MEAN DEVIATIONCalculate the mean deviation from the mean for the following data.40, 60, 35, 10, 70, 80, 15, 20, 30, 20Mean = 380/10 =38X D(x-mean)40 260 2235 310 2870 3280 4215 23 20 1830 820 18Mean deviation =19.6

QUARTILE DEVIATIONFrom the following calculate the quartile deviation and coefficientAnd quartile deviation.250, 275, 135, 152,173, 129,186Q 1 = 135, Q 3 = 250Q.D = Q3-Q1 / 2 = 250-135/2 = 57.5COEFFICIENT OF Q.D = Q3-Q1 / Q3+Q1 = 250-135 / 250+135 = 0.298

REGRESSIONFind the regression equation of the following data.xY

2543

2846

3549

3241

3636

3632

2931

3830

3433

3239

SUMMARY OUTPUT

Regression Statistics

Multiple R0.418081323

R Square0.174791993

Adjusted R Square0.071640992

Standard Error3.966172921

Observations10

Observations10

ANOVA

dfSSMSFSignificance F

Regression126.6557788926.655781.694525420.229236355

Residual8125.844221115.73053

Total9152.5

CoefficientsStandard Errort StatP-valueLower 95%Upper 95%Lower 95.0%Upper 95.0%

Intercept42.334170857.6580428555.5280670.0005550924.6746923659.9936524.6746959.99365

X Variable 1-0.258793970.198806285-1.301740.22923636-0.7172420840.199654-0.717240.199654

The regression equation of x on y is -0.25879397y + 42.33417085

PAIRED TWO SAMPLE FOR MEANSA random sample of 10 boys has the I.Q level of 70, 120,110, 101, 88, 83, 95, 98, 107, 100Do these data support the assumption of a population mean I.Q of 100 ?t-Test: Paired Two Sample for Means

Variable 1Variable 2

Mean97.2100

Variance203.7333330

Observations1010

Pearson Correlation#DIV/0!

Hypothesized Mean Difference0

df9

t Stat-0.620336

P(T