60 cm
30 cm
40 cm
30 cm
MMEdEd
NNEdEd VVEdEd
ZEd
DEd
Vij,Ed
Vij,Ed
Vfr,Ed
VEd, NEd, MEd
dh c
e 1
1
z =
0.9
· d
© 2014 HALFEN · TI-HUC 13-E · www.halfen.com
fig.: standard connection→ page 10 Technical Product Information HALFEN HUC Universal Connection
Design example: connection between steelwork and a concrete column using the HALFEN HSC-B Concrete Steel Connection References:
These static calculations are according to DIN EN 1992-1-1, DIN EN 1993-1-1 and DIN EN 1993-1-8. References to formulae refer to the Technical Product Information: “HALFEN HUC Universal connection” and “HALFEN HSC Stud Connector” as well as to the national technical approvals Z-21.8-1974 HSC-B Concrete Steel connection and Z-21.8-1973 HALFEN HSC Stud Connector.
Concrete C25/30B500Bbcol = 40 cm, hcol = 60 cmMain reinforcement: 12 Ø 25 mmStirrup reinforcement: dsw = 12 mm, s = 8 cmEnvironmental classification: XC1Concrete cover: cv = 2.5 cmFace plate dimensions: bc = 30 cm, hc = 30 cm
Forces: predominantly staticMEd = 160 kNmNEd = 120 kNVEd = 700 kN(Internal static forces as present between positioning and face plate – design deter-mining cross-section 1-1)Positioning plate is installed flush with the formwork
All publications referred to in this example are available for download in PDF format at www.halfen.com
Specifications
Fig.: positioning plate flush with the formwork → page 6 Technical Product Information HALFEN HUC Universal Connection
1 design cross-section 1-1
Face plate
3 mm positioning plate
Gravity axis
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Design Example
HALFEN HUC UNIVERSAL CONNECTION
2
friction coefficients μinf μsup
frictional component considered 0.1
0.2frictional component not considered 0
for verification in ULS
Table: page 10 Technical Product Information HALFEN HUC Universal Connection (Z-21.8-1974, Tab. 2)
Tensile force
ZEd = z
MEd + NEd ⋅ (0.5 · hc - 0.1 · d)
z
Assumption: edge distance of the upper bolt row e1 = 50 mmd = hc – e1 = 30.0 cm – 5.0 cm = 25.0 cmz = 0.9 ⋅ d = 0.9 ⋅ 25.0 cm = 22.5 cm
ZEd = 16000 kNcm
22.5 cm + 120 kN ·
(0.5 ⋅ 30 cm – 0.5 ⋅ 25 cm)22.5 cm
= 777.8 kN
Compressive force
DEd = z
MEd - NEd ⋅ z
(d - 0.5 ⋅ hc)
= 22.5 cm
16000 kNcm - 120 kN ⋅
22.5 cm(25 cm - 0.5 ⋅ 30 cm)
= 657.8 kN
Frictional component
Vfr,Ed,inf = DEd ⋅ μinf
Assumption:Frictional component will be considered
Vfr,Ed,inf = 657.8 kN ⋅ 0.1 = 65.8 kN(for verification of bolts, sleeves, local concrete failure)
Vfr,Ed,sup = DEd ⋅ μsup = 657.8 kN ⋅ 0.2 = 131.6 kN(for verification of concrete edge failure)
→ page 10 Technical Product Information HALFEN HUC Universal Connection (Z-21.8-1974, eq. 4)
→ page 10 Technical Product Information HALFEN HUC Universal Connection (Z-21.8-1974, eq. 3b)
→ page 10 Technical Product Information HALFEN HUC Universal Connection (Z-21.8-1974, appendix 3, pg. 3)
0
0
20
20
40
60
80
100
120
140
160
180
200
220
240
40 60 80 100 120 140 160 180 200 220 240 260 280 300 320
M 27 10.9
M 27 5.6
M 27 4.6
HSC-B 25
Nij,
Rd [
kN]
Vij,Rd [kN]
M 27 8.8
Design Example
HALFEN HUC UNIVERSAL CONNECTION
3© 2014 HALFEN · TI-HUC 13-E · www.halfen.com
Tension flange bolts:
Maximum tension loadmax ZEd = 213.4 kN
ntie,req = Nij,Rd
ZEd = 213.4 kN777.8 kN
= 3.6
Selected: ntie = 4
Stresses to tension flange bolts:
Nij,Ed = ntie
ZEd = 4
777.8 kN = 194.4 kN
Remaining shear force resistance:
Vij,Rd ≈ 120 kN
Total number of bolts:
ntot,req = Vij,Rd
VEd − Vfr,Ed,inf = 120 kN
700 kN − 65.8 kN = 5.3
Selected: ntot = 6
Shear stresses to bolts:
Vij,Ed = ntot
VEd − Vfr,Ed,inf = 6
700 kN − 65.8 kN = 105.7 kN
Strut: nstrut = ntot − ntie = 6 − 4 = 2
→ page 12 Technical Product Informa- tion HALFEN HUC Universal Con- nection “Pre-selection”
→ page 11 Technical Product Informa- tion HALFEN HUC Universal Con- nection (Z-21.8-1974, eq. 5 and 10)
→ page 11 Technical Product Informa- tion HALFEN HUC Universal Con- nection (Z-21.8-1974, eq. 6 and 11)
= yield force; reinforcement steel Fyd,25, see graph
(Taken from graph)
Determination of required number of sleeves and boltsGiven: HSC-B 25, bolts M 27, strength class 8.8
Fyd, 25 = 213.4 kN
90 (> 86)
70 (> 66) 80 (> 66)
220 (> 66)
70 (> 66)40
40
50 5040
50u
200
u = 50 mm (> min u = 36 mm)
40
[mm]
dL
u
aij
aij
aij
aij,edge
aij,edge
© 2014 HALFEN · TI-HUC 13-E · www.halfen.com
Design Example
HALFEN HUC UNIVERSAL CONNECTION
4
Dimensions, geometric regulations
HSC-B Bolt minimal distances hole diam.
ds[mm] [-]
aij,edge[mm]
aij[mm]
u[mm]
max dL[mm]
12 M12 40 30 21 13
16 M16 50 38 21 17
20 M20 63 48 27 21
25 M27 86 66 36 28.5
Fig.: page 9 Technical Product Informa-tion HALFEN HUC Universal Con-nection “Design of the hole pattern, minimum distances”
Hole pattern design
Except for the lower protrusion “u” the minimum and maximum distances of the bolts at the steelwork member have to be checked separately.
Table: page 9 Technical Product Infor-mation HALFEN HUC Universal Connec-tion (Z-21.8-1974, appendix 2)
face plate
Design Example
HALFEN HUC UNIVERSAL CONNECTION
5© 2014 HALFEN · TI-HUC 13-E · www.halfen.com
Stress areas of the bolts
bolt size Asp [mm²]
M 12 0.84
M 16 1.57
M 20 2.45
M 27 4.59
bolt resistances
strength fy,b,k [kN/cm²]
fu,b,k[kN/cm²]
αv
4.6 24 40 0.60
5.6 30 50 0.60
8.8 64 80 0.60
10.9 90 100 0.50
Verification for the bolts
Nij,Ed = 194.4 kN (per bolt)
Vij,Ed = 105.7 kN (per bolt)
Nij,Rd = k2 ⋅ m2
fub ⋅ ASp = 0.9 ⋅ 1.25
80 kN/cm² ⋅ 4.59 cm² = 264.4 kN
Vij,Rd = v ⋅ m2
fub ⋅ ASp = 0.60 ⋅ 1.25
80 kN/cm² ⋅ 4.59 cm² = 176.3 kN
→ page 11 Technical Product Information HALFEN HUC Universal connection (Z-21.8-1974, eq. 8)
Nij,Rd
Nij,Ed = 264.4 kN194.4 kN
= 0.74
Vij,Rd
Vij,Ed = 176.3 kN105.7 kN
= 0.60
Nij,Rd
Nij,Ed
2
+ Vij,Rd
Vij,Ed
2
= 0.742 + 0.602 = 0.91
Table: page 11 Technical Product Information HALFEN HUC Universal Connection
Table: page 11 Technical Product Information HALFEN HUC Universal Connection
→ page 11 Technical Product Informa- tion HALFEN HUC Universal Con- nection (Z-21.8-1974, eq. 7)
→ page 11 Technical Product Informa- tion HALFEN HUC Universal Con- nection (Z-21.8-1974, eq. 9)
0 20 40 60 80 100 120 140 160 180 200 220 240
0
20
40
60
80
100
120
140
160
180
200
220
240
260 280 300 320
Nij,
Rd [
kN]
Vij,Rd [kN]
HSC-B 25
HSC-B 20
HSC-B 16HSC-B 12
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Design Example
HALFEN HUC UNIVERSAL CONNECTION
6
Sleeve verification
Nij,Ed = 194.4 kN (per sleeve)Vij,Ed = 105.7 kN (per sleeve)
Verification: values pair (Vij,Ed, Nij,Ed) is between diameter-specific curve limit (given: HSC-B 25) and coordinate axes, see chart
Verification of the reinforcement steel
Nij,Ed = 194.4 kN (force per bar)
Fyd,25 = γs
fyk ⋅ As = 1.15
50 kN/cm² ⋅
4π
⋅ (2.5 cm)2
= 213.4 kN > 194.4 kN = Nij,Ed
Please note: anchorage has to be verified separately → see page 10
→ page 11 Technical Product Informa- tion HALFEN HUC Universal Con- nection (Z-21.8-1974, appendix 3, page 5, 6 )
→ Z-21.8-1974, diagram 1(105.7 kN, 194.4 kN)
xb
Design Example
HALFEN HUC UNIVERSAL CONNECTION
7© 2014 HALFEN · TI-HUC 13-E · www.halfen.com
Dimensions HSC-B
LM
Sw
ds
ds [mm] Sw [mm] LM [mm]
12 19 36
16 24 48
20 30 60
25 41 75
Localised concrete failure
Vij,Ed = 105.7 kN (per sleeve)
Resistance per sleeve Vij,loc,Rd = c
1.44 ⋅ Sw
2 ⋅ (fc ⋅ Rp,0.2)0.5
Sw = 41 mm (see table)
fck = 25 N/mm² ≤ 50 N/mm²
Rp,0,2 = 440 N/mm²
Vij,c,loc,Rd = 1.5
1.44 ⋅ 412 ⋅ (25 ⋅ 440)0,5 = 169253 N = 169.3 kN
Vij,loc,Rd
Vij,Ed = 169.3105.7
= 0.62 < 1.0
Concrete edge failure
Actions
Vconc,Ed = 2
VEd + Vfr,Ed,sup = 2
700 kN + 131.6 kN = 415.8 kN
Resistances
Vconc,Rd = 15 ⋅ cα
⋅ bc ⋅ LM ⋅ fck0.25
bc = 300 mm (Face plate width)
LM = 75 mm (see table page 4)
fck = 25 N/mm² ≤ 50 N/mm²
Vconc,Rd = 15 ⋅ 1.50.85
⋅ 300 ⋅ 75 ⋅ 250.25 = 427648 N = 427.6 kN
Vconc,Rd
Vconc,Ed = 427.6415.8
= 0.97 < 1.0
→ page 13 Technical Product Informa- tion HALFEN HUC Universal Con- nection (Z-21.8-1974, eq. 12)
→ page 13 Technical Product Informa- tion HALFEN HUC Universal Con- nection (Z-21.8-1974, eq. 14, 15)
Fig.: page 13 Technical Product Information HALFEN HUC Universal Connection
Fig.: page 13 Technical Product Information HALFEN HUC Universal Connection
Table: pg. 13 Technical Product Informa-tion HALFEN HUC Universal Connection
55
1010
Asl,bet
Asl,edge
aaijij
bbcolcol
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Design Example
HALFEN HUC UNIVERSAL CONNECTION
8
Primary reinforcement preventing tensile splitting
Asw,1 = 0.25 ⋅ ntot
VEd ⋅ 1 − aij,max
Sw ⋅ fyk
1.15
VEd = 700.0 kN ntot = 6 (total number of sleeves) Sw = 41 mm (wrench size see table page 7) aij,max = maximum distance between two sleeves in one rowTie: aij,max = 80 mm (upper position)Strut: aij,max = 220 mm (lower position)
Tie:
Asw,1,tie = 0.25 ⋅ 6
700.0 kN ⋅ 1 −
80 mm41 mm
⋅ 50.0 kN/cm²
1.15 = 0.33 cm²
Strut:
Asw,1,strut = 0.25 ⋅ 6
700.0 kN ⋅ 1 −
220 mm41 mm
⋅ 50.0 kN/cm²
1.15 = 0.54 cm²
The primary reinforcement is selected together with the secondary reinforcement for prevention of tensile splitting.
Secondary reinforcement preventing tensile splitting
Tie:
Asw,2,tie = 0.25 ⋅ 2
VEd ⋅ 1 − bcol
∑ aij ⋅ fyk
1.15
VEd = 700.0 kN ∑aij = 2 ⋅ 70 mm + 80 mm = 220 mm bcol = 400 mm fyk = 50 kN/cm²
Asw,2,tie = 0.25 ⋅ 2
700.0 kN ⋅ 1 −
400 mm220 mm
⋅ 50 kN/cm²
1.15 = 0.91 cm²
Strut:
Asw,2,strut = 0.25 ⋅ Vconc,Ed ⋅ 1 − bcol
∑ aij ⋅ fyk
1.15
Vconc,Ed = 415.8 kN ∑aij = 220 mm
Asw,2,strut = 0.25 ⋅ 415.8 kN ⋅ 1 − 400 mm220 mm
⋅ 50 kN/cm²
1.15 = 1.08 cm²
Min
mum
con
stru
ctio
nal d
ista
nces
[cm
]
→ page 14 Technical Product Informa- tion HALFEN HUC Universal Con- nection (Z-21.8-1974, eq. 17, 18)
Fig.: page 14 Technical Product Information HALFEN HUC Universal Connection “minimum constructional distances”
→ page 14 Technical Product Informa- tion HALFEN HUC Universal Con- nection (Z-21.8-1974, eq. 19, 21)
→ page 14 Technical Product Informa- tion HALFEN HUC Universal Con- nection (Z-21.8-1974, eq. 20, 21)
Design Example
HALFEN HUC UNIVERSAL CONNECTION
9© 2014 HALFEN · TI-HUC 13-E · www.halfen.com
Min. diameter, stirrup and main reinforcement
HSC-B [mm]
dsw,2 [mm]
dsl,edge[mm]
dsl,bet[mm]
12 6 12 10
16 6 12 10
20 8 12 12
25 12 20 20
Selection of the tensile splitting reinforcementMinimum diameter dsw,2 = 12 mm for HSC-B 25
Tie:
Asw,tie,tot = Asw,1,tie + Asw,2,tie = 0.33 cm² + 0.91 cm² = 1.24 cm²
Selected: 2 stirrups with dsw = 12 mm where: Asw,prov = 2.26 cm² > 1.24 cm² = Asw,req
Strut:
Asw,strut,tot = Asw,1,strut + Asw,2,strut = 0.55 cm² + 1.08 cm² = 1.63 cm²
Selected: 2 Stirrups with dsw = 12 mm where: Asw,prov = 2.26 cm² > 1.63 cm² = Asw,req
Layout: one stirrup is always placed directly below the sleeves, the second stirrup at a distance of 8 cm.The stirrups enclose the longitudinal column reinforcement.
Longitudinal reinforcement
The minimum diameters according to approval are dsl,edge = 20 mm and dsl,bet = 20 mm, see table.
The reinforcement has to be anchored above and below the steelwork element.
Existing: 5 ∅ 25 mm, continuous longitudinal reinforcement
→ see fig.: complete overview page 11
Table: page 14 Technical Product Information HALFEN HUC Universal Connection
bcolhcol
hbe
am
© 2014 HALFEN · TI-HUC 13-E · www.halfen.com
Design Example
HALFEN HUC UNIVERSAL CONNECTION
10
Minimum dimensionsanchor diam. Column
concreteclassdHSC
[mm]bcol,min [mm]
hcol,min [mm]
ds,col,min [mm]
12 240 240 12 C20/25 - C70/85
16 240 240 12 C20/25 - C70/85
20300 300
16C20/25 - C35/45
240 240 C40/50 - C70/85
25
300 400
20
C20/25
300 350 C25/30 - C30/37
300 300 C35/45 - C70/85
Anchorage of the tensile reinforcement
Degree of utilization of the reinforcement steel (see verification reinforcement steel on page 6 also)
213.4 kN194.4 kN
= 0.91
Selected: full anchorage of the reinforcement with HALFEN HSC Anchor heads according to approval Z-21.8-1973 (type HSC-B SH)→ Simplified anchorage verification by keeping to construction regulations
Requirements:Minimum dimensions of the column, see table:
bcol,min = 300 mm < bcol,prov = 400 mm hcol,min = 350 mm < hcol,prov = 600 mm
Minimum longitudinal reinforcement ratio of the column
ρcol,min = bcol ⋅ hcol
As1,col = bcol ⋅ hcol
As2,col ≥ 0.5 %
ρcol,1 = ρcol,2 = 40 cm ⋅ 60 cm
5 ⋅ π/4 ⋅ (2.5 cm)2
= 1.02 % ≥ 0.5 %
Minimum diameter of the longitudinal reinforcement from table: ds,col,min = 20 mm < ds,col,prov = 25 mm
Minimum stirrup reinforcement in the joint area, see figure :dsw = 8 mm, s = 100 mmExisting: dsw = 12 mm, s = 80 mm
The anchor heads are placed behind the longitudinal rein-forcement. See figure above
Load transfer
Load transfer has to be verified by the design engineer.This is also required if an alternative anchorage for the tension reinforcement e.g. bent reinforcement bars has been selected.
Fig.: page 6 Technical Product Informa-tion HALFEN HSC Stud Connector “Geometry, Minimum stirrup reinforce-ment” (Z-21.8-1973, appendix 3)
→ Page 6 Technical Product Informa- tion HALFEN HSC Stud Connector (Z-21.8-1973, eq. 1)
→ Page 6 Technical Product Informa- tion HALFEN HSC Stud Connector (Z-21.8-1973, appendix 7, page 2)
Table page 7 Technical Product Information HALFEN HSC Stud Con-nector (Z-21.8-1973, tab. 2)
Stirr
ups
diam
. 8 s
= 1
00
at h
col
Stirr
ups di
am. 8
s = 10
0
at h
beam
Stirr
ups
diam
. 8 s
= 10
0
at h
col
Stirrup
s diam
. 8 s = 100
at hbeam
L
ds
Design Example
HALFEN HUC UNIVERSAL CONNECTION
11© 2014 HALFEN · TI-HUC 13-E · www.halfen.com
Overview of the selected reinforcement
Tie reinforcement:
4 x Type HSC-B SH, ds = 25 mmL = hcol − tp − cv = 600 mm − 3 mm − 25 mm = 572 mmSleeves zinc electroplated
Strut reinforcement:
2 x Type HSC-B SH, ds = 25 mmL = 572 mmSleeves zinc electroplated
Fig.: overview of the selected reinforcement (except for the tensile splitting reinforcement no stirrups are shown)
Fig.: page 7 Technical Product Informa-tion HALFEN HUC Universal Connec-tion “product overview” „HSC-B female bar with anchor head”
310
300
310
300
tp = 3 mm
45
4540
40
70
8070
u = 50 mm
u50
5555
Liebigstr. 14 ⋅ 40764 Langenfeld ⋅ GERMANYTel.: +49 - (0)2173 / 970-9031Fax: +49 - (0)2173 / 970-420E-Mail: [email protected]
HALFEN GmbH
The Quality Management System of Halfen GmbH is certified for the locations in Germany, France, the Netherlands, Austria, Poland, Switzerland and the Czech Republic according to DIN EN ISO 9001:2008, Certificate No. QS-281 HH.
R -
038
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4 PD
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Hal
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any
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Design Example
HALFEN HUC UNIVERSAL CONNECTION
Face plate HSC-B FP:Measurements: thickness tc = … (determined by design engineer), Other measurements see figureSteel S 460 mill finish(determined by design engineer)Bolts M27
Positioning plate HSC-B P:Dimensions see figure(to facilitate installation the positioning plate is 5 mm wider on all sides than the face plate)Corrosion protection: zinc electroplatedAssembly flush with the formworkBolts M27Nailing holes: d = 3 mm
Not scope of delivery:Longitudinal and stirrup reinforcement6 pcs. bolts M 27 8.8 with washers
Fig.: face plate and positioning plate [all dimensions are in mm]
tc
Explanatory notes on order
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