Unit 1 Maths Mark Scheme (1560)
Transcript of Unit 1 Maths Mark Scheme (1560)
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General Certificate of Secondary Education
Mathematics
4360 Specification
43602H
Mark SchemePractice Paper Set 1
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Mark Schemes
Principal Examiners have prepared these mark schemes for practice papers. These mark schemes have not,therefore, been through the normal process of standardising that would take place for live papers.
Further copies of this ark !cheme are available to download from the "#" $ebsite% www.a&a.org.uk
Copyright © 2010 AQA and its licensors. All rights reserved.
The Assessment and Qualifications Alliance (AQA) is a company limited by guarantee registered in England and Wales 364473 and registered charitynumber !"73334#$egistered address AQA% &e'as treet% anchester !* 6E+
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"#" '(!E athematics ) *nit 2 +igher Tier , ark !cheme Practice Paper
Glossary for Mark Schemes
'(!E examinations are marked in such a wa- as to award positive achievement wherever possible. Thus,
for '(!E athematics papers, marks are awarded under various categories.
M ethod marks are awarded for a correct method which could leadto a correct answer.
A "ccurac- marks are awarded when following on from a correct
method. t is not necessar- to alwa-s see the method. This can beimplied.
!
arks awarded independent of method.
ark for #ualit- of $ritten (ommunication /#$(
M dep " method mark dependent on a previous method mark being
awarded.
dep " mark that can onl- be awarded if a previous independent markhas been awarded.
ft Follow through marks. arks awarded following a mistake in an
earlier step.
SC !pecial case. arks awarded within the scheme for a commonmisinterpretation which has some mathematical worth.
oe 1r e&uivalent. "ccept answers that are e&uivalent.
eg, accept 0. as well as2
3
4
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ark !cheme Practice Paper ) *nit 2 +igher Tier , "#" '(!E athematics
"nit 2 Hi#her $ier
% !ight of 300 and 2 or 2 3
5 "3
2&a' 602 73
2&(' 4.28 73
2&c' 60.2 9 42.8 3
662.: "3
3 /40;300 × 4:0 or 338 3 oe
4:0 ) their 338 "3 80;300 × 4:0 scores 2
/50 ÷ 4 or 3;4 < 50 or 34 3 oe not 3;4 of 50 or use of 40= or 44= for 3;4
50 ) their 34 "3 2;4× 50 scores 2
284 and 280 "3
!&uare,e-es or correct
conclusion from their working#3 /iii valid conclusion with working clearl- shown
4 < /28 , ,: > 4 3
< their 4? > 4 3 or < their 32
?0 "3 < 36 > 4 @ 40A scores 2 marks /one error
) 4 x 9 5 = 2 x 3
4 x ) 2 x = ,5 3
x = ,5 "3
!(3 for attempt at finding an output from aninput
!(2 for two attempts at finding outputs from twodifferent inputs with at least one input being
negative
6 25 56 82 B?0 320 B
3 or correct factor tree or repeated division for 25or ?0
identifies 320 "3
/packs of envelopes
2 /packs of address labels "3
5
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"#" '(!E athematics ) *nit 2 +igher Tier , ark !cheme Practice Paper
* 5.6 ) 5 or 0.6 3
0.6 < 300 5
3
20 "3!(2 for 20;300
!(3 for 3; or 0.2 oe
Alternate method
5.6 < 3005
3
320 "3
20 "3
+&a' ) 4 x 9 ? 3 allow one numerical or sign error
33 ) 4 x "3
+&(' x2 9 8 x ) x ) 4 3must have four termsA allow one numerical orsign error
x2 9 2 x ) 4 "3
,sight of 40 9 k B and B2/their 40 9 k 9 k
3
2/their 40 9 k 9 k = 63 3
k = 8 "3
/3st term = 5 "3
/ii logical working with ke- stepsclearl- shown
#3 do not award for TC
Alternate method --- (y $./
"ttempt to multipl- 3 b- 2 andadd an- number B and B
multipl- their answer b- 2 andadd the same number
3
"ttempt to subtract an- number from 63 anddivide b- 2 B and B
subtract the same number from their answerand divide b- 2
Defined attempt 3 must be closer to 63 /or to 3 than 3st attempt
k = 8 "3
/3st term = 5 "3 do not award #3 mark for TC
%0 ( 4 x 9 2 y 25 73
E y x 73
F y ) 5 2 x 73
%%&a' t 12 73
%%&(' w12 73
%%&c' 6 x -2 y4 or 6 y4/ x2 72 73 for two correct components
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ark !cheme Practice Paper ) *nit 2 +igher Tier , "#" '(!E athematics
%2ultipl-ing all terms b- /multiple
of 203
or valid attempt to subtract the fractions on the
G+! using a common denominator
6 x 9 32 ) x 9 30 3 allow one error
4 x 9 22 = 30 "3 4 x 9 22 = 3;2 scores "0
/ x = ,5 "3ft
ft from one arithmetic or sign error but not from a
conceptual error /such as on the line above
eg. sign error in 930 term leads to4 x 9 2 @ 30 /"0 and x @ 6;4 /"3ft
%3&a' ?.368 < 306 73
%3&(' 0.00:05 73
%4 x = bma – x! 3
x = bma – bmx 3
x " bmx = bma 3 - bma = -x - bmx
x1 " bm! = bma 3 - bma = x-1 # bm!
x = $ bma $
1 " bm! "3
x = $-bma $
-1 # bm!
%) a @ ,? 73
b @ 33 73
%6 √8√8 9 √8 ) √8 ) 3 3 5 termsA at least 4 correct
? "3
/y @ their ? < √4 √4 √4
3
/y = 2√4 "3
correct solution with all steps
clearl- shown#3 /ii
%*&a' x2 " x # % # 4 =0! 3
x2 " x # 12 =0! 3
x " 4! x # &! =0! 3 x " a! x " b! =0! 'here ab = (12
-4 and & "3
%*&(' n " 4!2 " n " 4! # 4n – n2 3 n2 " n # 4n # 4! # n # 4!2
n2 " %n " 16 " n " 4 # 4n – n2 3dep n2 " n # 4n " 16 # n2 " %n # 16
)n " 20 or )n " 4! "3 )n
mathematicall- correct andlogical argument ... clearl- shown
#3 /ii
?