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One-Step Towards Success
2014
PROFIT AND LOSS Quantitative Aptitude For: *Bank PO,SBI PO,IBPS PO Exams…
*Postal & Sorting Assistant Exams…
*SSC Combined Graduate Level Exams…
*LIC AAO and All other competitive examinations… Gateway to Knowledge
PROFIT & LOSS Definitions: Cost Price: The price at which an article is purchased is called the cost price or C.P. Selling Price: The price at which an article is sold is called the selling price or S.P. Marked (List) Price: The Price that is indicated or marked on the article is called marked price or M.P. Profit (Gain): If S.P. is greater than C.P., the seller is said to have a profit (gain). Loss: If S.P. is less than C.P., the seller is said to have a loss. Discount: It is reduction given on the Marked Price or List Price of an article.
Formulae: 1. Gain= (SP)-(CP)
2. Loss= (CP)-(SP)
3. Gain %= (Gain x 100
CP)
4. Loss %= (Loss x 100
CP)
5. SP= 100+Gain %
100 x CP
6. SP= (100−Loss %)
100 x CP
7. CP= 100
(100+Gain %) x SP
8. CP= 100
(100−Loss %) x SP
9. Discount= MP-SP
10. Discount%= (D
M.P. x 100)
11. SP= (100−D%
100x MP)
12. If a trader professes to
sell his goods at Cost Price,
but uses false weight, then
Gain (Profit) Percent,
= [Error
True Value −(Error) x 100]%
13. If a trade gets x% profit and x% loss in selling two similar articles, then in over all transaction, there is always a loss which is
Loss %= (𝑥
10)2
14. If an article is sold at a gain of 49%, then SP= 149% of CP. 15. If an article is sold at a loss of 49%, then SP= 51% of CP.
Mostly Asked Questions
(Fully Solved) Que.:- If the cost price of 12 pens is equal to the selling price of 8 pens, the gain percent is: Sol.:- Let C.P. of each pen be Rs.1. Then, C.P. of 8 pens= Rs.8 S.P. of 8 pens= Rs.12.
∴ Gain%= (Gain
C.P. x 100)
= (4
8 x 100) %
= 50%. Que.:- A shopkeeper purchased 70 kg of potatoes for Rs. 420 and sold the whole lot at the rate of Rs.6.50 per kg. What will be his gain percent? Sol.:- C.P. of 1kg potatoes,
= Rs. (420
70) = Rs. 6.
S.P. of 1kg potatoes, = Rs. 6.50.
∴ Gain%= (Gain
C.P. x 100)
= (0.50
6 x 100) %
= 25
3 % or 8
1
3 %.
Que.:- 100 oranges are bought at the rate of Rs.350 and sold at the rate of Rs.48 per dozen. The percentage of profit or loss is: Sol.:-
C.P. of 1 orange= Rs. (350
100)
= Rs. 3.50.
S.P. of 1 orange= Rs. (48
12)
= Rs. 4. Here, CP < SP
∴ Gain%= (Gain
C.P. x 100)
= (0.50
3.50 x 100) %
= 100
7 % or 14
2
7 %.
Que.:-A man gains 20% by selling an article for a certain price. If he sells it at double the price, the percentage of profit will be: Sol.:-
Let C.P. = Rs. x. Then, S.P. = Rs. (120% of C.P.) = Rs. (120% of x)
= Rs. 6𝑥
5
New S.P. = Rs. (2 x 6𝑥
5)
= Rs. 12𝑥
5
Profit = (SP-CP)
Profit = Rs. (12𝑥
5− 𝑥)
= Rs. 7𝑥
5
∴ Profit% = (7𝑥
5 x
1
𝑥 x 100) %
= 140%. Que.:- Some articles were bought at 6 for Rs. 5 and sold at 5 for Rs. 6. Gain percent is: Sol.:- Suppose, number of articles Bought = L.C.M. of 6 & 5 = 30. C.P. of 30 articles,
= Rs. (5
6 x 30) = Rs. 25.
S.P. of 30 articles,
= Rs. (6
5 x 30) = Rs. 36.
∴ Gain%= (Gain
C.P. x 100)
= (11
25 x 100) %
= 44%. Que.:- A fair price shopkeeper takes 10% profit on his goods. He lost 20% goods during theft. His loss percent is: Sol.:- Suppose he has 100 items. Let C.P. of each item be Rs.1. Total cost= Rs.100. No. of items left after theft = 80. S.P. of each item= Rs. 1.10 ∴ Total sale = Rs. (1.10 x 80) = Rs. 88. Hence,
Loss%= (Loss x 100
CP)
=(12
100 x 100)% or 12%.
Que.:- A trader marked the price of his commodity so as to include a profit of 25%. He allowed discount of 16% on the marked price. His actual profit was: Sol.:- Let C.P. be Rs. 100. Then,
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3
Marked price= Rs. 125. S.P. = 84% of Rs. 125
= Rs. (84
100 x 125)
= Rs. 105. ∴Profit% = (SP-CP) % = (105-100) % = 5%. Que.:- A shopkeeper sells 25 articles at Rs. 45 per article after giving 10% discount and earns 50% profit. If the discount is not given, the profit gained is: Sol.:- S.P. of 1 article= Rs. 45. Let marked price of each article be Rs. x. Then, S.P. = 90% of Rs. x
45 = 90𝑥
100
∴ x = Rs. (45 x 100
90)
= Rs. 50.
C.P. = 100
(100+Gain %) x SP
= Rs. (100
150 x 45)
= Rs. 30. ∴ Required Profit%,
= (Gain
C.P. x 100)
= (20
30 x 100) %
= 200
3 % or 66
2
3 %.
Que.:- A trader marked the selling price of an article at 10% above the cost price. At the time of selling, he allows certain discount and suffers a loss of 1%. He allowed a discount of: Sol.:- Let C.P. =Rs. 100. Then, Marked Price= Rs. 110. S.P. = Rs. 99. Discount = (M.P.-S.P.)
= Rs. (110-99)
= Rs. 11.
∴ Discount% = (D
M.P. x 100)
= (11
110 x 100) %
= 10 %.
Que.:- A trader marked his
goods at 20% above the
cost price. He sold half the
stock at the marked price,
one quarter at a discount
of 20% on the marked
price and the rest at a
discount of 40% on the
marked price. His total
gain is:
Sol.:-
Let Cost Price of whole stock
= Rs.100. Then, Marked Price
of whole Stock= Rs. 120.
M.P. of 1
2 stock= Rs. 60.
M.P. of 1
4 stock= Rs. 30.
∴Total S.P. is = Rs. [60+(80% of 30)+(60% of 30)]
= Rs. (60+24+18)
= Rs. 102.
Hence, Gain% = (S.P. – C.P.)%
= (102-100)% = 2%.
Que.:- The marked price of
a watch was Rs. 720. A man
bought the same for Rs.
550.80 after getting two
successive discounts, the
first being 10%. What was
the second discount rate?
Sol.:-
Let the 2nd discount rate be
x %. Then,
(100-x) % of 90 % of 720
= 550.80
∴ (100−𝑥)
100 x
90
100 x 720= 550.80
∴ 100 − 𝑥 = ( 55080
9 x 72) = 85
100 − 𝑥 = 85
∴ x = (100-85) = 15.
∴ 2nd discount rate= 15 %.
Que.:- A fan is listed at Rs.
1500 and a discount of
20% is offered on the list
price. What additional
discount must be offered to
the customer to bring the
net price to Rs. 1104?
Sol.:-
S.P. after 1st discount,
= Rs. (80
100 x 1500)
= Rs. 1200.
Net S.P. = Rs. 1104.
Discount on Rs. 1200= Rs. 96.
∴ Required discount,
= (D
M.P. x 100) %
= (96
1200 x 100) % = 8 %.
Que.:- A cloth merchant
sold half of his cloth at
20% profit, half of the
remaining at 20% loss and
the rest was sold at the cost
price. In the total
transaction, his gain or loss
will be:
Sol.:-
Let C.P. of whole be Rs. x.
C.P. of 1
2 stock= Rs.
𝑥
2
C.P. of 1
4 stock= Rs.
𝑥
4
Total S.P., = Rs. [(120% of
𝑥
2 ) + (80% of
𝑥
4) +
𝑥
4]
= Rs. (3𝑥
5+𝑥
5+
𝑥
4) = Rs.
21𝑥
20
Here, CP < SP
∴ Gain= Rs. (21𝑥
20− 𝑥) = Rs.
𝑥
20
∴ Gain%= (𝑥
20 x
1
𝑥 x 100) %
= 5 %.
Que.:- A man buys an
article for 10% less than its
value and sells it for 10%
more than its value. His
gain or loss percent is:
Sol.:-
Let the article be worth Rs. x.
C.P. = 90% of Rs. x
= Rs. 9𝑥
10
S.P. = 110% of Rs. x
= Rs. 11𝑥
10
Here, CP < SP
∴ Gain= Rs. (11𝑥
10−
9𝑥
10)
= Rs. 𝑥
5
∴ Gain%= (Gain x 100
CP)
= (𝑥
5 x
10
9𝑥 x 100) %
= 22 2
9 %.
Que.:- A man bought apples
at the rate of 8 for Rs. 34
and sold them at the rate of
12 for Rs. 57. How many
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4
apples should be sold to
earn a net profit of Rs. 45?
Sol.:-
C.P. of 1 apple= Rs. (34
8)
= Rs. 4.25.
S.P. of 1 apple= Rs. (57
12)
= Rs. 4.75.
Profit on each apple,
= (S.P. – C.P.)
= (4.75 – 4.25)
= Rs. 0.50.
∴ No. of apples required,
= (45
0.50) = 90.
Que.:- A man buys two
dozen bananas at Rs. 16
per dozen. After selling 18
bananas at the rate of Rs.
12 per dozen, the
shopkeeper reduced the
rate to Rs. 4 per dozen. The
percent loss is:
Sol.:-
C.P. = Rs. (16 x 2) = Rs. 32.
S.P. = Rs. (12 x 1.5 + 4 x 0.5)
= Rs. (18+2) = Rs. 20.
∴ Loss%= (Loss x 100
CP)
= (12
32 x 100) %
= 37.5 %.
Que.:- A man buys a cycle
for Rs. 1400 and sells it at a
loss of 15%. What is the
S.P. of the cycle?
Sol.:- S.P. = 85 % of C.P.
= 85 % of Rs. 1400
= Rs. (85
100 x 1400)
= Rs. 1190.
Que.:- When a plot is sold
for Rs.18,700 the owner
loses 15 %. At what price
must the plot be sold in
order to gain 15%?
Sol.:-
Let new S.P. be Rs. x.
Then, (100-loss%) : (1st S.P.)=(100+gain%) : (2nd S.P.)
(100-15%):(18,700)=(100+15%): x
85 : 18,700 = 115 : x
∴ x = (18,700 x 115
85) = 25,300.
∴ S.P. = Rs. 25,300.
Que.:- A person incurs 5%
loss by selling a watch for
Rs. 1140. At what price
should the watch be sold to
earn 5% profit?
Sol.:-
Let new S.P. be Rs. x. Then, (100-loss%):(1st S.P.) = (100+gain%):(2nd S.P.)
(100-5%):(1140)=(100+5%): x
95 : 1140 = 105 : x
∴ x = (1140 x 105
95) = 1260.
∴ S.P. = Rs. 1260.
Que.:- A man loses 10% by
selling an article for Rs.
180. At what price should
he sell it to gain 10%?
Sol.:-
Let new S.P. be Rs. x. Then, (100-loss%):(1st S.P.) = (100+gain%):(2nd S.P.)
(100-10%):(180)=(100+10%):x
90:180=110: x
∴ x = (180 x 110
90) = 220.
∴ SP = Rs. 220.
Que.:- A tradesman sold an
article at a loss of 20%. If
the SP had been increased
by Rs. 100, there would
have been a gain of 5%.
What was the cost price of
the article?
Sol.:-
Let the C.P. be Rs. x. Then,
(105% of x) - (80% of x)=100
∴ 25% of x = 100
∴ 25𝑥
100 = 100
∴ 𝑥
4 = 100
∴ x = 400.
So, C.P. = Rs. 400.
Que.:- A man bought a
horse and a carriage for Rs.
3000. He sold the horse at
a gain of 20% and the
carriage at a loss of 10%,
thereby gaining 2% on the
whole. Find the cost of the
horse.
Sol.:-
Let the C.P. of the horse be
Rs. x.
Then, C.P. of the carriage =
Rs. (3000- x).
∴20% of x – 10% of (3000- x)
= 2% of 3000
∴ 20𝑥
100 –
3000−𝑥
10 = 60
∴ 𝑥
5 –
3000−𝑥
10 = 60
∴ 10 x – 15000 + 5 x = 3000
∴ 15x = 15000+3000 = 18000
∴ x = 18000
15 = 1200.
Hence, C.P. of the horse = Rs.
1200.
Que.:- On selling 17 balls at
Rs. 720, there is a loss
equal to the cost price of 5
balls. The cost price of a
ball is:
Sol.:-
CP of 17 balls - SP of 17 balls
= CP of 5 balls.
∴ CP of 17 balls - CP of 5 balls
= SP of 17 balls.
∴CP of 12 balls=SP of 17 balls
= Rs. 720.
∴ CP of 1 ball = Rs. (720
12)
= Rs. 60.
Que.:- A pair of articles was
bought for Rs. 37.40 at a
discount of 15%. What
must be the marked price
of each of the articles?
Sol.:-
SP of each article = Rs. (37.40
2)
= Rs. 18.70
Let MP be Rs. x. Then,
SP = 85% of x
18.70 = 85𝑥
100
∴ x = (18.70 x 100
85) = 22.
∴ MP = Rs. 22.
Que.:- List price of an
article at a showroom is Rs.
2000 and it is being sold at
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5
successive discounts of
20% and 10%. Its net
selling price will be:
Sol.:-
S.P.= 90% of 80% of Rs. 2000
= Rs. (90
100 x
80
100 x 2000)
= Rs. 1440.
Que.:- The price of an
article is raised by 30%
and then two successive
discounts of 10% each are
allowed. Ultimately, the
price of the article is:
Sol.:-
Let the original price be Rs.
100. Then,
Marked price = Rs. 130.
Final price = 90% of 90% of
Rs. 130
= Rs. (90
100 x
90
100 x 130)
= Rs. 105.30.
∴ Increase in price
= (105.30-100)% = 5.3 %.
Que.:- By selling an article
at 𝟐
𝟓 of the marked price,
there is a loss of 25%. The
ratio of the marked price
and the cost price of the
article is:
Sol.:-
Let cost price = Rs. 100.
Then,
2
5 of (Marked Price) = 75
∴ Marked Price = Rs. (75 x 5
2)
= Rs. 375
2
∴ Required Ratio,
= 375
2 : 100
= 375 : 200
= 15 : 8.
Que.:- A shopkeeper sells a
badminton rackets, whose
marked price is Rs. 30, at a
discount of 15% and gives
a shuttle cock costing Rs.
1.50 free with each racket.
Even then he makes a
profit of 20%. His cost
price per racket is:
Sol.:-
Marked Price = Rs. 30.
S.P. = Rs. [(85
100 x 30) - 1.50]
= Rs. (25.50 - 1.50)
= Rs. 24.
Let C.P. be Rs. x. Then,
120% of x = 24
∴ x = (24
120 x 100)
= Rs. 20.
Que.:- A shopkeeper sold
sarees at Rs. 266 each after
giving 5% discount on
labelled price. Had he not
given the discount, he
would have earned a profit
of 12% on the cost price.
What was the cost price of
each saree?
Sol.:-
S.P. of 1 saree = Rs. 266.
Let the labelled price of each
saree be Rs. x. Then, 95𝑥
100 = 266
∴ x = Rs. (266
95 x 100) = Rs. 280.
Now,S.P.=Rs.280,profit=12%.
∴ C.P. of 1 saree,
= Rs. (100
112 x 280) = Rs. 250.
Que.:- An item when sold
for Rs. 1,690 earned 30%
profit on the cost price.
Then the cost price is:
Sol.:-
Cost price = Rs. (100
130 x 1,690)
= Rs. 1,300.
Que.:- A dealer purchased a
washing machine for Rs.
7,660. After allowing a
discount of 12% on its
marked price, he still gains
10%. Find the marked
price of the washing
machine.
Sol.:-
Cost price = Rs. 7,660.
S.P. = 110% of Rs. 7,660
= Rs. (110
100 x 7,660)
= Rs. 8,426.
Let marked price be Rs. x.
Then, S.P. = 88% of x
8,426 = (88𝑥
100)
∴ x = (8,426 x 100
88)
∴ x = Rs. 9,575.
∴ Marked Price = Rs. 9,575.
Que.:- A dealer marks his
goods 20% above cost
price. He then allows some
discount on it and marks a
profit of 12%. The rate of
discount is:
Sol.:-
Let Cost Price= Rs. 100. Then,
M.P. = Rs. 120, S.P. = Rs. 112.
∴ Discount = (MP-SP)
= Rs. (120-112)
= Rs. 8.
∴ Discount% = (D
M.P. x 100)
= (8
120 x 100) %
= 20
3 % or 6
2
3 %.
Que.:- A trader marked his
product 20% higher than
his cost price and then
gives 20% discount on the
marked price. The profit or
loss for selling the product
is:
Sol.:-
Let Cost Price= Rs. 100. Then,
Marked Price = Rs. 120.
S.P. = (100−D%
100x MP)
= (100−20%
100x 120)
= Rs. 96.
Here, CP > SP
∴ Loss = (CP-SP)
= (100-96) = 4
∴ Loss% = (Loss x 100
CP)
= (4 x 100
100) % = 4 %.
Que.:- A man sold an article
at a loss of 20%. If he could
sell it for Rs. 200 more, he
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6
would make a profit of 5%.
The cost price of the article
is:
Sol.:-
Let cost price be Rs. x. Then,
SP = (105% of x) - (80% of x)
200 = 25% of x
200 = 25𝑥
100
∴ x = Rs. (200 x 100
25) = Rs. 800.
Que.:- A man purchased an
article and sold it to B at a
profit of 25% and B sold it
to C at a loss of 10% and C
paid Rs. 675 for it. For how
much did A purchase it (in
Rs.)?
Sol.:-
125% of 90% of A = Rs. 675
∴ 125
100 x
90
100 x A = 675
∴ 45
40 x A = 675
∴ A = 675 x 40
45 = Rs. 600.
Que.:- A sells a bicycle to B
at a profit of 20%. B sells it
to C at a profit of 25%. If C
pays Rs. 225 for it, the cost
price of the bicycle for A is:
Sol.:-
125% of 120% of A = Rs. 225
∴ 125
100 x
120
100 x A = 225
∴ 30
20 x A = 225
∴ A = 225 x 20
30 = Rs. 150.
Que.:- A fair price
shopkeeper takes 10%
profit on his goods.
He lost 20% goods during
theft. His loss percent is:
Sol.:-
Suppose he has 100 items.
Let C.P. of each item be Rs. 1.
Total cost = Rs. 100. Number
of items left after theft = 80.
S.P. of each item = Rs. 1.10.
∴ Total sale = Rs. (1.10 x 80)
= Rs. 88.
Hence,
Loss%= (12
100 x 100) %= 12%.
Que.:- At what percent
above the cost price must a
shopkeeper mark his
goods so that he gains 20%
even after giving a discount
of 10% on the marked
price?
Sol.:-
Let C.P. = Rs. 100. Then,
S.P. = Rs. 120.
Let marked price be Rs. x.
Then, S.P. = 90% of x
120 = 90𝑥
100
∴ x = (120 x 100
90) = 133
1
3
∴ Marked Price,
= 133 1
3 % above CP.
Que.:- A man sold 18 cots
for Rs. 16,800, gaining
thereby the cost price of 3
cots. The C.P. of a cot is:
Sol.:- (S.P. of 18 cots) - (C.P. of 18 cots)
= (CP of 3 cots)
∴ (CP of 21 cots) = (SP of 18 cots)
= Rs. 16,800.
∴ (CP of 1 cot),
= Rs. (16,800
21) = Rs. 800.
Que.:- A dishonest dealer
uses a scale of 90 cm
instead of a metre scale
and claims to sell at cost
price. His profit is:
Sol.:- Gain% = (Gain x 100
CP)
= (10
90 x 100) %
= 11 1
9 %.
Que.:- 300 bananas were
purchased at Rs. 128 a
hundred. What should be
the selling price per dozen,
if a profit of Rs.66 is to be
made?
Sol.:-
Cost Price of 300 Bananas,
= 128
100 x 300 = Rs. 384
Profit = Rs. 66 … Given
∴ S.P. of 300 Bananas,
= 384 + 66 = Rs. 450
∴ Selling Price per dozen,
= 450
300 x 12 = Rs. 18.
Que.:- A sells an article to B
at a gain of 10%. B sells it
to C at a gain of 7 𝟏
𝟐 %. C
disposes of it at a loss of
25%. If the prime cost to
the manufacturer A was Rs.
3200,then find the price
obtained by C.
Sol.:-
A buys an article for Rs. 3200
and sells it at a gain of 10%.
∴ Cost Price to B,
= Rs. (3200 x 110
100)
B sells it at a gain of 15
2 %,
∴ Cost Price to C,
=Rs. (3200 x 110 x107.5
(100 x 100))
C sells it at a loss of 25 %,
∴ Price Obtained by C is
= Rs. (3200 x 110 x 107.5 x 75
(100 x 100 x 100))
= Rs. (3200 x 1.1 x 1.075 x 0.75)
= Rs. 2838.
Que.:- A sold a tape-
recorder to B for Rs. 4,860
at a loss of 19%. Again B
sold it to C at a price that
would give A, a profit of
17%. The gain of B is:
Sol.:-
Cost of tape-recorder paid by
A = 4860 x 100
81
= Rs. 6000.
Cost of tape-recorder paid by
C = 6000 x 117
100
= Rs. 7020.
∴ Gain of B = Rs. (7020-4860)
= Rs. 2160.
∴ Gain % = (Gain x 100
CP)
= (2160 x 100
4860)
= 400
9 % or 44
4
9 %.
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Que.:- If the selling price of
a product is increased by
Rs. 162, then the
businessman will make a
profit of 17% instead of a
loss of 19%. The cost price
of the product is:
Sol.:-
Let the cost price be Rs. x.
∴ if loss is 19%, then the
selling Price would have
been, x - 19% of x, i.e., 81𝑥
100
∴ 81𝑥
100 + 162 = x + 17% of x =
117𝑥
100
∴ 36 x = 16200
∴ x = Rs. 450.
Que.:- It costs Re. 1 to
photocopy a sheet of paper.
However, 2% discount is
allowed on all photocopies
done after first 1000
sheets. How much will it
cost to copy 5000 sheets of
paper?
Sol.:- Total cost,
=Rs. [1x1000+(100-2)% of 1x4000]
=Rs. (1000+0.98 x 4000)
=Rs. (1000+3920)
=Rs. 4920.
Que.:- If by selling 110
apples, the C.P. of 120
apples is realised, the gain
percentage is:
Sol.:-
Let C.P. of each apple be Rs.1.
C.P. of 110 apples = Rs. 110
S.P. of 110 apples = Rs. 120
∴ Gain % = (10
110 x 100) %
= 9 1
11 %.
Que.:- By selling 12 toffees
for a rupee, a man loses
20%. How many for a
rupee should he sell to get
a gain of 20%?
Sol.:-
Let S.P. of 12 toffees be Rs. x.
Then, 80 : 1 = 120 : x
∴ x = (120
80) =
3
2 .
For Rs. 3
2 , toffees sold = 12.
For Rs. 1 , toffees sold,
= (12 x 2
3) = 8.
Que.:- The cash difference
between the selling prices
of an article at a profit of
4% and 6% is Rs. 3. The
ratio of the two selling
prices is:
Sol.:-
Let C.P. of the article be Rs. x.
Then, Required ratio,
= 104% 𝑥
106% 𝑥 =
104
106 =
52
53 = 52:53.
Que.:- Peter bought an item
at 20% discount on its
original price. He sold it
with 40% increase on the
price he bought it. The new
sale price is by what
percent more than the
original price?
Sol.:-
Let the original price be Rs.
100. Then, C.P. = Rs. 80.
∴ S.P. = 140% of Rs. 80
= Rs. (140
100 x 80)
= Rs. 112.
∴ Required Percentage,
= (112 - 100) % = 12%.
Que.:- A dishonest dealer
professes to sell his goods
at cost price. But he uses a
false weight and thus gains
6 𝟏𝟖
𝟒𝟕 %. For a kg, he uses a
weight of:
Sol.:-
Let error = x gms. Then,
𝑥
1000−𝑥 x 100 = 6
18
47
∴ 100𝑥
1000−𝑥 =
300
47
∴ 47 x = 3 (1000 - x)
∴ 50 x = 3000
∴ x = 60.
∴ Weight used = (1000 - 60)
= 940 gms.
Que.:- A shopkeeper cheats
to the extent of 10% while
buying as well as selling, by
using false weights. His
total gain is:
Sol.:-
Rule:
Gain % = (100+𝑐𝑜𝑚𝑚𝑜𝑛 𝑔𝑎𝑖𝑛 %)2
100− 100
∴ Gain %= [ (100+10)2
100− 100] %
= (12100−10000
100) %
= 21 %.
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This is a compilation of chapterwise questions of Quantitative Aptitude that have been
recently asked in the various Competitive Examinations by SSC, IBPS, SBI, Railway,
Airforce, etc. This is a rare collection of more than 50 questions (On Profit & Loss) and
their respective explanations by Race Express.