VECTORS AND THE GEOMETRY OF SPACE

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VECTORS AND THE GEOMETRY OF SPACE 10

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Transcript of VECTORS AND THE GEOMETRY OF SPACE

Page 1: VECTORS AND  THE GEOMETRY OF SPACE

VECTORS AND THE GEOMETRY OF SPACE

10

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10.2Vectors

VECTORS AND THE GEOMETRY OF SPACE

In this section, we will learn about:

Vectors and their applications.

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The term vector is used by scientists to

indicate a quantity (such as displacement

or velocity or force) that has both magnitude

and direction.

VECTOR

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A vector is often represented by

an arrow or a directed line segment.

The length of the arrow represents the magnitude of the vector.

The arrow points in the direction of the vector.

REPRESENTING A VECTOR

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We denote a vector by either:

Printing a letter in boldface (v)

Putting an arrow above the letter ( )

DENOTING A VECTOR

v

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For instance, suppose a particle

moves along a line segment from

point A to point B.

VECTORS

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The corresponding displacement vector v

has initial point A (the tail) and terminal point

B (the tip).

We indicate this by writing v = .

VECTORS

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Notice that the vector u = has the same

length and the same direction as v even

though it is in a different position. We say u and v are equivalent (or equal)

and write u = v.

VECTORS

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The zero vector, denoted by 0, has

length 0.

It is the only vector with no specific direction.

ZERO VECTOR

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Suppose a particle moves from A to B.

So, its displacement vector is .

COMBINING VECTORS

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Then, the particle changes direction,

and moves from B to C—with displacement

vector .

COMBINING VECTORS

BC��������������

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The combined effect of these

displacements is that the particle

has moved from A to C.

COMBINING VECTORS

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The resulting displacement vector

is called the sum of and .

We write:

COMBINING VECTORS

AC��������������

AB��������������

BC��������������

AC AB BC ������������������������������������������

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In general, if we start with vectors u and v,

we first move v so that its tail coincides with

the tip of u and define the sum of u and v

as follows.

ADDING VECTORS

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If u and v are vectors positioned so the initial

point of v is at the terminal point of u, then

the sum u + v is the vector from the initial

point of u to the terminal point of v.

VECTOR ADDITION—DEFINITION

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The definition of vector addition is

illustrated here.

VECTOR ADDITION

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You can see why this definition is

sometimes called the Triangle Law.

TRIANGLE LAW

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Here, we start with the same vectors u and v

as earlier and draw another copy of v with

the same initial point as u.

VECTOR ADDITION

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Completing the parallelogram,

we see that:

u + v = v + u

VECTOR ADDITION

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VECTOR ADDITION

This also gives another way to construct

the sum:

If we place u and v so they start at the same point, then u + v lies along the diagonal of the parallelogram with u and v as sides.

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PARALLELOGRAM LAW

This is called the Parallelogram

Law.

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Draw the sum of the vectors a and b

shown here.

VECTOR ADDITION Example 1

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VECTOR ADDITION

First, we translate b and place its tail at the tip

of a—being careful to draw a copy of b that

has the same length and direction.

Example 1

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Then, we draw the vector a + b starting at

the initial point of a and ending at the terminal

point of the copy of b.

VECTOR ADDITION Example 1

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VECTOR ADDITION

Alternatively, we could place b so it starts

where a starts and construct a + b by

the Parallelogram Law.

Example 1

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It is possible to multiply a vector

by a real number c.

MULTIPLYING VECTORS

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In this context, we call the real

number c a scalar—to distinguish

it from a vector.

SCALAR

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For instance, we want 2v to be the same

vector as v + v, which has the same direction

as v but is twice as long.

In general, we multiply a vector by a scalar

as follows.

MULTIPLYING SCALARS

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If c is a scalar and v is a vector, the scalar

multiple cv is:

The vector whose length is |c| times the length

of v and whose direction is the same as v if

c > 0 and is opposite to v if c < 0.

If c = 0 or v = 0, then cv = 0.

SCALAR MULTIPLICATION—DEFINITION

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The definition is illustrated here.

We see that real numbers work like scaling factors here.

That’s why we call them scalars.

SCALAR MULTIPLICATION

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Notice that two nonzero vectors are

parallel if they are scalar multiples of

one another.

SCALAR MULTIPLICATION

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In particular, the vector –v = (–1)v has the

same length as v but points in the opposite

direction.

We call it the negative of v.

SCALAR MULTIPLICATION

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SUBTRACTING VECTORS

By the difference u – v of two vectors,

we mean:

u – v = u + (–v)

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So, we can construct u – v by first drawing

the negative of v, –v, and then adding it to

u by the Parallelogram Law.

SUBTRACTING VECTORS

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Alternatively, since v + (u – v) = u,

the vector u – v, when added to v,

gives u.

SUBTRACTING VECTORS

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So, we could construct u by means of

the Triangle Law.

SUBTRACTING VECTORS

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If a and b are the vectors shown here,

draw a – 2b.

SUBTRACTING VECTORS Example 2

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First, we draw the vector –2b pointing in

the direction opposite to b and twice as long.

Next, we place it with its tail at the tip of a.

SUBTRACTING VECTORS Example 2

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Finally, we use the Triangle Law to

draw a + (–2b).

SUBTRACTING VECTORS Example 2

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COMPONENTS

For some purposes, it’s best to

introduce a coordinate system and

treat vectors algebraically.

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COMPONENTS

Let’s place the initial point of a vector a

at the origin of a rectangular coordinate

system.

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Then, the terminal point of a has coordinates

of the form (a1, a2) or (a1, a2, a3).

This depends on whether our coordinate system is two- or three-dimensional.

COMPONENTS

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COMPONENTS

These coordinates are called

the components of a and we write:

a = ‹a1, a2› or a = ‹a1, a2, a3›

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We use the notation ‹a1, a2› for the ordered

pair that refers to a vector so as not to confuse

it with the ordered pair (a1, a2) that refers to

a point in the plane.

COMPONENTS

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For instance, the vectors shown here are

all equivalent to the vector whose

terminal point is P(3, 2).

3,2OP ��������������

COMPONENTS

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What they have in common is that the terminal

point is reached from the initial point by a

displacement of three units to the right and

two upward.

COMPONENTS

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We can think of all these geometric vectors

as representations of the algebraic vector

a = ‹3, 2›.

COMPONENTS

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POSITION VECTOR

The particular representation from

the origin to the point P(3, 2) is called

the position vector of the point P.

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POSITION VECTOR

In three dimensions, the vector

a = = ‹a1, a2, a3›

is the position vector of the point P(a1, a2, a3).

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COMPONENTS

Let’s consider any other representation

of a, where the initial point is A(x1, y1, z1) and

the terminal point is B(x2, y2, z2).

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COMPONENTS

Then, we must have:

x1 + a1 = x2, y1 + a2 = y2, z1 + a3 = z2

Thus,

a1 = x2 – x1, a2 = y2 – y1, a3 = z2 – z1

Thus, we have the following result.

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COMPONENTS

Given the points A(x1, y1, z1) and B(x2, y2, z2),

the vector a with representation is:

a = ‹x2 – x1, y2 – y1, z2 – z1›

Equation 1

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COMPONENTS

Find the vector represented by the directed

line segment with initial point A(2, –3, 4) and

terminal point B(–2, 1, 1).

By Equation 1, the vector corresponding to is:

a = ‹–2 –2, 1 – (–3), 1 – 4› = ‹–4, 4, –3›

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Example 3

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LENGTH OF VECTOR

The magnitude or length of the vector v

is the length of any of its representations.

It is denoted by the symbol |v| or║v║.

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LENGTH OF VECTOR

By using the distance formula to compute

the length of a segment , we obtain

the following formulas.

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LENGTH OF 2-D VECTOR

The length of the two-dimensional (2-D)

vector a = ‹a1, a2› is:

2 21 2| |a a a

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LENGTH OF 3-D VECTOR

The length of the three-dimensional (3-D)

vector a = ‹a1, a2, a3› is:

2 2 21 2 3| |a a a a

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ALGEBRAIC VECTORS

How do we add vectors

algebraically?

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ADDING ALGEBRAIC VECTORS

The figure shows that, if a = ‹a1, a2›

and b = ‹b1, b2›, then the sum is

a + b = ‹a1 + b1, a2 + b2›

at least for the case

where the components

are positive.

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ADDING ALGEBRAIC VECTORS

In other words, to add

algebraic vectors, we add

their components.

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SUBTRACTING ALGEBRAIC VECTORS

Similarly, to subtract vectors,

we subtract components.

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ALGEBRAIC VECTORS

From the similar triangles in the figure,

we see that the components of ca are

ca1 and ca2.

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MULTIPLYING ALGEBRAIC VECTORS

So, to multiply a vector by a scalar,

we multiply each component by that

scalar.

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2-D ALGEBRAIC VECTORS

If a = ‹a1, a2› and b = ‹b1, b2›, then

a + b = ‹a1 + b1, a2 + b2›

a – b = ‹a1 – b1 , a2 – b2›

ca = ‹ca1, ca2›

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3-D ALGEBRAIC VECTORS

Similarly, for 3-D vectors,

1 2 3 1 2 3 1 1 2 2 3 3

1 2 3 1 2 3 1 1 2 2 3 3

1 2 3 1 2 3

, , , , , ,

, , , , , ,

, , , ,

a a a b b b a b a b a b

a a a b b b a b a b a b

c a a a ca ca ca

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ALGEBRAIC VECTORS

If a = ‹4, 0, 3› and b = ‹–2, 1, 5›,

find:

|a| and the vectors a + b, a – b, 3b, 2a + 5b

Example 4

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ALGEBRAIC VECTORS

2 2 24 0 3

= 25

= 5

Example 4

|a|

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ALGEBRAIC VECTORS

+ = 4, 0, 3 + 2, 1, 5

= 4 + ( 2), 0 + 1, 3 + 5

= 2, 1, 8

a bExample 4

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ALGEBRAIC VECTORS

= 4, 0, 3 2, 1, 5

= 4 ( 2), 0 1, 3 5

= 6, 1, 2

a bExample 4

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ALGEBRAIC VECTORS

3 = 3 2, 1, 5

= 3( 2), 3(1), 3(5)

= 6, 3, 15

bExample 4

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ALGEBRAIC VECTORS

2 + 5 = 2 4, 0, 3 5 2, 1, 5

= 8, 0, 6 10, 5, 25

= 2, 5, 31

a bExample 4

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COMPONENTS

We denote:

V2 as the set of all 2-D vectors

V3 as the set of all 3-D vectors

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COMPONENTS

More generally, we will later need to

consider the set Vn of all n-dimensional

vectors.

An n-dimensional vector is an ordered n-tuple

a = ‹a1, a2, …, an›

where a1, a2, …, an are real numbers that are called the components of a.

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COMPONENTS

Addition and scalar multiplication are

defined in terms of components just as

for the cases n = 2 and n = 3.

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PROPERTIES OF VECTORS

If a, b, and c are vectors in Vn and c and d

are scalars, then

1. + = + 2. + ( + ) = ( + ) +

3. + 0 = 4. + ( ) = 0

5. ( + ) = + 6. ( + ) = +

7. ( ) = ( ) 8. 1 =

c c c c d c d

cd c d

a b b a a b c a b c

a a a a

a b a b a a a

a a a a

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PROPERTIES OF VECTORS

These eight properties of vectors can

be readily verified either geometrically or

algebraically.

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PROPERTY 1

For instance, Property 1 can be seen from

this earlier figure.

It’s equivalent to the Parallelogram Law.

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PROPERTY 1

It can also be seen as follows for the case

n = 2:

a + b = ‹a1, a2› + ‹b1, b2›

= ‹a1 + b1, a2 + b2›

= ‹b1 + a1, b2 + a2›

= ‹b1, b2› + ‹a1, a2›

= b + a

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PROPERTY 2

We can see why Property 2 (the associative

law) is true by looking at this figure and

applying the Triangle Law several times, as

follows.

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PROPERTY 2

The vector is obtained either by first

constructing a + b and then adding c or by

adding a to the vector b + c.

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VECTORS IN V3

Three vectors in V3 play

a special role.

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VECTORS IN V3

Let

i = ‹1, 0, 0›

j = ‹0, 1, 0›

k = ‹0, 0, 1›

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STANDARD BASIS VECTORS

These vectors i, j, and k are called

the standard basis vectors.

They have length 1 and point in the directions of the positive x-, y-, and z-axes.

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STANDARD BASIS VECTORS

Similarly, in

two dimensions,

we define:

i = ‹1, 0›

j = ‹0, 1›

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STANDARD BASIS VECTORS

If a = ‹a1, a2, a3›, then we can write:

1 2 3

1 2 3

1 2 3

, ,

,0,0 0, ,0 0,0,

1,0,0 0,1,0 0,0,1

a a a

a a a

a a a

a

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STANDARD BASIS VECTORS Equation 2

1 2 3a a a a i j k

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STANDARD BASIS VECTORS

Thus, any vector in V3

can be expressed in terms

of i, j, and k.

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STANDARD BASIS VECTORS

For instance,

‹1, –2, 6› = i – 2j + 6k

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STANDARD BASIS VECTORS

Similarly, in two dimensions, we can

write:

a = ‹a1, a2› = a1i + a2j

Equation 3

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COMPONENTS

Compare the geometric interpretation

of Equations 2 and 3 with the earlier

figures.

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COMPONENTS

If a = i + 2j – 3k and b = 4i + 7k,

express the vector 2a + 3b in terms

of i, j, and k.

Example 5

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COMPONENTS

Using Properties 1, 2, 5, 6, and 7 of vectors,

we have:

2a + 3b = 2(i + 2j – 3k) + 3(4i + 7k)

= 2i + 4j – 6k + 12i + 21k

= 14i + 4j + 15k

Example 5

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UNIT VECTOR

A unit vector is a vector whose

length is 1.

For instance, i, j, and k are all unit vectors.

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UNIT VECTORS

In general, if a ≠ 0, then the unit vector

that has the same direction as a is:

1| |

| | | |

au a

a a

Equation 4

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UNIT VECTORS

In order to verify this, we let c = 1/|a|.

Then, u = ca and c is a positive scalar; so, u has the same direction as a.

Also, 1| | | | | || | | | 1

| |c c u a a a

a

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UNIT VECTORS

Find the unit vector in

the direction of the vector

2i – j – 2k.

Example 6

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UNIT VECTORS

The given vector has length

So, by Equation 4, the unit vector with the same direction is:

2 2 2| 2 2 | 2 ( 1) ( 2)

9 3

i j k

1 2 1 23 3 3 3(2 2 ) i j k i j k

Example 6

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APPLICATIONS

Vectors are useful in many aspects of

physics and engineering.

In Chapter 13, we will see how they describe the velocity and acceleration of objects moving in space.

Here, we look at forces.

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FORCE

A force is represented by a vector because

it has both a magnitude (measured in pounds

or newtons) and a direction.

If several forces are acting on an object, the resultant force experienced by the object is the vector sum of these forces.

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FORCE

A 100-lb weight hangs from two wires.

Find the tensions (forces) T1 and T2

in both wires and their magnitudes

Example 7

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FORCE

First, we express T1 and T2

in terms of their horizontal and

vertical components.

Example 7

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FORCE

From the figure, we see that:

T1 = –|T1| cos 50° i + |T1| sin 50° j

T2 = |T2| cos 32° i + |T2| sin 32° j

E. g. 7—Eqns. 5 & 6

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FORCE

The resultant T1 + T2 of the tensions

counterbalances the weight w.

So, we must have:

T1 + T2 = –w

= 100 j

Example 7

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FORCE

Thus,

(–|T1| cos 50° + |T2| cos 32°) i

+ (|T1| sin 50° + |T2| sin 32°) j

= 100 j

Example 7

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FORCE

Equating components, we get:

–|T1| cos 50° + |T2| cos 32° = 0

|T1| sin 50° + |T2| sin 32° = 100

Example 7

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FORCE

Solving the first of these equations for |T2|

and substituting into the second,

we get:

11

| | cos50| | sin 50 sin 32 100

cos32

T

T

Example 7

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FORCE

So, the magnitudes of the tensions are:

1

100| | 85.64 lb

sin 50 tan 32 cos50

T

12

| | cos50| | 64.91 lb

cos32

T

T

Example 7

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FORCE

Substituting these values in Equations 5

and 6, we obtain the tension vectors

T1 ≈ –55.05 i + 65.60 j

T2 ≈ 55.05 i + 34.40 j

Example 7