11/12/14 Geometry Bellwork 11/12/14 Geometry Bellwork
1. 3x = 8x – 15
0 = 5x – 15
15 = 5x
x = 3
2. 6x + 3 = 8x – 14
3 = 2x – 14
17 = 2x
x = 8.5
3. 5x – 2 = 3x + 6
2x – 2 = 6
2x = 8
x = 4
AB = 2AM
AB = 2(5x – 2)
AB = 2(5*4 – 2) = 2(18)
AB = 36
5.2: Use Perpendicular Bisectors5.2: Use Perpendicular Bisectors
Objective: Use perpendicular bisectors to solve problemsA line segment (or line or ray) is a perpendicular bisector if it is perpendicular to another segment at its midpoint
Geometry – StandardG.PL.3Geometry – StandardG.PL.3
Prove and apply theorems about lines and angles, including the following: vertical angles are congruent; when a transversal crosses parallel lines, alternate interior angles are congruent, alternate exterior angles are congruent, and corresponding angles are congruent; when a transversal crosses parallel lines, same side interior angles are supplementary; and points on a perpendicular bisector of a line segment are exactly those equidistant from the endpoints of the segment.
POINTS, LINES, ANGLES
Geometry – StandardG.PL.5Geometry – StandardG.PL.5
Explain and justify the process used to construct, with a variety of tools and methods (compass and straightedge, string, reflective devices, paper folding, dynamic geometric software, etc.), congruent segments and angles, angle bisectors, perpendicular bisectors, altitudes, medians, and parallel and perpendicular lines.
POINTS, LINES, ANGLES
equidistant
CB
AB
4x 7x - 6
2
4x 4(2) 8
Check Points #1 and 2Check Points #1 and 2
ConcurrencyConcurrency
Concurrent – Three or more lines, rays, or segments that intersect in the same point
Point of concurrency – The point of intersection of the lines, rays, or segments
Work these out now!Work these out now!
2x = 5x – 6
0 = 3x – 6
6 = 3x
x = 2
AB = 4
3x + 8 = 7x – 16
8 = 4x – 16
24 = 4x
x = 6
AB = 26
6x + 11 = 11x – 9
11 = 5x – 9
20 = 5x
x = 4
AB = 35
Homework
11/12/14 Homework
11/12/14 Pages: 306-309:
Exercises: 3-5 all, 12-16 even, 24, 37, 38
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