Understanding the PDA Pile Stress Wave

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    -400

    -200

    0

    200

    400

    600

    800

    0 1 2 3 4 5 6

    Force&

    Vel*Z(Tons)

    t/(L/c)

    SWA plot

    Piletop force

    Force

    Vel*Z

    Wave up

    Wave down

    PDA Force

    PDA Vel*Z

    PDA Wup

    PDA Wdn

    I"35 ;36& *&.E+5 *8=*E$8$&9@

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    0

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    1

    1.2

    1.4

    1.6

    1.8

    2

    0 5 10 15 20 25 30 35 40

    FORCE

    TIME

    EFFECT OF Z

    1

    2

    5

    10

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    0.2

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    3"6%$(&)"* U

    0

    0.1

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    0.6

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    0 5 10 15 20 25 30 35 40

    FORCE

    TIME

    EFFECT OF Vo

    H = 0.6

    0.8

    1

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    0.3

    0.4

    0.5

    0.6

    0.7

    0.8

    0.9

    1

    0 5 10 15 20 25 30 35 40

    FORCE

    TIME

    EFFECT OF W1

    KeepingZ=1,K=,

    vary W

    2

    5

    10

    0.5

    0.2

    !"#$% '#((") * +,)-" +,..,/0

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    1 E. A.

    L.

    Smith, Pile driving analysis by the wave equation,

    J.

    Soil Mech. Found. ASCE, 86 35-61, 1960).

    2

    G. G. Goble and F. Rausche,

    WEAP8 6 program documentation in

    4

    Vols.

    Federal Highway Administration,Office of

    ,-$4%$76(/ P4%

  • 7/23/2019 Understanding the PDA Pile Stress Wave

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    Implementation, Washington DC, 1986.

    3

    F. Rausche, G. G. Goble and G. E Likins, Recent WEAP developments,

    Proc. 3rd Int. Con on Application of

    Sires-Wave Theory

    to

    Piles ,

    Ottawa, 1988, pp. 164-173.

    4. P. Midde ndorp and

    A

    F. van Weele, Application of characteristic tress wave method in offshore practice,

    Proc. 3rd

    Int.

    Con

    on Numerical Methods in Ofshore Piling,

    Nantes, Supplement, 1986, pp. 6-18.

    5 M. F. Randolph, Analysisof the dynamics of pile driving, n P.

    K

    Banerjee and R Buttefield eds.),

    Developments

    in

    oil Mechanics V: Advanced Geotechnical Analyses, Elsevier Applied Science, also Univers ity

    o

    Western Aus tralia

    Research Repor t No. G1001,

    1991.

    APPENDIX I: SOLUTION OF RAM/CUSHION/ANVIL MODEL

    The Laplace transform for the anvil velocity in the ram/cushion/anvil model is

    r

    Naming th e coefficients of the cubic denominator

    298 A J

    DEEKS

    A N D M F R A N D O L P H

    equation 32) can be written as

    a

    L g

    a + a s + u2s2 + s3

    Letting

    and

    if p is greater than zero, the cubic denominator of equation (58) has one real root and two

    imaginary roots. The inverse transform can be found readily if the following substitutions are

    made:

    This allows the cubic denominator to be factorized, and equation (58) becomes

    a0

    (S

    bi ) [ ( s

    + b2 2+ 01

    lif

    which can be expanded to

    Llif a {

    s + b 2 +

    w2

    + (b2 1 ) 2

    s +

    bl S + b2)2+ w

    S + b2) + w2

    Performing the inverse Laplace transform, the anvil velocity can be found.

    af a

    e -b if -bz f (coswt* + b,--b,sinut*)]

    m + b2

    l)

    This solution can be written in a simpler, more convenient form by making

    c a

    c1 bl

    c2

    b2

    l, 4 arctan-, F, ___

    w + cz

    The anvil velocity and the force on the pile head are then

    The spring force can be found by using the equilibrium equation

    f, n:

    + if

    HAMMER IMPACT FOR PI LE DRIVING

    299

    Differentiating equation 70), substituting into equation 71), and simplifying, he spring force can

    be expressed as

    where

    For most combinations of

    rn

    and

    kr

    p2

    is greater than zero, and the solution presented above

    applies. For a small range of combinations,

    p2

    is less than or equal to zero, and a different

    solution must be used. When this

    is

    the case, the cubic denominator has three real roots, and

    equation

    58)

    can be written in the following way:

    0

    + 271

    b 2 = ~ + 2 J Q c o s -

    3

    a 0

    f

    471

    b3 ~ J Q c o s

    3

    0

    arccos

    6)

    If bl, b2 and b3 are all distinct, equation 74) becomes

    1

    1

    Lti:

    =

    a

    +

    s

    + bI) b2 l) b3 l) S + b2) bl 2) b3 2)

    +

    S f b3) bl 3) b2 3)

    and the solution

    is

    given by

    f ,*

    Fp(e-blr*

    , ~ - b 2 t , ~ - b t )

    with

    300 A

    J DEEKS AND

    M. F.

    RANDOLPH

    The force in the spring is

    with

    86)

    a2 2 b3 z

    a2 l b3 l

    a2

    3 bz l

    a2

    , b2 3

    As

    ______

    Bs=--

    o a2

    l)

    2 l ) b 3 l

    Fs b

    However, iftwo of the roots are the same, the solution is different again. When is zero and

    b3 is

    equal to b Z , he solution becomes

    f t

    = F,e-clr* [l -c2r l b , t * ) ]

    f

    FSe-lr*[l -c2* 1

    b z A s t * ) ]

    @$?ka I"(/876(/ N4#$/)"* 4? D(

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