TEQ – Typical Exam Questions
J
Q
P
M
K
L
O
Given: JKLM is a parallelogram OLJO
OQOP Prove:
Statement Reason
2. Given
1. Given1. JKLM is a parallelogram
OLJO .2
21 .4
3. Opposite sides of a parallelogram are parallel
.3 MQLJPK
LOQJOP ΔΔ .6 ASAASA .6
.7 OQOP
43 .5
4. Parallel lines cut by a transversal form congruent alternate interior angles
5. Vertical angles are congruent
1
2
3
4
7. CPCTC
TEQ #1
DABC
BLDJ
ALCJ
Given: Parallelogram DEBK,
,
Prove:
C
J
L
D
B
K
E
A
Statement Reason1. Parallelogram
DEBK
DABC 2.
BLDJ .3
1. Given
2. Given
3. Given
5. Addition postulateJLBLJLDJ 5.
JBJLBL
DLJLDJ
6. 6. Partition postulate
JBDL 7. 7. Substitution postulate
4. Reflexive postulateJLJL 4.
.8 DKEB 8. Opposite sides of a parallelogram are parallel
21 .9 9. Parallel lines cut by a transversal form congruent alternate interior angles.
ΔALDJBΔ .10 C SASSAS .10
ALCJ 11. 11. CPCTC
Statement Reason
2. Given
3. Given
TEQ #3
6. Opposite sides of a parallelogram are both parallel and congruent
ACDF 2.
1. Given1. ABCD is a parallelogram
ABDCABDC and .6
ACEB 3.
anglesright
are 2 and 1 .4 4. Perpendicular segments form right angles
21 .5 5. All right angles are congruent
43 .7 7. Parallel lines cut by a transversal form congruent alternate interior angles
BEADFC ΔΔ .8 AASAAS .8
A
D C
B
1 2
4
3E
F
ACDF
Given: Parallelogram ABCD,
Prove: BEDF BEDF .9 CPCTC .9
Statement Reason
S
P Q
QRQ
PQRS amarallelogr :Given
P
P
2 to
congruentnot is 1 :Prove
PQRS amarallelogr 1. P 1. Given
TEQ #4
R QRQ 2. P 2. Given
21
3. 3. Assumption
4. PQRS is a rhombus 4. A parallelogram whose diagonal bisects an angle isa rhombus
5. 5. All sides of a rhombus are congruent
6.
6. Contradiction 2,5
Statement ReasonTEQ #5
2. Given
1. Given1. Rhombus ABCD
.3 EFDE 3. A midpoint divides a segment into two congruent parts
21 .4 4. Vertical angles are congruent
FEBDEC ΔΔ .7 ASAASA .7
.8 BFDC 8. CPCTC
43 .6 6. Parallel lines cut by a transversal form congruent alternate interior angles.
2. E is the midpoint of
.5 ABFDC 5. Opposite sides of a rhombus are parallel
.9 DADC 9. All sides of a rhombus are congruent
.10 BFAD 10. Substitution postulate
1
2
3
4
Statement Reason
TEQ #6
2. Given
1. Given1. ABDE is a parallelogram
DCAE .2
3. Opposite sides of a parallelogram are congruent
BDAE .3
4. Substitution postulateBDDC .4
5. A triangle with two congruent sides is isosceles
isosceles is .5 DBC
isosceles is :Prove DBC
Given: ABDE is a parallelogram
DCAE
Statement Reason
TEQ #7
2. Given
1. Given
2 1 .2
.3 ECAE 3. A segment bisector divides a segment into two congruent parts
7. Two lines cut by a transversal that form congruent alternate interior angles are parallel
.7 BCAD
CEBAED ΔΔ .5 ASAASA .5
.6 BCDA 6. CPCTC
A
D C
B
2
13
E
43 .4 4. Vertical angles are congruent
4
AC DB bisects .1
8. A quadrilateral that has one pair of opposite sides both parallel and congruent is a parallelogram
ramparallelog a is .8 ABCD
Statement Reason
TEQ #9
2. Given
1. Given
BEBD .2
3. AssumptionCA .3
4. Reflexive postulateBB .4
6. CPCTC
CBDABE .5
BCAB .1
ASA ASA .5
BEBD .6
CA .7 7. Contradiction 2,6
Statement Reason
TEQ #10
3. Opposite sides of a parallelogram are congruent
1. Given1. ABCD is a parallelogram
CBDA .3
CA .4 4. Opposite angles of a parallelogram are congruent
BCFDAE ΔΔ .5 SASSAS .5
Prove:
D
E
F
A
C
B
BCFDAE ΔΔ
Given: ABCD is a parallelogram
FCAE
2. GivenFCAE .2
Statement Reason
2. Given
1. Given1. ABCD is a parallelogram
.2 ACDE
BFCDEA ΔΔ .8 AASAAS .8
43 .7 7. Parallel lines cut by a transversal form congruent alternate interior angles
A
D C
B
12
4
3F
3. Given
anglesright
are 2 and 1 .4 4. Perpendicular segments form right angles
21 .5 5. All right angles are congruent
.9 FCAE 9. CPCTC
6. Opposite sides of a parallelogram are both congruent and parallel.
EACBF 3.
CBDACBDA , .6
FCAE :Prove
Statement Reason
S
P Q
Tat intersect RSand PQ
RS PQ:Given
RQand PSof
midpoint not the is T :Prove
RS PQ1. 1. Given
TEQ #8
R
Tat intersect RSand PQ2. 2. Given
3. PS and RQ
3. Assumption
4. 4. A midpoint divides a segment into two congruent parts.
5. 5. Vertical angles are congruent
6. 6.
T
7. 7. CPCTC8. 8. Contradiction 1,7
Top Related