Balanced Parentheses G = (V, , S, P) V = {S} = {(,)} Start variable is S P = { S --> (S) | SS | /\}

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Transcript of Balanced Parentheses G = (V, , S, P) V = {S} = {(,)} Start variable is S P = { S --> (S) | SS | /\}

Balanced ParenthesesG = (V, , S, P)

V = {S} = {(,)}Start variable is SP = { S --> (S) | SS | /\}

One Derivation Tree for ()(())()G = (V, , S, P)

V = {S} = {(,)}Start variable is SP = { S --> (S) | SS | /\}

S

First Expansion PhaseG = (V, , S, P)

V = {S} = {(,)}Start variable is SP = { S --> (S) | SS | /\}

S

S S

Second Expansion PhaseG = (V, , S, P)

V = {S} = {(,)}Start variable is SP = { S --> (S) | SS | /\}

S

S S

S S ( )S

Third Expansion PhaseG = (V, , S, P)

V = {S} = {(,)}Start variable is SP = { S --> (S) | SS | /\}

S

S S

( )S

/\

S

( )S

S

( )S

Fourth Expansion PhaseG = (V, , S, P)

V = {S} = {(,)}Start variable is SP = { S --> (S) | SS | /\}

S

S S

( )S

/\

S

( )S

S

( )S

( )S/\

Final Expansion PhaseG = (V, , S, P)

V = {S} = {(,)}Start variable is SP = { S --> (S) | SS | /\}

S

S S

( )S

/\

S

( )S

S

( )S

( )S/\

/\

Leftmost/Rightmost DerivationsG = (V, , S, P)

V = {S} = {(,)}Start variable is SP = { S --> (S) | SS | /\}

S

S S

( )S

/\

S

( )S

S

( )S

( )S/\

/\

Rightmost:S ==> SSLeftmost: S ==> SS

Leftmost/Rightmost VariablesG = (V, , S, P)

V = {S} = {(,)}Start variable is SP = { S --> (S) | SS | /\}

S

S S

( )S

/\

S

( )S

S

( )S

( )S/\

/\

Rightmost: S ==> SSLeftmost: S ==> SS

Second Derivation StepsG = (V, , S, P)

V = {S} = {(,)}Start variable is SP = { S --> (S) | SS | /\}

S

S S

( )S

/\

S

( )S

S

( )S

( )S/\

/\

Rightmost: S ==> SS ==> S(S)

Leftmost: S ==> SS ==> SSS

Leftmost/Rightmost VariablesG = (V, , S, P)

V = {S} = {(,)}Start variable is SP = { S --> (S) | SS | /\}

S

S S

( )S

/\

S

( )S

S

( )S

( )S/\

/\

Rightmost: S ==> SS ==> S(S)

Leftmost: S ==> SS ==> SSS

Third Derivation StepsG = (V, , S, P)

V = {S} = {(,)}Start variable is SP = { S --> (S) | SS | /\}

S

S S

( )S

/\

S

( )S

S

( )S

( )S/\

/\

Rightmost: S ==> SS ==> S(S) ==> S(/\)

Leftmost: S ==> SS ==> SSS ==> (S)SS

Leftmost/Rightmost VariablesG = (V, , S, P)

V = {S} = {(,)}Start variable is SP = { S --> (S) | SS | /\}

S

S S

( )S

/\

S

( )S

S

( )S

( )S/\

/\

Rightmost: S ==> SS ==> S(S) ==> S()

Leftmost: S ==> SS ==> SSS ==> (S)SS

Fourth Derivation StepsG = (V, , S, P)

V = {S} = {(,)}Start variable is SP = { S --> (S) | SS | /\}

S

S S

( )S

/\

S

( )S

S

( )S

( )S/\

/\

Rightmost: S ==> SS ==> S(S) ==> S() ==> SS()

Leftmost: S ==> SS ==> SSS ==> (S)SS ==> (/\)SS

Leftmost/Rightmost VariablesG = (V, , S, P)

V = {S} = {(,)}Start variable is SP = { S --> (S) | SS | /\}

S

S S

( )S

/\

S

( )S

S

( )S

( )S/\

/\

Rightmost: S ==> SS ==> S(S) ==> S() ==> SS()

Leftmost: S ==> SS ==> SSS ==> (S)SS ==> ()SS

Fifth Derivation StepsG = (V, , S, P)

V = {S} = {(,)}Start variable is SP = { S --> (S) | SS | /\}

S

S S

( )S

/\

S

( )S

S

( )S

( )S/\

/\

Rightmost: S ==> SS ==> S(S) ==> S() ==> SS() ==> S(S)()

Leftmost: S ==> SS ==> SSS ==> (S)SS ==> ()SS ==> ()(S)S

Leftmost/Rightmost VariablesG = (V, , S, P)

V = {S} = {(,)}Start variable is SP = { S --> (S) | SS | /\}

S

S S

( )S

/\

S

( )S

S

( )S

( )S/\

/\

Rightmost: S ==> SS ==> S(S) ==> S() ==> SS() ==> S(S)()

Leftmost: S ==> SS ==> SSS ==> (S)SS ==> ()SS ==> ()(S)S

Sixth Derivation StepsG = (V, , S, P)

V = {S} = {(,)}Start variable is SP = { S --> (S) | SS | /\}

S

S S

( )S

/\

S

( )S

S

( )S

( )S/\

/\

Rightmost: S ==> SS ==> S(S) ==> S() ==> SS() ==> S(S)() ==> S((S))()

Leftmost: S ==> SS ==> SSS ==> (S)SS ==> ()SS ==> ()(S)S ==> ()((S))S

Leftmost/Rightmost VariablesG = (V, , S, P)

V = {S} = {(,)}Start variable is SP = { S --> (S) | SS | /\}

S

S S

( )S

/\

S

( )S

S

( )S

( )S/\

/\

Rightmost: S ==> SS ==> S(S) ==> S() ==> SS() ==> S(S)() ==> S((S))()

Leftmost: S ==> SS ==> SSS ==> (S)SS ==> ()SS ==> ()(S)S ==> ()((S))S

Seventh Derivation StepsG = (V, , S, P)

V = {S} = {(,)}Start variable is SP = { S --> (S) | SS | /\}

S

S S

( )S

/\

S

( )S

S

( )S

( )S/\

/\

Rightmost: S ==> SS ==> S(S) ==> S() ==> SS() ==> S(S)() ==> S((S))() ==> S((/\))()

Leftmost: S ==> SS ==> SSS ==> (S)SS ==> ()SS ==> ()(S)S ==> ()((S))S ==> ()((/\))S

Leftmost/Rightmost VariablesG = (V, , S, P)

V = {S} = {(,)}Start variable is SP = { S --> (S) | SS | /\}

S

S S

( )S

/\

S

( )S

S

( )S

( )S/\

/\

Rightmost: S ==> SS ==> S(S) ==> S() ==> SS() ==> S(S)() ==> S((S))() ==> S(())()

Leftmost: S ==> SS ==> SSS ==> (S)SS ==> ()SS ==> ()(S)S ==> ()((S))S ==> ()(())S

Eighth Derivation StepsG = (V, , S, P)

V = {S} = {(,)}Start variable is SP = { S --> (S) | SS | /\}

S

S S

( )S

/\

S

( )S

S

( )S

( )S/\

/\

Rightmost: S ==> SS ==> S(S) ==> S() ==> SS() ==> S(S)() ==> S((S))() ==> S(())() ==> (S)(())()

Leftmost: S ==> SS ==> SSS ==> (S)SS ==> ()SS ==> ()(S)S ==> ()((S))S ==> ()(())S ==> ()(())(S)

Leftmost/Rightmost VariablesG = (V, , S, P)

V = {S} = {(,)}Start variable is SP = { S --> (S) | SS | /\}

S

S S

( )S

/\

S

( )S

S

( )S

( )S/\

/\

Rightmost: S ==> SS ==> S(S) ==> S() ==> SS() ==> S(S)() ==> S((S))() ==> S(())() ==> (S)(())()

Leftmost: S ==> SS ==> SSS ==> (S)SS ==> ()SS ==> ()(S)S ==> ()((S))S ==> ()(())S ==> ()(())(S)

Final Derivation StepsG = (V, , S, P)

V = {S} = {(,)}Start variable is SP = { S --> (S) | SS | /\}

S

S S

( )S

/\

S

( )S

S

( )S

( )S/\

/\

Rightmost: S ==> SS ==> S(S) ==> S() ==> SS() ==> S(S)() ==> S((S))() ==> S(())() ==> (S)(())() ==> (/\)(())()

Leftmost: S ==> SS ==> SSS ==> (S)SS ==> ()SS ==> ()(S)S ==> ()((S))S ==> ()(())S ==> ()(())(S) ==> ()(())(/\)

Ambiguous GrammarG = (V, , S, P)

V = {S} = {(,)}Start variable is SP = { S --> (S) | SS | /\}

S

S S

( )S

/\

S

( )S

S

( )S

( )S/\

/\

S

S

( )S

/\

S

S

( )S

/\

S

( )S

( )S

/\

We’ll show a second derivation tree for the string ()(())().This proves the grammar G is ambiguous.

Unambiguous GrammarG = (V, , S, P)

V = {S} = {(,)}Start variable is SP = { S --> (S) | SS | /\}

S’

S’ T

( )S’

/\( )

G’ = (V’, , S’, P’)

V = {S’,T} = {(,)}Start variable is S’P = { S’ --> S’T | /\ T --> (S’)}

S’

S’

/\

T

( )S’

/\

S’

S’

/\

T

( )S’

/\

T

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