Wireless Communications: System Design

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Wireless Communications: System Design. Dr. Mustafa Shakir. Issues in cell to cell moving. What are different levels of handoff. (1) Intra Cell (2) Inter cell (3) Inter system Importance of handoff. - PowerPoint PPT Presentation

Transcript of Wireless Communications: System Design

Page 1: Wireless Communications: System Design
Page 2: Wireless Communications: System Design

Wireless Communications: System Design

Dr. Mustafa Shakir

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Issues in cell to cell moving What are different levels of handoff. (1) Intra Cell (2) Inter cell (3) Inter system Importance of handoff. When no priority to handoff call blocking would be equal

for call initiation and call handoff. There are two strategies to give a priority to handoff. (1) Guard Channel: 100% guaranty for successful handoff

but It will cause low trunking efficiency. (2) Queuing Of Handoff Request: There can be

unsuccessful handoffs due to long delay in queue. --“Probability of forced termination” decreases at the cost

of reduced Total Carried Traffic. -- Queuing is possible because of the time available

between the Threshold power level and the Hand off power level.

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Umbrella Cell Approach

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Solution For More Handoffs Umbrella Cell Approach: Micro cells inside A macro cell.

---- Macro cell is defined by high power and lengthy tower. ---- Micro cells are defined inside the macro cell with less power and less height towers. ---- High speed MS are handled by macro cell and low speed subscribers are handled by micro cells. ---- This strategy increases the no of capacity channels per unit area and decreases the no of handoffs.

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Umbrella Cell Approach

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INTERFERENCE AND SYSTEM CAPACITY

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Interference It is a major limiting factor in the performance of cellular radio systems. (In comparison with wired comm. Systems, the amount and sources of interferences in Wireless Systems are greater.)

Creates bottleneck in increasing capacity

Sources of interference are:1. Mobile Stations2. Neighboring Cells

3. The same frequency cells 4. Non-cellular signals in the same spectrum

Interference in Voice Channels: Cross-Talk

Urban areas usually have more interference, because of:a)Greater RF Noise Floor, b) More Number of Mobiles

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Major Types Of Interference

1) Co-Channel Interference (CCI)

2) Adjacent Channel Interference (ACI)

3) Other services: like a competitor cellular service in the same area

1) Co-Channel Interference and System Capacity The cells that use the same set of frequencies are called co-channel cells.

The interference between signals from these cells is called Co-Channel Interference (CCI).

Cannot be controlled by increasing RF power. Rather, this will increase CCI.

Depends on minimum distance between co-channel cells.

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In constant cell size and RF power, CCI is a function of Distance between the co-channel cells(D), and the size of each cell (R).

Increasing ratio D/R, CCI decreases.

Define Channel Reuse Ratio = Q = D/R

The yellow cells use the same set of frequency channels, and hence, interfere with each other.

In case of N=7, there are 6 first-layer co-channels.

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Signal-to-interference ratio

S is the power of the signal of interest and Ik is the power of kth interference.

The signal strength at distance d from a source is

SIR =S

Ikk

1

6

S d n That is, received signal power is inversely related to nth

power of the distance.

where n = path loss exponent

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For hexagonal geometry, D/R can be calculated:

NQ 3

NRDQ 3/

Smaller Q provides larger capacity, since that would

mean smaller N. (Capacity 1/N).

Larger Q improves quality, owing to less CCI. for N=3, Q=3,

N=7, Q=4.58,

N=12, Q=6,

N=13, Q=6.24

R D

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Then we can express the SIR in terms of distance

where the denominator represents the users in neighboring clusters using the same channel.

Let D k=D be the distance between cell centers. Then

Note how S/I improves with the frequency reuse N.

Analog systems: U.S. AMPS required S/I ~= 18dB For n = 4, the reuse factor for AMPS is N 6.49, so N = 7.

Now, let us consider the worst case for a cluster size of N= 7. The mobile is at the edge of the cell. Express C/I as a function of actual distances.

6

1

S/I SIR=n

nk

k

R

D

( / ) ( 3 )S/I

6 6

n nD R N

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Worst Case Design

Worst case carrier-to-interference ratio

Let n = 4 and D/R = q,

Let reuse N = 7, then

Compute C/I and get C/I = 17.3 dB

2( ) 2 2( )

n

n n n

S R

I D R D D R

4 4 4

1

2( 1) 2 2( 1)

S

I q q q

q 3 7 4 6.

D + R

D + R

D -R

D -R

D

D

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If S/I min = 15 dB, what is the capacity for n = 4, n = 3

(a) n = 4, N = 7

N =7 can be used

(b) n = 3, N = 7

E

0 0

/ 3 7 4.58

( / ) ( 3 ) (4.58)18.66 dB>15 dB

6

n n n

D R

S D R N

I i i

SI

N

D R

SI

4 586

12 05

3 12 6 0

66

36 1556

3

3

..

/ .

.

dB<15 dB

Need larger

dB>15 dB

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(2) Adjacent Channel Interference Interference from channels that are adjacent in frequency,

The primary reason for that is Imperfect Receiver Filters which cause the adjacent channel energy to leak into your spectrum.

Problem is severer if the user of adjacent channel is in close proximity. Near-Far Effect

Near-Far Effect: The other transmitter(who may or may not be of the same type) captures the receiver of the subscriber.

Also, when a Mobile Station close to the Base Station transmits on a channel close to the one being used by a weaker mobile: The BS faces difficulty in discriminating the desired mobile user from the “bleed over” of the adjacent channel mobile.

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Unintended

Tx

Mobile User Rx

BS as Tx

Weaker signal

Strong “bleed over”

The Mobile receiver is captured by the unintended, unknown transmitter, instead of the desired base station

Near-Far Effect: Case 1

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Adjacent Channel

Mobile Tx

Desired Mobile Tx

BS as Rx

Weaker signal

Strong “bleed over”

The Base Station faces difficulty in recognizing the actual mobile user, when the adjacent channel bleed over is too high.

Near-Far Effect: Case 2

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Minimization of ACI

(1) Careful Filtering ---- min. leakage or sharp transition(2) Better Channel Assignment Strategy

Channels in a cell need not be adjacent: For channels within a cell, Keep frequency separation as large as possible.

Sequentially assigning cells the successive frequency channels.

Also, secondary level of interference can be reduced by not assigning adjacent channels to neighboring cells.

For tolerable ACI, we either need to increase the frequency separation or reduce the pass band BW.

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Power Control in Mobile Com

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What is power control ?

Both the BS and MS transmitter powers are adjusted dynamically over a wide range.

Typical cellular systems adjust their transmitter powers based on received signal strength.

TYPES OF POWER CONTROLo Open Loop Power Control

It depends solely on mobile unit, not as accurate as closed loop, but can react quicker to fluctuation in signal strength. In this there is no feed back from BS.

o Closed Loop Power ControlIn this BS makes power adjustment decisions and communicates to mobile on control channels

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Why power control ?

Near-far effect Mechanism to compensate for “channel

fading” Interference reduction, prolong battery life

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Improving Capacity in Cellular Systems Cost of a cellular network is proportional to the number

of Base Stations. The income is proportional to the number of users. Ways to increase capacity: New spectrum – expensive. PCS bands were sold for

$20B. Architectural approaches: cell splitting, cell sectoring,

microcell zones. Dynamic allocation of channels according to load in

the cell (non-uniform distribution of channels). Improve access technologies.

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Cell Splitting Cell Splitting is the process of subdividing the congested cell into

smaller cells (microcells), Each with its own base station and a corresponding reduction in antenna height and transmitter power.

Cell Splitting increases the capacity since number of clusters over coverage region would be increased thus increasing the number of channels.

New cells added having smaller radius than original cells and by installing these smaller cells (called microcells ) between existing cells , capacity increases due to additional number of channels per unit area.

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Cell splitting diagram 1

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An Example

The area covered by a circle with radius R is four times the area covered by the circle with radius R/2 The number of cells is increased four times

The number of clusters the number of channels and the capacity in the coverage area are increased Cell Splitting does not change the co-channel re-use ratio Q =D/R

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Transmit Power

New cells are smaller, so the transmit power of the new cells must be reduced

How to determine the transmit power? The transmit power of the new cells can be

found by examining the received power at the new and old cell boundaries and setting them equal

Pr(at the old cell boundary) is proportional to Pt1 * R-n

Pr(at the new cell boundary) is proportional to Pt2 * (R/2)-n

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Transmit Power

Take n=4, we get Pt2 = Pt1/16 We find that the transmit power must be

reduced by 16 times or 12 dB in order to use the microcells to cover the original area. While maintaining the same S/I.

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Application of cell splitting

When there are two cell sizes one cant simply use the same transmit power for all cells. If larger transmit power used for all cells some smaller cells would not be sufficiently separated from co channel cells. Using smaller Pt the larger cells might be left unserved.

So old channel broken to two channel groups corresponding to smaller and larger cell reuse.

Larger cell for less frequent hand off. Antenna down tilting focusing radiated energy from

base station to the ground to limit radio coverage of newly formed cells.

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Cell Sectoring Co channel interference may be reduced by replacing

omni directional antenna by several directional antennas. Given cell will receive interference and would transmit

with fraction of available co channel cells. Each sector uses directional antenna at the B.S and

assigned a set of channels. Partitioning into three 120 deg. sectors or six 60 deg.

sectors. Amount of CCI reduced by number of sectors. Reduced Tx Power…

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Cell Sectoring

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Example for sectoring

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Explanation For Cell Sectoring

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Effects of Sectoring Reduction in interference offered by sectoring would

enable to reduce the cluster size N and additional degree of freedom in channel assignment.

Increased number of antennas with shrinking cluster size and decrease in trunking efficiency due to channel sectoring at base station.

Since sectoring reduces the coverage area of a particular group of channels the number of handoffs increases

Available channels subdivided and dedicated to a specific antenna thus making up of several smaller pools contributing to decrease in trunking efficiency.

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Repeaters To provide dedicated coverage for hard to reach

areas Radio retransmitters for range extension. Upon receiving signals from base station forward

link the repeater amplifies and reradiates the base station signals to specific coverage region.

In building wireless coverage by installing Distributed Antenna Systems.

Repeaters must be provisioned to match the available capacity from the serving base station.

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Repeaters For Range Extension

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Microcell Zone The increased number of handoff as a result of sectoring

would result in an increased load on switching and control link elements of the mobile system.

Division into microcell zones and each of the three are connected to a single base station and share the same radio equipment.

Zones connected by a coaxial cable, fiber optic cable or microwave link to the base station.

Handoff not required while mobile travels between zones within cell.

Channel switching and a channel active only within zone of travelling.

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Scenario In Micro cell zone scenario each hexagon

represents a zone while the group of three hexagons represent a cell.

Zone Radius Rz is one hexagon radius. Capacity of Microcell is directly related to

distance betw. Cochannel cells and not zones.

No handoffs is required at the MSC. The base station radiation is localized and

interference is reduced

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Trunking & Grade Of Service

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Trunking and Grade of Service (GOS) Trunking A means for providing access to users on

demand from available pool of channels. With trunking, a small number of

channels can accommodate large number of random users.

Telephone companies use trunking theory to determine number of circuits required.

Trunking theory is about how a population can be handled by a limited number of servers.

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Terminologies Erlang:

One Erlang:

When a circuit is busy for one hour it handled a traffic of one erlang.

Grade of Service (GOS):

probability that a call is blocked (or delayed). Set-Up Time:

Traffic intensity is measured in Erlangs: time to allocate a channel. Blocked Call:

Call that cannot be completed at time of request due to congestion. Also referred to as Lost Call.

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Terminologies Contd.

Holding Time: (H)

Average duration of typical call. Load:

Traffic intensity across the whole system.

Request Rate: ()

Average number of call requests per unit time.

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Traffic Measurement (Erlangs) Traffic per user Au = H where is the request rate

and H is the holding time. For U users the load is A= U Au If traffic is trunked in C channels, then the traffic

intensity per channel is Ac= UAu /C Erlang B:

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The Erlang B Chart

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Example Example : An urban area has 2 million residents.

Three competing cellular systems provide service: System A 394 cells x 19 channels/cell. System B 98 cells x 57 channels/cell. System C 49 cells x 100 channels/cell. For each user = 2 calls/hr, H = 3min, GOS = 2%

blocking. Find the number of users that can be supported by each system. Note that these are not simultaneous users.

System A: Au= H = 2 x 3/60 = 0.1 Erlangs. From the curve for GOS = 0.02 and C = 19 => A = 12 Er. Users per cell (U) = A/Au = 12/0.1 = 120 users 120 users/cell x 394 cells = 47,280 users can be served.

Market penetration = 2.36%.

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No. of subscribers System C: Prob Blocking = 2% = 0.02 C =100 Au = H = 2 x 3/60 = 0.1 Erlangs. From table, A = 88 Erlangs. Users per cell U = A/Au = 88/0.1 =880 users 880 users/cell x 49 cells = 43,120.

Market penetration = 2.156%. System B: Prob Blocking = 2% = 0.02 C =57 Au = H = 2 x 3/60 = 0.1 Erlangs. From table, A = 45 Erlangs Users per cell U = A/Au = 45/0.1 = 450 users 450 users/cell x 98 cells = 44,100. Market penetration = 2.21%.

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Total No. of supported users = 47,280 + 44,100 + 43,120

= 134,500 users. Total market penetration for 3 systems =

6.725%

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