Unit 4: Right Triangles Triangle Inequality Pythagorean Theorem and its Converse Trigonometry...
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Transcript of Unit 4: Right Triangles Triangle Inequality Pythagorean Theorem and its Converse Trigonometry...
Unit 4: Right Triangles
• Triangle Inequality
• Pythagorean Theorem and its Converse
• Trigonometry
• Inverse Trigonometry
• Solving Right Triangles
Lesson 4.1
• Triangle Inequality
• Converse of the Pythagorean Theorem
• More Classifying Triangles
Triangle Inequality
• The sum of the lengths of any two sides of a triangle is greater than the length of the third side.
Practice the Triangle Inequality
• Can the following lengths represent the sides of a triangle?
1) 5, 4, 3Yes, add any two together and they are larger than the third side.
2) 5, 6, 7Yes, add any two together and they are larger than the third side.
3) 5, 5, 10No, 5+5 is equal to 10, not greater than 10.
Special Parts in a Right Triangle
• Right triangles have special names that go with it parts.
• For instance:– The two sides that form the right angle are called
the legs of the right triangle.
– The side opposite the right angle is called the hypotenuse.
• The hypotenuse is always the longest side of a right triangle.
legs
hypotenuse
Pythagorean Theorem
• c2 = a2 + b2
– c is always the hypotenuse– a and b are the legs in any order
a
b
c
Converse of the Pythagorean Theorem
• If c2 = a2 + b2 is true, then the triangle in question is a right triangle.– You need to verify the three sides of the triangle given will make
the Pythagorean Theorem true when plugged in.
– Remember the largest number given is always the hypotenuse• Which is c in the Pythagorean Theorem
Acute Triangles fromPythagorean Theorem
• If c2 < a2 + b2, then the triangle is an acute triangle.– So when you check if it is a right triangle and the answer for c2 is
smaller than the answer for a2 + b2, then the triangle must be acute
• It essentially means the hypotenuse shrunk a little!• And the only way to make it shrink is to make the right angle shrink
as well!
a
b
c
Obtuse Triangles fromPythagorean Theorem
• If c2 > a2 + b2, then the triangle is an obtuse triangle.– So when you check if it is a right triangle and the answer for c2 is
larger than the answer for a2 + b2, then the triangle must be obtuse
• It essentially means the hypotenuse grew a little!
• And the only way to make it grow is to make the right angle grow as well!
a
b
c
Practice
Determine if the following sides create triangle. If they do determine if it is a right, obtuse, or an acute triangle.
A) 38, 77, 86 B) 10.5, 36.5, 37.5
c2 = a2 + b2
clongest side
c2 = a2 + b2
862 = 382 + 772 37.52 = 10.52 + 36.52
7396 = 1444 + 5929 1406.25 = 110.25 + 1332.25
7396 = 7373 1406.25 = 1442.57396 > 7373 1406.25 < 1442.5
obtuse acute
Triangle Y/N Triangle Y/N
Right Triangle?
Lesson 4.3
Trigonometric Ratios
Trigonometric Ratios
• A trigonometric ratio is a ratio of the lengths of any two sides in a right triangle.
• You must know:– one angle in the triangle other than the right angle
– one side (any side) of the triangle.
• These help find any other side of the triangle.
Sine
• The sine is a ratio of– side opposite the known angle, and…– the hypotenuse
• Abbreviated– sin
• This is used to find one of those sides.– Use your known angle as a reference point
θ
a
b
c
sin θ = side opposite θ
hypotenuse
b= c
Cosine• The cosine is a ratio of
– side adjacent the known angle, and…– the hypotenuse
• Abbreviated– cos
• This is used to find one of those sides.– Use your known angle as a reference point
θa
b
c
cos θ = side adjacent θ
hypotenuse
a= c
Tangent• The tangent is a ratio of
– side opposite the known angle, and…– side adjacent the known angle
• Abbreviated– tan
• This is used to find one of those sides.– Use your known angle as a reference point
θa
b
c
tan θ = side opposite θ
side adjacent θ
b=
a
SOHCAHTOA• This is a handy way of
remembering which ratio involves which components.
• Remember to start at the known angle as the reference point.
• Also, each combination is a ratio– So the sin is the
opposite side divided by the hypotenuse
Soh
Cah
Toa
in
pposite
ypotenuse
os
djacent
ypotenuse
anpposite
djacent
Example 5
• First determine which trig function you want to use by identifying the known parts and the variable side.
• Use that function on your calculator to find the decimal equivalent for the angle.
• Set that number equal to the ratio of side lengths and solve for the variable side using algebra.
If you do not have a calculator with trig buttons, then turn to p845 in book for a table of all trig ratios up to 90o.
x7
42o
4x37o
xsin 42o =
77 (sin 42o) = x
7 (.6691) = x = 4.683
4cos 37o =
x
Get x out of denominator first by multiplying both sides by x.
x (cos 37o) = 4x =
4cos 37o=
4.7986 = 5.008
Lesson 4.4
Inverse Trigonometric Ratios: Solving for missing angles in a right
triangle.
Inverse Trig RatiosInverse trig ratios are used to find the measure of the angles of a triangle.
The catch is…you must know two side lengths.
Those sides determine which ratio to used based on the same ratios we had from before.
SOHCAHTOA
Finding Side Lengths Finding Angle Measures
sin sin-1
cos cos-1
tan tan-1
Example 8
• You still base your ratio on what sides are you working with compared to the angle you want to find.
• Only now, your variable is θ.• So once you find your ratio, you will then use the
inverse function of your ratio from your calculator
47
θ
917θ
SOHCAHTOA
sin θ = 4
7θ = sin-1
θ = sin-1 .5714
θ = 34.8o
cos θ = 917
θ = cos-1
θ = cos-1 .5294
4
7917
θ = 58.0o