Unit 10 – The Mole
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Transcript of Unit 10 – The Mole
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Unit 10 – The Mole
Essential Questions:•What is the relationship between a mole of a substance and its mass?•How can the mole of a substance be calculated?•How can the percent composition of a compound be determined?•How does the molecular formula of a compound compare with the empirical formula?
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Molecular and Formula Masses The sum of the masses of all the atoms in a
compound Molecular Mass – mass in a molecule (covalent) Formula Mass – mass in a formula unit (ionic) Unit is amu for either of them
Example: Formula Mass of CaCO3
1 atom of Ca = 40.08 amu = 40.08 amu 1 atom of C = 12.01 amu = 12.01 amu 3 atoms of O = 3 x 16.00 amu = 48.00 amu
100.08 amu
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Example:
Find the formula mass of (NH4)2SO3
2 N = 2(14.01 amu) = 28.02 amu8 H = 8(1.01 amu) = 8.08 amu1 S = 32.07 amu = 32.07 amu3 O = 3(16.00 amu) = 48.00 amu
1 formula unit = 116.17 amu
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Try these problems:
1.HNO3
2.C6H10O5
3.Al3(PO4)2
= 63.02 amu
= 162.16 amu
= 270.88 amu
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Mole
• A counting number (like a dozen)
• 6.02 X 1023 (in scientific notation)
• This number is named in honor of Amedeo Avogadro (1776 – Amedeo Avogadro (1776 – 1856)1856)• Discovered that no matter
what the gas was, there were the same number of molecules present in the same volume
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Mole – 6.02 x 1023
particles
1 mole C
1 mole H2O
1 mole NaCl
= 6.02 x 1023 C atoms
= 6.02 x 1023 H2O
molecules
= 6.02 x 1023 NaCl formula units
6.02 x 1023 Na+ ions and
6.02 x 1023 Cl– ions
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Avogadro’s Number as Conversion Avogadro’s Number as Conversion FactorFactor
Particles = Moles 6.02 x 1023 particles
1 mole
Or Moles = Particles 1 mole
6.02 x 1023 particles
Note that a particle could be an atom
OR a molecule!
You MUST use dimensional analysis for
conversions!
X
X
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Examples:
How many molecules are in 3.5 moles of H2O?
How many moles are present in 465 molecules of NO2?
How many atoms of nitrogen are in 3.15 moles of NH3?
How many atoms of chlorine are in .862 moles of MgCl2?
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Molar Mass
Molar Mass- the mass of one mole of a substance
Unit is grams/mole (g/mole or g/mol) Equivalent to the molecular mass in
amu
Ex: molar mass of Iron = 55.85 g /mole molecular mass of Iron = 55.85 amu
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Mass and Mole Relationships1.Find the number of moles
present in 56.7 g of HNO3.2.Find the number of grams
present in 4.5 moles of C6H10O5.
3.Find the number of moles present in 12.31 g of H2SO4.
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Percent Composition
Finding what percent of the total weight of a compound is made up of a particular element
Formula for calculating % composition:
Total amu of the element in the compound
Total formula amu
X 100%
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Example
Calculate the % composition of BeO
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Example
Calculate the % composition of Ca(OH)2
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Example
Calculate the % composition of Al(NO3)3
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Chemical Formulas
Formulas give the relative numbers Formulas give the relative numbers of atoms or moles of each element of atoms or moles of each element in a formula unit - always a whole in a formula unit - always a whole number ratio (number ratio (the law of definite the law of definite proportionsproportions).).
1 molecule NO1 molecule NO22 : 2 atoms of O for : 2 atoms of O for every 1 atom of Nevery 1 atom of N
1 mole of NO1 mole of NO22 : 2 moles of O atoms : 2 moles of O atoms to every 1 mole of N atomsto every 1 mole of N atoms
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Law of Multiple Proportions When any two elements, A and B,
combine to form more than one compound, the different masses of B that unite with a fixed mass of A bear a small whole-number ratio to each other
Example: In H2O, the proportion of H:O = 2:16 or
1:8 In H2O2, H:O is 2:32 or 1:16
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Empirical vs. Molecular Formula Empirical Formula - The formula of
a compound that expresses the smallest whole number ratio of the atoms present.Ionic formulas are always empirical formulas
Molecular Formula - The formula that states the actual number of each kind of atom found in one molecule of the compound.
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Determine the Empirical Formula From the Molecular FormulaAll you need to do is reduce!!1.C6H6
2.Fe3(CO)9
3.BaCl2
4.P4O10
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Determine the Molecular Formula from the Empirical Formula Calculate the molar mass of the
Empirical Formula. Divide the molar mass of the
Molecular Formula by the molar mass of the Empirical Formula
Multiply the numbers of each type of atom by that number
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Determine the Molecular Formula from the Empirical Formula Examples:
Molecular Mass: 26.04 g/mol Empirical Formula: CH
Molecular Formula: C2H2
Molecular Mass: 380.88 g/mol Empirical Formula: SeO3
Molecular Formula Se3O9
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**Remember this**Percent to massMass to moleDivide by smallMultiply 'til whole
To Obtain Empirical To Obtain Empirical FormulaFormula 1.1. Assume the percent is out of Assume the percent is out of
100 grams. That means you can 100 grams. That means you can change the % sign to grams.change the % sign to grams.
2.2. Calculate the number of Calculate the number of molesmoles of of each element.each element.
3.3. Divide each by the smallest Divide each by the smallest number of moles to obtain the number of moles to obtain the simplest whole number ratio.simplest whole number ratio.
4.4. If whole numbers are not If whole numbers are not obtainedobtained** in step 3), multiply in step 3), multiply through by the smallest number through by the smallest number that will give all whole numbersthat will give all whole numbers
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Calculating the Empirical Formula Example #1
Given that a compound is composed of 60.0% Mg and 40.0% O, find the empirical formula.
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Calculating the Empirical Formula Example #2
A compound is analyzed and is found to contain 13.5g of calcium, 10.8g of oxygen, and 0.675g of hydrogen. Calculate the empirical formula of this compound.
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Calculating the Empirical Formula Example #3:
NutraSweet is a zero calorie sweetener used in many food products. A sample is analyzed and it’s percent composition is as follows; 57.14% carbon, 6.16% hydrogen, 9.52% nitrogen, and the rest is oxygen. Calculate the empirical formula of NutraSweet.
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Try this!
A compound is found to contain 68.5% carbon, 8.63% hydrogen, and 22.8% oxygen. The molecular weight of this compound is known to be approximately 140.00 g/mol. Find the empirical and molecular formulas.