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http://www.ec.it-hiroshima.ac.jp/jcd/

1)

1/10

iv

2)

(1)

(a) (b) 2

(a)

0.7 0.8

(b)

2 12.

(1)

v

(2)

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(3)

(4)

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1.

0.2 0.2 %

0.5 0.5 %

1 1.0 % 0.5

1.5 1.5 %

2.5 2.5 %

2/3

3)

(a) precision

(b) accuracy

vi

2

4) 2 1)

0.1 V 1 V 10 V 3 0.8 V

1 V 10 V 2

: : : :

: : : :

2

1-1

1.

1.

2. 2.1 (WDM Wavelength Division Multiplexing)

IEEE1394

2 12000

2.2

(a)DIM-BLE

510nm

510nm( )

1(b)

3 2

2000

1-2

2.3

USB2000CCD

CCD 2048

3. 3.1

3.2 (LED) LED LED

(LD) 3.3 DIM-RED DIM-BLE

3.4 DIM-RED( ) DIM-BLE( )

DIM-REDDIM-BLE 3)

3.5 ( SH4001) 10m

4. 4.1 ( )

4.2 LED LED LED LD

( ) 4.3 LD LED

4.4 3.3 3.4 4.5 3.4 3.3

LED /

CD )

2-1

2. MATLAB/Simulink

1. RL MATLAB/Simulink

MATLAB/Simulink MATLAB

2. MATLAB/Simulink

2.1

42 52

2 5 2 4 = 10 8 = 2 --------------------------------------------------------------------------------------------------------------------

>> A = [2 2 ; 4 5]; >> det(A) ans =

2

[ ] det(A)

2-2

)

Hint I 4~6 1~3

1

A1

A

1A

2-3

2.2

i(t)(t)

(t) = L i(t)

V(t) = dttd )(

(t)

V(t) = Ldttdi )(

i(t)

= i(t) + L dttdi )(

i(t) = dttRiEL

))((1

2-4

Step Mux

Step

Ri(t) integrator

V=IR

.3 RC

RC

Hint ) RC q (t) = C v (t)

i (t)=dttdq )(

2-5

RLC

Hint ) RLC

E = Ldttdi )( + Ri(t) +

C1 dtti )(

2-6

3. 3.1

3.2

3.3 MATLAB

MATLAB

3.4

T=0

3.4- 1 -

. . 1.

2.

2.1 a.

( )

b.

( ) c.

( 10)

3.4- 2 -

d. V V

( 11 12)

3.4- 3 -

e. (AND) ( 13 14) Y=A B ” ” ” ” ” ” f. (OR) ( 15 16) Y=A B ” ” ” ” ” ” g. (NOT) ( 17 18) h. ( 19 21) RC

3.4- 4 -

i. 22

( ) CR

CR ( 23 24)

j. CR

CR( 25 26)

k.

( 27 28)

3.4- 5 -

l.

( 29 30) 3.

3.1

a.

CR b.

CR c.

d.

3.4- 6 -

e. (AND) ”0”,”1”

f. (OR) ”0”,”1”

g. (NOT) ”0”,”1”

h. CR

i. 2 2 (CR)

j. 2

k. 2 2 (RR)

l.

3.2 a.

b.

3.3 .

. 4.

(1)

(2)

(3) (4) (5) (6)

(2) 1981 1989 1987 (2) 1988

5-1

IEEE1394

IEEE1394

AV AVDV b

MPEG2 MD CDIEEE1394 1 125 s 1

ACK

DV CCD

M DV 1MPEG

IEEE1394

5-2

IEEE1394

IEEE1394

22

high low

2 XOR1 0 1 0 1 0

125

sec

CH

1

CH

2

CH

N

Long

Short

5-3

IEEE1394 8B10B 8 5 3

1 5B 6B 3B 4B10 3

1 0 2 8B10B0 1

5 0 10

1 0 1 00 1

1 0 1 1 0 0 0 1

1011 001

5-4

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4 DVC PC IEEE1394

2POF 2 DVC PC6

IEEE1394 1

2.1 4 IEEE1394 11

2.3CH CH2 2

100Mbps

8B 10B 2.4 8B 10B 100Mbps

8B 10B8B 10B

1 0 0 1 1 0 1 0

8 80ns

3 5

5B6B 3B4B 6 4

1 0 1 0 1 1 0 1 1 0

10 80ns

5-5

8B 10Bm n

6-1

1

2

4

1 2 Web 3 E-Mail 4

6-2

PC jikken-vineWireshark

UC RFIDucode

2.1

Wireshark Wireshark Network Analyzer

Wireshark

Wireshark jikken OK

Wireshark

Start

6-3

Wireshark

6-4

2.2

Wireshark

Ethereal

1

Continue without Saving

6-5

No.

Time 0

Source

Destination

Protocol

Info

2

3 3.1

LAN 2Wireshark

Destination

3.2

WWW Web

1 Wireshark 2 FireFox

Web 3

Web

URL http://www.google.co.jp Web

6-6

3.3 [email protected]

PC

1 [email protected]

2 Wireshark 3 Sylpheed 4 Sylpheed 5

3.4

UC RFID ucode

ucode

6-7

ucode

4

7.8- 1 -

7.8. C 1. 1 C

2

2. 2.1 1

100”question1.cpp”

//question1.cpp //saikoro #include #include #define count 100 void main(void) { int z,i,n[7]; double t; // for(i=1; i

7.8- 2 -

2.2 2

10×10 0 9 n[k] 10×10” question2.cpp”

k n[k] 0 n[0] 1 n[1] 2 : : : : : 9 n[9]

//question2.cpp //histogram #include #include void main(void) { int i,j,k,n[10]; int v[10][10]; // for(i=0;i

7.8- 3 -

2.3 3

10 i number[i]=100+i data[i]” question3.cpp”

//question3.cpp //Bubble_Sort #include #include #include #define MAX 10 void sort(int data[], int number[], int n); void main(void) { int data[MAX]; int number[MAX]; int i; for(i=0;i

7.8- 4 -

printf(“%8d%6d%6d¥n”, i, number[i], data[i]); }

sort(data, number,MAX); printf(“ ¥n ¥n”);

for(i=0;i

7.8- 5 -

CPU 2 “1 “0

2

3.5 contour

4 44 -1 S S R R

0 -1 0

-1 4 -1

0 -1 0

3.6 halftone

1

1 1 1

1 2 1

1 1 1

3.7 median

3×3 9 9 5

3.8 BMP

bitmap image / bitmap graphicspixel

RGB

7.8- 6 -

x

B G R B G R

B G R B G R

B G R B G R

B G R B G R

B G R B G R

4. 4.1 1

visualC++ 1 3

”JPEG” ” .jpg” ”.JPG”

2

2 2 USB 4.2 2

1

1

” ” ”in” ”24 ”

7.8- 7 -

”in” ”4_1 histogram” ”4_2 inverse” ”4_3 monochrome” ”4_4 bi-level” ”4_5 contour” ”4_6 smooth” 2

1 ”in_1” 1 ”in_2” 4_1 histogram

c”in” ”histogram”

”histogram”

4_2 inverse c

”in” ”inverse”

4_3 monochrome

c unsigned char Y; for(y=1;y

7.8- 8 -

c for(y=1;y

7.8- 9 -

4_7 median

c

”in_1” ”median_1” ”in_2” ”median_2”

5.

9.10-1

9. 10. LSI

ASIC(Application Specific integrated Circuit) ASIC IC

LSI ASIC IC

CAD(computer aided design)MOS IC

MOS MOS IC MOS MOS MOS FET field effect transistor FET

MOS metal oxide semiconductorMOS FET Si

FET +S

D GA Si IC

Si Al FET

9.10-2

MOS FET MOS FET ID-VDS

linear region saturation regionVT, threshold

voltage

VDS VGS VT

ID = W L COX ((VGS VT) VDS 1/2 VDS2

VDS VGS VT 3

ID = W L COX (VGS VT)2 4

9.10-3

2.4 CMOS pMOS nMOS

CMOS CMOS OFF

3 CMOS 2.5 inverter 2NAND

inverter

2NAND

pMOS

nMOS

DDV ”H” pMOS OFF

nMOS ON”L”

”L” pMOS ON

nMOS OFF”H”

DDV

DDV

A

B

”H” pMOS OFFnMOS ON

”L”

”L” pMOS ONnMOS OFF

”H”

A ”H” B ”H” A pMOS OFFnMOS ON B pMOS OFF nMOSON ”L”

A ”H” B ”L” A pMOS OFFnMOS ON B pMOS ON nMOSOFF ”H”

A ”L” B ”H” A pMOS ONnMOS OFF B pMOS OFF nMOS

ON ”H” A ”L” B ”L” A pMOS ON

nMOS OFF B pMOS ON nMOSOFF ”H”

9.10-4

2.6 invereter

inverter 2.7 Inverter 2NAND

7 inverter 8 2NAND

9.10-5

3. Alpha-SX

Alpha-SXSmartSpice

4. 4.1 SmartSpice 4.2 inverter 4.3 2NAND 5. 5.1 2NOR 5.2 2NAND nMOS 5.3

MOS-IC FET

11-1

11.

1.

12

2. Al Cu “ ”

Pa Pascal 1 Pa 1 m2 1 N

P

= (1)

R 8.31451 J/mol K V [m3] T [K]

S [l/min]

(1) t

= (2)

t [s] P0 [Pa]

Si

1×10-5 Pa

Al Cu

nm m

10-3 Pa

2.1

A[m2]

Mv [kg/s]( A8 Hertz-Knudsen )

= 4.38 × 10 [kg/s] (3)

11-2

mu 1/NA NA 6.022×1023 mol 1 ps T

M

d

dm

= A (4)

r

vd [m/s] (3)

= A (5)

[kg/m3] t

d

= = A (6)

A Vc [m3]

= (7)

2.2

AT 11.2

c

= (8)

11.1

11-3

tq

= 2 (9)

=2.65×103

kg/m3 G =29.5 GPa

= (10)

(9), (10) (8)

= = (11)

N

= = 1670 [Hz·m] (12)

(11)

d = = (13)

(13) r dx

= (14)

r dx (14) dtq (13)

d = (15)

11.2

11-4

(15)

(15) dx

r1, r2 d

= = | | (16)

3.

11.3 Cu

11.3

11-5

(1)

(2)

(3)

(4) 0.1 Pa

4. (1) (1) (2)

(2)

(3)

(4) 300 K N

(5)

A

1.1

JIS

1×10-13 Torr 1.3×10-11 Pa

1×10-10 Torr 1.3×10-8 Pa

1.2

1 Torr = 133.3 Pa [N/m2] =[Pa]

1 atm = 760 Torr [=760 mmHg]

1 Pa = 0.75×10-2 Torr

1982 Pascal

10-3 Torr = 1.33×10-1 Pa

10-6 Torr = 1.33×10-4 Pa

1.3

Maxwell-Boltzmann

11-6

(1)

n P T

= (A1)

P [Torr] n [cm-3]

= 9.66 × 10 10 [ /cm3]

Table 1 P n 300K

P [Torr] n [ /cm3]

760 2.4×1019

10-1 3.2×1015

10-2 3.2×1014

10-3 3.2×1013

10-4 3.2×1012

10-5 3.2×1011

10-6 3.2×1010

10-7 3.2×109

10-13 3.2×103

Boyle Charles' law

= =

R 8.314 J/ K mol

M = =

m 1 NA

= = 6.022 × 10 mol

NA 1 mol

(Loschmidt's number : NL) 0 1

1mol NA =

11-7

6.022×1023 mol-1 Vm = 22.4×10 3 m3mol-1

NL = 2.69×1025 m-3

=

= =

= . / . × = 1.38 × 10 = : Boltzmann constant

= =

n n = / V

= (A2)

(2)

c = = 146 [m/s] (A3)

c = = 2.5 × 10 [m2/s2] (A4)

M

Table 2

M [m/s] @ 300 K [m/s] @ 2000 K H2 2.016 1.8×103 4.6×103

N2 28.01 4.8×102 1.2×103

O2 32.00 4.5×102 1.2×103

Al 26.98 4.9×102 1.3×103

Ag 107.9 2.4×102 6.3×102

Au 197.0 1.8×102 4.7×102

T M T M

100 m/s 1 km/

11-8

= ( ) = 4 2/

exp

= (A5)

= = (A6)

cT

(3)

NS [1/cm s]

= c (A7)

P [Torr] M

= 3.52 × 10 [ / cm2 s] (A8)

NS

Table 3

M T [K] P [Torr] NS [ / cm2 s]

H2 2.016 300 10-5 14.3×1015

N2 28.01 300 10-5 3.84×1015 O2 32.00 300 10-5 3.59×1015

28.98 300 10-5 3.78×1015 Ar 39.95 300 10-5 3.22×1015

P P = 10-5 Torr 1015 /cm2

s

P

12-1

12. Hall

1.

Hall

11

B

2. J E J E

= (1)

r =1/

1 S l I (1)

= (2)

(2)

= = =

= (3)

R

r R

1 R 2 R

12-2

l S

1 R

R

2

3. 3 x J z

B y

-y

y EH -y

x

Hall effect hole

Hall 1879 Edwin Herbert Hall

3

q n

v J

= (4)

= (5)

x (5)

EH

+ = 0 (6)

12-3

(5) (6) EH

= (7)

(1)

= = (8)

= 1/

J B

q = -e q = +e RH

n RH

4. 4.1 B

4

4 l0 B

12-4

B = (9)

=

(9) I B

(1)

(2) I 0 A 0.5 A 4 A

B

(3) 4 A 0 A 0.5 A B

(4)

4.2 r Hall

(1) AB 20, 40, 100 mA CD

(2)

CD

5

A, B

C, D

D, E

12-5

4.3 (8) w

= (10)

w (10) I = wdJ

= (11) I VH B

m

= (12)

(1)

(2) 100 mA

(3) (0, 1, … , 5 A) VH

(4) 4.1

(5)

RH

5. (1) B (9)

(2) (11)

(3) RS r

(4) n (5) = E = 1 V/m v

実験実験Cテキスト目次諸注意CD１. 光通信特性２.MATLABSimulinkを用いた基礎問題の解析3.4. パルス回路５. マルチメディア光コミュニケーションシステム６. インターネットワーキングシステム7.8. c言語による画像処理1.目的2.基本練演習2.1練習問題12.2練習問題22.3練習問題3

3.理論3.1 輝度ヒストグラム（histogram）3.2 輝度反転（inverse）3.3 モノクロ（monochrome）3.4 2値化表示（bi-level）3.5 輪郭強調（contour）3.6 平滑化（halftone）3.7 メディアンフィルタ（median）3.8 BMP形式

4.実験方法4.1第1週目の実験4.2第2週目の実験

5.検討

9.10. LSI設計の基本11. 真空蒸着による金属薄膜の作製と膜厚測定12. 金属薄膜の電気伝導率とホール係数（Hall効果）

Download - 広島工業大学 電子情報工学科ec.it-hiroshima.ac.jp/jcd/JikkenC2017.pdf · >Ó¼(Kh Ù >Ó (DL Ù >Ó MÅ(rÁmö&5 ! >Ó &AOdf N 8 Û 96&5 ! N 8 â)©¾

Download - 広島工業大学電子情報工学科ec.it-hiroshima.ac.jp/jcd/JikkenC2017.pdf · >Ó¼(Kh Ù >Ó (DL Ù >Ó MÅ(rÁmö&5 ! >Ó &AOdf N 8 Û 96&5 ! N 8 â)©¾