulation the critical current density is 520 A/mm².
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Dipole designConductor length needed
With a straight length of 500 mmBlock 1: 69 mBlock 2: 105 mBlock 3: 142 mOnly block 3 needs « flare dance » end.
Or 1260 m of 12 mm wide ribbons needed (or 202 k$)
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We may be able to discuss this number!
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Dipole design
Junctions
Main conductor: SC face to face
Mid point and end connections: SC back to back
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Thank you for your attention
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Which HTS will fit?
Bi2212
YBCO
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Bi 2212
Assume we can make a Rutherford cable using a round wire with 25% SC material
Ic @ 4.2K & 20T = 82A
Winding with 20% insulation
No cabling degradation
Good head treatment
Je = 130 A/mm²
We may expect B = 2.72T
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YBCO
Using AMSC 344 Cu (made for magnets)4.55 x 0.22 = 1 mm²Ic @ 4.2K & 10T = 325AIc @ 4.2K & 15T = 245AExtrapolation : Ic @ 4.2K & 20T = 165AWinding with 20% insulationNo winding degradation
Je = 130 A/mm²We may expect B = 2.72T
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Measured values
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YBCO
Using AMSC 344 S (with stainless steel, not made for magnets)
1.41 mm²Ic @ 4.2K & 15T = 580AExtrapolation : Ic @ 4.2K & 20T = 500AWinding with 20% insulationNo winding degradation
Je = 285 A/mm²We may expect B = 5.96T
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Measured value
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YBCOUsing Super Power SCS 4050i
(with kapton insulation)
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Unit Ribbon Insulated
Width mm 4 4.2
Thickness mm 0.1 0.3
Cross section mm² 0.4
SC cross section mm² 0.004
Cu Cross section mm² 0.016
SC / Non SC ratio % 1%
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YBCO ribbon characterization
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Results (with 0.1 µV/cm criterion) :
Je = 275 A/mm² @ 20K & 13T
We may reach what we need !
(287 A/mm² @ 4.2K & 18T)
Worrying concern: this tape blew up after 8 critical current measurement under 15T at 4.2K and 30K
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YBCO ribbon characterization
Test “as purchased”
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Test after “damaging quench”
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YBCO ribbon characterization•Some measurements problems :
To much heat power generated in the sample-current leads junctions : Uneasy to regulate the température.
The problem is corrected but we haven’t done the tests again yet.
•It’s very difficult to limit the heat generation next to the sample when high current (> 500A) flows through the sample over long period of time (> 20s).
A new measurement setup is needed for high current under low field
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A rough mechanical approach - Forces Blo
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1040 tonnes
50 tonnes
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A rough mechanical approach - Stresses
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Stress 270 MPa20 mm
Mid plane Stress 17 MPa
Interbloc Stress 9 MPa
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StructureWhy should we keep the insert in a
circular bore?
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Winding
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How to use ribons for the mid plane pancake ?
Can we assemble ribbons to increase Ic ?
Can we mix Bi2212 and YBCO in the same insert ?
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Winding
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Winding developments can be inspired from the INNOVAC project (Danish Technical Institute/Danfysik/ Siemens)
From an IOP presentation by Nikolaj Zangenberg, Danish Technological Institute
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ProtectionBloc 4
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Can we allow HTS to quench ?HTS material degradation often observed after
quench
Where could we have copper ?The need of high current density does not
leave place for stabilizer
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It may be wise to add a contribution of the HTS fringe field on the Nb3Sn
winding.
A sub task with T3 and T4 people for the interface definition is strongly
needed !
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