Trigonometry and Vectors Applied to 2D Kinematics Teacher Excellence Workshop June 19, 2009.
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Transcript of Trigonometry and Vectors Applied to 2D Kinematics Teacher Excellence Workshop June 19, 2009.
Trigonometry and Vectors Applied to 2D Kinematics
Teacher Excellence WorkshopJune 19, 2009
There are two kinds of quantities…
Vectors are quantities that have both magnitude and direction, such as… distance, speed, mass, heat, temperature,
time…etc.
Scalars are quantities that have magnitude only, such as… displacement, velocity, acceleration, force…
etc.
Direction of Vectors Vectors are drawn as rays, or
arrows. An angle gives the direction.
Ax
Typical vector angle ranges
x
yQuadrant I0 < < 90o
Quadrant II90o < < 180o
Quadrant III180o < < 270o
Quadrant IV270o < < 360o
Direction of Vectors What angle range would this vector have? What would be the exact angle, and how
would you determine it?
Bx
Between 180o and 270o
or between-270o and -180o
Magnitude of Vectors The magnitude of a vector is the size of
whatever the vector represents. Graphically, the magnitude is represented by
the length of the vector. Symbolically, the magnitude is represented
as │A│or A
AIf vector A represents a displacement of three miles to the north…
B
Then vector B, which is twice as long, would represent a displacement of six miles to the north!
Trigonometry needed for High School Physics pythagorean theorem
sin, cos, tan (SOHCAHTOA) sin-1, cos-1, tan-1
θ
opposite
adjacent
hypotenuse
2 2 2hypotenuse adjacent opposite
A
B
RA + B = R
Graphical Addition of Vectors
R is called the resultant vector!
B
A
B
R A + B = R
The Equilibrant Vector
The vector -R is called the equilibrant. It is the inverse of the resultant. Whenever you add a vector and its inverse, you get zero.
-R
Getting components from a vector
y component
A
x
y
Ay
Ax
cos
cos
cos
x
x
adjacent
hypotenuse
A
AA A
x component
sin
sin
sin
y
y
opposite
hypotenuse
A
AA A
Getting a vector from components
angle
A
x
y
Ay
Ax
2
2 2
2 2 2
2 2
x y
x y
hypotenuse
adjacent opposite
A A A
A A A
magnitude
1
1
tan
tan
tan y
x
opposite
adjacent
opposite
adjacent
A
A
Component Addition of Vectors
1) Resolve each vector into its x- and y-components.
2) Add the x-components together to get Rx and the y-components to get Ry.
3) Calculate the magnitude of the resultant with the Pythagorean Theorem (R2 = Rx
2 + Ry2).
4) Determine the angle with the inverse tangent equation ( = tan-1 Ry/Rx.)
Vector Addition Lab
1. Attach spring scales to force board such that they all have different readings.
2. Slip graph paper between scales and board and carefully trace your set up.
3. Record readings of all three spring scales.4. Detach scales from board and remove graph paper.5. On top of your tracing, draw a force diagram by
constructing vectors proportional in length to the scale readings. Point the vectors in the direction of the forces they represent. Connect the tails of the vectors to each other in the center of the drawing.
6. On a separate sheet of graph paper, add together graphically. the three vectors
7. Then add the three vectors by component. 8. Did you get a resultant? Did you expect one? How
big is it compared to your vectors? What does the resultant represent?
Relative Motion Relative motion problems are difficult to
do unless one applies vector addition concepts.
Let’s consider a swimmer in a river. Define a vector for a swimmer’s velocity
and another vector for the velocity of the water relative to the ground. Adding those two vectors will give you the velocity of the swimmer relative to the ground.
Relative Motion
Vs
Vw
Vobs = Vs + Vw
Vw
Relative Motion
Vs
Vw
Vobs = Vs + Vw
Vw
Relative Motion
Vs
Vw
Vobs = Vs + Vw
Vw
Practice Problem: You are paddling a canoe in a river that is flowing at 4.0 mph east. You are capable of paddling at 5.0 mph.a)If you paddle east, what is your velocity relative to the shore?
b)If you paddle west, what is your velocity relative to the shore?
c)You want to paddle straight across the river, from the south to the north. At what angle to you aim your boat relative to the shore? Assume east is 0o.
Practice Problem: You are paddling a canoe in a river that is flowing at 4.0 mph east. You are capable of paddling at 5.0 mph.a)If you paddle east, what is your velocity relative to the shore?
b)If you paddle west, what is your velocity relative to the shore?
c)You want to paddle straight across the river, from the south to the north. At what angle to you aim your boat relative to the shore? Assume east is 0o.
Key to Solving 2-D Problems
1. Resolve all vectors into components x-component Y-component
2. Work the problem as two one-dimensional problems.
Each dimension can obey different equations of motion.
3. Re-combine the results for the two components at the end of the problem.
Sample problem: A particle passes through the origin with a speed of 6.2 m/s traveling along the y axis. If the particle accelerates in the negative x direction at 4.4 m/s2
. What are the x and y positions at 5.0 seconds?
Sample problem: A particle passes through the origin with a speed of 6.2 m/s traveling along the y axis. If the particle accelerates in the negative x direction at 4.4 m/s2
. What are the x and y positions at 5.0 seconds?
Projectile Motion
Something is fired, thrown, shot, or hurled near the earth’s surface.
Horizontal velocity is constant and not accelerated.
Vertical velocity is accelerated. In most high school physics
classes, air resistance is ignored.
Launch Angle Launch angles can range from -90o
(throwing something straight down) to +90o (throwing something straight up) and everything in between.
90°
(up) (down)-90°
(up and out)
40° 0°
(horizontal)
Sample problem: Playing shortstop, you throw a ball horizontally to the second baseman with a speed of 22 m/s. The ball is caught by the second baseman 0.45 s later.
a) How far were you from the second baseman?
b) What is the distance of the vertical drop?
Sample problem: Playing shortstop, you throw a ball horizontally to the second baseman with a speed of 22 m/s. The ball is caught by the second baseman 0.45 s later.
a) How far were you from the second baseman?
b) What is the distance of the vertical drop?
Problem: A soccer ball is kicked with a speed of 9.50 m/s at an angle of 25o above the horizontal. If the ball lands at the same level from which is was kicked, how long was it in the air?
Problem: A soccer ball is kicked with a speed of 9.50 m/s at an angle of 25o above the horizontal. If the ball lands at the same level from which is was kicked, how long was it in the air?
Projectile over level ground
x
y
Range
Mathematically, the trajectory is defined by a highly symmetric parabola. The projectile spends half its time traveling up, the other half traveling down.
MaximumHeight
Acceleration of a projectile
g
g
g
g
g
x
y
Acceleration points down at 9.8 m/s2 for the entire trajectory of all projectiles.
Velocity of a projectile
vy
vx
vx
vy
vx
vy
vx
x
y
vx
vy
The velocity is tangent to path and can be resolved into components.
Position graphs for 2-D projectiles
x
y
t
y
t
x
Velocity graphs for 2-D projectiles
t
Vy
t
Vx
Acceleration graphs for 2-D projectiles
t
ay
t
ax
Derive the range equation:
R = vo2sin(2)/g.