Tutorial 13 Planar dynamics of rigid body

15
Tutorial 13 Planar dynamics of rigid body Zhengjian, XU DEC 3rd, 2008

description

Tutorial 13 Planar dynamics of rigid body. Zhengjian, XU DEC 3rd, 2008. Rotation about a fixed axis for a mass point. Angular momentum:. Where H is the angular momentum with respect to the center of mass. Calculation of moment of inertia. A. O. B. A bar:. L. y. Rectangle:. h. O. - PowerPoint PPT Presentation

Transcript of Tutorial 13 Planar dynamics of rigid body

Tutorial 13 Planar dynamics of

rigid bodyZhengjian, XU

DEC 3rd, 2008

Rotation about a fixed axis for a mass point

dt

dmm

vrarFr

vrv

rvr

mdt

d

dt

dm

dt

md

)(

MH

Fr dt

dAngular momentum:

Where H is the angular momentum with respect to the center of mass

Calculation of moment of inertia dmrrmI

m

ii 22

Circle:

Rectangle:

A bar:2

12

1mlIO

A BO

L

2

3

1mlII BA

x

y

O

2

12

1mhI x 2

12

1mbI y

)(12

1 22 bhmIO

O x

y

b

h

R2

4

1mRIO

2

8

1mRII yx

Another method: parallel-axis method

Example 1 A horizontal force F = 30 lb is applied to the 230-lb refrigerator as

shown. Friction is negligible. (a) What is the magnitude of the refrigerator’s acceleration? (b) What normal forces are exerted on the refrigerator by the floor at

A and B?

Solution: Assume the box doesnot tip over, then the box

has only horizontal velocity and acceleration.

NA NB

F

G28in

60in

28in

Vx, axxx

maF F

0 BAyNNGF

0141432 BAONNFM

Force equilibrium:

What’s the condition of F for tipping?

O

2ft/s2.4xa

lb7.80AN lb3.149BN

Example 2 Bar AB rotates with a constant angular velocity of 10 rad/s in the co

unterclockwise direction. The masses of the slender bars BC and CDE are 2 kg and 3.6 kg, respectively. The y axis points upward.

Determine the components of the forces exerted on bar BC by the pins at B and C at the instant shown.

Bx

By

Cy

Cx

B

C

C

D

ECx

Cy

1. Dynamics analysis:

xBCxx amCB G

yBCyy amCB

Moment equlibrium equations

BCBCyxyx ICCBB )35.02.0()35.02.0(

CDDCEy IC 40.0

Bx

By

Cy

Cx

2 Kinematics analysis

B

C

C

D

E

VBVC

At this instant, point A is the instantaneous center of BC.

ABABAB

BCABBCB

R

Rv

400

400

CDCDCE

BCACBCC

R

Rv

400

700

Cx

Cy

rad/s 10 ABBC

rad/s 5.174

7 BCCD

)(m/s jjja 2B 404.0100)( 2 ABAB R

BCBCBC2

BC RαR)(aa BCFrom AB-BC:

From CD: jijiaC CDCDCDCDCD α.RαR 405.122)( 2

From the kinematics analysis:

rad/s 10BC

rad/s 5.17CD