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Solutions Manual c System Dynamics, Third Edition …...Problem 2.3 continued: d) Z x 5 dx x = 2 Z t 0 e 4t dt ln xjx 5 = 1 2 e 4t 1 ln x 5 = 1 2 e 4t 1 x(t) = 5 p e e1 2 e 4t c 2014
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