Download - y = 2x + 5; domain = {2, 2, 4}...2x — 3 5x — 3 3x — 1 5 2x -1 4x — 2 y — —3x+5 Twice x minus 5 A. c. D. one-half of x plus 4 4 added to negative one-half of x the product

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Page 1: y = 2x + 5; domain = {2, 2, 4}...2x — 3 5x — 3 3x — 1 5 2x -1 4x — 2 y — —3x+5 Twice x minus 5 A. c. D. one-half of x plus 4 4 added to negative one-half of x the product

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February 22, 2018

Warm up back of p 13

Find the range (y) values given each function and domain (x).

y = x ­ 5; domain = 4, 6, 8

y = ­2x + 5; domain = ­2, 2, 4

x x­5 y468

x ­2x+5 y

­224

Page 2: y = 2x + 5; domain = {2, 2, 4}...2x — 3 5x — 3 3x — 1 5 2x -1 4x — 2 y — —3x+5 Twice x minus 5 A. c. D. one-half of x plus 4 4 added to negative one-half of x the product

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February 22, 2018

Page 3: y = 2x + 5; domain = {2, 2, 4}...2x — 3 5x — 3 3x — 1 5 2x -1 4x — 2 y — —3x+5 Twice x minus 5 A. c. D. one-half of x plus 4 4 added to negative one-half of x the product

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February 22, 2018

Page 4: y = 2x + 5; domain = {2, 2, 4}...2x — 3 5x — 3 3x — 1 5 2x -1 4x — 2 y — —3x+5 Twice x minus 5 A. c. D. one-half of x plus 4 4 added to negative one-half of x the product

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February 22, 2018

Page 5: y = 2x + 5; domain = {2, 2, 4}...2x — 3 5x — 3 3x — 1 5 2x -1 4x — 2 y — —3x+5 Twice x minus 5 A. c. D. one-half of x plus 4 4 added to negative one-half of x the product

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February 22, 2018

Page 6: y = 2x + 5; domain = {2, 2, 4}...2x — 3 5x — 3 3x — 1 5 2x -1 4x — 2 y — —3x+5 Twice x minus 5 A. c. D. one-half of x plus 4 4 added to negative one-half of x the product

16a_graphing functions.notebook

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February 22, 2018

Page 7: y = 2x + 5; domain = {2, 2, 4}...2x — 3 5x — 3 3x — 1 5 2x -1 4x — 2 y — —3x+5 Twice x minus 5 A. c. D. one-half of x plus 4 4 added to negative one-half of x the product

16a_graphing functions.notebook

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February 22, 2018

Page 8: y = 2x + 5; domain = {2, 2, 4}...2x — 3 5x — 3 3x — 1 5 2x -1 4x — 2 y — —3x+5 Twice x minus 5 A. c. D. one-half of x plus 4 4 added to negative one-half of x the product

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February 22, 2018


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