12 Apr 202312 Apr 2023 Created by Mr. Lafferty Maths Dept.Created by Mr. Lafferty Maths Dept.
Exact Values
Angles greater than 90o
TrigonometryTrigonometryw
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Useful Notation & Area of a triangle
Using Area of Triangle Formula
Cosine Rule Problems
Sine Rule Problems
Mixed Problems
S5 Int2
12 Apr 202312 Apr 2023 Created by Mr Lafferty Maths DeptCreated by Mr Lafferty Maths Dept
Starter QuestionsStarter Questions
o
21. Factorise x - 36
2. A car depreciates at 20% each year.
How much is it worth af ter 4 years if it cost
£ 15 000 initially.
3. What sin30 as a f raction.
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S5 Int2
12 Apr 202312 Apr 2023 Created by Mr Lafferty Maths DeptCreated by Mr Lafferty Maths Dept
Exact ValuesExact Values
Learning IntentionLearning Intention Success CriteriaSuccess Criteria
1.1. Recognise basic triangles Recognise basic triangles and exact values for sin, and exact values for sin, cos and tan 30cos and tan 30oo, 45, 45oo, 60, 60oo . .
1. To build on basic trigonometry values.
2.2. Calculate exact values for Calculate exact values for problems.problems.
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S5 Int2
22
2
60º
60º
60º 1
60º
230º3
This triangle will provide exact values for
sin, cos and tan 30º and 60º
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S5 Int2
Some special values of Sin, Cos and Tan are useful left as fractions, We call these exact values
x 0º 30º 45º 60º 90º
Sin xº
Cos xº
Tan xº
½
½
3
3
2
3
20
1
0
1
0
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1
3
Exact ValuesExact Valuesw
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S5 Int2
1 145º
45º
2
Consider the square with sides 1 unit
11
We are now in a position to calculate exact values for sin, cos and tan of 45o
x 0º 30º 45º 60º 90º
Sin xº
Cos xº
Tan xº
½
½
3
3
2
3
20
1
0
1
0
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1
3
1 2
1 2
1
12 Apr 202312 Apr 2023 Created by Mr Lafferty Maths DeptCreated by Mr Lafferty Maths Dept
Now try Exercise 1Ch8 (page 94)
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S5 Int2
Exact ValuesExact Values
12 Apr 202312 Apr 2023 Created by Mr Lafferty Maths DeptCreated by Mr Lafferty Maths Dept
Starter QuestionsStarter Questions
1. Write down the Compound I nterest Formula
and identif y each term.
2. A house increases by 3% each year.
How much is it worth in 5 years if it cost
£ 40 000 initially.
3. What is the .oexact value of sin 45
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S5 Int2
12 Apr 202312 Apr 2023 Created by Mr. Lafferty Maths Dept.Created by Mr. Lafferty Maths Dept.ww
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Angles Greater than Angles Greater than 9090oo
1. Introduce definition of sine, cosine and tangent over 360o using triangles with the unity circle.
1.1. Find values of sine, cosine Find values of sine, cosine and tangent over the range and tangent over the range 00o o to 360to 360oo..
2.2. Recognise the symmetry Recognise the symmetry and equal values for sine, and equal values for sine, cosine and tangent.cosine and tangent.
S5 Int2
Apr 12, 2023Apr 12, 2023 www.mathsrevision.comwww.mathsrevision.com 1111
xy
rAngles Greater than Angles Greater than
9090oo
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S5 Int2
We will now use a new definition to cater for ALL angles.
O x-axis
r
y-axis
y
xAo
New Definitions
siny
Ar
P(x,y)
cosx
Ar
tany
Ax
12 Apr 202312 Apr 2023 Created by Mr Lafferty Maths DeptCreated by Mr Lafferty Maths Deptww
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TrigonometryTrigonometryAngles over 900S5 Int2
(1.2, 1.6)
53o
The radius line is 2cm.The point (1.2, 1.6).
Find sin cos and tan forthe angle.
1.6sin 53 0.8
2o
1.2cos53 0.6
2o
1.6tan53 1.33
1.2o
Check answer with
calculator
Example 1
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TrigonometryTrigonometryAngles over 900S5 Int2
(-1.8, 0.8)
127o
The radius line is 2cm.The point (-1.8, 0.8).
Find sin cos and tan forthe angle.
0.8sin127 0.4
2o
1.8cos127 0.9
2o
0.8tan53 0.44
1.8o
Check answer with
calculator
Example 1
1) Sin 135o
2) Cos 150o
3) Tan 135o
4) Sin 225o
5) Cos 270o
What Goes In The Box ?What Goes In The Box ?
Write down the equivalent values of the following in term of the first quadrant (between 0o and 90o):
sin 45o
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S5 Int2
1) Sin 300o
2) Cos 360o
3) Tan 330o
4) Sin 380o
5) Cos 460o
-cos 45o
-tan 45o
-sin 45o
-cos 90o
- sin 60o
cos 0o
- tan 30o
sin 20o
- cos 80o
12 Apr 202312 Apr 2023 Created by Mr Lafferty Maths DeptCreated by Mr Lafferty Maths Dept
Now try Exercise 2Ch8 (page 97)
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TrigonometryTrigonometryAngles over 900S5 Int2
12 Apr 202312 Apr 2023 Created by Mr Lafferty Maths DeptCreated by Mr Lafferty Maths Deptww
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TrigonometryTrigonometryAngles over 900S5 Int2
Extension for unit 2 Trigonometry
GSM Software
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Int 2
All +ve
Sin +ve
Tan +ve Cos +ve
180o - xo
180o + xo 360o - xo
Angles Greater than Angles Greater than 9090oo
(0,1)
(-1,0)
(0,-1)
(1,0)0A
Two diagrams display same data in a different format
12 Apr 202312 Apr 2023 Created by Mr. Lafferty Maths Dept.Created by Mr. Lafferty Maths Dept.
Starter QuestionsStarter Questionsw
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2
o
1. Find the area of the triangle.
2. Factorise x - 4x +3
3. Find the exact value of cos 120 .
S5 Int2
8cm
3cm
12 Apr 202312 Apr 2023 Created by Mr. Lafferty Maths Dept.Created by Mr. Lafferty Maths Dept.ww
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Area of a Area of a TriangleTriangle
1. To show the standard way of labelling a triangle.
2. Find the area of a triangle using basic trigonometry knowledge.
1.1. Be able to label a triangle Be able to label a triangle properly. properly.
2.2. Find the area of a triangle Find the area of a triangle using basic trigonometry using basic trigonometry knowledge.knowledge.
S5 Int2
12 Apr 202312 Apr 2023 Created by Mr Lafferty Maths DeptCreated by Mr Lafferty Maths Dept
Labelling TrianglesLabelling Trianglesw
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S5 Int2
A
B
C
A
aB
b
Cc
Small letters a, b, c refer to distancesCapital letters A, B, C refer to angles
In Mathematics we have a convention for labelling triangles.
F
E
D
F
E
D12 Apr 202312 Apr 2023 Created by Mr Lafferty Maths DeptCreated by Mr Lafferty Maths Dept
Labelling TrianglesLabelling Trianglesw
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S5 Int2
d
e
f
Have a go at labelling the following triangle.
12 Apr 202312 Apr 2023 Created by Mr Lafferty Maths DeptCreated by Mr Lafferty Maths Dept
Area of a TriangleArea of a TriangleS5 Int2
A
B
12cm C
10cm
Example 1 : Find the area of the triangle ABC.
50o
(i) Draw in a line from B to AC
(ii) Calculate height BD
D
o BDSin50 =
10oBD = 10 Sin50 = 7.66
2
1
2
0.5 12 7.66 46
Area base height
cm
(iii) Area
7.66cm
12 Apr 202312 Apr 2023 Created by Mr Lafferty Maths DeptCreated by Mr Lafferty Maths Dept
Area of a TriangleArea of a TriangleS5 Int2
Q
P
20cm R
12cm
Example 2 : Find the area of the triangle PQR.
40o
(i) Draw in a line from P to QR
(ii) Calculate height PS
S
o PSSin40 =
10oPS = 12 Sin40 = 7.71
2
1
2
0.5 20 7.71 77.1
Area base height
cm
(iii) Area
7.71cm
12 Apr 202312 Apr 2023 Created by Mr. Lafferty Maths Dept.Created by Mr. Lafferty Maths Dept.
Now try Exercise 3Ch8 (page 99)
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Constructing Pie Constructing Pie ChartsCharts
S5 Int2
12 Apr 202312 Apr 2023 Created by Mr. Lafferty Maths Dept.Created by Mr. Lafferty Maths Dept.
Starter QuestionsStarter Questionsw
ww
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2. Find the volume of a cylinder 15cm in height
and 10cm in diameter.
3. Write down the two values f or sin
that give a value of 0.5
x x
S5 Int2
12 Apr 202312 Apr 2023 Created by Mr. Lafferty Maths Dept.Created by Mr. Lafferty Maths Dept.ww
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1.1. Know the formula for the Know the formula for the area of any triangle.area of any triangle.
1. To explain how to use the Area formula for ANY triangle.
S5 Int2
Area of ANY TriangleArea of ANY Triangle
2.2. Use formula to find area of Use formula to find area of any triangle given two any triangle given two length and angle in length and angle in between.between.
General Formula forGeneral Formula forArea of ANY TriangleArea of ANY Triangle
Consider the triangle below:
Ao Bo
Co
ab
c
h
Area = ½ x base x height 1
2A c h
What does the sine of Ao equal
sin o hA
b
Change the subject to h. h = b
sinAoSubstitute into the area formula
1sin
2oA c b A
1sin
2oA bc A
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12 Apr 202312 Apr 2023 Created by Mr Lafferty Maths DeptCreated by Mr Lafferty Maths Dept
Area of ANY TriangleArea of ANY Trianglew
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S5 Int2
A
B
C
A
aB
b
Cc
The area of ANY triangle can be found by the following formula.
sin1
Area= ab C2
sin1
Area= ac B2
sin1
Area= bc A2
Another version
Another version
Key feature
To find the areayou need to
knowing 2 sides and the
angle in between (SAS)
12 Apr 202312 Apr 2023 Created by Mr Lafferty Maths DeptCreated by Mr Lafferty Maths Dept
Area of ANY TriangleArea of ANY Trianglew
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S5 Int2
A
B
C
A
20cmB
25cm
Cc
Example : Find the area of the triangle.
sinC1
Area= ab2
The version we use is
30o
120 25 sin30
2oArea
210 25 0.5 125Area cm
12 Apr 202312 Apr 2023 Created by Mr Lafferty Maths DeptCreated by Mr Lafferty Maths Dept
Area of ANY TriangleArea of ANY Trianglew
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S5 Int2
D
E
F
10cm
8cm
Example : Find the area of the triangle.
sin1
Area= df E2
The version we use is
60o
18 10 sin 60
2oArea
240 0.866 34.64Area cm
What Goes In The Box What Goes In The Box ??
Calculate the areas of the triangles below:
(1)
23o
15cm
12.6cm
(2)
71o
5.7m
6.2m
A =36.9cm2
A =16.7m2
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Key feature
Remember (SAS)
12 Apr 202312 Apr 2023 Created by Mr. Lafferty Maths Dept.Created by Mr. Lafferty Maths Dept.
Now try Exercise 4Ch8 (page 100)
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S5 Int2
Area of ANY TriangleArea of ANY Triangle
12 Apr 202312 Apr 2023 Created by Mr. Lafferty Maths Dept.Created by Mr. Lafferty Maths Dept.
Starter QuestionsStarter Questionsw
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2
1. Multiply out the brackets and simplif y
5(y- 5) - 7(5- y)
2. Find the gradient and the y - intercept
3 f or the line with equation y = 5x -
4
3. Factorise x -100
S5 Int2
12 Apr 202312 Apr 2023 Created by Mr. Lafferty Maths Dept.Created by Mr. Lafferty Maths Dept.ww
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1.1. Know how to use the sine Know how to use the sine rule to solve REAL LIFE rule to solve REAL LIFE problems involving problems involving lengths.lengths.
1. To show how to use the sine rule to solve REAL LIFE problems involving finding the length of a side of a triangle .
Sine RuleSine RuleS5 Int2
C
B
A12 Apr 202312 Apr 2023 Created by Mr Lafferty Maths DeptCreated by Mr Lafferty Maths Dept
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S5 Int2
a
b
c
The Sine Rule can be used with ANY triangle as long as we have been given enough information.
Works for any Triangle
a b c= =
SinA SinB SinC
Deriving the rule
B
C
A
b
c
a
Consider a general triangle ABC.
The Sine Rule
Draw CP perpendicular to BA
P
CPSinB CP aSinB
a
CP
also SinA CP bSinAb
aSinB bSinA
aSinBb
SinA
a bSinA SinB
This can be extended to
a b cSinA SinB SinC
or equivalentlySinA SinB SinCa b c
Calculating Sides Calculating Sides Using The Sine RuleUsing The Sine Rule
10m
34o
41o
a
Match up corresponding sides and angles:
sin 41oa
10
sin 34o
Rearrange and solve for a. 10sin 41
sin34
o
oa 10 0.656
11.740.559
a m
Example 1 : Find the length of a in this triangle.
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S4 Credit
A
B
C
sin sin sino
a b c
A B C
Calculating Sides Calculating Sides Using The Sine Using The Sine
RuleRule
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S4 Credit
10m133o
37o
d
sin133od
10
sin 37o
10sin133
sin 37
o
od
10 0.731
0.602d
=
12.14m
Match up corresponding sides and angles:
Rearrange and solve for d.
Example 2 : Find the length of d in this triangle.
C
D
E
sin sin sino
c d e
C D E
What goes in the Box What goes in the Box ??
Find the unknown side in each of the triangles below:
(1) 12cm
72o
32o
a
(2)
93o
b47o
16mm
a = 6.7cm b =
21.8mm
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12 Apr 202312 Apr 2023 Created by Mr Lafferty Maths DeptCreated by Mr Lafferty Maths Dept
12 Apr 202312 Apr 2023 Created by Mr. Lafferty Maths Dept.Created by Mr. Lafferty Maths Dept.
Now try Ex 6&7 Ch8 (page 103)
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Sine RuleSine Rule
12 Apr 202312 Apr 2023 Created by Mr. Lafferty Maths Dept.Created by Mr. Lafferty Maths Dept.
Starter QuestionsStarter Questionsw
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1. Factorise 9x - 36
2. Find the gradient and the y - intercept
3 1 f or the line with equation y = - x +
4 5
3. Write down the two values of cos
1 that give you a value of
2
S5 Int2
12 Apr 202312 Apr 2023 Created by Mr. Lafferty Maths Dept.Created by Mr. Lafferty Maths Dept.ww
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1.1. Know how to use the sine Know how to use the sine rule to solve problems rule to solve problems involving angles.involving angles.
1. To show how to use the sine rule to solve problems involving finding an angle of a triangle .
Sine RuleSine RuleS5 Int2
Calculating Angles Calculating Angles
Using The Sine Using The Sine RuleRule
Example 1 :
Find the angle Ao
A
45m
23o
38m
Match up corresponding sides and angles:
45
sin oA 38
sin 23o
Rearrange and solve for sin Ao
45sin 23sin
38
ooA = 0.463 Use sin-1 0.463 to find Ao
1sin 0.463 27.6o oA ww
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S4 Credit
sin sin sin
a b c
A B C
B
C
Calculating Angles Calculating Angles
Using The Sine Using The Sine RuleRule
143o
75m
38m
X
38
sin oX
75
sin143o
38sin143sin
75
ooX = 0.305
1sin 0.305 17.8o oX
Example 2 :
Find the angle Xo
Match up corresponding sides and angles:
Rearrange and solve for sin Xo
Use sin-1 0.305 to find Xo
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S4 Credit
Y
Z
sin sin sin
x y z
X Y Z
What Goes In The Box What Goes In The Box ??
Calculate the unknown angle in the following:
(1)
14.5m
8.9m
Ao
100o (2)
14.7cm
Bo
14o
12.9cm
Ao = 37.2o
Bo = 16o
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S5 Int2
12 Apr 202312 Apr 2023 Created by Mr. Lafferty Maths Dept.Created by Mr. Lafferty Maths Dept.
Now try Ex 8 & 9Ch8 (page 106)
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Sine RuleSine Rule
12 Apr 202312 Apr 2023 Created by Mr. Lafferty Maths Dept.Created by Mr. Lafferty Maths Dept.
Starter QuestionsStarter Questionsw
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2
1. Find the gradient of the line that passes
through the points ( 1,1) and (9,9).
2. Find the gradient and the y - intercept
f or the line with equation y = 1 - x
3. Factorise x - 64
S5 Int2
12 Apr 202312 Apr 2023 Created by Mr. Lafferty Maths Dept.Created by Mr. Lafferty Maths Dept.ww
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1.1. Know when to use the Know when to use the cosine rule to solve cosine rule to solve problems.problems.
1. To show when to use the cosine rule to solve problems involving finding the length of a side of a triangle .
Cosine RuleCosine RuleS5 Int2
2. 2. Solve problems that Solve problems that involve finding the length involve finding the length of a side.of a side.
C
B
A12 Apr 202312 Apr 2023 Created by Mr Lafferty Maths DeptCreated by Mr Lafferty Maths Dept
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S5 Int2
a
b
c
The Cosine Rule can be used with ANY triangle as long as we have been given enough information.
Works for any Triangle
cos2 2 2a =b +c - 2bc A
Deriving the rule
A
B
C
a
b
c
Consider a general triangle ABC. We require a in terms of b, c and A.
Draw BP perpendicular to AC
b
Px b - x
BP2 = a2 – (b – x)2
Also: BP2 = c2 – x2
a2 – (b – x)2 = c2 – x2
a2 – (b2 – 2bx + x2) = c2 – x2
a2 – b2 + 2bx – x2 = c2 – x2
a2 = b2 + c2 – 2bx*
a2 = b2 + c2 – 2bcCosA*Since Cos A = x/c x = cCosA
When A = 90o, CosA = 0 and reduces to a2 = b2 + c2
1
When A > 90o, CosA is negative, a2 > b2 + c2 2
When A < 90o, CosA is positive, a2 > b2 + c2 3
The Cosine Rule
The Cosine Rule generalises Pythagoras’ Theorem and takes care of the 3 possible cases for Angle A.
a2 > b2 + c2
a2 < b2 + c2
a2 = b2 + c2
A
A
A
1
2
3
Pythagoras + a bitPythagoras - a bit
Pythagoras
a2 = b2 + c2 – 2bcCosA
Applying the same method as earlier to the other sides produce similar formulae
for b and c. namely:b2 = a2 + c2 – 2acCosB
c2 = a2 + b2 – 2abCosC
A
B
C
a
b
c
The Cosine Rule
The Cosine rule can be used to find:
1. An unknown side when two sides of the triangle and the included angle are given.
2. An unknown angle when 3 sides are given.
Finding an unknown side.
12 Apr 202312 Apr 2023 Created by Mr Lafferty Maths DeptCreated by Mr Lafferty Maths Dept
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How to determine when to use the Cosine Rule.
Works for any Triangle
1. Do you know ALL the lengths.
2. Do you know 2 sides and the angle in between.
SASOR
If YES to any of the questions then Cosine Rule
Otherwise use the Sine Rule
Two questions
Using The Cosine Using The Cosine RuleRule
Example 1 : Find the unknown side in the triangle below: L5m
12m
43o
Identify sides a,b,c and angle Ao
a =
L b =
5 c =
12 Ao = 43o
Write down the Cosine Rule.
Substitute values to find a2.a2 =
52 + 122 - 2 x 5 x 12 cos 43o
a2 =
25 + 144
- (120 x
0.731 )
a2 =
81.28 Square root to find “a”.
a = L = 9.02m
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S5 Int2 Works for any Triangle
Example 2 :
Find the length of side M.
137o
17.5 m
12.2 m
M
Identify the sides and angle.
a = M
b = 12.2 C = 17.5 Ao = 137o
Write down Cosine Rule
a2 = 12.22 + 17.52 – ( 2 x 12.2 x 17.5 x cos 137o )
a2 = 148.84 + 306.25 – ( 427 x – 0.731 )Notice the two negative
signs.a2 = 455.09 + 312.137
a2 = 767.227
a = M = 27.7m
Using The Cosine Using The Cosine RuleRule
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S5 Int2 Works for any Triangle
What Goes In The What Goes In The Box ?Box ?
Find the length of the unknown side in the triangles:
(1)78o
43cm
31cmL
(2)
8m
5.2m
38o
M
L = 47.5cm
M = 5.05m
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S5 Int2
12 Apr 202312 Apr 2023 Created by Mr. Lafferty Maths Dept.Created by Mr. Lafferty Maths Dept.
Now try Ex 12Ch8 (page 112)
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S5 Int2
Cosine RuleCosine Rule
12 Apr 202312 Apr 2023 Created by Mr. Lafferty Maths Dept.Created by Mr. Lafferty Maths Dept.
Starter QuestionsStarter Questionsw
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2
1. I f lines have the same gradient
What is special about them.
2. Factorise x +4x -12
3. Find the missing angles.
S5 Int2
54o
12 Apr 202312 Apr 2023 Created by Mr. Lafferty Maths Dept.Created by Mr. Lafferty Maths Dept.ww
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1.1. Know when to use the Know when to use the cosine rule to solve cosine rule to solve REAL LIFE problems.problems.
1. To show when to use the cosine rule to solve REAL LIFE problems involving finding an angle of a triangle .
Cosine RuleCosine RuleS5 Int2
2. 2. Solve Solve REAL LIFE problems problems that involve finding an that involve finding an angle of a triangle.angle of a triangle.
C
B
A12 Apr 202312 Apr 2023 Created by Mr Lafferty Maths DeptCreated by Mr Lafferty Maths Dept
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S5 Int2
a
b
c
The Cosine Rule can be used with ANY triangle as long as we have been given enough information.
Works for any Triangle
cos2 2 2a =b +c - 2bc A
Finding Angles Finding Angles Using The Cosine RuleUsing The Cosine Rule
Consider the Cosine Rule again:We are going to change the subject of the formula to cos Ao
Turn the formula around:b2 + c2 – 2bc cos Ao = a2
Take b2 and c2 across.-2bc cos Ao = a2 – b2 – c2
Divide by – 2 bc.2 2 2
cos2
o a b cA
bc
Divide top and bottom by -12 2 2
cos2
o b c aA
bc
You now have a formula for finding an angle if you know all three sides of the triangle.w
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S5 Int2 Works for any Triangle
Write down the formula for cos Ao
2 2 2
cos2
o b c aA
bc
Label and identify Ao and a , b and c.
Ao = ? a = 11b = 9 c = 16
Substitute values into the formula.
2 2 29 16 11cos
2 9 16oA
Calculate cos Ao .Cos Ao =0.75
Use cos-1 0.75 to find Ao
Ao = 41.4o
Example 1 : Calculate the
unknown angle xo .
Finding Angles Finding Angles Using The Cosine RuleUsing The Cosine Rule
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S5 Int2 Works for any Triangle
Example 2: Find the unknown
Angle in the triangle:
Write down the formula.
2 2 2
cos2
o b c aA
bc
Identify the sides and angle.
Ao = yo a = 26 b = 15 c = 13
2 2 215 13 26cos
2 15 13oA
Find the value of cosAo
cosAo = - 0.723The negative tells you the angle is obtuse.
Ao = yo =136.3oww
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S5 Int2
Finding Angles Finding Angles Using The Cosine RuleUsing The Cosine Rule
Works for any Triangle
What Goes In The Box ?What Goes In The Box ?
Calculate the unknown angles in the triangles below:
(1)
10m
7m5m Ao
Bo
(2) 12.7c
m
7.9cm
8.3cm
Ao =111.8o
Bo = 37.3o
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S5 Int2
12 Apr 202312 Apr 2023 Created by Mr. Lafferty Maths Dept.Created by Mr. Lafferty Maths Dept.
Now try Ex 13Ch8 (page 114)
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S5 Int2
Cosine Rule Cosine Rule
12 Apr 202312 Apr 2023 Created by Mr. Lafferty Maths Dept.Created by Mr. Lafferty Maths Dept.
Starter QuestionsStarter Questionsw
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2
1. A washing machine is reduced by 10%
in a sale. I t's sale price is £ 360.
What was the original price.
2. Factorise x - 7x +12
3. Find the missing angles.
S5 Int2
61o
12 Apr 202312 Apr 2023 Created by Mr. Lafferty Maths Dept.Created by Mr. Lafferty Maths Dept.ww
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1.1. Be able to recognise the Be able to recognise the correct trigonometric correct trigonometric formula to use to solve a formula to use to solve a problem involving problem involving triangles.triangles.
1. To use our knowledge gained so far to solve various trigonometry problems.
Mixed problemsMixed problemsS5 Int2
SOH CAH TOA
25o
15 mAD
The angle of elevation of the top of a building
measured from point A is 25o. At point D which is
15m closer to the building, the angle of elevation is
35o Calculate the height of the building.
T
B
Angle TDA =
145o
Angle DTA =
10o
o o
1525 10
TDSin Sin
o15 2536.5
10Sin
TD mSin
35o
36.5
o3536.5TB
Sin
o36.5 25 0. 93TB Sin m
180 – 35 = 145o
180 – 170 = 10o
sin sin sin
t d a
T D A
Exam Type Questions
A fishing boat leaves a harbour (H) and travels due East for 40 miles to a marker buoy (B). At B the boat turns left and sails for 24 miles to a lighthouse (L). It then returns to harbour, a distance of 57 miles.
(a) Make a sketch of the journey.
(b) Find the bearing of the lighthouse from the harbour. (nearest degree)
H40 miles
24 miles
B
L
57 miles
A
2 2 257 40 242 57 40
CosAx x
A 20.4o
90 0 020.4 7 oBearing
Exam Type Questions
A
The angle of elevation of the top of a column measured from point A, is 20o. The angle of elevation of the top of the statue is 25o. Find the height of the statue when the measurements are taken 50 m from its base
50 m
Angle BCA =
70o
Angle ACT = Angle ATC =
110o
65o
o 5020Cos
AC o
5020
ACCos
53.21 m
o o
53.215 65
TCSin Sin
o
53.21 5 (1 )
655.1
SinTC m dp
Sin
B
T
C
180 – 110 = 70o 180 – 70 = 110o 180 – 115 = 65o
20o
25o
5o
SOH CAH TOA
53.21 (2 )m dp
Exam Type Questions
sin sin sin
t d a
T D A
2 2 2
2b c a
CosAbc
An AWACS aircraft takes off from RAF Waddington (W) on a navigation exercise. It flies 530 miles North to a point (P) as shown, It then turns left and flies to a point (Q), 670 miles away. Finally it flies back to base, a distance of 520 miles.
Find the bearing of Q from point P.
2 2 2530 670 5202 530 670
CosPx x
48.7oP
180 22948.7 oBearing
P
670 miles
W
530 miles
Not to Scale
Q
520 miles
Exam Type Questions
12 Apr 202312 Apr 2023 Created by Mr. Lafferty Maths Dept.Created by Mr. Lafferty Maths Dept.
Now try Ex 14Ch8 (page 117)
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S5 Int2
Mixed Problems Mixed Problems
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