Unit .2

21
Copyright © 2011 Pearson, Inc. P.2 Cartesian Coordinat e System

description

Unit .2

Transcript of Unit .2

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P.2Cartesian

Coordinate System

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What you’ll learn about

Cartesian Plane Absolute Value of a Real Number Distance Formulas Midpoint Formulas Equations of Circles Applications

… and whyThese topics provide the foundation for the material that

will be covered in this textbook.

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The Cartesian Coordinate Planeor Rectangular Coordinate System

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Quadrants

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Absolute Value of a Real Number

The is

, if 0

| | if 0.

0, if 0

a a

a a a

a

absolute value of a real number a

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Example Using the Definition of Absolute Value

Evaluate:

7

5

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Solution

Evaluate:

7 7

because 7 0, 4 7 7

5 5 5 because 3.14, 5 0

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Properties of Absolute Value

Let a and b be real numbers.

1. | a |0

2. | -a || a |

3. | ab || a || b |

4. a

b

| a |

| b |, b 0

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Distance Formula (Number Line)

Let a and b be real numbers.

The distance between a and b is a b .

Note that a b b a .

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Distance Formula (Coordinate Plane)

The distance d between points P x1 , y1 and Q x2 , y2 in the coordinate plane is

d x1 x2 2 y1 y2 2.

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The Distance Formula using the Pythagorean Theorem

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Example Finding the Distance Between Two Points

(2,7) and 5,3

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Solution

d 2 5 2 7 3 2

3 2 4 2

9 16

25

5

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Midpoint Formula (Number Line)

The midpoint of the line segment

with endpoints a and b is

a b

2.

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Midpoint Formula (Coordinate Plane)

The midpoint of the line segment

with endpoints (a,b) and (c,d ) is

a c

2,b d

2

.

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Standard Form Equation of a Circle

The standard form equation of a circle

with center (h,k)and radius r is

(x h)2 (y k)2 r2 .

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Standard Form Equation of a Circle

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Example Finding Standard Form Equations of Circles

Find the standard form equation of the

circlewith center (2, 3) and radius 4.

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Example Finding Standard Form Equations of Circles

(x h)2 (y k)2 r2 where h 2, k 3,and r 4.

Thus the equation is (x 2)2 (y 3)2 16.

Find the standard form equation of the

circlewith center (2, 3) and radius 4.

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Quick Review

2 2

2 2

2 2

-5 31. Find the distance between and .

4 2Use a calculator to evaluate the expression. Round answers

to two decimal places.

2. 8 6

-12 83.

2

4. 3 5

5. 2 5 1 3

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Quick Review Solutions

2 2

2 2

2 2

-5 31. Find the distance between and .

4 2Use a calculator to evaluate the expression. Round answers

to two decimal places.

2. 8 6

-12 83.

2

4. 3 5

5. 2

2.75

10

-2

5.83

3.5 1 3 61