Game Theory Analysis of Self-Awareness and Politeness

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EasyChair Preprintโ„– 3083

Game Theory Analysis of Self-Awareness andPoliteness

Huanhuan Guo and Biao Gao

EasyChair preprints are intended for rapiddissemination of research results and areintegrated with the rest of EasyChair.

March 31, 2020

Game Theory Analysis of Self-awareness and Politeness

Huanhuan Guo1 Biao Gao

2*

1Graduate School of Economics, Kobe University, 2-1, Rokkodai, Nada, Kobe, 657-8501, Japan

2Graduate School of Business Administration, Kobe University, 2-1, Rokkodai, Nada, Kobe, 657-8501, Japan

Abstract

This paper studies human irrational behavior from the perspective of behavioral

economics. Through the establishment of a game model, we can understand why

people do not seek help from others when they are clearly in trouble. By adding

politeness and self-awareness as influencing factors, people's help-seeking and

help-giving behavior was clarified by seeking Bayesian Nash equilibrium. As a result,

we clarified the relationship between politeness, self-awareness and the willingness of

the help seekers as well as the helpers. Specifically, on one hand, from the

perspective of the help seekers, we can distinguish people who are likely to seek help

from who are unlikely to seek help. On the other hand, from the perspective of helpers,

we can distinguish people who are likely to help from who are unlikely to help others.

Keywords: Game Theory; Bayesian Nash equilibrium; Self-awareness; Politeness;

Behavioral economics

*Corresponding author.

E-mail address:Biaogao.edu@outlook.com (Biao Gao)

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1. Introduction

This study explores the psychological mechanism of human help-seeking and

help-giving behavior based on game theory. Take Japanese society as an example,

living in Japan, the Japanese often refuse to ask for help. One important reason is

politeness. In order not to make trouble for others, Japanese people treat others

politely. However, if help seekers care about making trouble for others too much, it's

hard to seek for help (Bendixsen & Wyller, 2019; Martochhio, 2005). On the other

hand, from the aspect of helpers, helpers will feel sympathy for help seekers when

they are asked for help, so they would decide to help or not immediately (Bohns &

Flynn, 2015). Besides, self-awareness is also an important reason why help seekers

can be embarrassed (Barbee, Rowatt & Cunningham, 1996). In this study,

self-awareness is to speculate about what others think of themselves. In other words,

people with strong self-awareness would care too much about othersโ€™ opinions.

People with low self-awareness would less likely care about what others think. In order

not to be looked down upon by others, help seekers with strong self -awareness are

relatively difficult to send a signal. For the same reason, in order not to be looked

down upon by others, helpers with strong self-awareness may help others forcibly if

they are asked. Hashimoto (2015) stated that there are two reasons to explain: the

first reason why help seekers do not ask is that if their help-seeking is low yield and

high cost to helpers, help seekers would also have negative emotions such as debt

and apology. This politeness as human nature will affect people's help-seeking

behavior. The second reason is that if help seekers accept helper's assistance, they're

afraid they won't be able to repay and being ungrateful, so they have to suppress their

request in advance. From a game theory perspective, this study does not consider the

action of future recompense and only analyzes from the nature of self -awareness. We

assume that people with self-awareness should care about how others think of

themselves, and can thus affect their help-seeking behavior accordingly.

The research objective of this study is as follows: On one hand, from the

perspective of the help seekers, it is important to distinguish people who are likely to

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seek help from who are unlikely to seek help. On the other hand, from the perspective

of helpers, it is also important to distinguish people who are likely to help from who are

unlikely to help others. This study is thus expected to make important contributions by

analyzing human help-seeking and giving behavior from the aspects of politeness and

self-awareness. We would be able to clarify the relationship between politeness,

self-awareness and the willingness of the help seekers as well as the helpers.

Consequently, to fulfill the objectives of the study, we first set up the game theory

model. After that, we find the Bayesian Nash equilibrium. Finally, the results of

equilibrium are summarized.

2. Model

In this study, we firstly established a game model, which is given by Harsanyi

(1967) and adopted by many researchers, such as Myatt & Wallace (2004); Huang &

Zhu (2020).

The characters on the stage are player A as a help-seeker and player B as a

helper. A can be people with the low ability signed as ๐ฟ or high ability signed as ๐ป .

Player B can also be people with the low ability or high ability. The utility function of

each player is:

๐‘ˆ ๐‘ˆ ๐‘ˆ

๐‘ˆ

๐‘ˆ

is the utility of the actual cost paid. ๐‘ˆ

is related to the basic cost c and the

ability cost of that player, thus, ๐‘ˆ ๐‘Ž from player A's point of view, if player B

does not help him, he has to work on it by himself, that is ๐‘ˆ ๐‘Ž

๐ด ; If Player B

helps, he can do it without effort, that is ๐‘ˆ๐ด ; from player B's point of view, if he

helps player A, he has to make his own efforts, that is ๐‘ˆ๐ต ๐‘Ž

๐ต๐‘; If he does not help,

he does not have to make effort๏ผŒthat is ๐‘ˆ๐ต . The player with high ability cost less;

on the contrary, the player with low ability cost more.

๐‘ˆ

is the utility of self-awareness, which is related to the degree of

self-awareness๏ผŒrepresented by ๐›ผ, and the speculation about how others think of

3

๐ดโฌš

โฌš

๐ดโฌš

โฌš๐ดโฌš

โฌš

๐ดโฌš

โฌš

(1 ๐‘ƒ๐ด

โฌš)

๐ตโฌš

โฌš

๐ตโฌš

โฌš

๐ป๐ต

โฌš

๐ฟ๐ต

โฌš

๐‘โฌš

โฌš

๐‘โฌš

โฌš

๐‘โฌš

โฌš (((1 ๐‘ƒ

๐ต

โฌš) ๐‘ƒ

๐ต

โฌš

๐‘ƒ๐ต

โฌš (1 ๐‘ƒ

๐ต

โฌš)

๐ตโฌš

โฌš

๐ตโฌš

โฌš

๐ตโฌš

โฌš

๐ตโฌš

โฌš

sos

n n

h

so

sos

so

n

n

h h

n

n

n

n

h ๐ตโฌš

โฌš

๐›พโฌš

โฌš

๐›ฟโฌš

โฌš

๐œ–โฌš

โฌš

๐œƒโฌš

โฌš

1 ๐œ–โฌš

โฌš

๐œ‡โฌš

โฌš

๐œ‹โฌš

โฌš

1 ๐œƒโฌš

โฌš ๐œŒ

โฌš

โฌš

๐œโฌš

โฌš

1 ๐›ฟโฌš

โฌš

1 ๐œ‡โฌš

โฌš

1 ๐œ‹โฌš

โฌš

1 ๐œโฌš

โฌš

1-ฮณ

1-ฯ

๐ดโฌš

โฌš

n

n

h

himself, represented by ๐ธ(๐‘Ž). Thus, ๐‘ˆ ๐›ผ[๐ธ(๐‘Ž) ๐‘Ž

]. ๐ธ

๐ต.๐‘Ž๐ด ๐‘†๐‘’๐‘’๐‘˜

/ means player

B speculates on A's ability when player A seeks for help; ๐ธ๐ต.๐‘Ž๐ด ๐‘๐‘œ๐‘ก ๐‘ ๐‘’๐‘’๐‘˜

/ means

player B speculates on player A's ability when player A doesn't seek for help;

๐ธ๐ด.๐‘Ž๐ต ๐ป๐‘’๐‘™๐‘

/ means player A speculates on player B's ability when player B helps;

๐ธ๐ด.๐‘Ž๐ต ๐‘๐‘œ๐‘ก ๐‘’๐‘™๐‘

/ means player A speculates on player B's ability when player B

doesn't help. ๐‘ˆ

is the effect of politeness, and the degree of politeness ฮฒ (0 < ฮฒ < 1)

is related to the basic cost and his actual ability, thus, ๐‘ˆ ๐›ฝ๐‘๐‘Ž.

Player A's utility in seeking help is:

๐‘ˆ๐ด ๐‘†๐‘’๐‘’๐‘˜

๐›ผ๐ด 0๐ธ๐ต .๐‘Ž๐ด ๐‘†๐‘’๐‘’๐‘˜/ ๐‘Ž๐ด1 ๐›ฝ๐ด๐‘๐‘Ž๐ต

Player A's utility when he doesn't seek help is:

๐‘ˆ๐ด ๐‘๐‘œ๐‘ก ๐‘ ๐‘’๐‘’๐‘˜

๐‘Ž๐ด๐‘ ๐›ผ

๐ด 0๐ธ๐ต .๐‘Ž๐ด ๐‘๐‘œ๐‘ก ๐‘ ๐‘’๐‘’๐‘˜/ ๐‘Ž๐ด1

The utility of player B's help is:

๐‘ˆ๐ต ๐ป๐‘’๐‘™๐‘

๐‘Ž๐ต๐‘ ๐›ผ

๐ต 0๐ธ๐ด .๐‘Ž๐ต ๐ป๐‘’๐‘™๐‘/ ๐‘Ž๐ต1

The utility of player B without help is:

๐‘ˆ๐ต ๐‘๐‘œ๐‘ก โ„Ž๐‘’๐‘™๐‘

๐›ผ๐ต 0๐ธ๐ด .๐‘Ž๐ต ๐‘๐‘œ๐‘ก โ„Ž๐‘’๐‘™๐‘/ ๐‘Ž๐ต1 ๐›ฝ๐ต๐‘๐‘Ž๐ด

When the difference between the ability predicted by others and his actual ability

is positive, it is ๐›ผ ; and when it is negative, it becomes ๐›ผ

. The relationship between

๐›ผ and ๐›ผ

is ๐›ผ

๐›ผ

as follows:

Nature enters twice in this game. The game tree is as follows:

๐ฟ๐ด

โฌš ๐‘ƒ

๐ด

โฌš

๐ป๐ด

โฌš

๐ป๐ต

โฌš

๐ฟ๐ต

โฌš

4

The probability of ๐ฟ๐ด

with high ability is ๐‘ƒ๐ด

; The probability of ๐ป๐ด

with low

ability is ๏ผˆ๏ผ‘๏ผ๐‘ƒ๐ด๏ผ‰; ๐ฟ

๐ดโ€™s probability of seeking help is ๐‘ž; its probability of not seeking

help ๏ผ‘ ๐‘ž; The probability of ๐ป๐ดโ€™s help-seeking is ๐‘ž ; Its probability of not seeking for

help is ๏ผ‘ ๐‘ž . Let the probability of ๐ฟ๐ด

be ๐‘ƒ๐ด

, the probability of ๐ป๐ด

be ๏ผˆ๏ผ‘๏ผ๐‘ƒ๐ด๏ผ‰.

Let the probability of ๐ฟ๐ต

be ๐‘ƒ๐ต

, the probability of๐ป๐ต

be ๏ผˆ๏ผ‘๏ผ๐‘ƒ๐ต๏ผ‰. The probability of

๐ฟ๐ต

giving help is ๐‘Ÿ , its probability of not help is ๏ผ‘ ๐‘Ÿ . The probability of ๐ป๐ต

giving

help is ๐‘Ÿ, its probability of not help is ๏ผ‘ ๐‘Ÿ. Thus, the belief of player A and B at

each point is:

๐›พ (1๏ผ๐‘ƒ๐ต )๐‘ž๐‘ƒ๐ด

๐‘ž๐‘ƒ๐ด .1๏ผ๐‘ƒ๐ต / ๐‘ž .1๏ผ๐‘ƒ๐ต /(1๏ผ๐‘ƒ๐ด )

๐‘ž๐‘ƒ๐ด

๐‘ž๐‘ƒ๐ด ๐‘ž (1๏ผ๐‘ƒ๐ด )ใ€ 1 ๐›พ

๐‘ž (1๏ผ๐‘ƒ๐ด )

๐‘ž๐‘ƒ๐ด ๐‘ž (1๏ผ๐‘ƒ๐ด )ใ€

๐œŒ ๐‘ƒ๐ต ๐‘ž๐‘ƒ๐ด

๐‘ž๐‘ƒ๐ด ๐‘ƒ๐ต ๐‘ž ๐‘ƒ๐ต (1๏ผ๐‘ƒ๐ด )

๐‘ž๐‘ƒ๐ด

๐‘ž๐‘ƒ๐ด ๐‘ž (1๏ผ๐‘ƒ๐ด )ใ€ 1 ๐œŒ

๐‘ž (1๏ผ๐‘ƒ๐ด )

๐‘ž๐‘ƒ๐ด ๐‘ž (1๏ผ๐‘ƒ๐ด )ใ€

ํœ€ ( ๏ผ๐‘ƒ๐ต )๐‘ž๐‘ƒ๐ด ๐‘Ÿ

๐‘ž๐‘ƒ๐ด ( ๏ผ๐‘ƒ๐ต )๐‘Ÿ+๐‘ž๐‘ƒ๐ต ๐‘ƒ๐ด ๐‘Ÿ =

( ๏ผ๐‘ƒ๐ต )๐‘Ÿ

( ๏ผ๐‘ƒ๐ต )๐‘Ÿ+๐‘ƒ๐ต ๐‘Ÿ ใ€ 1 ํœ€

๐‘ƒ๐ต ๐‘Ÿ

.1๏ผ๐‘ƒ๐ต /๐‘Ÿ ๐‘ƒ๐ต ๐‘Ÿ ใ€

๐œ‡ (1๏ผ๐‘ƒ๐ต )(1๏ผ๐‘ƒ๐ด )๐‘ž ๐‘Ÿ

๐‘ž .1๏ผ๐‘ƒ๐ต /(1๏ผ๐‘ƒ๐ด )๐‘Ÿ ๐‘ž ๐‘ƒ๐ต (1๏ผ๐‘ƒ๐ด )๐‘Ÿ

(1๏ผ๐‘ƒ๐ต )๐‘Ÿ

.1๏ผ๐‘ƒ๐ต /๐‘Ÿ ๐‘ƒ๐ต ๐‘Ÿ ใ€ 1 ๐œ‡

๐‘ƒ๐ต ๐‘Ÿ

( ๏ผ๐‘ƒ๐ต )๐‘Ÿ+๐‘ƒ๐ต ๐‘Ÿ ใ€

๐œƒ (1๏ผ๐‘ƒ๐ต )๐‘ƒ๐ด ๐‘ž(1 ๐‘Ÿ)

๐‘ž.1๏ผ๐‘ƒ๐ต /๐‘ƒ๐ด (1 ๐‘Ÿ) ๐‘ž๐‘ƒ๐ต ๐‘ƒ๐ด (1 ๐‘Ÿ )

(1๏ผ๐‘ƒ๐ต )(1 ๐‘Ÿ)

.1๏ผ๐‘ƒ๐ต /(1 ๐‘Ÿ) ๐‘ƒ๐ต (1 ๐‘Ÿ )ใ€ 1 ๐œƒ

๐‘ƒ๐ต (1 ๐‘Ÿ )

.1๏ผ๐‘ƒ๐ต /(1 ๐‘Ÿ) ๐‘ƒ๐ต (1 ๐‘Ÿ )ใ€

๐œ‹ (1๏ผ๐‘ƒ๐ต )(1 ๐‘ƒ๐ด )๐‘ž (1 ๐‘Ÿ)

๐‘ž .1๏ผ๐‘ƒ๐ต /(1 ๐‘ƒ๐ด )(1 ๐‘Ÿ) ๐‘ž ๐‘ƒ๐ต (1 ๐‘ƒ๐ด )(1 ๐‘Ÿ )

(1๏ผ๐‘ƒ๐ต )(1 ๐‘Ÿ)

.1๏ผ๐‘ƒ๐ต /(1 ๐‘Ÿ) ๐‘ƒ๐ต (1 ๐‘Ÿ )ใ€1 ๐œ‹

๐‘ƒ๐ต (1 ๐‘Ÿ )

.1๏ผ๐‘ƒ๐ต /(1 ๐‘Ÿ) ๐‘ƒ๐ต (1 ๐‘Ÿ )ใ€

๐›ฟ (1 ๐‘ž)๐‘ƒ๐ด .1๏ผ๐‘ƒ๐ต /

(1 ๐‘ž)๐‘ƒ๐ด .1๏ผ๐‘ƒ๐ต / (1 ๐‘ž ).1๏ผ๐‘ƒ๐ต /(1๏ผ๐‘ƒ๐ด )

(1 ๐‘ž)๐‘ƒ๐ด

(1 ๐‘ž)๐‘ƒ๐ด (1 ๐‘ž )(1๏ผ๐‘ƒ๐ด )ใ€

1 ๐›ฟ (1 ๐‘ž ).1๏ผ๐‘ƒ๐ต /(1๏ผ๐‘ƒ๐ด )

(1 ๐‘ž)๐‘ƒ๐ด .1๏ผ๐‘ƒ๐ต / (1 ๐‘ž ).1๏ผ๐‘ƒ๐ต /(1๏ผ๐‘ƒ๐ด )=

( ๐‘ž )( ๏ผ๐‘ƒ๐ด )

( ๐‘ž)๐‘ƒ๐ด +( ๐‘ž )( ๏ผ๐‘ƒ๐ด )

Therefore, if player A seeks for help, player B is in two situations: help and not

help. Take the utility of player A when player B helps as ๐‘ˆ๐ด๐‘ ๐‘’๐‘’๐‘˜๐‘‚

, and the utility of

player A when player B doesn't help A as ๐‘ˆ๐ด๐‘ ๐‘’๐‘’๐‘˜๐‘‹

. Thus,

๐‘ˆ๐ด ๐‘†๐‘’๐‘’๐‘˜๐‘‚

๐›ผ๐ด 0๐ธ๐ต .๐‘Ž๐ด ๐‘†๐‘’๐‘’๐‘˜/ ๐‘Ž๐ด1 ๐›ฝ๐ด๐‘๐‘Ž๐ต

5

๐‘ˆ๐ด ๐‘†๐‘’๐‘’๐‘˜๐‘‹

๐‘Ž๐ด๐‘ ๐›ผ

๐ด 0๐ธ๐ต .๐‘Ž๐ด ๐‘†๐‘’๐‘’๐‘˜/ ๐‘Ž๐ด1

Player A's utility is:

๐‘ˆ๐ด ๐‘†๐‘’๐‘’๐‘˜

๐‘ƒ๐ต 0๐‘Ÿ ๐‘ˆ๐ด ๐‘†๐‘’๐‘’๐‘˜๐‘‚ (1 ๐‘Ÿ )๐‘ˆ๐ด ๐‘†๐‘’๐‘’๐‘˜๐‘‹1

(1 ๐‘ƒ๐ต),๐‘Ÿ๐‘ˆ

๐ด ๐‘†๐‘’๐‘’๐‘˜๐‘‚ (1 ๐‘Ÿ)๐‘ˆ

๐ด ๐‘†๐‘’๐‘’๐‘˜๐‘‹-

๐‘ˆ๐ด ๐‘๐‘œ๐‘ก ๐‘ ๐‘’๐‘’๐‘˜

๐‘Ž๐ด๐‘ ๐›ผ

๐ด 0๐ธ๐ต .๐‘Ž๐ด ๐‘๐‘œ๐‘ก ๐‘ ๐‘’๐‘’๐‘˜/ ๐‘Ž๐ด1

In the case of ๐ป๐ด high ability:

0๐ธ๐ต.๐‘Ž๐ด ๐‘†๐‘’๐‘’๐‘˜/ ๐ป๐ด 1 (1 ๐‘ƒ

๐ต) [๐ฟ๐ด ๐›พ ๐ป๐ด (1 ๐›พ)] ๐‘ƒ๐ต [๐ฟ๐ด ๐œŒ ๐ป๐ด (1 ๐œŒ)] ๐ป๐ด

[๐ฟ๐ด ๐›พ ๐ป๐ด (1 ๐›พ)] ๐ป๐ด > 0

0๐ธ๐ต.๐‘Ž๐ด ๐‘๐‘œ๐‘ก ๐‘ ๐‘’๐‘’๐‘˜/ ๐ป๐ด 1 (1 ๐‘ƒ

๐ต) [๐ฟ๐ด ๐›ฟ ๐ป๐ด (1 ๐›ฟ)] ๐‘ƒ๐ต [๐ฟ๐ด ๐œ ๐ป๐ด (1 ๐œ)] ๐ป๐ด

[๐ฟ๐ด ๐›ฟ ๐ป๐ด (1 ๐›ฟ)] ๐ป๐ด > 0

Therefore, ๐›ผ๐ด

of both parties is ๐›ผ๐ด

. Player A's utility in seeking help is:

๐‘ˆ๐ด ๐‘†๐‘’๐‘’๐‘˜

๐‘ƒ๐ต 0๐‘Ÿ ๐‘ˆ๐ด ๐‘†๐‘’๐‘’๐‘˜๐‘‚ (1 ๐‘Ÿ )๐‘ˆ๐ด ๐‘†๐‘’๐‘’๐‘˜๐‘‹1

(1 ๐‘ƒ๐ต),๐‘Ÿ๐‘ˆ

๐ด ๐‘†๐‘’๐‘’๐‘˜๐‘‚ (1 ๐‘Ÿ)๐‘ˆ

๐ด ๐‘†๐‘’๐‘’๐‘˜๐‘‹-

,๐‘ƒ๐ต๐‘Ÿ (1 ๐‘ƒ

๐ต)๐‘Ÿ-๐‘ˆ

๐ด ๐‘†๐‘’๐‘’๐‘˜๐‘‚ ,๐‘ƒ

๐ต (1 ๐‘Ÿ ) (1 ๐‘ƒ๐ต )(1 ๐‘Ÿ)-๐‘ˆ๐ด ๐‘†๐‘’๐‘’๐‘˜๐‘‹

,๐‘ƒ๐ต๐‘Ÿ .1 ๐‘ƒ

๐ต/ ๐‘Ÿ-* ๐›ผ

๐ด1[[๐ฟ๐ด ๐›พ ๐ป๐ด (1 ๐›พ)] ๐ป๐ด ] ๐›ฝ๐ด๐‘๐‘Ž๐ต+ ,๐‘ƒ๐ต (1 ๐‘Ÿ )

.1 ๐‘ƒ๐ต/ (1 ๐‘Ÿ)-* ๐‘๐ป

๐ด ๐›ผ

๐ด1[[๐ฟ๐ด ๐›พ ๐ป๐ด (1 ๐›พ)] ๐ป๐ด ]+

Player A's utility when he doesn't seek for help is:

๐‘ˆ๐ด ๐‘๐‘œ๐‘ก ๐‘ ๐‘’๐‘’๐‘˜

๐‘Ž๐ด๐‘ ๐›ผ

๐ด 0๐ธ๐ต .๐‘Ž๐ด ๐‘๐‘œ๐‘ก ๐‘ ๐‘’๐‘’๐‘˜/ ๐‘Ž๐ด1

6

๐ป๐ด๐‘ ๐›ผ

๐ด1[[๐ฟ๐ด ๐›ฟ ๐ป๐ด (1 ๐›ฟ)] ๐ป๐ด ]

In the case of ๐ฟ๐ด

with low ability:

0๐ธ๐ต.๐‘Ž๐ด seek

/ ๐ฟ๐ด1 (1 ๐‘ƒ

๐ต) [๐ฟ๐ด ๐›พ ๐ป๐ด (1 ๐›พ)] ๐‘ƒ๐ต [๐ฟ๐ด ๐œŒ ๐ป๐ด (1 ๐œŒ)] ๐ฟ๐ด

[๐ฟ๐ด ๐›พ ๐ป๐ด (1 ๐›พ)] ๐ฟ๐ด 0

0๐ธ๐ต.๐‘Ž๐ด ๐‘๐‘œ๐‘ก ๐‘ ๐‘’๐‘’๐‘˜/ ๐ป๐ด 1 (1 ๐‘ƒ

๐ต) [๐ฟ๐ด ๐›ฟ ๐ป๐ด (1 ๐›ฟ)] ๐‘ƒ๐ต [๐ฟ๐ด ๐œ ๐ป๐ด (1 ๐œ)] ๐ฟ๐ด

[๐ฟ๐ด ๐›ฟ ๐ป๐ด (1 ๐›ฟ)] ๐ฟ๐ด 0

Therefore, ๐›ผ๐ด

of both parties are ๐›ผ๐ด

. When player A seeks for help, the utility is:

๐‘ˆ๐ด ๐‘†๐‘’๐‘’๐‘˜

๐‘ƒ๐ต 0๐‘Ÿ ๐‘ˆ๐ด ๐‘†๐‘’๐‘’๐‘˜๐‘‚ (1 ๐‘Ÿ )๐‘ˆ๐ด ๐‘†๐‘’๐‘’๐‘˜๐‘‹1

(1 ๐‘ƒ๐ต),๐‘Ÿ๐‘ˆ

๐ด ๐‘†๐‘’๐‘’๐‘˜๐‘‚ (1 ๐‘Ÿ)๐‘ˆ

๐ด ๐‘†๐‘’๐‘’๐‘˜๐‘‹-

,๐‘ƒ๐ต๐‘Ÿ (1 ๐‘ƒ

๐ต)๐‘Ÿ-๐‘ˆ

๐ด ๐‘†๐‘’๐‘’๐‘˜๐‘‚ ,๐‘ƒ

๐ต (1 ๐‘Ÿ ) (1 ๐‘ƒ๐ต )(1 ๐‘Ÿ)-๐‘ˆ๐ด ๐‘†๐‘’๐‘’๐‘˜๐‘‹

,๐‘ƒ๐ต๐‘Ÿ .1 ๐‘ƒ

๐ต/ ๐‘Ÿ-* ๐›ผ

๐ด2[[๐ฟ๐ด ๐›พ ๐ป๐ด (1 ๐›พ)] ๐ฟ๐ด ] ๐›ฝ๐ด๐‘๐‘Ž๐ต+ ,๐‘ƒ๐ต (1 ๐‘Ÿ )

.1 ๐‘ƒ๐ต/ (1 ๐‘Ÿ)-* ๐‘๐ฟ

๐ด ๐›ผ

๐ด2[[๐ฟ๐ด ๐›พ ๐ป๐ด (1 ๐›พ)] ๐ฟ๐ด ]+

Player A's utility when he doesn't seek for help is:

๐‘ˆ๐ด ๐‘๐‘œ๐‘ก ๐‘†๐‘’๐‘’๐‘˜

๐ฟ๐ด๐‘ ๐›ผ

๐ด2[[๐ฟ๐ด ๐›ฟ ๐ป๐ด (1 ๐›ฟ)] ๐ฟ๐ด ]

In the case of ๐ป๐ต

with high ability:

0๐ธ๐ด .๐‘Ž๐ต ๐ป๐‘’๐‘™๐‘/ ๐‘Ž๐ต 1 ๐‘ƒ๐ด [๐ฟ๐ต (1 ํœ€) ๐ป๐ต ํœ€] (1 ๐‘ƒ

๐ด) [๐ฟ๐ต (1 ๐œ‡) ๐ป๐ต ๐œ‡] ๐ป๐ต

๐ฟ๐ต (1 ํœ€) ๐ป๐ต ํœ€ ๐ป๐ต > 0

0๐ธ๐ด .๐‘Ž๐ต ๐‘๐‘œ๐‘ก โ„Ž๐‘’๐‘™๐‘/ ๐ป๐ต 1 ๐‘ƒ๐ด [๐ฟ๐ต (1 ๐œƒ) ๐ป๐ต ๐œƒ] (1 ๐‘ƒ

๐ด) [๐ฟ๐ต (1 ๐œ‹) ๐ป๐ต ๐œ‹] ๐ป๐ต

7

๐ฟ๐ต(1 ๐œƒ) ๐ป

๐ต๐œƒ ๐ป

๐ต> 0

Therefore, ๐›ผ๐ต

of both parties are ๐›ผ๐ต

. At this time, the utility of player B when he

helps is:

๐‘ˆ๐ต ๐ป๐‘’๐‘™๐‘

๐ป๐ต๐‘ ๐›ผ

๐ต1 0๐ธ๐ด .๐‘Ž๐ต ๐ป๐‘’๐‘™๐‘/ ๐ป๐ต 1

๐ป๐ต๐‘ ๐›ผ

๐ต1, ๐ฟ

๐ต(1 ํœ€) ํœ€๐ป

๐ต ๐ป

๐ต-

The utility of player B when he doesnโ€™t help is:

๐‘ˆ๐ต ๐‘๐‘œ๐‘ก โ„Ž๐‘’๐‘™๐‘

๐›ผ๐ต1 0๐ธ๐ด .๐‘Ž๐ต ๐‘๐‘œ๐‘ก โ„Ž๐‘’๐‘™๐‘/ ๐ป๐ต 1 ๐›ฝ๐ต๐‘๐‘Ž๐ด

๐›ผ๐ต1 [๐ฟ๐ต (1 ๐œƒ) ๐ป๐ต ๐œƒ ๐ป๐ต ] ๐›ฝ๐ต๐‘๐‘Ž๐ด

In the case of ๐ฟ๐ต

:

0๐ธ๐ด.๐‘Ž๐ต help

/ ๐‘Ž๐ต1 ๐‘ƒ

๐ด0๐ฟ๐ต(1 ํœ€) ๐ป

๐ตํœ€1 .1 ๐‘ƒ

๐ด/ 0๐ฟ

๐ต(1 ๐œ‡) ๐ป

๐ต๐œ‡1 ๐ฟ

๐ต

๐ฟ๐ต (1 ํœ€) ๐ป๐ต ํœ€ ๐ฟ๐ต 0

0๐ธ๐ด .๐‘Ž๐ต ๐‘›๐‘œ โ„Ž๐‘’๐‘™๐‘/ ๐‘Ž๐ต 1 ๐‘ƒ๐ด [๐ฟ๐ต (1 ๐œƒ) ๐ป๐ต ๐œƒ] (1 ๐‘ƒ

๐ด) [๐ฟ๐ต (1 ๐œ‹) ๐ป๐ต ๐œ‹] ๐ฟ๐ต

๐ฟ๐ต(1 ๐œƒ) ๐ป

๐ต๐œƒ ๐ฟ

๐ต 0

Therefore, ๐›ผ๐ต

of both parties are ๐›ผ๐ต

. At this time, the utility of player B when he

helps is:

๐‘ˆ๐ต ๐ป๐‘’๐‘™๐‘

๐ฟ๐ต๐‘ ๐›ผ

๐ต2 0๐ธ๐ด .๐‘Ž๐ต ๐ป๐‘’๐‘™๐‘/ ๐ฟ๐ต 1

๐ฟ๐ต๐‘ ๐›ผ

๐ต2, ๐ฟ

๐ต(1 ํœ€) ํœ€๐ป

๐ต ๐ฟ

๐ต-

The utility of player B when he doesnโ€™t help is:

๐‘ˆ๐ต ๐‘๐‘œ๐‘ก โ„Ž๐‘’๐‘™๐‘

๐›ผ๐ต2 0๐ธ๐ด .๐‘Ž๐ต ๐‘๐‘œ๐‘ก โ„Ž๐‘’๐‘™๐‘/ ๐ฟ๐ต 1 ๐›ฝ๐ต๐‘๐‘Ž๐ด

๐›ผ๐ต2 [๐ฟ๐ต (1 ๐œƒ) ๐ป๐ต ๐œƒ ๐ฟ๐ต ] ๐›ฝ๐ต๐‘๐‘Ž๐ด

3. Equilibrium Analysis

Now let's analyze the equilibrium. For player A and player B, when they decide

their strategy, because they would select the strategy with larger util ity, thus we should

8

compare the difference of the utility of playersโ€™ different selection.

In the case of ๐ป๐ต :

๐‘ˆ๐ต ๐ป๐‘’๐‘™๐‘

๐‘ˆ๐ต ๐‘๐‘œ๐‘ก โ„Ž๐‘’๐‘™๐‘

๐ป๐ต๐‘ ๐›ผ

๐ต1 [ ๐ฟ๐ต (1 ํœ€) ๐ป๐ต ํœ€ ๐ป๐ต ] ๐›ผ๐ต1 [๐ฟ๐ต (1 ๐œƒ) ๐ป๐ต ๐œƒ ๐ป๐ต ] ๐›ฝ๐ต๐‘๐‘Ž๐ด

๐›ผ๐ต1(๐ฟ๐ต ๐ป

๐ต)(ํœ€ ๐œƒ) ๐‘(๐›ฝ

๐ต๐‘Ž๐ด ๐ป

๐ต)

In the case of LB :

๐‘ˆ๐ต ๐ป๐‘’๐‘™๐‘

๐‘ˆ๐ต ๐‘๐‘œ๐‘ก โ„Ž๐‘’๐‘™๐‘

๐ฟ๐ต๐‘ ๐›ผ

๐ต2 0๐ธ๐ด .๐‘Ž๐ต ๐ป๐‘’๐‘™๐‘/ ๐ฟ๐ต 1 ๐›ผ๐ต2 0๐ธ๐ด .๐‘Ž๐ต ๐‘๐‘œ๐‘ก โ„Ž๐‘’๐‘™๐‘/ ๐ฟ๐ต 1 ๐›ฝ๐ต๐‘๐‘Ž๐ด

๐ฟ๐ต๐‘ ๐›ผ

๐ต2 [๐ฟ๐ต (1 ํœ€) ๐ป๐ต ํœ€ ๐ฟ๐ต ] ๐›ผ๐ต2 [๐ฟ๐ต (1 ๐œƒ) ๐ป๐ต ๐œƒ ๐ฟ๐ต ] ๐›ฝ๐ต๐‘๐‘Ž๐ด

๐›ผ๐ต2(๐ฟ๐ต ๐ป

๐ต)(ํœ€ ๐œƒ) ๐‘(๐›ฝ

๐ต๐‘Ž๐ด ๐ฟ

๐ต)

In the case of ๐ป :

๐‘ˆ๐ด ๐‘†๐‘’๐‘’๐‘˜

๐‘ˆ๐ด ๐‘๐‘œ๐‘ก ๐‘†๐‘’๐‘’๐‘˜

,๐‘ƒ๐ต๐‘Ÿ .1 ๐‘ƒ

๐ต/ ๐‘Ÿ-* ๐›ผ

๐ด1[[๐ฟ๐ด ๐›พ ๐ป๐ด (1 ๐›พ)] ๐ป๐ด ] ๐›ฝ๐ด๐‘๐‘Ž๐ต+ ,๐‘ƒ๐ต (1 ๐‘Ÿ )

.1 ๐‘ƒ๐ต/ (1 ๐‘Ÿ)- { ๐‘๐ป

๐ด ๐›ผ

๐ด1[[๐ฟ๐ด ๐›พ ๐ป๐ด (1 ๐›พ)] ๐ป๐ด ]}

๐ป๐ด๐‘ ๐›ผ

๐ด1[[๐ฟ๐ด ๐›ฟ ๐ป๐ด (1 ๐›ฟ)] ๐ป๐ด ]

๐›ผ๐ด1( ๐›พ ๐›ฟ) .๐ฟ๐ด ๐ป๐ด / (๐‘Ÿ ๐‘ƒ ๐‘Ÿ ๐‘ƒ ๐‘Ÿ)๐‘(๐ป๐ด ๐›ฝ๐ด๐‘Ž๐ต)

In the case of ๐ฟ๐ด :

๐‘ˆ๐ด ๐‘†๐‘’๐‘’๐‘˜

๐‘ˆ๐ด ๐‘๐‘œ๐‘ก ๐‘ ๐‘’๐‘’๐‘˜

,๐‘ƒ๐ต๐‘Ÿ .1 ๐‘ƒ

๐ต/ ๐‘Ÿ-* ๐›ผ

๐ด2[[๐ฟ๐ด ๐›พ ๐ป๐ด (1 ๐›พ)] ๐ฟ๐ด ] ๐›ฝ๐ด๐‘๐‘Ž๐ต+ ,๐‘ƒ๐ต (1 ๐‘Ÿ )

.1 ๐‘ƒ๐ต/ (1 ๐‘Ÿ)- { ๐‘๐ฟ

๐ด ๐›ผ

๐ด2[[๐ฟ๐ด ๐›พ ๐ป๐ด (1 ๐›พ)] ๐ฟ๐ด ]} ๐ฟ๐ด๐‘

9

๐›ผ๐ด2[[๐ฟ๐ด ๐›ฟ ๐ป๐ด (1 ๐›ฟ)] ๐ฟ๐ด ]

๐›ผ๐ด2( ๐›พ ๐›ฟ) .๐ฟ๐ด ๐ป๐ด / (๐‘Ÿ ๐‘ƒ ๐‘Ÿ ๐‘ƒ ๐‘Ÿ)๐‘(๐ฟ๐ด ๐›ฝ๐ด๐‘Ž๐ต)

Player belief:

ํœ€ .1๏ผ๐‘ƒ

๐ต/ ๐‘Ÿ

.1๏ผ๐‘ƒ๐ต/ ๐‘Ÿ ๐‘ƒ

๐ต๐‘Ÿ ใ€๐œƒ

.1๏ผ๐‘ƒ๐ต/ (1 ๐‘Ÿ)

ใ€๐œŒ ๐›พ ๐‘ž๐‘ƒ

๐ด

๐‘ž๐‘ƒ๐ด ๐‘ž .1๏ผ๐‘ƒ

๐ด/ใ€

๐›ฟ (1 ๐‘ž)๐‘ƒ

๐ด

(1 ๐‘ž)๐‘ƒ๐ด (1 ๐‘ž ) .1๏ผ๐‘ƒ

๐ด/ใ€

Furthermore, B with high ability can expect Aโ€™s ability as ๐‘Ž๐ด ๐›พ ๐ฟ

๐ด (1

๐›พ) ๐ป๐ด

.The ability of B with low ability can expect Aโ€™s ability as ๐‘Ž๐ด ๐œŒ ๐ฟ

๐ด (1

๐œŒ) ๐ป๐ด

We thus substitute them into utility function. In addition, Player A with either

the high ability or low ability would decide to seek help or not, player B with either

the high ability or low ability would decide to help or not. When player A is helped by

player B with high ability, r = 1; when player B with high ability doesn't help, r = 0;

when player B with low ability helps, ๐‘Ÿ 1; when player B with low ability doesn't

help, ๐‘Ÿ When player A with low ability seek for help, q = 1; when player A with

low ability doesn't seek for help, q = 0; when player A with high ability seeks for help

๐‘ž 1, when player A with high ability doesn't seek for help ๐‘ž In summary,

there are situations including ๐‘Ÿ 1 ๐‘Ÿ ๐‘Ÿ 1 ๐‘Ÿ ๐‘ž 1 ๐‘ž ๐‘ž 1 ๐‘ž . As

a result, there are 16 combinations. According to calculating there are nine

equilibriums. The following section will discuss these equilibriums.

The first equilibrium is: ๐ป๐ต

help; ๐ฟ๐ต

not help; ๐ฟ๐ด

seek; ๐ป๐ด not seek

โ‘  ๐‘Ÿ 1 ๐‘Ÿ 0 ๐‘ž 1 ๐‘ž 1

In the case of ๐ป๐ต

๐‘ˆ๐ต ๐ป๐‘’๐‘™๐‘

๐‘ˆ๐ต ๐‘๐‘œ๐‘ก โ„Ž๐‘’๐‘™๐‘

๐›ผ๐ต1(๐ฟ๐ต ๐ป

๐ต)(ํœ€ ๐œƒ) ๐‘(๐›ฝ

๐ต๐‘Ž๐ด ๐ป

๐ต)

๐›ผ๐ต1(๐ฟ๐ต ๐ป

๐ต) ๐‘(๐›ฝ

๐ต , ๐‘ƒ

๐ด๐ฟ๐ด .1 ๐‘ƒ

๐ด/๐ป

๐ด- ๐ป

๐ต)

In order to meet the condition ๐‘ˆ๐ต ๐ป๐‘’๐‘™๐‘

๐‘ˆ๐ต ๐‘๐‘œ๐‘ก ๐‘’๐‘™๐‘

> , there must be:

10

๐›ฝ๐ต> ๐›ผ

๐ต1

.๐ฟ๐ต ๐ป

๐ต/

๐‘, ๐‘ƒ๐ด๐ฟ๐ด .1 ๐‘ƒ

๐ด/๐ป

๐ด-

๐ป๐ต

, ๐‘ƒ๐ด๐ฟ๐ด .1 ๐‘ƒ

๐ด/๐ป

๐ด-

The relationship between ๐›ฝ๐ต and ๐›ผ

๐ต is shown in the following figure:

In the case of ๐ฟ๐ต

:

๐‘ˆ๐ต ๐ป๐‘’๐‘™๐‘

๐‘ˆ๐ต ๐‘๐‘œ๐‘ก โ„Ž๐‘’๐‘™๐‘

๐›ผ๐ต2(๐ฟ๐ต ๐ป

๐ต)(ํœ€ ๐œƒ) ๐‘(๐›ฝ

๐ต๐‘Ž๐ด ๐ฟ

๐ต)

๐›ผ๐ต2(๐ฟ๐ต ๐ป

๐ต) ๐‘(๐›ฝ

๐ต๐‘Ž๐ด ๐ฟ

๐ต)

In order to meet the condition ๐‘ˆ๐ต help

๐‘ˆ๐ต not help

, there must be:

๐›ฝ๐ต ๐›ผ

๐ต2

.๐ฟ๐ต ๐ป

๐ต/

๐‘,๐‘ƒ๐ด๐ฟ๐ด .1 ๐‘ƒ

๐ด/๐ป

๐ด-

๐ฟ๐ต

๐‘ƒ๐ด๐ฟ๐ด .1 ๐‘ƒ

๐ด/๐ป

๐ด

The relationship between ๐›ฝ๐ต and ๐›ผ

๐ต is shown in the following figure:

Next, let ๐ป๐ต

=๐ป๐ด ๐ฟ๐ต

=๐ฟ๐ด ๐‘ƒ๐ต

=๐‘ƒ๐ด ๐›ผ๐ต ๐›ผ

๐ด =๐›ผ

๐›ผ๐ต ๐›ผ

๐ด =๐›ผ

๐›ฝ๐ด ๐›ฝ

๐ต. In this

case, set the difference between ๐›ผ

and ๐›ผ

to ฮพ. Thus, ๐›ผ ๐›ผ

๐œ‰ . Because

player B must meet the conditions of ๐ป๐ต

and ๐ฟ๐ต

, we thus find the union set of ๐ป๐ต

and ๐ฟ๐ต

. To put the two figures above together, we must distinguish between

occasions between ๐‘๐ฟ๐ต

๐ฟ๐ต ๐ป๐ต

๐œ‰ >๐‘๐ป๐ต

๐ฟ๐ต ๐ป๐ต

as case 1๐ต and๐‘๐ฟ๐ต

๐ฟ๐ต ๐ป๐ต

๐œ‰ ๐‘๐ป๐ต

๐ฟ๐ต ๐ป๐ต

as case

๐ต. At this point:

11

Case 1๐ต๏ผš Case ๐ต๏ผšโˆ…

In the case of ๐ป๐ด

๐‘ˆ๐ด ๐‘†๐‘’๐‘’๐‘˜

๐‘ˆ๐ด ๐‘๐‘œ๐‘ก ๐‘ ๐‘’๐‘’๐‘˜

๐›ผ๐ด1( ๐›พ ๐›ฟ) .๐ฟ๐ด ๐ป๐ด / (๐‘Ÿ ๐‘ƒ ๐‘Ÿ ๐‘ƒ ๐‘Ÿ)๐‘(๐ป๐ด ๐›ฝ๐ด๐‘Ž๐ต)

๐›ผ๐ด ( ๐›พ ๐›ฟ) .๐ฟ

๐ด ๐ป

๐ด/ (1 ๐‘ƒ

๐ต)๐‘(๐ป

๐ด ๐›ฝ

๐ด๐ป๐ต)๏ผŒ

Therefore, in order to meet the condition ๐‘ˆ๐ด Seek

๐‘ˆ๐ด Not seek

> , there must be:

๐›ฝ๐ด ๐›ผ

๐ด

( ๐›พ ๐›ฟ)(๐ฟ๐ด ๐ป๐ด )

๐‘๐ป๐ต ( ๐‘ƒ๐ต ) ๐ป๐ด

๐ป๐ต

. Because there are ( ๐›พ ๐›ฟ) > and ( ๐›พ ๐›ฟ) , The

relationship between ๐›ฝ๐ด and ๐›ผ

๐ด is shown in the following figure:

In the case of ๐ฟ๐ด

๐‘ˆ๐ด ๐‘†๐‘’๐‘’๐‘˜

๐‘ˆ๐ด ๐‘๐‘œ๐‘ก ๐‘ ๐‘’๐‘’๐‘˜

๐›ผ๐ด2( ๐›พ ๐›ฟ) .๐ฟ๐ด ๐ป๐ด / .1 ๐‘ƒ

๐ต/ ๐‘(๐ฟ

๐ด ๐›ฝ

๐ด๐‘Ž๐ต)

๐›ผ๐ด2( ๐›พ ๐›ฟ) .๐ฟ

๐ด ๐ป

๐ด/ .1 ๐‘ƒ

๐ต/ ๐‘(๐ฟ

๐ด ๐›ฝ

๐ด๐ป๐ต-)

Therefore, in order to meet the condition ๐‘ˆ๐ด ๐‘†๐‘’๐‘’๐‘˜

๐‘ˆ๐ด ๐‘๐‘œ๐‘ก ๐‘ ๐‘’๐‘’๐‘˜

> , there must be:

๐›ฝ๐ด ๐›ผ

๐ด

( ๐›พ ๐›ฟ)(๐ฟ๐ด ๐ป๐ด )

๐‘๐ป๐ต .1๏ผ๐‘ƒ๐ต / ๐ฟ๐ด

๐ป๐ต

.

Because there are ( ๐›พ ๐›ฟ) > and ( ๐›พ ๐›ฟ) the relationship between

12

๐›ฝ๐ด and ๐›ผ

๐ด is shown in the following figure:

Because player B must meet the conditions of ๐ป๐ด

and ๐ฟ๐ด

, we thus find the

union set of ๐ป๐ด

and ๐ฟ๐ด

. Owing to ๐œ‰ > , ๐‘๐ฟ๐ด ( ๐‘ƒ๐ต )

๐ฟ๐ด ๐ป๐ด

๐œ‰ must be less

than ๐‘๐ป๐ด ( ๐‘ƒ๐ต )

๐ฟ๐ด ๐ป๐ด

. Therefore:

Player A and B must satisfy all of the conditions of game equilibrium case1๐ต or

case ๐ต. Thus, the result that satisfies the conditions of player A and B is 0 < ฮพ < C. The

figure is as follows:

โ‘ก ๐‘Ÿ 1 ๐‘Ÿ 0 ๐‘ž 1 ๐‘ž 0

In the case of ๐ป๐ต

13

๐‘ˆ๐ต ๐ป๐‘’๐‘™๐‘

๐‘ˆ๐ต ๐‘๐‘œ๐‘ก โ„Ž๐‘’๐‘™๐‘

๐›ผ๐ต1(๐ฟ๐ต ๐ป

๐ต)(ํœ€ ๐œƒ) ๐‘(๐›ฝ

๐ต๐‘Ž๐ด ๐ป

๐ต)

๐›ผ๐ต1(๐ฟ๐ต ๐ป

๐ต) ๐‘(๐›ฝ

๐ต๐ฟ๐ด ๐ป

๐ต)

Therefore, in order to meet the condition ๐‘ˆ๐ต ๐‘’๐‘™๐‘

๐‘ˆ๐ต ๐‘›๐‘œ๐‘ก ๐‘’๐‘™๐‘

> , there must be:

๐›ฝ๐ต> ๐›ผ

๐ต1

.๐ฟ๐ต ๐ป

๐ต/

๐‘๐ฟ๐ด

๐ป๐ต

๐ฟ๐ด

The relationship between ๐›ฝ๐ต and ๐›ผ

๐ต is shown in the following figure:

In the case of ๐ฟ๐ต

๐‘ˆ๐ต ๐ป๐‘’๐‘™๐‘

๐‘ˆ๐ต ๐‘๐‘œ๐‘ก โ„Ž๐‘’๐‘™๐‘

๐›ผ๐ต2(๐ฟ๐ต ๐ป

๐ต)(ํœ€ ๐œƒ) ๐‘(๐›ฝ

๐ต๐‘Ž๐ด ๐ฟ

๐ต)

๐›ผ๐ต2(๐ฟ๐ต ๐ป

๐ต) ๐‘(๐›ฝ

๐ต๐ฟ๐ด ๐ฟ

๐ต)

Therefore, in order to meet the condition ๐‘ˆ๐ต ๐‘’๐‘™๐‘

๐‘ˆ๐ต ๐‘›๐‘œ๐‘ก ๐‘’๐‘™๐‘

, there must be:

๐›ฝ๐ต ๐›ผ

๐ต2

.๐ฟ๐ต ๐ป

๐ต/

๐‘๐ฟ๐ด

๐ฟ๐ต

๐ฟ๐ด

The relationship between ๐›ฝ๐ต and ๐›ผ

๐ต is shown in the following figure:

To put the two figures above together, we must distinguish between occasions

between ๐‘๐ฟ๐ต

๐ฟ๐ต ๐ป๐ต

๐œ‰ >๐‘๐ป๐ต

๐ฟ๐ต ๐ป๐ต

as case 1๐ต and๐‘๐ฟ๐ต

๐ฟ๐ต ๐ป๐ต

๐œ‰ ๐‘๐ป๐ต

๐ฟ๐ต ๐ป๐ต

as case ๐ต . At this

point:

14

Case 1๐ต๏ผš Case ๐ต๏ผšโˆ…

In the case of ๐ป๐ด

๐‘ˆ๐ด ๐‘†๐‘’๐‘’๐‘˜

๐‘ˆ๐ด ๐‘๐‘œ๐‘ก ๐‘ ๐‘’๐‘’๐‘˜

๐›ผ๐ด1( ๐›พ ๐›ฟ) .๐ฟ๐ด ๐ป๐ด / (๐‘Ÿ ๐‘ƒ ๐‘Ÿ ๐‘ƒ ๐‘Ÿ)๐‘(๐ป๐ด ๐›ฝ๐ด๐‘Ž๐ต)

๐›ผ๐ด1.๐ฟ๐ด ๐ป

๐ด/ (1 ๐‘ƒ )๐‘(๐ป๐ด ๐›ฝ๐ด๐ป๐ต )

Therefore, in order to meet the condition ๐‘ˆ๐ด ๐‘ ๐‘’๐‘’๐‘˜

๐‘ˆ๐ด ๐‘›๐‘œ๐‘ก ๐‘ ๐‘’๐‘’๐‘˜

there must be:

๐›ฝ๐ด> ๐›ผ

๐ด1

.๐ฟ๐ด ๐ป

๐ด/

๐‘(1 ๐‘ƒ )๐ป๐ต

1

The relationship between ๐›ฝ๐ด and ๐›ผ

๐ด is shown in the following figure:

In the case of ๐ฟ๐ด

๐‘ˆ๐ด ๐‘†๐‘’๐‘’๐‘˜

๐‘ˆ๐ด ๐‘๐‘œ๐‘ก ๐‘ ๐‘’๐‘’๐‘˜

๐›ผ๐ด2( ๐›พ ๐›ฟ) .๐ฟ๐ด ๐ป๐ด / .1 ๐‘ƒ

๐ต/ ๐‘(๐ฟ

๐ด ๐›ฝ

๐ด๐‘Ž๐ต)

๐›ผ๐ด2.๐ฟ๐ด ๐ป

๐ด/ .1 ๐‘ƒ

๐ต/ ๐‘(๐ฟ

๐ด ๐›ฝ

๐ด๐ป๐ต)

Therefore, in order to meet the condition ๐‘ˆ๐ด ๐‘ ๐‘’๐‘’๐‘˜

๐‘ˆ๐ด ๐‘›๐‘œ๐‘ก ๐‘ ๐‘’๐‘’๐‘˜

> there must be:

๐›ฝ๐ด ๐›ผ

๐ด2

.๐ฟ๐ด ๐ป

๐ด/

๐‘๐ป๐ต.1๏ผ๐‘ƒ

๐ต/ ๐ฟ๐ด

๐ป๐ต

The relationship between ๐›ฝ๐ด and ๐›ผ

๐ด is shown in the following figure:

15

To put the two figures above together, we must distinguish between occasions

between ๐‘๐ฟ๐ด ( ๐‘ƒ๐ต )

๐ฟ๐ด ๐ป๐ด

๐œ‰ >๐‘๐ป๐ด ( ๐‘ƒ๐ต )

๐ฟ๐ด ๐ป๐ด

as case 1๐ด and ๐‘๐ฟ๐ด ( ๐‘ƒ๐ต )

๐ฟ๐ด ๐ป๐ด

๐œ‰ ๐‘๐ป๐ด ( ๐‘ƒ๐ต )

๐ฟ๐ด ๐ป๐ด

as case

๐ด. At this point:

Case 1๐ด๏ผš Case ๐ด๏ผšโˆ…

Player A must satisfy all of the conditions of game equilibrium case1๐ด. Player B must

satisfy all of the conditions of game equilibrium case1๐ต. To satisfy both case1๐ด and

case1๐ต, there must be ๐œ‰ .1 ๐‘ƒ๐ต/. The figure is as follows:

โ‘ข ๐‘Ÿ 1 ๐‘Ÿ 0 ๐‘ž 0 ๐‘ž 0

In the case of ๐ป๐ต

๐‘ˆ๐ต ๐ป๐‘’๐‘™๐‘

๐‘ˆ๐ต ๐‘๐‘œ๐‘ก โ„Ž๐‘’๐‘™๐‘

๐›ผ๐ต1(๐ฟ๐ต ๐ป

๐ต)(ํœ€ ๐œƒ) ๐‘(๐›ฝ

๐ต๐‘Ž๐ด ๐ป

๐ต)

๐›ผ๐ต1(๐ฟ๐ต ๐ป

๐ต) ๐‘(๐›ฝ

๐ต,๐›พ ๐ฟ

๐ด (1 ๐›พ)๐ป

๐ด- ๐ป

๐ต)

Therefore, in order to meet the condition ๐‘ˆ๐ต ๐ป๐‘’๐‘™๐‘

๐‘ˆ๐ต ๐‘๐‘œ๐‘ก ๐‘’๐‘™๐‘

> there must be:

๐›ฝ๐ต> ๐›ผ

๐ต1

.๐ฟ๐ต ๐ป

๐ต/

๐‘,๐›พ ๐ฟ๐ด (1 ๐›พ)๐ป

๐ด-

๐ป๐ต

๐›พ ๐ฟ๐ด (1 ๐›พ) ๐ป

๐ด

The relationship between ๐›ฝ๐ต and ๐›ผ

๐ต is shown in the following figure:

16

In the case of ๐ฟ๐ต

๐‘ˆ๐ต ๐ป๐‘’๐‘™๐‘

๐‘ˆ๐ต ๐‘๐‘œ๐‘ก ๐‘’๐‘™๐‘

๐›ผ๐ต (๐ฟ๐ต ๐ป

๐ต)(ํœ€ ๐œƒ) ๐‘(๐›ฝ

๐ต๐‘Ž๐ด ๐ฟ

๐ต)

๐›ผ๐ต2(๐ฟ๐ต ๐ป

๐ต) ๐‘(๐›ฝ

๐ต,๐œŒ ๐ฟ

๐ด (1 ๐œŒ)๐ป

๐ด- ๐ฟ

๐ต)

Therefore, In order to meet the condition ๐‘ˆ๐ต ๐ป๐‘’๐‘™๐‘

๐‘ˆ๐ต ๐‘๐‘œ๐‘ก ๐‘’๐‘™๐‘

there must be:

๐›ฝ๐ต ๐›ผ

๐ต2

.๐ฟ๐ต ๐ป

๐ต/

๐‘,๐œŒ ๐ฟ๐ด (1 ๐œŒ)๐ป

๐ด-

๐ฟ๐ต

๐œŒ ๐ฟ๐ด (1 ๐œŒ) ๐ป

๐ด

The relationship between๐›ฝ๐ต and ๐›ผ

๐ต is shown in the following figure:

To put the two figures above together, we must distinguish between occasions

between ๐‘๐ฟ๐ต

๐ฟ๐ต ๐ป๐ต

๐œ‰ >๐‘๐ป๐ต

๐ฟ๐ต ๐ป๐ต

as case 1๐ต and ๐‘๐ฟ๐ต

๐ฟ๐ต ๐ป๐ต

๐œ‰ ๐‘๐ป๐ต

๐ฟ๐ต ๐ป๐ต

as case ๐ต . At this

point:

Case 1๐ต๏ผš Case ๐ต๏ผšโˆ…

In the case of ๐ป๐ด

๐‘ˆ๐ด ๐‘†๐‘’๐‘’๐‘˜

๐‘ˆ๐ด ๐‘๐‘œ๐‘ก ๐‘ ๐‘’๐‘’๐‘˜

17

๐›ผ๐ด1( ๐›พ ๐›ฟ) .๐ฟ๐ด ๐ป๐ด / (๐‘Ÿ ๐‘ƒ๐ต ๐‘Ÿ

โ€ฒ ๐‘ƒ

๐ต๐‘Ÿ) ๐‘ .๐ป

๐ด ๐›ฝ

๐ด๐‘Ž๐ต/

๐›ผ๐ด1( ๐›พ ๐›ฟ) .๐ฟ

๐ด ๐ป

๐ด/ .1 ๐‘ƒ

๐ต/ ๐‘(๐ป

๐ด ๐›ฝ

๐ด๐ป๐ต)

Therefore, In order to meet the condition ๐‘ˆ๐ด ๐‘†๐‘’๐‘’๐‘˜

๐‘ˆ๐ด ๐‘๐‘œ๐‘ก ๐‘ ๐‘’๐‘’๐‘˜

there must be:

๐›ฝ๐ด> ๐›ผ

๐ด1

( ๐›พ ๐›ฟ) .๐ฟ๐ด ๐ป๐ด /

๐‘๐ป๐ต.1๏ผ๐‘ƒ

๐ต/

1

When ( ๐›พ ๐›ฟ) > and ( ๐›พ ๐›ฟ) , the relationship between ๐›ฝ๐ต

and ๐›ผ๐ต

is

shown in the following figure:

In the case of ๐ฟ๐ด

๐‘ˆ๐ด ๐‘†๐‘’๐‘’๐‘˜

๐‘ˆ๐ด ๐‘๐‘œ๐‘ก ๐‘ ๐‘’๐‘’๐‘˜

๐›ผ๐ด2( ๐›พ ๐›ฟ) .๐ฟ๐ด ๐ป๐ด / .1 ๐‘ƒ

๐ต/ ๐‘ .๐ฟ

๐ด ๐›ฝ

๐ด๐‘Ž๐ต/

๐›ผ๐ด2( ๐›พ ๐›ฟ) .๐ฟ

๐ด ๐ป

๐ด/ .1 ๐‘ƒ

๐ต/ ๐‘(๐ฟ

๐ด ๐›ฝ

๐ด๐ป๐ต)

Therefore, In order to meet the condition ๐‘ˆ๐ด ๐‘†๐‘’๐‘’๐‘˜

๐‘ˆ๐ด ๐‘๐‘œ๐‘ก ๐‘ ๐‘’๐‘’๐‘˜

there must be:

๐›ฝ๐ด> ๐›ผ

๐ด2

( ๐›พ ๐›ฟ) .๐ฟ๐ด ๐ป๐ด /

๐‘๐ป๐ต.1๏ผ๐‘ƒ

๐ต/

๐ฟ๐ด

๐ป๐ต

When ( ๐›พ ๐›ฟ) > and ( ๐›พ ๐›ฟ) , the relationship between๐›ฝ๐ด and ๐›ผ

๐ด is

shown in the following figure:

:

Does not exist

18

Owing to:

๐›ผ ๐›ผ

๐œ‰,

๐‘๐ฟ๐ด ( ๐‘ƒ๐ต )

๐ฟ๐ด ๐ป๐ด

๐œ‰ >๐‘๐ป๐ต ( ๐‘ƒ๐ต )

(๐ฟ๐ด ๐ป๐ด ) as case 1๐ด

๐‘๐ฟ๐ด ( ๐‘ƒ๐ต )

๐ฟ๐ด ๐ป๐ด

๐œ‰ ๐‘๐ป๐ต ( ๐‘ƒ๐ต )

๐ฟ๐ด ๐ป๐ด

as case

๐ด are as follows:

Case 1๐ด๏ผš Case ๐ด๏ผš

Player A must satisfy all of the conditions of game equilibrium case1 A and player

B must satisfy all of the conditions of game equilibrium case1 B and case ๐ต. Because

case ๐ต is an empty set, the union set of case ๐ต and case 1๐ด is also an empty set.

To satisfy both case1๐ต and case1๐ด, there must be ๐œ‰ .1 ๐‘ƒ๐ต/ To satisfy both

case1๐ต and case ๐ด, there must be .1 ๐‘ƒ๐ต/ ๐œ‰ Both of them are shown in the

following figure:

Does not exist

19

โ‘ฃ ๐‘Ÿ 0 ๐‘Ÿ 0 ๐‘ž 1 ๐‘ž 1

In the case of ๐ป๐ต

๐‘ˆ๐ต ๐ป๐‘’๐‘™๐‘

๐‘ˆ๐ต ๐‘๐‘œ๐‘ก โ„Ž๐‘’๐‘™๐‘

๐›ผ๐ต1(๐ฟ๐ต ๐ป

๐ต)(ํœ€ ๐œƒ) ๐‘(๐›ฝ

๐ต๐‘Ž๐ด ๐ป

๐ต)

๐›ผ๐ต1(๐ฟ๐ต ๐ป

๐ต),ํœ€ (1 ๐‘ƒ

๐ต)- ๐‘(๐›ฝ

๐ต,๐‘ƒ๐ด๐ฟ๐ด (1 ๐‘ƒ

๐ด)๐ป

๐ด- ๐ป

๐ต)

Therefore, In order to meet the condition ๐‘ˆ๐ด ๐ป๐‘’๐‘™๐‘

๐‘ˆ๐ด ๐‘๐‘œ๐‘ก ๐‘’๐‘™๐‘

there must be:

๐›ฝ๐ต ๐›ผ

๐ต1

.๐ฟ๐ต ๐ป

๐ต/ ,ํœ€ (1 ๐‘ƒ

๐ต)-

๐‘,๐‘ƒ๐ด๐ฟ๐ด (1 ๐‘ƒ

๐ด)๐ฟ๐ด-

๐ป๐ต

๐‘ƒ๐ด๐ฟ๐ด (1 ๐‘ƒ

๐ด)๐ฟ๐ด

When (ํœ€ ๐œƒ) > (ํœ€ ๐œƒ) , the relationship between ๐›ฝ๐ต and ๐›ผ

๐ต is

shown in the following figure:

In the case of ๐ฟ๐ต

๐‘ˆ๐ต ๐ป๐‘’๐‘™๐‘

๐‘ˆ๐ต ๐‘๐‘œ๐‘ก โ„Ž๐‘’ ๐‘

๐›ผ๐ต2(๐ฟ๐ต ๐ป

๐ต)(ํœ€ ๐œƒ) ๐‘(๐›ฝ

๐ต๐‘Ž๐ด ๐ฟ

๐ต)

20

๐›ผ๐ต2(๐ฟ๐ต ๐ป

๐ต),ํœ€ (1 ๐‘ƒ

๐ต)- ๐‘*๐›ฝ

๐ต,๐‘ƒ๐ด๐ฟ๐ด .1 ๐‘ƒ

๐ด/๐ป

๐ด- ๐ฟ

๐ต+

Therefore, in order to meet the condition ๐‘ˆ๐ต ๐ป๐‘’๐‘™๐‘

๐‘ˆ๐ต ๐‘๐‘œ๐‘ก ๐‘’๐‘™๐‘

there must be:

๐›ฝ๐ต ๐›ผ

๐ต2

.๐ฟ๐ต ๐ป

๐ต/ ,ํœ€ (1 ๐‘ƒ

๐ต)-

๐‘,๐‘ƒ๐ด๐ฟ๐ด .1 ๐‘ƒ

๐ด/๐ป

๐ด-

๐ฟ๐ต

,๐‘ƒ๐ด๐ฟ๐ด .1 ๐‘ƒ

๐ด/๐ป

๐ด-

When (ํœ€ ๐œƒ) > (ํœ€ ๐œƒ) , the relationship between๐›ฝ๐ต and ๐›ผ

๐ต is

shown in the following figure:

Owing to ๐œ‰ > , ๐‘๐ฟ๐ต

๐ฟ๐ต ๐ป๐ต

๐œ‰ must be less than ๐‘๐ป๐ต

๐ฟ๐ต ๐ป๐ต

. Therefore, the union

set is:

In the case of ๐ป๐ด

๐‘ˆ๐ด ๐‘†๐‘’๐‘’๐‘˜

๐‘ˆ๐ด ๐‘๐‘œ๐‘ก ๐‘ ๐‘’๐‘’๐‘˜

๐›ผ๐ด1(๐›พ ๐›ฟ) .๐ฟ

๐ด ๐ป

๐ด/ (๐‘Ÿ ๐‘ƒ

๐ต๐‘Ÿโ€ฒ ๐‘ƒ

๐ต๐‘Ÿ) ๐‘(๐ป

๐ด ๐›ฝ

๐ด๐‘Ž๐ต)

๐›ผ๐ด1(๐‘ƒ๐ด ๐›ฟ) .๐ฟ

๐ด ๐ป

๐ด/

Therefore, In order to meet the condition ๐‘ˆ๐ด ๐‘†๐‘’๐‘’๐‘˜

๐‘ˆ๐ด ๐‘๐‘œ๐‘ก ๐‘ ๐‘’๐‘’๐‘˜

> there must be:

21

(๐‘ƒ๐ด ๐›ฟ)

When ( ๐›พ ๐›ฟ) , the relationship between ๐›ฝ๐ด and ๐›ผ

๐ด is shown in the

following figure:

In the case of ๐ฟ๐ด

๐‘ˆ๐ด ๐‘†๐‘’๐‘’๐‘˜

๐‘ˆ๐ด ๐‘๐‘œ๐‘ก ๐‘ ๐‘’๐‘’๐‘˜

๐›ผ๐ด2(๐›พ ๐›ฟ) .๐ฟ

๐ด ๐ป

๐ด/ (๐‘Ÿ ๐‘ƒ

๐ต๐‘Ÿโ€ฒ ๐‘ƒ

๐ต๐‘Ÿ) ๐‘(๐ฟ

๐ด ๐›ฝ

๐ด๐‘Ž๐ต)

๐›ผ๐ด2(๐‘ƒ๐ด ๐›ฟ) .๐ฟ

๐ด ๐ป

๐ด/

Therefore, in order to meet the condition ๐‘ˆ๐ด ๐‘†๐‘’๐‘’๐‘˜

๐‘ˆ๐ด ๐‘๐‘œ๐‘ก ๐‘ ๐‘’๐‘’๐‘˜

> there must be:

(๐‘ƒ๐ด ๐›ฟ) , When ( ๐›พ ๐›ฟ) , the relationship between ๐›ฝ

๐ด and ๐›ผ

๐ด is shown in

the following figure:

The condition of player B and player A is ๐œ‰. As shown in the following figure,

โ‘ค ๐‘Ÿ 0 ๐‘Ÿ 0 ๐‘ž 0 ๐‘ž 0

In the case of ๐ป๐ต

๐‘ˆ๐ต ๐‘†๐‘’๐‘’๐‘˜

๐‘ˆ๐ต ๐‘๐‘œ๐‘ก ๐‘ ๐‘’๐‘’๐‘˜

๐›ผ๐ต1(๐ฟ๐ต ๐ป

๐ต)(ํœ€ ๐œƒ) ๐‘(๐›ฝ

๐ต๐‘Ž๐ด ๐ป

๐ต)

๐›ผ๐ต1(๐ฟ๐ต ๐ป

๐ต),ํœ€ (1 ๐‘ƒ

๐ต)- ๐‘(๐›ฝ

๐ต,๐›พ๐ฟ

๐ด (1 ๐›พ)๐ป

๐ด- ๐ป

๐ต)

22

Therefore, in order to meet the condition ๐‘ˆ๐ต ๐‘†๐‘’๐‘’๐‘˜

๐‘ˆ๐ต ๐‘๐‘œ๐‘ก ๐‘†๐‘’๐‘’๐‘˜

there must be:

(๐›ฝ๐ต ๐›ผ

๐ต

(๐ฟ๐ต ๐ป๐ต ),๐œ€ ( ๐‘ƒ๐ต )-

๐‘,๐›พ๐ฟ๐ด+( ๐›พ)๐ป๐ด -

๐ป๐ต

,๐›พ๐ฟ๐ด+( ๐›พ)๐ป๐ด -, when ( ํœ€ ๐œƒ) > and ( ํœ€ ๐œƒ) , the

relationship between ๐›ฝ๐ต and ๐›ผ

๐ต is shown in the following figure:

In the case of ๐ฟ๐ต

๐‘ˆ๐ต ๐ป๐‘’๐‘™๐‘

๐‘ˆ๐ต ๐‘๐‘œ๐‘ก โ„Ž๐‘’๐‘™๐‘

๐›ผ๐ต2(๐ฟ๐ต ๐ป

๐ต)(ํœ€ ๐œƒ) ๐‘(๐›ฝ

๐ต๐‘Ž๐ด ๐ฟ

๐ต)

๐›ผ๐ต2(๐ฟ๐ต ๐ป

๐ต),ํœ€ (1 ๐‘ƒ

๐ต)- ๐‘*๐›ฝ

๐ต,๐œŒ๐ฟ

๐ด (1 ฯ)๐ป

๐ด- ๐ฟ

๐ต+

Therefore, in order to meet the condition ๐‘ˆ๐ต ๐ป๐‘’๐‘™๐‘

๐‘ˆ๐ต ๐‘๐‘œ๐‘ก ๐‘’๐‘™๐‘

there must be:

๐›ฝ๐ต ๐›ผ

๐ต2

.๐ฟ๐ต ๐ป

๐ต/ ,ํœ€ (1 ๐‘ƒ

๐ต)-

๐‘,๐œŒ๐ฟ๐ด (1 ฯ)๐ป

๐ด-

๐ฟ๐ต

,๐œŒ๐ฟ๐ด (1 ฯ)๐ป

๐ด-

When ( ํœ€ ๐œƒ) > and ( ํœ€ ๐œƒ) , the relationship between ๐›ฝ๐ต and ๐›ผ

๐ต is

shown in the upper right of the following figure:

23

Since ๐œ‰ > , ๐‘๐ฟ๐ต

๐ฟ๐ต ๐ป๐ต

๐œ‰ is always smaller than ๐‘๐ป๐ต

๐ฟ๐ต ๐ป๐ต

. Thus, the union set is

In the case of ๐ป๐ด

๐‘ˆ๐ด ๐‘†๐‘’๐‘’๐‘˜

๐‘ˆ๐ด ๐‘๐‘œ๐‘ก ๐‘ ๐‘’๐‘’๐‘˜

๐›ผ๐ด1(๐›พ ๐›ฟ) .๐ฟ

๐ด ๐ป

๐ด/ (๐‘Ÿ ๐‘ƒ

๐ต๐‘Ÿโ€ฒ ๐‘ƒ

๐ต๐‘Ÿ) ๐‘(๐ป

๐ด ๐›ฝ

๐ด๐‘Ž๐ต)

๐›ผ๐ด1(ฮณ ๐‘ƒ

๐ด) .๐ฟ

๐ด ๐ป

๐ด/

Therefore, in order to meet the condition ๐‘ˆ๐ด ๐‘†๐‘’๐‘’๐‘˜

๐‘ˆ๐ด ๐‘๐‘œ๐‘ก ๐‘ ๐‘’๐‘’๐‘˜

there must

be: (ฮณ ๐‘ƒ๐ด) > , when ( ๐›พ ๐›ฟ) > , the relationship between ๐›ฝ

๐ด and ๐›ผ

๐ด is

shown in the upper right of the following figure:

In the case of ๐ฟ๐ด

๐‘ˆ๐ด ๐‘†๐‘’๐‘’๐‘˜

๐‘ˆ๐ด ๐‘๐‘œ๐‘ก ๐‘ ๐‘’๐‘’๐‘˜

๐›ผ๐ด2(๐›พ ๐›ฟ) .๐ฟ

๐ด ๐ป

๐ด/ (๐‘Ÿ ๐‘ƒ

๐ต๐‘Ÿโ€ฒ ๐‘ƒ

๐ต๐‘Ÿ) ๐‘(๐ฟ

๐ด ๐›ฝ

๐ด๐‘Ž๐ต)

๐›ผ๐ด2(ฮณ ๐‘ƒ

๐ด) .๐ฟ

๐ด ๐ป

๐ด/

Therefore, in order to meet the condition ๐‘ˆ๐ด ๐‘†๐‘’๐‘’๐‘˜

๐‘ˆ๐ด ๐‘๐‘œ๐‘ก ๐‘ ๐‘’๐‘’๐‘˜

there must

24

be: (ฮณ ๐‘ƒ๐ด) > , when ( ๐›พ ๐›ฟ) > , the relationship between ๐›ฝ

๐ด and ๐›ผ

๐ด is

shown in the following figure:

Player B's all conditions and player A's all conditions must be met. Thus, the

result is ๐œ‰. The figure is shown as follows:

โ‘ฅ ๐‘Ÿ 1 ๐‘Ÿ 1 ๐‘ž 0 ๐‘ž 0

In the case of ๐ป๐ต

๐‘ˆ๐ต ๐ป๐‘’๐‘™๐‘

๐‘ˆ๐ต ๐‘๐‘œ๐‘ก โ„Ž๐‘’๐‘™๐‘

๐›ผ๐ต1(๐ฟ๐ต ๐ป

๐ต)(ํœ€ ๐œƒ) ๐‘(๐›ฝ

๐ต๐‘Ž๐ด ๐ป

๐ต)

๐›ผ๐ต1(๐ฟ๐ต ๐ป

๐ต),.1 ๐‘ƒ

๐ต/ ๐œƒ- ๐‘(๐›ฝ

๐ต,๐›พ๐ฟ

๐ด (1 ๐›พ)๐ป

๐ด- ๐ป

๐ต)

Therefore, in order to meet the condition ๐‘ˆ๐ต ๐ป๐‘’๐‘™๐‘

๐‘ˆ๐ต ๐‘๐‘œ๐‘ก ๐‘’๐‘™๐‘

> there must be:

๐›ฝ๐ต ๐›ผ

๐ต1

.๐ฟ๐ต ๐ป

๐ต/ ,.1 ๐‘ƒ

๐ต/ ๐œƒ-

๐‘,๐›พ๐ฟ๐ด (1 ๐›พ)๐ป

๐ด-

๐ป๐ต

,๐›พ๐ฟ๐ด (1 ๐›พ)๐ป

๐ด-

When ( ํœ€ ๐œƒ) > and ( ํœ€ ๐œƒ) , the relationship between ใ€๐›ฝ๐ตand ๐›ผ

๐ต is

shown in the following figure:

25

In the case of ๐ฟ๐ต

๐‘ˆ๐ต ๐ป๐‘’๐‘™๐‘

๐‘ˆ๐ต ๐‘๐‘œ๐‘ก โ„Ž๐‘’๐‘™๐‘

๐›ผ๐ต2(๐ฟ๐ต ๐ป

๐ต)(ํœ€ ๐œƒ) ๐‘(๐›ฝ

๐ต๐‘Ž๐ด ๐ฟ

๐ต)

๐›ผ๐ต2(๐ฟ๐ต ๐ป

๐ต),.1 ๐‘ƒ

๐ต/ ๐œƒ- ๐‘*๐›ฝ

๐ต,๐œŒ๐ฟ

๐ด (1 ฯ)๐ป

๐ด- ๐ฟ

๐ต+

Therefore, in order to meet the condition ๐‘ˆ๐ต ๐ป๐‘’๐‘™๐‘

๐‘ˆ๐ต ๐‘๐‘œ๐‘ก ๐‘’๐‘™๐‘

> there must be:

๐›ฝ๐ต ๐›ผ

๐ต2

.๐ฟ๐ต ๐ป

๐ต/ ,.1 ๐‘ƒ

๐ต/ ๐œƒ-

๐‘,๐œŒ๐ฟ๐ด (1 ฯ)๐ป

๐ด-

๐ฟ๐ต

,๐œŒ๐ฟ๐ด (1 ฯ)๐ป

๐ด-

When ( ํœ€ ๐œƒ) > and( ํœ€ ๐œƒ) , the relationship between ๐›ฝ๐ตand ๐›ผ

๐ต is

shown in the following figure:

To combine the two figures above together, we must distinguish between

occasions between ๐‘๐ฟ๐ต

๐ฟ๐ต ๐ป๐ต

๐œ‰ >๐‘๐ป๐ต

๐ฟ๐ต ๐ป๐ต

as case 1๐ต and๐‘๐ฟ๐ต

๐ฟ๐ต ๐ป๐ต

๐œ‰ ๐‘๐ป๐ต

๐ฟ๐ต ๐ป๐ต

as case ๐ต.

At this time,

26

Case 1๐ต๏ผš Case ๐ต๏ผš

In the case of ๐ป๐ด

๐‘ˆ๐ด ๐‘†๐‘’๐‘’๐‘˜

๐‘ˆ๐ด ๐‘๐‘œ๐‘ก ๐‘ ๐‘’๐‘’๐‘˜

๐›ผ๐ด1(๐›พ ๐›ฟ) .๐ฟ

๐ด ๐ป

๐ด/ (๐‘Ÿ ๐‘ƒ

๐ต๐‘Ÿโ€ฒ ๐‘ƒ

๐ต๐‘Ÿ) ๐‘(๐ป

๐ด ๐›ฝ

๐ด๐‘Ž๐ต)

๐›ผ๐ด1(ฮณ ๐‘ƒ

๐ด) .๐ฟ

๐ด ๐ป

๐ด/ ๐‘*๐ป

๐ด ๐›ฝ

๐ด 0๐‘ƒ๐ต ๐ฟ๐ต .1 ๐‘ƒ๐ต/๐ป

๐ต1+

Therefore, In order to meet the condition ๐‘ˆ๐ด seek

๐‘ˆ๐ด ๐‘›๐‘œ๐‘ก ๐‘ ๐‘’๐‘’๐‘˜

there must be:

๐›ฝ๐ด> ๐›ผ

๐ด1

(ฮณ ๐‘ƒ๐ด) .๐ฟ

๐ด ๐ป

๐ด/

๐‘ 0๐‘ƒ๐ต๐ฟ๐ต .1 ๐‘ƒ

๐ต/๐ป

๐ต1

๐ป๐ด

,๐‘ƒ๐ต๐ฟ๐ต .1 ๐‘ƒ

๐ต/๐ป

๐ต-

When ( ๐›พ ๐›ฟ) > and ( ๐›พ ๐›ฟ) , the relationship between ๐›ฝ๐ด

and ๐›ผ๐ด

is

shown in the following figure:

In the case of ๐ฟ๐ด

๐‘ˆ๐ด ๐‘†๐‘’๐‘’๐‘˜

๐‘ˆ๐ด ๐‘๐‘œ๐‘ก ๐‘ ๐‘’๐‘’๐‘˜

๐›ผ๐ด2(๐›พ ๐›ฟ) .๐ฟ

๐ด ๐ป

๐ด/ (๐‘Ÿ ๐‘ƒ

๐ต๐‘Ÿโ€ฒ ๐‘ƒ

๐ต๐‘Ÿ) ๐‘(๐ฟ

๐ด ๐›ฝ

๐ด๐‘Ž๐ต)

๐›ผ๐ด2(ฮณ ๐‘ƒ

๐ด) .๐ฟ

๐ด ๐ป

๐ด/ (๐‘Ÿ ๐‘ƒ

๐ต๐‘Ÿโ€ฒ ๐‘ƒ

๐ต๐‘Ÿ) ๐‘*๐ฟ

๐ด ๐›ฝ

๐ด 0๐‘ƒ๐ต ๐ฟ๐ต .1 ๐‘ƒ๐ต/๐ป

๐ต1+

27

Therefore, in order to meet the condition ๐‘ˆ๐ด seek

๐‘ˆ๐ด ๐‘›๐‘œ๐‘ก ๐‘ ๐‘’๐‘’๐‘˜

there must be:

๐›ฝ๐ด> ๐›ผ

๐ด2

(ฮณ ๐‘ƒ๐ด) .๐ฟ

๐ด ๐ป

๐ด/

๐‘ 0๐‘ƒ๐ต๐ฟ๐ต .1 ๐‘ƒ

๐ต/๐ป

๐ต1

๐ฟ๐ด

0๐‘ƒ๐ต๐ฟ๐ต .1 ๐‘ƒ

๐ต/๐ป

๐ต1

When ( ๐›พ ๐›ฟ) > and ( ๐›พ ๐›ฟ) , the relationship between ๐›ฝ๐ดand ๐›ผ

๐ด is

shown in the following figure:

O g o ๐›ผ ๐›ผ

๐œ‰, there is

๐‘๐ฟ๐ด

๐ฟ๐ด ๐ป๐ด

๐œ‰ >๐‘๐ป๐ด

๐ฟ๐ด ๐ป๐ด

as case 1๐ด ๐‘๐ฟ๐ด

๐ฟ๐ด ๐ป๐ด

๐œ‰ ๐‘๐ป๐ด

๐ฟ๐ด ๐ป๐ด

as

case ๐ด. At this time,

Case 1๐ด๏ผš Case ๐ด๏ผš

Player A must satisfy all of the conditions of game equilibrium case1๐ด ๐ด. Player

B must satisfy all of the conditions of game equilibrium case1๐ต ๐ต. Thus๏ผŒthe result

of the union set of case1๐ต and case1๐ด is 0<ฮพ<c. It is shown in the following figure:

28

Since the results of the union set of case 1๐ต and case ๐ด are ๐œ‰ , ๐œ‰ > , ฮพ

does not exist. Since the results of the union set of case ๐ต and case 1๐ด are ๐œ‰ > ใ€

๐œ‰ ๐œ‰ does not exist. The result of the union set of case ๐ต and case ๐ด is ๐œ‰ > .

The figure is shown as follows:

โ‘ฆ ๐‘Ÿ 1 ๐‘Ÿ 1 ๐‘ž 1 ๐‘ž 1

In the case of ๐ป๐ต

๐‘ˆ๐ต ๐ป๐‘’๐‘™๐‘

๐‘ˆ๐ต ๐‘๐‘œ๐‘ก โ„Ž๐‘’๐‘™๐‘

๐›ผ๐ต1(๐ฟ๐ต ๐ป

๐ต)(ํœ€ ๐œƒ) ๐‘(๐›ฝ

๐ต๐‘Ž๐ด ๐ป

๐ต)

๐›ผ๐ต1(๐ฟ๐ต ๐ป

๐ต),.1 ๐‘ƒ

๐ต/ ๐œƒ- ๐‘(๐›ฝ

๐ต,๐›พ๐ฟ

๐ด (1 ๐›พ)๐ป

๐ด- ๐ป

๐ต)

Therefore, in order to meet the condition ๐‘ˆ๐ต ๐‘’๐‘™๐‘

๐‘ˆ๐ต ๐‘›๐‘œ๐‘ก ๐‘’๐‘™๐‘

> there must be:

๐›ฝ๐ต ๐›ผ

๐ต1

.๐ฟ๐ต ๐ป

๐ต/ ,.1 ๐‘ƒ

๐ต/ ๐œƒ-

๐‘,๐›พ๐ฟ๐ด (1 ๐›พ)๐ป

๐ด-

๐ป๐ต

,๐›พ๐ฟ๐ด (1 ๐›พ)๐ป

๐ด-

When ( ํœ€ ๐œƒ) > and ( ํœ€ ๐œƒ) , the relationship betweenใ€๐›ฝ๐ตand๐›ผ

๐ต is

shown in the following figure:

29

In the case of ๐ฟ๐ต

๐‘ˆ๐ต ๐ป๐‘’๐‘™๐‘

๐‘ˆ๐ต ๐‘๐‘œ๐‘ก โ„Ž๐‘’๐‘™๐‘

๐›ผ๐ต2(๐ฟ๐ต ๐ป

๐ต)(ํœ€ ๐œƒ) ๐‘(๐›ฝ

๐ต๐‘Ž๐ด ๐ฟ

๐ต)

๐›ผ๐ต2(๐ฟ๐ต ๐ป

๐ต),.1 ๐‘ƒ

๐ต/ ๐œƒ- ๐‘*๐›ฝ

๐ต,๐œŒ๐ฟ

๐ด (1 ฯ)๐ป

๐ด- ๐ฟ

๐ต+

Therefore, in order to meet the condition ๐‘ˆ๐ต ๐‘’๐‘™๐‘

๐‘ˆ๐ต ๐‘›๐‘œ๐‘ก ๐‘’๐‘™๐‘

> there must be:

๐›ฝ๐ต ๐›ผ

๐ต2

.๐ฟ๐ต ๐ป

๐ต/ ,.1 ๐‘ƒ

๐ต/ ๐œƒ-

๐‘,๐œŒ๐ฟ๐ด (1 ฯ)๐ป

๐ด-

๐ฟ๐ต

,๐œŒ๐ฟ๐ด (1 ฯ)๐ป

๐ด-

When ( ํœ€ ๐œƒ) > and ( ํœ€ ๐œƒ) , the relationship between ๐›ฝ๐ตand ๐›ผ

๐ต is

shown in the following figure:

To put the two figures above together, we must distinguish between occasions

between ๐‘๐ฟ๐ต

๐ฟ๐ต ๐ป๐ต

๐œ‰ >๐‘๐ป๐ต

๐ฟ๐ต ๐ป๐ต

as case 1๐ต and ๐‘๐ฟ๐ต

๐ฟ๐ต ๐ป๐ต

๐œ‰ ๐‘๐ป๐ต

๐ฟ๐ต ๐ป๐ต

as case ๐ต. At this

point:

30

Case 1๐ต๏ผš Case ๐ต๏ผš

In the case of ๐ป๐ด

๐‘ˆ๐ด ๐‘†๐‘’๐‘’๐‘˜

๐‘ˆ๐ด ๐‘๐‘œ๐‘ก ๐‘ ๐‘’๐‘’๐‘˜

๐›ผ๐ด1(๐›พ ๐›ฟ) .๐ฟ

๐ด ๐ป

๐ด/ (๐‘Ÿ ๐‘ƒ

๐ต๐‘Ÿโ€ฒ ๐‘ƒ

๐ต๐‘Ÿ) ๐‘(๐ป

๐ด ๐›ฝ

๐ด๐‘Ž๐ต)

๐›ผ๐ด1(๐‘ƒ๐ด ๐›ฟ) .๐ฟ

๐ด ๐ป

๐ด/ ๐‘*๐ป

๐ด ๐›ฝ

๐ด 0๐‘ƒ๐ต ๐ฟ๐ต .1 ๐‘ƒ๐ต/๐ป

๐ต1+

Therefore, in order to meet the condition ๐‘ˆ๐ด ๐‘ ๐‘’๐‘’๐‘˜

๐‘ˆ๐ด ๐‘›๐‘œ๐‘ก ๐‘ ๐‘’๐‘’๐‘˜

> there must be:

๐›ฝ๐ด> ๐›ผ

๐ด1

(๐‘ƒ๐ด ๐›ฟ) .๐ฟ

๐ด ๐ป

๐ด/

๐‘ 0๐‘ƒ๐ต๐ฟ๐ต .1 ๐‘ƒ

๐ต/๐ป

๐ต1

๐ป๐ด

,๐‘ƒ๐ต๐ฟ๐ต .1 ๐‘ƒ

๐ต/๐ป

๐ต-

When ( ๐›พ ๐›ฟ) > and ( ๐›พ ๐›ฟ) , the relationship between ๐›ฝ๐ดand ๐›ผ

๐ด is

shown in the following figure:

In the case of ๐ฟ๐ด

๐‘ˆ๐ด ๐‘†๐‘’๐‘’๐‘˜

๐‘ˆ๐ด ๐‘๐‘œ๐‘ก ๐‘ ๐‘’๐‘’๐‘˜

๐›ผ๐ด2(๐›พ ๐›ฟ) .๐ฟ

๐ด ๐ป

๐ด/ (๐‘Ÿ ๐‘ƒ

๐ต๐‘Ÿโ€ฒ ๐‘ƒ

๐ต๐‘Ÿ) ๐‘(๐ฟ

๐ด ๐›ฝ

๐ด๐‘Ž๐ต)

๐›ผ๐ด2(๐‘ƒ๐ด ๐›ฟ) .๐ฟ

๐ด ๐ป

๐ด/ ๐‘*๐ฟ

๐ด ๐›ฝ

๐ด 0๐‘ƒ๐ต ๐ฟ๐ต .1 ๐‘ƒ๐ต/๐ป

๐ต1+

Therefore, in order to meet the condition ๐‘ˆ๐ด ๐‘ ๐‘’๐‘’๐‘˜

๐‘ˆ๐ด ๐‘›๐‘œ๐‘ก ๐‘ ๐‘’๐‘’๐‘˜

> there must be:

31

๐›ฝ๐ด ๐›ผ

๐ด2

(๐‘ƒ๐ด ๐›ฟ) .๐ฟ

๐ด ๐ป

๐ด/

๐‘ 0๐‘ƒ๐ต๐ฟ๐ต .1 ๐‘ƒ

๐ต/๐ป

๐ต1

๐ฟ๐ด

0๐‘ƒ๐ต๐ฟ๐ต .1 ๐‘ƒ

๐ต/๐ป

๐ต1

When ( ๐›พ ๐›ฟ) > and ( ๐›พ ๐›ฟ) , the relationship between ๐›ฝ๐ดand ๐›ผ

๐ด is

shown in the following figure:

Since ๐œ‰ > , ๐‘๐ฟ๐ด

๐ฟ๐ด ๐ป๐ด

๐œ‰ is always smaller than ๐‘๐ป๐ด

๐ฟ๐ด ๐ป๐ด

. Thus, the union set is:

Player B must satisfy all of the conditions of game equilibrium case 1๐ต or

case ๐ต, so does player A. Thus, the result that satisfies the conditions of player A and

B is ๐œ‰ . The figure is

32

To satisfy Case ๐ต and player Aโ€™s conditions, the result is 1 > ๐œ‰ > . The figure

is as follows:

โ‘ง ๐‘Ÿ 1 ๐‘Ÿ 1 ๐‘ž 1 ๐‘ž 0

In the case of ๐ป๐ต

๐‘ˆ๐ต ๐ป๐‘’๐‘™๐‘

๐‘ˆ๐ต ๐‘๐‘œ๐‘ก โ„Ž๐‘’๐‘™๐‘

๐›ผ๐ต1(๐ฟ๐ต ๐ป

๐ต)(ํœ€ ๐œƒ) ๐‘(๐›ฝ

๐ต๐‘Ž๐ด ๐ป

๐ต)

๐›ผ๐ต1(๐ฟ๐ต ๐ป

๐ต),.1 ๐‘ƒ

๐ต/ ๐œƒ- ๐‘(๐›ฝ

๐ต๐ฟ๐ด ๐ป

๐ต)

Therefore, in order to meet the condition ๐‘ˆ๐ต ๐ป๐‘’๐‘™๐‘

๐‘ˆ๐ต ๐‘๐‘œ๐‘ก ๐‘’๐‘™๐‘

> there must be:

๐›ฝ๐ต> ๐›ผ

๐ต1

.๐ฟ๐ต ๐ป

๐ต/ ,.1 ๐‘ƒ

๐ต/ ๐œƒ-

๐‘๐ฟ๐ด

๐ป๐ต

๐ฟ๐ด

The relationship between ๐›ฝ๐ตand ๐›ผ

๐ต is shown in the following figure:

In the case of ๐ฟ๐ต

๐‘ˆ๐ต ๐ป๐‘’๐‘™๐‘

๐‘ˆ๐ต ๐‘๐‘œ๐‘ก โ„Ž๐‘’๐‘™๐‘

๐›ผ๐ต2(๐ฟ๐ต ๐ป

๐ต)(ํœ€ ๐œƒ) ๐‘(๐›ฝ

๐ต๐‘Ž๐ด ๐ฟ

๐ต)

๐›ผ๐ต2(๐ฟ๐ต ๐ป

๐ต),.1 ๐‘ƒ

๐ต/ ๐œƒ- ๐‘(๐›ฝ

๐ต๐ฟ๐ด ๐ฟ

๐ต)

Therefore, in order to meet the condition ๐‘ˆ๐ต ๐ป๐‘’๐‘™๐‘

๐‘ˆ๐ต ๐‘๐‘œ๐‘ก ๐‘’๐‘™๐‘

> there must be:

33

๐›ฝ๐ต> ๐›ผ

๐ต2

.๐ฟ๐ต ๐ป

๐ต/ ,.1 ๐‘ƒ

๐ต/ ๐œƒ-

๐‘๐ฟ๐ด

๐ฟ๐ต

๐ฟ๐ด

The relationship between ๐›ฝ๐ตand ๐›ผ

๐ต is shown in the following figure:

To combine the two figures above together, we must distinguish between

occasions between ๐‘๐ฟ๐ต

๐ฟ๐ต ๐ป๐ต

๐œ‰ >๐‘๐ป๐ต

๐ฟ๐ต ๐ป๐ต

as case 1๐ต and๐‘๐ฟ๐ต

๐ฟ๐ต ๐ป๐ต

๐œ‰ ๐‘๐ป๐ต

๐ฟ๐ต ๐ป๐ต

as case ๐ต.

At this point,

Case 1๐ต๏ผš Case ๐ต๏ผš

In the case of ๐ป๐ด

๐‘ˆ๐ด ๐‘†๐‘’๐‘’๐‘˜

๐‘ˆ๐ด ๐‘๐‘œ๐‘ก ๐‘ ๐‘’๐‘’๐‘˜

๐›ผ๐ด1(๐›พ ๐›ฟ) .๐ฟ

๐ด ๐ป

๐ด/ (๐‘Ÿ ๐‘ƒ

๐ต๐‘Ÿโ€ฒ ๐‘ƒ

๐ต๐‘Ÿ) ๐‘(๐ป

๐ด ๐›ฝ

๐ด๐‘Ž๐ต)

๐›ผ๐ด1.๐ฟ๐ด ๐ป

๐ด/ ๐‘*๐ป

๐ด ๐›ฝ

๐ด 0๐‘ƒ๐ต ๐ฟ๐ต .1 ๐‘ƒ๐ต/๐ป

๐ต1+

Therefore, in order to meet the condition ๐‘ˆ๐ด ๐‘†๐‘’๐‘’๐‘˜

๐‘ˆ๐ด ๐‘๐‘œ๐‘ก ๐‘ ๐‘’๐‘’๐‘˜

there must be:

34

๐›ฝ๐ด> ๐›ผ

๐ด1

.๐ฟ๐ด ๐ป

๐ด/

๐‘ 0๐‘ƒ๐ต๐ฟ๐ต .1 ๐‘ƒ

๐ต/๐ป

๐ต1

๐ป๐ด

,๐‘ƒ๐ต๐ฟ๐ต .1 ๐‘ƒ

๐ต/๐ป

๐ต-

The relationship between ๐›ฝ๐ดand ๐›ผ

๐ด is shown in the following figure:

In the case of ๐ฟ๐ด

๐‘ˆ๐ด ๐‘†๐‘’๐‘’๐‘˜

๐‘ˆ๐ด ๐‘๐‘œ๐‘ก ๐‘ ๐‘’๐‘’๐‘˜

๐›ผ๐ด2(๐›พ ๐›ฟ) .๐ฟ

๐ด ๐ป

๐ด/ (๐‘Ÿ ๐‘ƒ

๐ต๐‘Ÿโ€ฒ ๐‘ƒ

๐ต๐‘Ÿ) ๐‘(๐ฟ

๐ด ๐›ฝ

๐ด๐‘Ž๐ต)

๐›ผ๐ด2.๐ฟ๐ด ๐ป

๐ด/ ๐‘*๐ฟ

๐ด ๐›ฝ

๐ด0๐‘ƒ๐ต๐ฟ๐ต .1 ๐‘ƒ

๐ต/๐ป

๐ต1+

Therefore, in order to meet the condition ๐‘ˆ๐ด ๐‘†๐‘’๐‘’๐‘˜

๐‘ˆ๐ด ๐‘๐‘œ๐‘ก ๐‘ ๐‘’๐‘’๐‘˜

> there must be:

๐›ฝ๐ด ๐›ผ

๐ด2

.๐ฟ๐ด ๐ป

๐ด/

๐‘ 0๐‘ƒ๐ต๐ฟ๐ต .1 ๐‘ƒ

๐ต/๐ป

๐ต1

๐ฟ๐ด

0๐‘ƒ๐ต๐ฟ๐ต .1 ๐‘ƒ

๐ต/๐ป

๐ต1

The relationship between ๐›ฝ๐ดand ๐›ผ

๐ด is shown in the following figure:

Since ๐›ผ ๐›ผ

๐œ‰, there are

๐‘๐ฟ๐ด

๐ฟ๐ด ๐ป๐ด

๐œ‰ >๐‘๐ป๐ด

๐ฟ๐ด ๐ป๐ด

as case 1๐ด and ๐‘๐ฟ๐ด

๐ฟ๐ด ๐ป๐ด

๐œ‰ ๐‘๐ป๐ด

๐ฟ๐ด ๐ป๐ด

as case ๐ด. At this point,

35

Case 1๐ด๏ผš Case ๐ด๏ผšโˆ…

Player B must satisfy all of the conditions of game equilibrium case1๐ต or case ๐ต,

Player A must satisfy all of the conditions of game equilibrium case1๐ด or case ๐ด,

Because case ๐ด is an empty set, the union set of case 1๐ต and case ๐ต is also an

empty set. Thus, the result that satisfies both case1๐ต and case1๐ด is ๐œ‰ The

figure is as follows:

Since the result of the union set of case ๐ต and case 1๐ด is ๐œ‰ > , ๐œ‰ , ฮพ does

not exist.

The above section discusses the 8 equilibriums. The next section will discuss why

the following 8 situations are not equilibrium:

โ‘จ ๐‘Ÿ ๐‘Ÿ ๐‘ž 1 ๐‘ž

In the case of ๐ฟ๐ด

๐‘ˆ๐ด ๐‘†๐‘’๐‘’๐‘˜

๐‘ˆ๐ด ๐‘๐‘œ๐‘ก ๐‘ ๐‘’๐‘’๐‘˜

,๐‘ƒ๐ต๐‘Ÿ .1 ๐‘ƒ

๐ต/ ๐‘Ÿ-* ๐›ผ

๐ด2[[๐ฟ๐ด ๐›พ ๐ป๐ด (1 ๐›พ)] ๐ฟ๐ด ] ๐›ฝ๐ด๐‘๐‘Ž๐ต+ ,๐‘ƒ๐ต (1 ๐‘Ÿ )

.1 ๐‘ƒ๐ต/ (1 ๐‘Ÿ)- { ๐‘๐ฟ

๐ด ๐›ผ

๐ด2[[๐ฟ๐ด ๐›พ ๐ป๐ด (1 ๐›พ)] ๐ฟ๐ด ]}

๐ฟ๐ด๐‘ ๐›ผ

๐ด2[[๐ฟ๐ด ๐›ฟ ๐ป๐ด (1 ๐›ฟ)] ๐ฟ๐ด ]

36

๐›ผ๐ด2.๐ฟ๐ด ๐ป

๐ด/ (๐‘Ÿ ๐‘ƒ ๐‘Ÿ ๐‘ƒ ๐‘Ÿ)๐‘(๐ฟ๐ด ๐›ฝ๐ด๐‘Ž๐ต)

๐›ผ๐ด2.๐ฟ๐ด ๐ป

๐ด/

Owing to ๐‘ˆ๐ด ๐‘†๐‘’๐‘’๐‘˜

๐‘ˆ๐ด ๐‘๐‘œ๐‘ก ๐‘ ๐‘’๐‘’๐‘˜

> must be satisfied, ๐‘ˆ๐ด ๐‘†๐‘’๐‘’๐‘˜

๐‘ˆ๐ด ๐‘๐‘œ๐‘ก ๐‘ ๐‘’๐‘’๐‘˜

must

be less than 0. This contradicts ๐‘ž 1.

โ‘ฉ ๐‘Ÿ 0 ๐‘Ÿ 0 ๐‘ž 0 ๐‘ž 1

In the case of ๐ฟ๐ด

๐‘ˆ๐ด ๐‘†๐‘’๐‘’๐‘˜

๐‘ˆ๐ด ๐‘๐‘œ๐‘ก ๐‘ ๐‘’๐‘’๐‘˜

๐›ผ๐ด2(๐›พ ๐›ฟ) .๐ฟ

๐ด ๐ป

๐ด/ (๐‘Ÿ ๐‘ƒ ๐‘Ÿ ๐‘ƒ ๐‘Ÿ)๐‘(๐ฟ๐ด ๐›ฝ๐ด๐‘Ž๐ต)

๐›ผ๐ด2( 1) .๐ฟ

๐ด ๐ป

๐ด/

Owing to ๐›ผ๐ด ( 1) .๐ฟ

๐ด ๐ป

๐ด/ is always positive, ๐‘ˆ

๐ด ๐‘†๐‘’๐‘’๐‘˜ ๐‘ˆ

๐ด ๐‘๐‘œ๐‘ก ๐‘ ๐‘’๐‘’๐‘˜ must be

greater than 0. This contradicts ๐‘ž .

โ‘ช ๐‘Ÿ 1 ๐‘Ÿ 0 ๐‘ž 0 ๐‘ž 1

In the case of ๐ฟ๐ด

๐‘ˆ๐ด ๐‘†๐‘’๐‘’๐‘˜

๐‘ˆ๐ด ๐‘๐‘œ๐‘ก ๐‘ ๐‘’๐‘’๐‘˜

๐›ผ๐ด2(๐›พ ๐›ฟ) .๐ฟ

๐ด ๐ป

๐ด/ (๐‘Ÿ ๐‘ƒ ๐‘Ÿ ๐‘ƒ ๐‘Ÿ)๐‘(๐ฟ๐ด ๐›ฝ๐ด๐‘Ž๐ต)

๐›ผ๐ด2( 1) .๐ฟ

๐ด ๐ป

๐ด/ .1 ๐‘ƒ

๐ต/ ๐‘*๐ฟ

๐ด ๐›ฝ

๐ด 0๐‘ƒ๐ต ๐ฟ๐ต .1 ๐‘ƒ๐ต/๐ป

๐ต1+

Owing to ๐›ผ๐ด ( 1) .๐ฟ

๐ด ๐ป

๐ด/ and .1 ๐‘ƒ

๐ต/ ๐‘*๐ฟ

๐ด ๐›ฝ

๐ด0๐‘ƒ๐ต๐ฟ๐ต .1

๐‘ƒ๐ต/๐ป

๐ต1+are always positive, ๐‘ˆ

๐ด ๐‘†๐‘’๐‘’๐‘˜ ๐‘ˆ

๐ด ๐‘๐‘œ๐‘ก ๐‘ ๐‘’๐‘’๐‘˜ must be greater than 0. This

contradicts ๐‘ž .

โ‘ซ ๐‘Ÿ 0 ๐‘Ÿ 1 ๐‘ž 1 ๐‘ž 0

In the case of ๐ฟ๐ต

๐‘ˆ๐ต ๐ป๐‘’๐‘™๐‘

๐‘ˆ๐ต ๐‘๐‘œ๐‘ก โ„Ž๐‘’๐‘™๐‘

๐›ผ๐ต2(๐ฟ๐ต ๐ป

๐ต)(ํœ€ ๐œƒ) ๐‘(๐›ฝ

๐ต๐‘Ž๐ด ๐ฟ

๐ต)

๐›ผ๐ต2(๐ฟ๐ต ๐ป

๐ต)( 1) ๐‘(๐›ฝ๐ต๐ฟ๐ด ๐ฟ๐ต )

Owing to ๐›ผ๐ต (๐ฟ๐ต ๐ป

๐ต)( 1) and๐‘ .๐›ฝ

๐ต๐ฟ๐ด ๐ฟ

๐ต/ are always negative, ๐‘ˆ

๐ต ๐ป๐‘’๐‘™๐‘

๐‘ˆ๐ต ๐‘๐‘œ๐‘ก ๐‘’๐‘™๐‘

must be less than 0. This contradicts ๐‘Ÿ 1.

โ‘ฌ ๐‘Ÿ 1 ๐‘Ÿ 1 ๐‘ž 0 ๐‘ž 1

In the case of ๐ฟ๐ด

๐‘ˆ๐ด ๐‘†๐‘’๐‘’๐‘˜

๐‘ˆ๐ด ๐‘๐‘œ๐‘ก ๐‘ ๐‘’๐‘’๐‘˜

๐›ผ๐ด2(๐›พ ๐›ฟ) .๐ฟ

๐ด ๐ป

๐ด/ (๐‘Ÿ ๐‘ƒ ๐‘Ÿ ๐‘ƒ ๐‘Ÿ)๐‘(๐ฟ๐ด ๐›ฝ๐ด๐‘Ž๐ต)

๐›ผ๐ด2( 1) .๐ฟ

๐ด ๐ป

๐ด/ ๐‘*๐ฟ

๐ด ๐›ฝ

๐ด 0๐‘ƒ๐ต ๐ฟ๐ต .1 ๐‘ƒ๐ต/๐ป

๐ต1+

Owing to ๐›ผ๐ด ( 1) .๐ฟ

๐ด ๐ป

๐ด/ and ๐‘*๐ฟ

๐ด ๐›ฝ

๐ด0๐‘ƒ๐ต๐ฟ๐ต .1 ๐‘ƒ

๐ต/๐ป

๐ต1+ are

always positive, ๐‘ˆ๐ด Seek

๐‘ˆ๐ด Not seek

must be greater than 0. This contradicts ๐‘ž .

37

โ‘ญ ๐‘Ÿ 0 ๐‘Ÿ 1 ๐‘ž 1 ๐‘ž 1

In the case of ๐ฟ๐ต

๐‘ˆ๐ต ๐ป๐‘’๐‘™๐‘

๐‘ˆ๐ต ๐‘๐‘œ๐‘ก โ„Ž๐‘’๐‘™๐‘

๐›ผ๐ต2(๐ฟ๐ต ๐ป

๐ต)(ํœ€ ๐œƒ) ๐‘(๐›ฝ

๐ต๐‘Ž๐ด ๐ฟ

๐ต)

๐›ผ๐ต2(๐ฟ๐ต ๐ป

๐ต)( 1) ๐‘(๐›ฝ๐ต๐ฟ๐ด ๐ฟ๐ต )

Owing to ๐›ผ๐ต (๐ฟ๐ต ๐ป

๐ต)( 1) and๐‘(๐›ฝ

๐ต๐ฟ๐ด ๐ฟ

๐ต) are always negative, ๐‘ˆ

๐ต ๐ป๐‘’๐‘™๐‘

๐‘ˆ๐ต ๐‘๐‘œ๐‘ก ๐‘’ ๐‘

must be less than 0. This contradicts ๐‘Ÿ 1.

โ‘ฎ ๐‘Ÿ 0 ๐‘Ÿ 1 ๐‘ž 0 ๐‘ž 0

In the case of ๐ฟ๐ต

๐‘ˆ๐ต ๐ป๐‘’๐‘™๐‘

๐‘ˆ๐ต ๐‘๐‘œ๐‘ก โ„Ž๐‘’๐‘™๐‘

๐›ผ๐ต2(๐ฟ๐ต ๐ป

๐ต)(ํœ€ ๐œƒ) ๐‘(๐›ฝ

๐ต๐‘Ž๐ด ๐ฟ

๐ต)

๐›ผ๐ต2(๐ฟ๐ต ๐ป

๐ต)( 1) ๐‘(๐›ฝ๐ต๐ฟ๐ด ๐ฟ๐ต )

Owing to ๐›ผ๐ต (๐ฟ๐ต ๐ป

๐ต)( 1) and ๐‘(๐›ฝ

๐ต๐ฟ๐ด ๐ฟ

๐ต) are always negative, ๐‘ˆ

๐ต ๐ป๐‘’๐‘™๐‘

๐‘ˆ๐ต ๐‘๐‘œ๐‘ก ๐‘’๐‘™๐‘

must be less than 0. This contradicts ๐‘Ÿ 1.

โ‘ฏ ๐‘Ÿ 0 ๐‘Ÿ 1 ๐‘ž 0 ๐‘ž 1

In the case of ๐ฟ๐ต

๐‘ˆ๐ต ๐ป๐‘’๐‘™๐‘

๐‘ˆ๐ต ๐‘๐‘œ๐‘ก โ„Ž๐‘’๐‘™๐‘

๐›ผ๐ต2(๐ฟ๐ต ๐ป

๐ต)(ํœ€ ๐œƒ) ๐‘(๐›ฝ

๐ต๐‘Ž๐ด ๐ฟ

๐ต)

๐›ผ๐ต2(๐ฟ๐ต ๐ป

๐ต)( 1) ๐‘(๐›ฝ๐ต๐ป๐ด ๐ฟ๐ต )

Owing to ๐›ผ๐ต (๐ฟ๐ต ๐ป

๐ต)( 1) and๐‘(๐›ฝ

๐ต๐ป๐ด ๐ฟ

๐ต) are always negative, ๐‘ˆ

๐ต ๐ป๐‘’๐‘™๐‘

๐‘ˆ๐ต ๐‘๐‘œ๐‘ก ๐‘’๐‘™๐‘

must be less than 0. This contradicts ๐‘Ÿ 1.

4. Discussion

Based on the above equilibrium analysis results, the difference in self-awareness

ฮพ is greatest when it is larger than c, it becomes equilibriumโ‘ฅ and equilibriumโ‘ฆ. In

other words, when the degree of loss avoidance of the player is the highest, there are

equilibriumโ‘ฅ and equilibriumโ‘ฆ. At this time, the helper always helps, regardless of

help-seekersโ€™ ability. When ๐œ‰ is small, there are equilibriumโ‘  , equilibriumโ‘ก ,

equilibriumโ‘ข, equilibriumโ‘ฅ, equilibriumโ‘ฆ and equilibriumโ‘ง. At this time, player B

with high ability would help. ๐›ผ

is the largest in equilibrium โ‘ฃ , equilibrium โ‘ค ,

equilibrium โ‘ฅ and equilibrium โ‘ฆ . At this time, we concluded that helpers and

38

help-seekers behave similarly, regardless of ability.

With respect to the helper, by equilibrium โ‘ฃ and equilibrium โ‘ค , if the

self-awareness ฮฑ is large but the politeness ฮฒ is very small, neither player B with high

ability nor with low ability would help. By equilibrium โ‘  , equilibrium โ‘ก and

equilibrium โ‘ข, if self-awareness ฮฑ and politeness ฮฒ are within a certain range, player

B with high ability would help, player B with low ability would not. In equilibrium โ‘ฅ,

equilibrium โ‘ฆ and equilibrium โ‘ง, when self-awareness ฮฑ and politeness ฮฒ are all

large, either player B with the high ability or low ability would help.

With respect to the help-seeker, in equilibriumโ‘ฆ, If politeness ๐›ฝ is small when

seeking help, either player A with low ability and with high ability would seek help. In

equilibrium โ‘ก and equilibrium โ‘ง, if self-awareness ฮฑ and politeness ฮฒ are within a

certain range, player A with high ability would not seek help, however, player A with

low ability would seek help. In equilibrium โ‘ข and equilibrium โ‘ฅ , when

self-awareness ฮฑ and politeness ฮฒ are both large, either player B with the high ability

or low ability would not seek help.

In situationโ‘ซ , situationโ‘ญ , situationโ‘ฎ and situationโ‘ฏ where there is no

equilibrium, it is impossible that player B with high ability does not help but help with

low ability. While the psychological effect of self-awareness ๐›ผ and politeness ๐›ฝ

affect human behavior, it is impossible to force others to do things beyond your

abilities.

In situationโ‘ฉ, situationโ‘ช, situationโ‘ฌ and situationโ‘ฏ, it is unlikely that player

with low abilities would not seek help and player with high abilities would seek help.

5. Implications

This paper studies human irrational behavior from the perspective of behavioral

economics. Through the establishment of a game model, we can understand why

people do not seek help when they are clearly in trouble. Because people have the

nature of politeness, it is difficult to ask for help from others if they are excessively

39

polite, and help others if they are excessively polite. Besides, people with strong

self-awareness are easy to care about what others think of themselves. In order to

build a good impression, they may not ask others for help, but they may help others

although it is not their original intention. Specifically speaking, from the perspective of

the help seeker, it is difficult to make clear what kind of people are likely to seek help

and what kind of people are unlikely to seek help. On the other hand, from the

perspective of helpers, what kind of people are likely to help and what kind of people

are unlikely to help.

Consequently, this study found that when the loss avoidance degree of players is

the largest, the helper will help others. Besides, when the loss avoidance degree of

players is small, people with high ability would help. In addition, people with higher

self-awareness would take the same action. If self-awareness is great, but the degree

of politeness is relatively small, no matter the ability is high or low, they will not help

each other. If the level of politeness is very low, people with the low ability or high

ability would seek help. When politeness and self-awareness are within a certain

range, neither big nor small, people with high ability would help, people with low ability

would not help; people with low ability would seek help, but people with high ability

would not seek help. When politeness and self-awareness are both great, people with

the high ability or low ability would not seek help.

6. Conclusion

This study analyzes whether people would seek help or help others from two

basic human characteristics of self-awareness and politeness. We found that, first, the

more polite the helper is to the help seeker, the easier to help. Second, helper with a

higher level of self-awareness and wish to keep a better impression from the help

seekers would help. However, helper with low ability would not grudgingly help others.

Help seeker with higher the degree of politeness would be less likely to seek help;

Besides, help seeker with a higher degree of self-awareness and care more about

40

other people's impression would not seek help.

7. Limitations and Future Directions

To simplify the model, the study has limitations. First, this study does not consider

the repaying, in other words, whether the help will be repaid in the future. Second, this

study only considered two psychological factors, politeness and self-awareness;

however, there could be other psychological factors which would influence human

behavior in this situation.

Future studies can consider the act of repaying; the game model can be set as a

repeated game. In addition, other psychological factors can be considered in the game

model for a better understanding of human help-seeking and help-giving behavior.

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