y – y 1 = m(x – x 1 )

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y – y 1 = m(x – x 1 ) Equation of a Straight Line This allows use to find the equation of a straight line if we know its slope and one coordinate it passes through. x coordinate slope y coordinate

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Equation of a Straight Line. y – y 1 = m(x – x 1 ). x coordinate. y coordinate. slope. This allows use to find the equation of a straight line if we know its slope and one coordinate it passes through. Find the equation of the line (a) passing through (-2 , 3) with slope = 3 - PowerPoint PPT Presentation

Transcript of y – y 1 = m(x – x 1 )

Page 1: y  – y 1  = m(x – x 1 )

y – y1 = m(x – x1)

Equation of a Straight Line

This allows use to find the equation of a straight line if we know its slope and one coordinate it passes through.

x coordinateslopey coordinate

Page 2: y  – y 1  = m(x – x 1 )

Find the equation of the line

(a) passing through (-2 , 3) with slope = 3

(b) Passing through (4 , 7) with slope = 2/3

y – y1 = m(x – x1) y – 3 = 3(x - -2)

y – 3 = 3x + 6

y = 3x + 9

y – y1 = m(x – x1) y – 7 = 2/3(x – 4)

3y – 21 = 2x - 8

3y = 2x + 13

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Find the equation of the line

1.passing through (2 , 1) with slope = 2

2. Passing through (3 , 2) with slope = 3

3. Passing through (-4 , 2) with slope = 5

4. Passing through (-2 , -3) with slope = -3

5. Passing through (5 , 3) with slope = 2/5

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Find the equation of a straight line parallel to 2y = 4x + 5 which passes through (-1 , 3)

y = 2x + 5/3

2y = 4x + 5 y – y1 = m(x – x1)

y – 3 = 2(x - -1)

y – 3 = 2x + 2

y = 2x + 5

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Find the equation of a straight line perpendicular to 3y = x - 2 which passes through (4 , 5)

y = x/3 - 2/3

3y = x - 2 y – y1 = m(x – x1)

y – 5 = -3(x - 4)

y – 5 = -3x + 12

y + 3x = 17

m = 1/3

Perp = -3

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1. Find the equation of a straight line parallel to y = 2x + 5 which passes through (4 , 5)

2. Find the equation of a straight line parallel to 2y + 6x = 18 which passes through (2 , -4)

3. Find the equation of a straight line parallel to 3y = 4x - 2 which passes through (3 , 2)

4. Find the equation of a straight line perpendicular to y = 2x + 3 which passes through (1 , 3)

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Find the equation of the line passing through the points (4 , 5) and (-2, 3).

m = 3 - 5

-2 - 4= -2/-6 = 1/3

y – 5 = 1/3(x – 4)

3y – 15 = x - 4

3y = x + 11

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Find the equation of the line passing through the points

1) (2 , 3) and (8 , 6)

2) (-3, 1) and (7 , 6)