What is motion? Acceleration Momentum. Changing Position ◦ All matter in universe is constantly...
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Transcript of What is motion? Acceleration Momentum. Changing Position ◦ All matter in universe is constantly...
What is motion?
Acceleration
Momentum
Changing Position◦All matter in universe is constantly in motion◦If something is changing position it is in
motion◦To determine if an object is in motion, a
point of reference is needed
Final position of motion depends on both distance traveled and the direction
Distance would be the actual movement from start to end
Displacement includes the distance between start and finish and the ending point…. Sometimes it will be equal to zero, if you end up at same point that you started
See example on page 523
Speed is the distance an object travels in a period of time
S = D/T (units would be meters/second)
Average speed is found by taking total distance traveled by the total time
Instantaneous speed is the speed of an object at one instant of time (police using radar is an example)
Constant speed is speed that doesn’t vary on its movement (cruise control on car is put on constant speed)
Graphing using time (x axis) and distance (y axis) Constant speed
Which I moving at a faster pace?
Velocity of an object is the speed of an object and the direction of its motion
The difference of velocity and speed is that velocity refers to a direction
Velocity changes if you change speed or if you change direction
V = D/T (any changes in speed or direction changes its velocity)
Units are in m/s
Speeding up: a positive acceleration results in an object speeding up
Slowing down: a negative acceleration results in an object slowing down also known as deceleration
Changing Direction: Any change of direction results in change of velocity and a change in acceleration
Page 531
To solve physic problems these steps need to be shown on your paper◦ 1. list all information given◦ 2. write down what your ask to solve◦ 3. write down formula that you are using◦ 4. plug in data into formula including units◦ 5. solve and check if the answer makes sense◦ 6. record answer with its proper units
Bike increases speed from 4 m/s to 6 m/s in 5 seconds
Vi = 4 m/s A= 6m/s – 4 m/s Vf = 6 m/s 5 s T = 5 s A = ? A = .4 m/s/s or .4 m/s2
A= Vf-V bike speeds up .4 m/s every second T
Bike slows down from 4 m/s to 2 m/s in 5 seconds
Vf = 2 m/s A = 2 m/s- 4m/s Vi = 4 m/s 5s T = 5 s A=?
◦ A = -.4 m/s/s or -.4 m/s2
A = Vf-Vi (notice it is a negative acceleration)
T
Graphing accelerated Motion
http://www.physicsclassroom.com/mmedia/index.cfm#kinema
When a collision occurs changes in motion of the colliding objects depends on their masses and their velocities before the collisions
Mass: is the amount of matter in an object (the more mass, the harder to change its motion)
The tendency of an object to resist a change in its motion is called inertia and is dependent on its mass
A larger mass or an object moving faster is harder to stop than a smaller one or a slower one
Momentum is a measure of how hard it is to stop an object and is dependent on the objects mass and velocity
P = mv (where P is momentum, m is mass and v is
velocitiy)
Use the same process as before
To solve physic problems these steps need to be shown on your paper
1. list all information given2. write down what your ask to solve3. write down formula that you are using4. plug in data into formula including units5. solve and check if the answer makes sense6. record answer with its proper units
Calculate momentum of a 14 kg bike traveling 2m/s
M=14 kg p = mv V= 2m/s P =? P = 14 kg X 2 m/s p = 28 kg*m/s
The total momentum of a group of objects remains constant unless outside forces act on the group is known as the law of conservation of momentum
In a cue ball hitting billiard balls all the momentum of the original collision equals all of the momentums of the billiard balls when they are hit excluding outside force like friction
Some collisions bounce off each other, others stick together after contact
Momentum before equals momentum after collisions
p =p M1V1 =M2V2
Page 536 backpack weighs 2 kg is thrown at velocity of 5 m/s east. A student grabs it that weighs 48 kg. What was his velocity after catching it
Mbp = 2 kg Mbp(Vbp) = (Ms + Mbp)(Vs) Vbp = 5 m/s 2kg*5m/s=(2 kg+48kg)*Vs
Ms = 48 kg 10kg*m/s=50kg*V2
Vs = ? .2 m/s east = Vs
2 objects same mass and same speed collide Since they have same momentum before collision, they
have zero momentum
After collision the 2 objects bounce off with same velocity but opposite directions, therefore there is no momentum after collision