Download - Shear Strength of Soil

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  • Shear Strength of SoilsCEL 610 Foundation Engineering

  • Strength of different materials

  • Shear failure of soilsSoils generally fail in shearAt failure, shear stress along the failure surface (mobilized shear resistance) reaches the shear strength.

  • Shear failure of soilsSoils generally fail in shear

  • Retaining wallShear failure of soilsAt failure, shear stress along the failure surface (mobilized shear resistance) reaches the shear strength.Soils generally fail in shear

  • Shear failure mechanismThe soil grains slide over each other along the failure surface.No crushing of individual grains.

  • Shear failure mechanismAt failure, shear stress along the failure surface () reaches the shear strength (f).

  • Mohr-Coulomb Failure Criterion(in terms of total stresses)f is the maximum shear stress the soil can take without failure, under normal stress of .

  • Mohr-Coulomb Failure Criterion(in terms of effective stresses)f is the maximum shear stress the soil can take without failure, under normal effective stress of .u = pore water pressure

  • Mohr-Coulomb Failure CriterionShear strength consists of two components: cohesive and frictional.

  • c and are measures of shear strength.Higher the values, higher the shear strength.

  • Mohr Circle of stressResolving forces in s and t directions,

  • Mohr Circle of stress

  • Mohr Circle of stress

  • Mohr Circles & Failure Envelope

  • Mohr Circles & Failure EnvelopecThe soil element does not fail if the Mohr circle is contained within the envelopeGL

  • Mohr Circles & Failure EnvelopeYcGL

  • sOrientation of Failure PlanefFailure envelope

  • Mohr circles in terms of total & effective stresses=

  • Failure envelopes in terms of total & effective stresses=If X is on failure

  • Mohr Coulomb failure criterion with Mohr circle of stress

  • Mohr Coulomb failure criterion with Mohr circle of stress

  • Other laboratory tests include,Direct simple shear test, torsional ring shear test, plane strain triaxial test, laboratory vane shear test, laboratory fall cone testDetermination of shear strength parameters of soils (c, f or c, f)

  • Laboratory testsField conditions

  • Laboratory testsSimulating field conditions in the laboratoryStep 2Apply the corresponding field stress conditions

  • Direct shear testSchematic diagram of the direct shear apparatus

  • Direct shear testPreparation of a sand specimenDirect shear test is most suitable for consolidated drained tests specially on granular soils (e.g.: sand) or stiff clays

  • Direct shear testPreparation of a sand specimen

  • Direct shear testTest procedure

  • Direct shear testStep 2: Lower box is subjected to a horizontal displacement at a constant rate

  • Direct shear test

  • Direct shear testAnalysis of test resultsNote: Cross-sectional area of the sample changes with the horizontal displacement

  • Direct shear tests on sandsStress-strain relationship

  • Direct shear tests on sandsHow to determine strength parameters c and f

  • Direct shear tests on sandsSand is cohesionless hence c = 0Direct shear tests are drained and pore water pressures are dissipated, hence u = 0Therefore, f = f and c = c = 0

  • Direct shear tests on claysFailure envelopes for clay from drained direct shear testsIn case of clay, horizontal displacement should be applied at a very slow rate to allow dissipation of pore water pressure (therefore, one test would take several days to finish)

  • Interface tests on direct shear apparatusIn many foundation design problems and retaining wall problems, it is required to determine the angle of internal friction between soil and the structural material (concrete, steel or wood)

  • Triaxial Shear Test

  • Triaxial Shear TestSpecimen preparation (undisturbed sample)

  • Triaxial Shear TestSpecimen preparation (undisturbed sample)

  • Triaxial Shear TestSpecimen preparation (undisturbed sample)

  • Triaxial Shear TestSpecimen preparation (undisturbed sample)

  • Types of Triaxial TestsIs the drainage valve open?Is the drainage valve open?

  • Types of Triaxial Tests

  • Consolidated- drained test (CD Test)Step 1: At the end of consolidationStep 2: During axial stress increaseStep 3: At failure

  • Deviator stress (q or Dsd) = s1 s3Consolidated- drained test (CD Test)

  • Volume change of sample during consolidationConsolidated- drained test (CD Test)

  • Stress-strain relationship during shearingConsolidated- drained test (CD Test)

  • CD tests How to determine strength parameters c and f

  • CD tests Since u = 0 in CD tests, s = sTherefore, c = c and f = f cd and fd are used to denote them

  • CD tests Failure envelopesFor sand and NC Clay, cd = 0Therefore, one CD test would be sufficient to determine fd of sand or NC clay

  • CD tests Failure envelopesFor OC Clay, cd 0

  • Some practical applications of CD analysis for clays t = in situ drained shear strength1. Embankment constructed very slowly, in layers over a soft clay deposit

  • Some practical applications of CD analysis for clays 2. Earth dam with steady state seepage

  • Some practical applications of CD analysis for clays 3. Excavation or natural slope in clayt = In situ drained shear strength Note: CD test simulates the long term condition in the field. Thus, cd and fd should be used to evaluate the long term behavior of soils

  • Consolidated- Undrained test (CU Test)Step 1: At the end of consolidationStep 2: During axial stress increaseStep 3: At failure

  • Volume change of sample during consolidationConsolidated- Undrained test (CU Test)

  • Stress-strain relationship during shearingConsolidated- Undrained test (CU Test)

  • CU tests How to determine strength parameters c and f

  • CU tests How to determine strength parameters c and ffcuMohr Coulomb failure envelope in terms of total stressesccuEffective stresses at failureuf

  • CU tests Shear strength parameters in terms of total stresses are ccu and fcuShear strength parameters in terms of effective stresses are c and f

    c = cd and f = fd

  • CU tests Failure envelopesFor sand and NC Clay, ccu and c = 0Therefore, one CU test would be sufficient to determine fcu and f(= fd) of sand or NC clay

  • Some practical applications of CU analysis for clays t = in situ undrained shear strength1. Embankment constructed rapidly over a soft clay deposit

  • Some practical applications of CU analysis for clays 2. Rapid drawdown behind an earth damt = Undrained shear strength of clay coreCore

  • Some practical applications of CU analysis for clays 3. Rapid construction of an embankment on a natural slope Note: Total stress parameters from CU test (ccu and fcu) can be used for stability problems where, Soil have become fully consolidated and are at equilibrium with the existing stress state; Then for some reason additional stresses are applied quickly with no drainage occurring

  • Unconsolidated- Undrained test (UU Test)Data analysisInitial volume of the sample = A0 H0Volume of the sample during shearing = A HSince the test is conducted under undrained condition,A H = A0 H0A (H0 DH) = A0 H0A (1 DH/H0) = A0

  • Unconsolidated- Undrained test (UU Test)Step 1: Immediately after sampling=+Step 2: After application of hydrostatic cell pressureDuc = B Ds3Note: If soil is fully saturated, then B = 1 (hence, Duc = Ds3)

  • Unconsolidated- Undrained test (UU Test)Step 3: During application of axial loadDud = ABDsd=+

  • Unconsolidated- Undrained test (UU Test)Combining steps 2 and 3,Du = Duc + DudTotal pore water pressure increment at any stage, DuDu = B [Ds3 + ADsd]

  • Unconsolidated- Undrained test (UU Test)Step 1: Immediately after samplingStep 2: After application of hydrostatic cell pressureStep 3: During application of axial loadStep 3: At failure

  • Unconsolidated- Undrained test (UU Test)Mohr circle in terms of effective stresses do not depend on the cell pressure. Therefore, we get only one Mohr circle in terms of effective stress for different cell pressures

  • Unconsolidated- Undrained test (UU Test)Mohr circles in terms of total stresses

  • Unconsolidated- Undrained test (UU Test)Effect of degree of saturation on failure envelopeS < 100%S > 100%

  • Some practical applications of UU analysis for clays t = in situ undrained shear strength1. Embankment constructed rapidly over a soft clay deposit

  • Some practical applications of UU analysis for clays 2. Large earth dam constructed rapidly with no change in water content of soft clay

  • Some practical applications of UU analysis for clays 3. Footing placed rapidly on clay deposit Note: UU test simulates the short term condition in the field. Thus, cu can be used to analyze the short term behavior of soils

  • Unconfined Compression Test (UC Test)s1 = sVC + Ds s3 = 0 Confining pressure is zero in the UC test

  • Unconfined Compression Test (UC Test)f = 1/2 = qu/2 = cu

  • Various correlations for shear strengthFor NC clays, the undrained shear strength (cu) increases with the effective overburden pressure, s0For OC clays, the following relationship is approximately trueFor NC clays, the effective friction angle (f) is related to PI as follows

  • Shear strength of partially saturated soilsIn the previous sections, we were discussing the shear strength of saturated soils. However, in most of the cases, we will encounter unsaturated soilsPore water pressure can be negative in unsaturated soils

  • Shear strength of partially saturated soilsBishop (1959) proposed shear strength equation for unsaturated soils as followsWhere, sn ua = Net normal stressua uw = Matric suction= a parameter depending on the degree of saturation (c = 1 for fully saturated soils and 0 for dry soils) Fredlund et al (1978) modified the above relationship as followsWhere, tanfb = Rate of increase of shear strength with matric suction

  • Shear strength of partially saturated soilsTherefore, strength of unsaturated soils is much higher than the strength of saturated soils due to matric suction

  • How it become possible build a sand castle

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