Vertical Circular Motion. Roller Coaster Twirling a Ball on a String Vertically x mg T T = 0; v cr...

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Vertical Circular Motion

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Transcript of Vertical Circular Motion. Roller Coaster Twirling a Ball on a String Vertically x mg T T = 0; v cr...

Page 1: Vertical Circular Motion. Roller Coaster Twirling a Ball on a String Vertically x mg T T = 0; v cr mg ma R T mg ma R T cannot be negative, the bob.

Vertical Circular Motion

Page 2: Vertical Circular Motion. Roller Coaster Twirling a Ball on a String Vertically x mg T T = 0; v cr mg ma R T mg ma R T cannot be negative, the bob.

Roller Coaster

Page 3: Vertical Circular Motion. Roller Coaster Twirling a Ball on a String Vertically x mg T T = 0; v cr mg ma R T mg ma R T cannot be negative, the bob.

Roller Coaster

Page 4: Vertical Circular Motion. Roller Coaster Twirling a Ball on a String Vertically x mg T T = 0; v cr mg ma R T mg ma R T cannot be negative, the bob.

Twirling a Ball on a String VerticallyTwirling a Ball on a String Vertically

gRvvgRv

mgR

vmTIfmg

R

vmT

R

vmmgT

R

vmF

topcrtopcr

net

__

22

22

or

0

x

mgT

T = 0; vcr

mgmaR

T

mgmaR T cannot be

negative, the bob will fall down!

mgmaR

Page 5: Vertical Circular Motion. Roller Coaster Twirling a Ball on a String Vertically x mg T T = 0; v cr mg ma R T mg ma R T cannot be negative, the bob.

If an object is moving in a circular path but at varying speeds, it must have a tangential component to its acceleration as well as the radial one.

Non-uniform Circular Motion

Page 6: Vertical Circular Motion. Roller Coaster Twirling a Ball on a String Vertically x mg T T = 0; v cr mg ma R T mg ma R T cannot be negative, the bob.

Ferris Wheel

Page 7: Vertical Circular Motion. Roller Coaster Twirling a Ball on a String Vertically x mg T T = 0; v cr mg ma R T mg ma R T cannot be negative, the bob.

Sustained vertical spinning• Ever wonder what a bike

tire feels like?• At constant speed, the

centripetal acceleration is constant (v2/r), but the direction of gravity keeps changing!

• Feel heavier at bottom than at top

• This ride definitely turns your world around!

Page 8: Vertical Circular Motion. Roller Coaster Twirling a Ball on a String Vertically x mg T T = 0; v cr mg ma R T mg ma R T cannot be negative, the bob.

Bucket of Water

WE,W

aNB,W

water

Page 9: Vertical Circular Motion. Roller Coaster Twirling a Ball on a String Vertically x mg T T = 0; v cr mg ma R T mg ma R T cannot be negative, the bob.

Bridges & Speed BumpsBridges & Speed Bumps

gRvN

m

NRgRv

R

vmNmg

R

vmF

Cr

net

0

2

2

The curvature of the bridge/bump and your speed determines if you are going to stay on the bump (N>0) or if you are going to bump: fly off it!

Page 10: Vertical Circular Motion. Roller Coaster Twirling a Ball on a String Vertically x mg T T = 0; v cr mg ma R T mg ma R T cannot be negative, the bob.

How fast do you need to drive to leave the ground?

Page 11: Vertical Circular Motion. Roller Coaster Twirling a Ball on a String Vertically x mg T T = 0; v cr mg ma R T mg ma R T cannot be negative, the bob.

Connected BodiesConnected Bodies

Two different masses (m < M) are connected

by a string going through a tube. Predict

what will happen when you whirl the

lighter mass with constant but high speed.

Base your prediction on the CM model.

m

M1. Mass M will be falling down since it is heavier

2. Mass M will be moving up and then stop

3. Mass M will move up and then will fall down

4. It is impossible to whirl the lighter mass around

Page 12: Vertical Circular Motion. Roller Coaster Twirling a Ball on a String Vertically x mg T T = 0; v cr mg ma R T mg ma R T cannot be negative, the bob.

Connected Bodies - AnalysisConnected Bodies - Analysis

m

MgRv

R

vmMg

TMgR

vmT

FR

vmF

Mnet

mnet

)cos(

)cos(

0

)cos(

0

2

2

_

2

_

If the mv2/R is > Mg, the mass M will accelerate upwards. Notice, the mass m will always rotate so the string is not horizontal. It happens so T has a vertical component to cancel out the mg!

m

M

T

mgx

y

Page 13: Vertical Circular Motion. Roller Coaster Twirling a Ball on a String Vertically x mg T T = 0; v cr mg ma R T mg ma R T cannot be negative, the bob.

Satellites in Circular Orbits

Page 14: Vertical Circular Motion. Roller Coaster Twirling a Ball on a String Vertically x mg T T = 0; v cr mg ma R T mg ma R T cannot be negative, the bob.

Weightlessness in Space Shuttle

Page 15: Vertical Circular Motion. Roller Coaster Twirling a Ball on a String Vertically x mg T T = 0; v cr mg ma R T mg ma R T cannot be negative, the bob.

Artifical Gravity


Gloss or y Principal of Mg t

Gloss or y Principal of Mg t

349 Mg t History

349 Mg t History

R v v Resultant force toward center F c = mv 2 R Consider TOP of circle: AT TOP: T mg T + mg + T = mv 2 R T = - mg mv 2 R.

R v v Resultant force toward center F c = mv 2 R Consider TOP of circle: AT TOP: T mg T + mg + T = mv 2 R T = - mg mv 2 R.

PLANE KINETICS OF RIGID BODIESgn.dronacharya.info/ECE2Dept/Downloads/question_papers/... · 2016. 4. 28. · F ma mg ma a m s F T T mg T T tdk t t t n dk A B A B 2.45 /2 2 4.905 at

PLANE KINETICS OF RIGID BODIESgn.dronacharya.info/ECE2Dept/Downloads/question_papers/... · 2016. 4. 28. · F ma mg ma a m s F T T mg T T tdk t t t n dk A B A B 2.45 /2 2 4.905 at

Mg Mg Ma Ma Chit Ma Wa

Mg Mg Ma Ma Chit Ma Wa

Review exercise 1€¦ · (1 sin ) substituting for from equation cos sin (1 sin ) tan cos cos T T mr F ma a r mg mr T mg mh mh ¬ (1) 2 2 as tan by basic trigonometry 1 sin sin r

Review exercise 1€¦ · (1 sin ) substituting for from equation cos sin (1 sin ) tan cos cos T T mr F ma a r mg mr T mg mh mh ¬ (1) 2 2 as tan by basic trigonometry 1 sin sin r

Department of Police and Emergency Management Hierarchy of ... Documents... · f d t 9 and EMERG ENCY MA T N f d t and MG MGMT Department of Police and Emergency Management 47 Liverpool

Department of Police and Emergency Management Hierarchy of ... Documents... · f d t 9 and EMERG ENCY MA T N f d t and MG MGMT Department of Police and Emergency Management 47 Liverpool

Scanned by CamScanner - mmu.edu.mm · Mg Thu Ya Win Htet Ma Wine Sat Sat Min Ma Thu Thu Naing Mg Kyaw Zin Mg Mg M g Htay Lin Aung Ma 00 00 Khin Ma Khin Sisar Naing Ma Myo Kyi Pyar

Scanned by CamScanner - mmu.edu.mm · Mg Thu Ya Win Htet Ma Wine Sat Sat Min Ma Thu Thu Naing Mg Kyaw Zin Mg Mg M g Htay Lin Aung Ma 00 00 Khin Ma Khin Sisar Naing Ma Myo Kyi Pyar

Min Thein Kha -- surveillance hnin mg ma mya lay

Min Thein Kha -- surveillance hnin mg ma mya lay

Friction. Newton’s Second Law W = mg W = mg Gives us F = ma Gives us F = ma.

Friction. Newton’s Second Law W = mg W = mg Gives us F = ma Gives us F = ma.

cyc Hz sec T - Flipping Physics...cosθ=mg F in =F T in =! F T sinθ=ma c =m v t 2 r ⎛ ⎝ ⎜ ⎞ ⎠ ∑ ⎟ v t =rωorv t = Δx Δt = C T = 2πr T F T cosθ=mg⇒F T = mg cosθ!

cyc Hz sec T - Flipping Physics...cosθ=mg F in =F T in =! F T sinθ=ma c =m v t 2 r ⎛ ⎝ ⎜ ⎞ ⎠ ∑ ⎟ v t =rωorv t = Δx Δt = C T = 2πr T F T cosθ=mg⇒F T = mg cosθ!

Selected Problems from Chapter 5. 1) mg T ma F=ma mg-T=ma T=m(g-a) T=700(9.8-3.8)= 4200 = 4.2 kN up.

Selected Problems from Chapter 5. 1) mg T ma F=ma mg-T=ma T=m(g-a) T=700(9.8-3.8)= 4200 = 4.2 kN up.

Deformation Mechanisms and High Strain Rate …Deformation Mechanisms and High Strain Rate Properties of Magnesium (Mg) and Mg Alloys by Bin Li, Logan Shannahan, Evan Ma, Kaliatt T.

Deformation Mechanisms and High Strain Rate …Deformation Mechanisms and High Strain Rate Properties of Magnesium (Mg) and Mg Alloys by Bin Li, Logan Shannahan, Evan Ma, Kaliatt T.

Siebel Order Mg t Infra

Siebel Order Mg t Infra

Mg t 303 Lecture Notes 3

Mg t 303 Lecture Notes 3

Crowd Mg t Guidelines

Crowd Mg t Guidelines

PRODUCT MONOGRAPH - Sandoz...Sandoz Diltiazem T Page 1 of 29 PRODUCT MONOGRAPH PrSANDOZ DILTIAZEM T Diltiazem Hydrochloride Extended-Release Capsules 120 mg, 180 mg, 240 mg, 300 mg

PRODUCT MONOGRAPH - Sandoz...Sandoz Diltiazem T Page 1 of 29 PRODUCT MONOGRAPH PrSANDOZ DILTIAZEM T Diltiazem Hydrochloride Extended-Release Capsules 120 mg, 180 mg, 240 mg, 300 mg

Mg t 501 Authentic Mcq s

Mg t 501 Authentic Mcq s

Linda Netterville, MA, RD, LD · Limit to 1,500 mg/day ... kcal. 834 kcal % Fat. 30%. 18%. Fiber. 7 gm. 9 g; Calcium. 400 mg. 1129 mg. Potassium. 1,200 mg. 1666 mg; Sodium. 1,200

Linda Netterville, MA, RD, LD · Limit to 1,500 mg/day ... kcal. 834 kcal % Fat. 30%. 18%. Fiber. 7 gm. 9 g; Calcium. 400 mg. 1129 mg. Potassium. 1,200 mg. 1666 mg; Sodium. 1,200

NDB No. 43205 Beverage, instant breakfast powder ......148.4 1.71 1.00 625 625 0 0 0 2083 0 0 9.37 9.37 0.0 0 90.0 mg mg mg mg mg mg µg µg µg µg mg mg µg µg ... NR Z Z T Protein

NDB No. 43205 Beverage, instant breakfast powder ......148.4 1.71 1.00 625 625 0 0 0 2083 0 0 9.37 9.37 0.0 0 90.0 mg mg mg mg mg mg µg µg µg µg mg mg µg µg ... NR Z Z T Protein