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2x 4y 10 2 x + 4y 2x + 4y = 102 x + 4y + 102= 180 2x = 102 - 4y 51 – 2y + 4y + 102 = 180 2y + 153 = 180 2y = 27 x = 51 - 2y x = 51 – 2(13.5) x = 51 – 27.
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downloadlink.org · 3.6.4: Ifthesideofthepenparalleltothewallhaslengthxandthetwoperpendicularsidesbothhave lengthy,thenwearetomaximizeareaA=xygivenx+2y=600.Thus A=A(y)=y(600−2y),
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