Verification of Clausius Clapeyron Equation
-
Upload
francis-anand -
Category
Documents
-
view
220 -
download
0
Transcript of Verification of Clausius Clapeyron Equation
7/22/2019 Verification of Clausius Clapeyron Equation
http://slidepdf.com/reader/full/verification-of-clausius-clapeyron-equation 1/2
Verification of Clausius Clapeyron Equation
Aim: To verify Clausius Clapeyron Equation by determining the Specific enthalpy of saturated water and
saturated steam
Apparatus: Fixed volume pressure cooker (3 liters), Pressure gauge (2Kg/cm2), digital thermometer and
a stove
Principle: The specific enthalpy of saturated water (h f ) depends on its pressure in accordance with the
equation, h = u + PV, by knowing the specific enthalpy of water at 1 atm and the specific enthalpy of
saturated steam the specific enthalpy of evaporations can be determined as the difference of the specificenthalpy of water and specific enthalpy of saturated steam
For saturated water the specific enthalpy at normal pressure of 1 atm = h f = 419kJ/kg
For saturated steam the specific enthalpy = hg = 2676kJ/kg
Therefore,
The specific enthalpy of evaporation hgf = hg -hf =2676 – 419 = 2257kJ/kg
Procedure:
1. The volume of the pressure cooker is noted as 3 litres.
2. The pressure cooker fitted with a pressure gauge is filled with water up to two third of
its volume.
3. The lid is closed and placed on hot plate which is switched on.
4. The digital thermometer is now placed in its position and the room temperature is noted as 28oC.
5. The rise in temperature with time is noticed by the thermometer. When temperature reaches 90oC,
both the temperature and pressure gauges are monitored carefully.
6. Above l00oC, the pressure in the gauge starts increasing. The temperature and pressure are
recorded in table, at suitable intervals of pressure until the pressure in the cooker is releasedthrough the whistle of the cooker. The readings obtained are tabulated in the tabular column.
7. A graph is drawn taking (ln P) on Y axis and ( 1/T) along X axis ,From the straight line graph, the
slope is calculated as
Slope = h1gf / R
R=8.3144J/mole
The molecular weight of water is 18, hence hgf = h1gf x l8 kJ/kg.
Result: The linearity of the graph proves the Clausius Clapeyron equation and the specific enthalpy of
evaporation hgf is found to be………………………………..J/kg
7/22/2019 Verification of Clausius Clapeyron Equation
http://slidepdf.com/reader/full/verification-of-clausius-clapeyron-equation 2/2
Tabular Column
TemperatureoC
Temperature
K
Pressure(P1)
Kg/cm2
Pressure (P)
Pascal (9.8 x P1) x104
ln (P) 1/T
x103 K -1
Graph:
lnP
1/T
Slope = AB/BC = h1gf / R