Volume, Mass & Density
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Carpentry & Joinery Phase 4 Module 1 Unit 20 Volume, Mass & Density Volume, Mass & Density m³ m³ kg kg Sample Sample Questions Questions & & Solutions Solutions
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Volume, Mass & Density. m³. kg. Sample Questions & Solutions. 4.5m. 1.8m. 38m. 5m. 2.4m. 55m. 7.5m. Volume. Calculate the volume of the shapes below in m 3. Volume of cuboid = L x B x H Volume of large cuboid = 7.5 x 2.4 x 4.5 = 81m³ Volume of small cuboid - PowerPoint PPT Presentation
Transcript of Volume, Mass & Density
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Volume, Mass & DensityVolume, Mass & Density
m³m³
kgkgSample Sample Questions & Questions & SolutionsSolutions
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VolumeVolumeCalculate the volume of the shapes below in m3
Volume of cuboid = L x B x H
Volume of large cuboid
= 7.5 x 2.4 x 4.5 = 81m³
Volume of small cuboid
= 5 x 2.4 x 1.8= 21.6m³
Shape volume = 81 – 21.6 = 59.4m³59.4m³
38m
55m
Volume = πr² x h
= 3.14 x (38 x 38 )x 55
= 3.14 x 1,444 x 55
= 249,379 m249,379 m33
7.5m2.
4m
4.5
m
5m
1.8
m
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VolumeVolume• Find the volume of concrete required to fill twenty
timber shutters measuring 2.5 meters in height and having a cross sectional area of 0.35m x 0.3m ?
• Answer = 20 (L x B x H)
= 20 (0.35 x 0.3 x 2.5)
= 5.25m5.25m33 of concrete of concrete
2.5m
0.35m0.3m
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VolumeVolume• Calculate the volume of concrete required in order to pour a
concrete raft foundation 9.3m x 2.7m, having a depth of 300mm and with a perimeter edge beam support of 300mm x 300mm
Volume of main slab = L x B x H = 9.3 x 2.7 x 0.3
= 7.533m³7.533m³• Volume of edge beam = 2(9.3 x 0.3 x 0.30 = 2(2.1* x 0.3 x 0.3)
So total = 7.533 + 2(9.3 x 0.3 x 0.3) + 2(2.1 x 0.3 x 0.3 )
= 9.585m³ of concrete9.585m³ of concrete **Note: edge beam measured full length on long sides so short sides are reduced by 2 x 0.3m to 2.1mNote: edge beam measured full length on long sides so short sides are reduced by 2 x 0.3m to 2.1m
Section through foundation
2.7m
300mm
300mm
300mm
edge beam
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Volume, Mass & DensityVolume, Mass & Density
• Calculate the density of a load of hardwood with a total volume of 1.85m3 and a mass of 975Kg.
Density =Density = Mass Mass
VolumeVolume
Answer; Density = 975 ÷ 1.85
= = 527Kg/m527Kg/m33
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Volume, Mass & DensityVolume, Mass & Density• Calculate the volume of timber from the cutting list below.
• Calculate the total weight of the timber if the density of the timber is 430kg/m3.
• Mass (Weight ) = Volume x Density)Mass (Weight ) = Volume x Density)
Mass = 0.0756 x 430
= 32.508kg 32.508kg
No. Off Length Width Thickness
1 7.2m 100mm 35mm
2 4.8m 75mm 35mm
2 1.8m 75mm 35mm
2 3m 75mm 35mm
Total = 0.0756m0.0756m33
Volume (m3)
0.0252
0.0252
0.00945
0.01575
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Volume, Mass & DensityVolume, Mass & DensityCalculate the total mass (weight) of a load of 2 types of timber of the following density:
(a) European Spruce 430kg/m3
(b) Douglas Fir 527kg/m3
If 20 planks 4.8m x 225mm x 75mm of each species are to be carried on a lorry•Answer:
Volume of each stack = 20(4.8 x 0.225 x 0.075)
= 1.62m1.62m33
Mass of European Spruce = 1.62 x 430 = 696.6 kg696.6 kg
Mass of Douglas Fir = 1.62 x 527 = 853.74kg 853.74kg Total = 1,550.34kg1,550.34kg
