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Mark Scheme

Sample Assessment Material 2018

Pearson Edexcel International GCSEIn Physics (4PH1) Paper 1P

Pearson Edexcel International GCSEin Science Double Award (4SD0) Paper 1P

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Sample Assessment Material 2018All the material in this publication is copyright© Pearson Education Ltd 2018

General Marking Guidance

All candidates must receive the same treatment. Examiners must mark the first candidate in exactly the same way as they mark the last.

Mark schemes should be applied positively. Candidates must be rewarded for what they have shown they can do rather than penalised for omissions.

Examiners should mark according to the mark scheme not according to their perception of where the grade boundaries may lie.

There is no ceiling on achievement. All marks on the mark scheme should be used appropriately.

All the marks on the mark scheme are designed to be awarded. Examiners should always award full marks if deserved, i.e. if the answer matches the mark scheme. Examiners should also be prepared to award zero marks if the candidate’s response is not worthy of credit according to the mark scheme.

Where some judgement is required, mark schemes will provide the principles by which marks will be awarded and exemplification may be limited.

When examiners are in doubt regarding the application of the mark scheme to a candidate’s response, the team leader must be consulted.

Crossed out work should be marked UNLESS the candidate has replaced it with an alternative response.

Subject specific marking guidance Symbols, terms used in the mark scheme

Round brackets ( ): words inside round brackets are to aid understanding of the marking point but are not required to award the point

Curly brackets { }: indicate the beginning and end of a list of alternatives (separated by obliques), where necessary, to avoid confusion

Oblique /: words or phrases separated by an oblique are alternatives to each other and either answer should receive full credit.

ecf: indicates error carried forward which means that a wrong answer given in an early part of a question is used correctly to a later part of a question.

You will not see ‘owtte’ (or words to that effect). Alternative correct wording should be credited in every answer unless the mark scheme has specified specific.

The Additional Guidance column is used for extra guidance to clarify any points in the mark scheme. It may be used to indicate:

what will not be accepted for that marking point in which case the phrase ‘do not accept’ will be alongside the relevant marking point

it might have examples of possible acceptable answers which will be adjacent to that marking point

Question number Answer Notes Mark

s1 a C (6000 Ω) 1

b C (5 milliseconds) 1

c i vectors have magnitude and direction (1) ALLOW size for magnitude

2

scalars have magnitude/size (but no direction) (1)

ii mass temperature energy

all three for (2)any two for (1)

2

Total for question 1 = 7 marks


s2 a B (microwaves) 1

b C (can cause skin burns) 1

c i D (ultraviolet) 1

ii speed = frequency × wavelength any form, accepted symbols e.g. v = f x

1

iii rearrangement (1) 3substitution (1)evaluation (1)

e.g. = v/f( =) 200 000 000/ 4.5 × 1014

( =) 4.4 × 10-7 (m)



s3 a stopping distance increases with

speed (1)2

non-linear relationship (1)

b 139 138-140 1

c line drawn is similar shape (1) 2

line always below the pre-existing line (1)

d thermal energy store (1) 2

of the brakes and surroundings increases (1)

mechanically / by heating (1)

e (a component of) the weight of the car opposes motion (1)

2

greater decelerating force (1) ACCEPT greater deceleration



s4 a switches lamps

S1 S2 S3 1 2 3 4

1 CLOSED OPEN OPEN

2 CLOSED OPEN CLOSED

3 OPEN CLOSED CLOSED

4 CLOSED CLOSED CLOSED

(1) for each correct line

3

b correct symbol (1) 2

in parallel across lamp 2 (1)

c correct symbol (1) 2

draw on the lamp 4 branch (1)

d i voltage = current × resistance any form, correct symbols e.g. V = I × R

1

ii calculation of battery voltage / rearrangement (1)

3

substitution (1)

evaluation (1)

e.g. 4.5 V OR R= V/I seen(R =) 4.5/0.54(R =) 8.3 (Ω) ALLOW 8.33333 (Ω) etc

2.78, 2.8 gains 2 marks

iii 2.3 (V) ALLOW 2.25 (V) 1ACCEPT 0.75 (V) if incorrect voltage used in (d)(ii)



s5 a i any four from: 4

M1 use of a thermometer to measure temperature

M2 use same starting temperature

M3 use each rod in turn

M4 start timer when Bunsen lit/rod placed in water

M5 record the time at which each cm of paint changes colour

ii copper and aluminium would have faster colour change (1)

3

wood and plastic would not change colour (1)

ALLOW idea that wood and plastic would only change colour very slightly

because metals are good conductors/ORA (1)

b i UP on RHS (1) 2

DOWN on LHS (1)

ii any three from: 3M1 water gets hot

M2 water expands/spaces between particles expand

M3 water becomes less dense

M4 hot water rises

M5 cool water drawn in to replace rising water and process repeats



s6 a the Sun, Solar System, Milky Way,

Universeall needed in order 1

b rearrangement (1) 4

substitution (1)

conversion of time into s (1)

evaluation (1)

e.g.r = v ×T 2 π(r =) 8.204 × 16.69 2 π(r =) 8.204 × 16.69 × 24 × 60 × 60 2 π(r =) 1.883 × 106 km ALLOW correctly

rounded values to other numbers of s.f.

c star X begins as a low mass star but star Y begins as a high mass star (1)

4

star X will stay on the main sequence line for longer than Star Y (1)

star X will become a red giant but star Y will become a red supergiant (1)

star X will end as a white dwarf but star Y will end as a neutron star/black hole (1)


Question number Answer Notes Marks

7 a i acceleration/eq (1) 2

non-constant rate (1)

ii constant velocity/eq 1

iii (constant) acceleration (1) 2

moving in the opposite direction (1)

b i substitution (1) 2

evaluation (1)

e.g.= (6.8-0)/200.34 (m/s2)

ALLOW answers in the range 0.34-0.36 (m/s2)

ii distance = area under graph (1) 3

clear attempt at calculation of triangular area (1)

evaluation (1)

e.g.0.5x 12.5 x 10= 62.5 (m)

c substitution (1) 3

rearrangement (1)

evaluation (1)

e.g.22 2 = 14 2 – 2 x 3 x ss = 22 2 – 14 2 6 = 48 (m)

ACCEPT d for s



8 a

Material Alpha Beta Gamma

paper

aluminium 2mm thick

lead 2cm thick

Award (1) for each correct row

3

b labelled diagram to show: source (1)

4

GM tube (1)

counter/ratemeter (1)

absorber placed between source and GM tube (1)

c i A (cosmic rays) 1

ii take reading without the source present (1)

2

subtract this reading from the reading with source (for the same length of time) (1)

d any two suitable from: 2e.g. handle with tongs/eqkeep a distance from source/ do not point source at body/eqkeep source in lead lined box

Total for Question 8 = 12 marks


9 a same element/same number of protons in nucleus (1)

2

different numbers of neutrons (1)

b idea that it contains some of the radioactive isotope

ALLOW idea that the steel contains some other substance other than steel

1

c 84 (1)4 and 2 (1)205 (1)

209 4 205Po + Pb

84 2 82

3

d does not lose/gain any p or n (1) 2

because gamma is an EM wave (1) ALLOW idea that nucleus loses energy

e i correct line drawn

0 100 200 300 400 500 600 700 8000

500

1000

1500

2000

2500

30001

ii data point recorded (1) 3

second time seen for halved count rate (1)

time between these 2 points evaluated in the range 125 ±10 (years) (1)



10 a i pressure difference = height × density × g

accepted symbols, any rearrangement e.g p = h × × g

1

ii substitution (1) 2

evaluation (1)

e.g.(p =) 1050 × 10 × 70(p =) 740 000 (Pa) ALLOW 735 000 (Pa)

iii 100 000 + 735 000 = 8.35 x 105 Pa 1

b i pressure = force ÷ area accepted symbols, any rearrangement e.g. p = F/A

1

ii rearrangement (1) 3

substitution (1)

evaluation (1)

e.g.F = p × A(F =) 6.5 × 105 x 2.5(F =) 1.6 x 106 (N) 16.25 x 105

c pressure decreases (1) 2

because density has decreased (1)



11 a iron is a soft magnetic material/steel is a hard magnetic material (1)

2

iron will demagnetise easily/ORA (1)

b i wire moves/experiences a force (1) 2

into the plane of the paper/eq (1) ACCEPT however expressed

ii any three from: 3M1 current perpendicular to the

magnetic field

M2 magnetic field around the current carrying wire

M3 two magnetic fields interact

M4 producing a force on the wire

M5 as predicted by catapult effect / LH rule

iii wire will now move out of plane of paper

ACCEPT opposite direction than in (b)(i)

1

Total for Question 11= 8 marks

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