Uniform Circular Motion (Ch 6) Uniform Circular Motion,...
Transcript of Uniform Circular Motion (Ch 6) Uniform Circular Motion,...
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Uniform Circular Motion (Ch 6)
• A force, Fr , is directed towardthe center of the circle
• This force is associated withan acceleration, ac
• Applying Newton’s SecondLaw along the radial directiongives
Uniform Circular Motion, cont
• A force causing acentripetal acceleration actstoward the center of thecircle
• It causes a change in thedirection of the velocityvector
• If the force vanishes, theobject would move in astraight-line path tangent tothe circle
Centripetal Force
• The force causing the centripetal accelerationis sometimes called the centripetal force
• This is not a new force, it is a new role for aforce
• It is a force acting in the role of a force thatcauses a circular motion
Conical Pendulum (HW Prob 9)
• The object is in equilibrium inthe vertical direction andundergoes uniform circularmotion in the horizontaldirection
• Newton’s 2nd Law says:
z
r
2
Motion in a Horizontal Circle
• The speed at which the object movesdepends on the mass of the object and thetension in the cord
• The centripetal force is supplied by thetension
Horizontal (Flat) Curve
• The force of static friction suppliesthe centripetal force
• The maximum speed at which the carcan negotiate the curve is given by:
• Solve for v. Does it depend on themass of the car?
Banked Curve
• These are designed withfriction equaling zero
• There is a component of thenormal force that supplies thecentripetal force
Loop-the-Loop
• This is an example of avertical circle
• At the bottom of the loop (b),the upward force experiencedby the object is greater than itsweight
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Loop-the-Loop, Part 2
• At the top of the circle(c), the force exerted onthe object is less thanits weight
Non-Uniform Circular Motion
• The acceleration and forcehave tangential components
• Fr produces the centripetalacceleration
• Ft produces the tangentialacceleration
• ΣF = ΣFr + ΣFt
Vertical Circle with Non-UniformSpeed
• The gravitational force exertsa tangential force on theobject• Look at the components of Fg
• The tension at any point canbe found
Top and Bottom of Circle
• The tension at the bottom is amaximum
• The tension at the top is a minimum• If Ttop = 0, then
you can then solve for minimumspeed at top(HW Prob 17)
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Motion in Accelerated Frames
• A fictitious force results from an acceleratedframe of reference• A fictitious force appears to act on an object in the
same way as a real force, but you cannot identifya second object for the fictitious force
“Centrifugal” Force
• From the frame of thepassenger (b), a forceappears to push her towardthe door
• From the frame of the Earth,the car applies a leftward forceon the passenger
• The outward force is oftencalled a centrifugal force• It is a fictitious force due to the
acceleration associated with thecar’s change in direction
“Coriolis Force”
• This is an apparent forcecaused by changing theradial position of an object ina rotating coordinate system
• The result of the rotation isthe curved path of the ball
Fictitious Forces, examples
• Although fictitious forces are not real forces,they can have real effects
• Examples:• Objects in the car do slide
• You feel pushed to the outside of a rotatingplatform
• The Coriolis force is responsible for the rotation ofweather systems and ocean currents
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Fictitious Forces in Linear Systems
• The inertial observer (a) sees
• The noninertial observer (b)sees
Fictitious Forces in a RotatingSystem
• According to the inertial observer (a), the tension is the centripetalforce
• The noninertial observer (b) sees
Motion with Resistive Forces
• NOTE: this will not be on exam
• Motion can be through a medium• Either a liquid or a gas
• The medium exerts a resistive force, R, on an objectmoving through the medium
• The magnitude of R depends on the medium
• The direction of R is opposite the direction of motionof the object relative to the medium
• R nearly always increases with increasing speed
• For objects moving at high speeds throughair, the resistive force is approximately equalto the square of the speed
• R = ½ DρAv2
• D is a dimensionless empirical quantity that calledthe drag coefficient
• ρ is the density of air
• A is the cross-sectional area of the object
• v is the speed of the object
Air Resistance: R Proportional To v2