YearPopulation 1950676,806 1960604,332 1970520,117 1980423,938 1990369,879 Source: The city of...

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Year Populati on 1950 676,806 1960 604,332 1970 520,117 1980 423,938 1990 369,879 Source: http://en.wikipedia.org/wiki/Pitt sburgh The city of Pittsburgh, PA was a major steel producer in the first half of the twentieth century. However, like many major industrial American cities, the population of Pittsburgh has decreased since 1950. The table shows the population of Pittsburgh in various years. 1. Graph the data, using years since 1950 . 2. Find the equation of the regression line for 3. Explain what the slope of the ….regression line means in this setting. 4. the data. In the year 2000, the census gave the population of Pittsburgh as 334,563. Was the regression model valid through the year 2000? Explain. Warm-up

Transcript of YearPopulation 1950676,806 1960604,332 1970520,117 1980423,938 1990369,879 Source: The city of...

Page 1: YearPopulation 1950676,806 1960604,332 1970520,117 1980423,938 1990369,879 Source:  The city of Pittsburgh, PA was.

Year Population

1950 676,806

1960 604,332

1970 520,117

1980 423,938

1990 369,879Source: http://en.wikipedia.org/wiki/Pittsburgh

The city of Pittsburgh, PA was a major steel producer in the first half of the twentieth century. However, like many major industrial American cities, the population of Pittsburgh has decreased since 1950.

The table shows the population of Pittsburgh in various years.

1. Graph the data, using years since 1950.

2. Find the equation of the regression line for

3. Explain what the slope of the ….regression line means in this setting.

4.

the data.

In the year 2000, the census gave the population of Pittsburgh as 334,563. Was the regression model valid through the year 2000? Explain.

Warm-up

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y = -7942.48x + 677864

No, the model is not valid through the year 2000. The model’s estimate for the population of Pittsburgh in the year 2000 is 280,740, well below the actual 2000 Pittsburgh population.

where x = years since 1950 and y = population

Warm-up

Source: http://en.wikipedia.org/wiki/Pittsburgh

Year Population

1950 676,806

1960 604,332

1970 520,117

1980 423,938

1990 369,879Source: http://en.wikipedia.org/wiki/Pittsburgh

0

10

20

30

40

The city of Pittsburgh, PA was a major steel producer in the first half of the twentieth century. However, like many major industrial American cities, the population of Pittsburgh has decreased since 1950.

The table shows the population of Pittsburgh in various years.

1. Graph the data, using years since 1950.

2. Find the equation of the regression line for

3. Explain what the slope of the …. ….regression line means in this setting.

4.

the data.

In the year 2000, the census gave the population of Pittsburgh as 334,563. Was the regression model valid through the year 2000? Explain.

It represents the average yearly decrease in population, approximately 7942 people.

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1. Work in groups of 3 or 4 people. More than four people in a group is not acceptable. Working alone is not acceptable2. Work should not be done on the question paper. 3. Include a cover page with the names of group members.4. Show all work neatly, clearly, and completely. Whenever appropriate, answer in full sentences. It is strongly recommended that group members carefully proofread each other’s solutions.5. Several questions ask for graphs. All graphs should be imported from a computer and/or a graphing calculator. Include the viewing window or show the scale on the axes.6. Put thought into your explanations. Do not hesitate to research them on the Web. Don’t take the easy way out!7. Begin this group project as soon as possible and complete the problems gradually. For example, questions 1 – 8 deal with subject matter we have already covered in class and can be completed immediately. 8. Each group member must individually complete and turn in the form on the following page: “Assessment of Group Effectiveness.” These will be kept confidential.9. This project is worth 60 points.

MATH 1101FINAL GROUP PROJECT

Due – Last class before final exam (see syllabus)December 4

Page 4: YearPopulation 1950676,806 1960604,332 1970520,117 1980423,938 1990369,879 Source:  The city of Pittsburgh, PA was.

Assessment of Group Effectiveness

Please rate your group on each of the following statements by circling the rating that applies. ( 1 = Strongly Disagree, 5 = Strongly Agree )

1. The group functioned smoothly, with all members contributing equally. 1 2 3 4 5 Strongly disagree Strongly agree

2. Members of the group proofread each other’s work and gave appropriate input. 1 2 3 4 5 Strongly disagree Strongly agree

3. Group members met deadlines established by the group for completing work. 1 2 3 4 5 Strongly disagree Strongly agree

4. Group members were present for all group meetings. 1 2 3 4 5 Strongly disagree Strongly agree

If any group member made little or no contribution to the group project, please indicate the name of that group member. This will be kept confidential.

Names of the other group members:

__________________________________

__________________________________

__________________________________

Your Name: ___________________________

Page 5: YearPopulation 1950676,806 1960604,332 1970520,117 1980423,938 1990369,879 Source:  The city of Pittsburgh, PA was.

Answers to even-numbered HW problemsSection 3.4

Ex 2a) P = .181t – 349.775 where t = years, P = enrollment in millions

b) The slope means the enrollment increased, on average, by .181 million (181,000) students per year.

c) P(2007) = 13.492 million (13,492,000)

d) No. If the trend had been valid in 1993, the expected enrollment that year would have been 10.958 million,

not 11.2 million.

P =.181t + 12.406using t = years since 2001

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x

y

1 2 3 4 5 6 7 8 9

8

7

6

5

4

3

2

1

3x – 2y = 10

x + 2y = –2

•(2, -2)

is the point where the two

lines cross.

12

1 xy

y = x – 5 2

3

is the solution to this system of two linear equations.

This method of solution is called the “crossing graphs” method.

Page 7: YearPopulation 1950676,806 1960604,332 1970520,117 1980423,938 1990369,879 Source:  The city of Pittsburgh, PA was.

(2, -2)

is the point where the two

lines cross.

3x – 2y = 10

x + 2y = –2

12

1 xy

y = x – 5 2

3

is the solution to this system of two linear equations.

Page 8: YearPopulation 1950676,806 1960604,332 1970520,117 1980423,938 1990369,879 Source:  The city of Pittsburgh, PA was.

(2, -2)

is the point where the two

lines cross.

3x – 2y = 10

x + 2y = –2

12

1 xy

y = x – 5 2

3

is the solution to this system of two linear equations.

Page 9: YearPopulation 1950676,806 1960604,332 1970520,117 1980423,938 1990369,879 Source:  The city of Pittsburgh, PA was.

3x – 2y = 10

x + 2y = –2

y3x – 2 = 10

–6y – 6 – 2y = 10

y = –2

x + 2y = –2

x + 2(–2) = –2

Solution to the system: (2, -2)

Substitution Method

x = – 2y – 2

(–2y – 2)

–8y = 16x = 2

Page 10: YearPopulation 1950676,806 1960604,332 1970520,117 1980423,938 1990369,879 Source:  The city of Pittsburgh, PA was.

3x – 2y = 10

x + 2y = –2 12

1 xy

y3x – 2 = 10 = 10

1

2

1x

3x + x + 2 = 10

x = 22 + 2y = –2

y = –2

Solution to the system: (2, -2)

Substitution Method

Page 11: YearPopulation 1950676,806 1960604,332 1970520,117 1980423,938 1990369,879 Source:  The city of Pittsburgh, PA was.

3x – 2y = 10

x + 2y = -2

Because the coefficients of y in the two equations are opposites, adding the equations will eliminate the y-variable.

3x – 2y = 10

x + 2y = -2+

4x = 8

x = 2 2 + 2y = -2

y = -2

Solution to the system: (2, -2)

Elimination Method (Linear Combination)

Page 12: YearPopulation 1950676,806 1960604,332 1970520,117 1980423,938 1990369,879 Source:  The city of Pittsburgh, PA was.

3x – 2y = 19

7x + 3y = 6

(3, -5)

3(3x – 2y = 19)

2(7x + 3y = 6)

9x – 6y = 57

14x + 6y = 12+

23x = 69

x = 3

3x – 2y = 19

3(3) – 2y = 19

–2y = 10

y = –5

Page 13: YearPopulation 1950676,806 1960604,332 1970520,117 1980423,938 1990369,879 Source:  The city of Pittsburgh, PA was.

Practice

Two systems of linear equations are given below. Solve one using the substitution method, and one using the elimination method.

3x – 5y = 47

8x + 3y = 11

2x + 3y = 7

5x – y = 9

(4, –7) (2, 1)

Page 14: YearPopulation 1950676,806 1960604,332 1970520,117 1980423,938 1990369,879 Source:  The city of Pittsburgh, PA was.

Year Kennesaw State

Valdosta State

1980 3,903 4,9011981 4,195 4,9091982 4,779 5,5481983 5,383 5,835http://www.usg.edu/research/documents/enrollment_reports/rpt79-88.pdf

Shown above are the enrollments at Kennesaw State College and Valdosta State College at the beginning of the school years listed.

1.Using years since 1980, Make scatter plots of the enrollment data for both schools on the same calculator screen.

2.Using linear regression models for both schools, and assuming the trends continued, identify the year in which the Kennesaw State’s enrollment overtook Valdosta State’s enrollment.

Page 15: YearPopulation 1950676,806 1960604,332 1970520,117 1980423,938 1990369,879 Source:  The city of Pittsburgh, PA was.

Year Kennesaw State

Valdosta State

1980 3,903 4,9011981 4,195 4,9091982 4,779 5,5481983 5,383 5,835

Shown above are the enrollments at Kennesaw State College and Valdosta State College at the beginning of the school years listed.

1.Using years since 1980, Make scatter plots of the enrollment data for both schools on the same calculator screen.

2.Using linear regression models for both schools, and assuming the trends continued, identify the year in which the Kennesaw State’s enrollment overtook Valdosta State’s enrollment.

http://www.usg.edu/research/documents/enrollment_reports/rpt79-88.pdf

Regression model for KSU

y = 502.4x +3811.4

Regression model for VSU

y = 344.1x + 4782.1

Page 16: YearPopulation 1950676,806 1960604,332 1970520,117 1980423,938 1990369,879 Source:  The city of Pittsburgh, PA was.

Section 3.5:

Do not read Section 3.5

Page 298 # S-11, S-12, S-16

Pages 299 – 300 # 5, 6, 10

HOMEWORK

ALSO

DOWNLOAD, PRINT, AND COMPLETE THE PRACTICE TEST.

X

DON’T FORGET TO DOWNLOAD AND PRINT A COPY OF THE FINAL GROUP PROJECT.