Charles Hakes Fort Lewis College1. Charles Hakes Fort Lewis College2 Introduction The Celestial...

Post on 22-Dec-2015

214 views 0 download

Transcript of Charles Hakes Fort Lewis College1. Charles Hakes Fort Lewis College2 Introduction The Celestial...

Charles HakesFort Lewis College 1

Charles HakesFort Lewis College 2

Introduction

The Celestial Sphere

Charles HakesFort Lewis College 3

Outline

• Lab notes• Review• Observing the Sun• Unit Conversions• RA/Dec• SETI

Charles HakesFort Lewis College 4

Notes

• Homework 1 due on Friday. • Sun lab(s) due in “box”:

• Noontime Sun by next Friday 5:00• Sunset part1 by next Friday 5:00

• Lab Resources Part B next week.• Binocular lab next Mon,Thur (?)

Charles HakesFort Lewis College 5

Observing the Sun

• http://sunearth.gsfc.nasa.gov/eclipse/SEhelp/safety2.html

• http://www.mreclipse.com/Special/filters.html

Charles HakesFort Lewis College 6

Measuring Angles

• A fist at arms length is about 10°• Fingers spread wide are about 15°• Three fingers together are about 5°• One pinky width is about 1°• The full moon is almost exactly 0.5°

Charles HakesFort Lewis College 7

Dimensional Analysis

• Dimensional Analysis is VERY helpful in problem solving.

• Check your equations with specific units.• Velocity example - how do distance (x), time (t),

and Velocity (V) relate?

V = x/t

Charles HakesFort Lewis College 8

Dimensional Analysis Example - Which equation is correct?

A) velocity = distance * time

B) time = velocity * distance

C) time = distance / velocity

D) time = velocity / distance

Charles HakesFort Lewis College 9

Which equation is correct?

A) velocity = distance * time

B) time = velocity * distance

C) time = distance / velocity

D) time = velocity / distance

Charles HakesFort Lewis College 10

Velocity Exercise

• The laser travels 9.6m across the room. How many seconds does it take?

Charles HakesFort Lewis College 11

Light Travel Time Across the Room (9.6 meters)

A) 2.9x106 sec

B) 2.9x10-6 sec

C) 3.2x10-5 sec

D) 3.2x10-8 sec

Charles HakesFort Lewis College 12

Light Travel Time Across the Room (9.6 meters)

A) 2.9x106 sec

B) 2.9x10-6 sec

C) 3.2x10-5 sec

D) 3.2x10-8 sec

Charles HakesFort Lewis College 13

Conversion Factors

• Conversion factors are equivalence statements expressed in the form of ratios

• Example: 1 in = 2.54 cm• Conversion factors let you express a

quantity in terms of other units without changing its physical value.

Charles HakesFort Lewis College 14

Conversion Exercise

• Convert 0.61 m to inches.

Charles HakesFort Lewis College 15

How many inches is 0.61m?

A) 0.24 inches

B) 1.56 inches

C) 24.0 inches

D) 156 inches

Charles HakesFort Lewis College 16

How many inches is 0.61m?

A) 0.24 inches

B) 1.56 inches

C) 24.0 inches

D) 156 inches

Charles HakesFort Lewis College 17

How many light years was that 9.6 m?

A) 9.1x1012 ly

B) 1.0x10-15 ly

C) 2.9x109 ly

D) 1.1x10-14 ly

Charles HakesFort Lewis College 18

How many light years was that 9.6 m?

A) 9.1x1012 ly

B) 1.0x10-15 ly

C) 2.9x109 ly

D) 1.1x10-14 ly

Charles HakesFort Lewis College 19

Significant Figures

• Example• 4.56 has three significant figures.• 4.56x106 also has three significant figures.• .000456 also has three significant figures.

• A calculation output can not have more significant figures than the input.• If an equation has a whole number (for example 2) it is

considered to be 2.00000 etc.• Calculation hint - it is often best to keep all available

figures until the last step, and then round your answer.

Charles HakesFort Lewis College 20

Scientific Notation

• What does 1.0x106 mean?• Positive exponents mean shift the decimal place to the

right (bigger numbers).• Negative exponents mean shift the decimal place to the

left (smaller numbers).• Usually only have one digit to the left of the decimal.• Most calculators have a single key to add the (x10^)

term. (EXP, EE)

Charles HakesFort Lewis College 21

Measurements

Multiple Prefix

109 giga-

106 mega-

103 kilo-

10-2 centi-

10-3 milli-

10-6 micro-

10-9 nano-

Charles HakesFort Lewis College 22

Algebra Hint

• The following relationship will be useful to remember:

Charles HakesFort Lewis College 23

Introduction

The Celestial Sphere

Charles HakesFort Lewis College 24

Oslo, Norway is 60°N latitude. What declination line passes through the zenith in Oslo?

A) 0°

B) 30° N

C) 60° N

D) 90° N

Charles HakesFort Lewis College 25

Oslo, Norway is 60°N latitude. What declination line passes through the zenith in Oslo?

A) 0°

B) 30° N

C) 60° N

D) 90° N

Charles HakesFort Lewis College 26

Astronomy Picture of the Day

http://antwrp.gsfc.nasa.gov/apod/ap080922.html

Charles HakesFort Lewis College 27

The Celestial Sphere

• Locations to note• North celestial pole• Celestial equator

• Declination corresponds to latitude. • Right ascension corresponds to

longitude. • RA and Dec are “fixed” onto the

celestial sphere.

Charles HakesFort Lewis College 28

Figure P.4Right Ascension and Declination

Charles HakesFort Lewis College 29

Declination

• Declination corresponds to latitude. • Units are degrees (and minutes and

seconds). • Durango’s latitude is +37.275° N.

The declination line passing directly overhead is also +37.275° N.

Charles HakesFort Lewis College 30

Oslo, Norway is 60°N latitude. How high does the star Polaris appear?

A) 0°

B) 30° N

C) 60° N

D) 90° N

Charles HakesFort Lewis College 31

Oslo, Norway is 60°N latitude. How high does the star Polaris appear?

A) 0°

B) 30° N

C) 60° N

D) 90° N

Charles HakesFort Lewis College 32

What is the southernmost declination line visible from Oslo (at 60° N)?

A) 60° N

B) 30° N

C) 0°

D) 30° S

Charles HakesFort Lewis College 33

What is the southernmost declination line visible from Oslo (at 60° N)?

A) 60° N

B) 30° N

C) 0°

D) 30° S

Charles HakesFort Lewis College 34

Standing on the equator, you can see…

A) the celestial equator directly overhead

B) entire celestial sphere during a 24 hour day

C) both celestial poles on your horizon

D) all of the above

Charles HakesFort Lewis College 35

Standing on the equator, you can see…

A) the celestial equator directly overhead

B) entire celestial sphere during a 24 hour day

C) both celestial poles on your horizon

D) all of the above

Charles HakesFort Lewis College 36

Durango’s latitude is 37.275° N. What is the southernmost declination line visible?

A) 0°

B) 37.275° S

C) 52.725° S

Charles HakesFort Lewis College 37

Durango’s latitude is 37.275° N. What is the southernmost declination line visible?

A) 0°

B) 37.275° S

C) 52.725° S

Charles HakesFort Lewis College 38

Right Ascension

• Right Ascension corresponds to longitude. • Units are Hours (and minutes and seconds).• The trick (as with longitude) is to decide on

the zero point.• Longitude zero is at the observatory in

Greenwich England.• RA zero is where the sun crosses the

celestial equator going north.• RA is always moving w.r.t. longitude.

Charles HakesFort Lewis College 39

PRS question

• How long is the following exposure?

Charles HakesFort Lewis College 40

Figure P.3The Northern Sky

Charles HakesFort Lewis College 41

How long is the exposure? Enter the correct number of hours.

A) 4

B) 5

C) 6

D) 7

E) 8

Charles HakesFort Lewis College 42

Three Minute Paper

• Write 1-3 sentences.• What was the most important thing

you learned today?• What questions do you still have

about today’s topics?