Total Program

5/13/2018 Total Program - slidepdf.com

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/* area of triangle with sides a, b, c*/

#include<stdio.h>

#include<conio.h>

#include<math.h>float area(float a, float b, float c);

void main()

{

float a, b, c, z;

clrscr();

printf("\nenter three sides of the triangle:");

scanf("%f%f%f", &a, &b, &c);

z=area(a, b, c);

printf("\n\n area of the triangle=%3f", z);

getch();

}

/*function to calculate area from a formula*/

float area(float a, float b, float c)

{

float s, m, x;

s=(a+b+c)/2;

m=s*(s-a)*(s-b)*(s-c);

x=sqrt(m);

return(x);

}

******************************output***************************

enter three sides of the triangle:8 9 6



/*calculation of aggregate percentage marks*/

#include <stdio.h>

#include <conio.h>

void main(){

int m1,m2,m3,m4,m5,aggr;

float per;

clrscr();

printf("\nenter marks in 5 subjects:");

scanf("%d%d%d%d%d",&m1,&m2,&m3,&m4,&m5);

aggr=m1+m2+m3+m4+m5;

per=aggr/ 5;

printf("\n aggregate marks=%d",aggr);

printf("\n percentage marks =%f", per);

printf("\n\n\n\n\npress any key to exit....");

getch() ;

}

****************************************output**************

enter marks in 5 subjects:98 59 88 69 80

aggregate marks=394

percentage marks =78.000000

press any key to exit....



/* program to find a number & its frequency in array */

#include<stdio.h>

#include<conio.h>

void main()

{ int num[25], i, count=0,n;

clrscr();

printf("\nenter 25 elements of array:\n");

for(i=0; i<=24; i++)

scanf("%d", & num[i]); /* array elements */

printf("\nenter an element to search:");

scanf("%d", &n);

for(i=0; i<=24; i++)

{

if(num[i]==n)

count++;

}

printf("\nthe number%d found%d time(s) in the array", n,

count);

printf("\n\n\n\n\npress any key to exit.....");

getch();

}

*********************************output************************

enter 25 elements of array:

34 45 2 78 54 23 45 9 4 23 45 65 19 78 34 56 78 24 7 45 23 32 43

76 8

enter an element to search:56

the number56 found1 time(s) in the array

press any key to exit.....



/*program to calculate power of a value*/

#include<stdio.h>

#include<conio.h>

long power(int,int);

void main(){

int x,y;

long pow;

clrscr();

printf("enter two number:");

scanf("%d%d", &x, &y);

pow=power(x,y); /*function call*/

printf("\n%d to the power %d=%d", x,y, pow);

printf("\n\n\n\n\n press any key to exit.....");

getch();

}

long power(int x, int y)

{ int i;

long p=1;

for(i=1; i<=y; i++)

p=p*x;

return(p);

}

**********************output*******************************

enter two number:25 3

25 to the power 3=15625




/*check if point lies within a circle*//*the center of the circle has been assumed to be at o,o*/

#include<stdio.h>

#include<conio.h>

void main()

{

int x,y,r;

int dis,d;

clrscr();

printf("\n enter the radius of the circle & coordinates of the

point(x,y):\n");

scanf("%d%d%d",&r,&x,&y);

dis= x*x+y*y; /*or use poe() function*/

d=r*r;

if(dis==d)

printf("\n point is on the circle");

else

{

if(dis>d)

printf("point is outside the circle");

else

printf("point is inside the");

}

printf("\n\n\n\n\n press any key to exit....");

getch();

}

*****************************output**********************

enter the radius of the circle & coordinates of the point(x,y):

3 6,3

point is outside the circle




/* to find greatest number using conditional operators */

#include<stdio.h>

#include<conio.h>

void main()

{ int n1, n2, n3, great;

clrscr();

printf("enter three numbers:");

scanf("%d%d%d", &n1, &n2, &n3);

great= n1>n2?(n1>n3?n1:n3):(n2>n3?n2:n3);

printf("greatest number is:%d", great);

printf("\n\n\n\n\npress any key to exit.........");

getch();

}

******************output*****************

enter three numbers: 25 58 36

greatest number is:58

press any key to exit.........



/*conversion of distance*/

#include<stdio.h>

#include<conio.h>

void main()

{ float km, m, cm, ft, inch;

clrscr();

printf("\nenter the distance in kilometers:");

scanf("%f",&km);

m=km*1000;

cm=m*100;

inch=cm/2.54;

ft=inch/12;

printf("\ndistabce in meters=%f",m);

printf("\ndistance in centimeter=%f",cm);

printf("\ndistance in feet=%f",ft);

printf("\ndistance in inches=%f",inch);

printf("\n\n\n\n\npress any key to exit.....");

getch();

}

*********************output**************************

enter the distance in kilometers:9

distabce in meters=9000.000000

distance in centimeter=900000.000000

distance in feet=29527.560547

distance in inches=354330.718750




/*interchanging of contents of two variable c&d*/

#include<stdio.h>

#include<conio.h>

void main(){

int c,d,e;

clrscr();

printf("\nenter the number of location c:");

scanf("%d",&c);

printf("\nenter the number of location d:");

scanf("%d",&d);

/*interchanging the contents of two variables using a third

variables as temporary store*/

e=c;

c=d;

d=e;

printf("\nnew number at location c=%d",c);

printf("\nnew number at location d=%d",d);

printf("\n\n\n\n\npress any key to exit.......");

getch();

}

********************************output*******************

enter the number of location c:69

enter the number of location d:36

new number at location c=36

new number at location d=69

press any key to exit.......



/*sum of digits of a 5 digits number*/

#include<stdio.h>

#include<conio.h>

void main()

{ int num,a,n;

int sum=0; /*sum initialised tozero as otherwise it will

contain garbage value*/

clrscr();

printf("\nenter a 5 digit number( less than 32767)");

scanf("%d",&num);

a=num%10; /*last digit extracted as remainder*/

n=num/10; /*remaining digits*/sum=sum+a; /*sum updated with

addition of extracted digit*/

a=n%10; /*4th digit*/

n=n/10;

sum= sum+a;

a=n%10; /*3rd digit*/

n=n/10;

sum=sum+a;

a=n%10; /*2nd digit*/

n=n/10;

sum=sum+a;

a=n%10; /*1st digit*/

sum=sum+a;

printf("\n the sum of the 5 digits of %d is %d",num,sum);

printf("\n\n\n\n\npress any key to exit....");

getch();

}

*****************************output*********************

enter a 5 digit number( less than 32767)12345

the sum of the 5 digits of 12345 is 15




/*binary equivalent of a decimal number*/

#include<stdio.h>

#include<conio.h>

int binary(int);

void main(){

int num;

clrscr();

printf("\nenter the number:");

scanf("%d", &num);

binary(num); /*factorial call*/

printf("\n\n\n\npress any key to exit.....");

getch();

}

/*function to convert decimal to binary*/

int binary(int n)

{

int r;

r=n%2;

n=n/2;

if(n==0)

{

printf("\n the binary equivalent is %d", r);

return(r);

}

else

binary(n); /*recursive call*/

printf("%d", r);}

****************************output*******************************

enter the number:97

the binary equivalent is 1100001




/*to display particular pattern*/

#include<stdio.h>

#include<conio.h>

void main()

{ int i, j, k, l, sp;

sp=20;

for(i=1, k=1; i<5; i++)

{

for(l=1; l<=sp; l++)

printf(" ");

sp=2;

for(j=1; j<=i; j++, k++)

printf("%d",k);

printf("\n");

}


getch();

}

**********************output***********************

1

23

456

78910




/*to display a particular pascal’s triangle series*/

#include<stdio.h>

#include<conio.h>

void main()

{ int i,j, k, t, f1, f2, f3, z, sp;sp=20;

clrscr();

for(i=0; i<=4; i++)

{ for(k=0; k<sp-i; k++)

printf(" ");

sp-=2;

for(j=0; j<=i; j++)

{

f1=f2=f3=1;

t=i;

while(t!=0)

{

f1=f1*t;

t--;

}

t=j;

while(t!=0)

{

f2=f2*t;

t--;

}

t=i-j;

while(t!=0){

f3=f3*t;

t--;

}

z=f1/(f2*f3);

printf("%4d ",z);

}

printf("\n");

}

getch();

}

***************************output****************************

1

1 1

1 2 1

1 3 3 1

1 4 6 4 1



/*check whether a number is even or odd*/

#include<stdio.h>

#include<conio.h>

void main()

{ int n;

clrscr();

printf(" enter any number");

scanf("%d",&n);

if(n%2==0) /*remainder after division by 2*/

printf("\nthe number is even");

else

printf("\n the number is odd");


getch();

}

*********************************OUTPUT*******************

enter any number361

the number is odd




/*BUBBLE sort*/

#include<stdio.h>

#include<conio.h>

void main()

{ int a[25], i, j, m, t;

clrscr();

printf("\n enter 25 numbers:");

for(i=0; i<=24; i++)

scanf("%d", &a[i]); /*enter array elements*/

for(i=0; i<=24; i++) /*number of passes*/

{

for(j=0; j<24-i; j++) /* start anthor loop from begning*/

{

/*compare an element with the next element one by one*/

if(a[j]> a[j+1])

{

t=a[j]; /* interchange the two if first is great*/

a[j]=a[j+1];

a[j+1]=t;

}

}

}

printf("\n sorted number are:\n");

for(i=0; i<=24; i++)

printf("%d ", a[i]);


getch();}

*************************output***************************

enter 25 numbers:5 6 9 3 5 1 7 85 36 25 32 9 56 1 5 16 25 36 98

57 21 12 35 26 56

sorted number are:

1 1 3 5 5 5 6 7 9 9 12 16 21 25 25 26 32 35 36 36 56 56 57 85 98




/*Generate first 25 terms of fibonacci sequence*/

#include<stdio.h>

#include<conio.h>

void fibo(int, int);

void main(){

int i, t, old=0, current=1, new;

clrscr();

printf("%d %d ", old, current);

fibo(old, current);


getch();

}

void fibo(int old, int current)

{

static int terms=2;

int new;

if(terms<20)

{

new=old+current ;

printf("%d ", new);

terms=terms+1;

fibo(current, new);

}

else

return;

}

************************output*******************

0 1 1 2 3 5 8 13 21 34 55 89 144 233 377 610 987 1597 2584 4181




/* to calculate gross salary of ramesh*/

#include <stdio.h>

#include <conio.h>

void main(){

float bp,da ,hra,grpay;

clrscr(); /*clears screen*/

printf("\nenter the basic pay of ramesh:");

scanf("%f",&bp);

da = 0.4*bp;

hra = 0.2*bp;

grpay = bp+da+hra;/*gross pay = sum of basic & all

allowances*/

printf("\nbasic pay of ramesh =%f",bp);

printf("\ndearness allowance =%f",da);

printf("\nhouse rent allowance=%f",hra);

printf("\ngross pay of ramesh is %f",grpay);

printf("\n\n\n\n\npress any key to exit.........");

getch(); /*reads a character from keyboard*/

}

*****************************output********************

enter the basic pay of ramesh:10000

basic pay of ramesh =10000.000000

dearness allowance =4000.000000

house rent allowance=2000.000000

gross pay of ramesh is 16000.000000

press any key to exit.........



/* insertion sort */

#include<stdio.h>

#include<conio.h>

void main()

{ int a[25], i, j, k, t;

clrscr();

printf("\nenter 10 number:\n");

for(i=0; i<=9; i++)

scanf("%d", &a[i]); /* enter array elements */

for(i=1; i<=9; i++) /* number of passes */

{

t=a[i];

for(j=0; j<i; j++)

{

if(t<a[j])

{

for(k=i; k>=j; k--)

a[k]=a[k-1]; /* interchange elements */

a[j]=t;

break;

}

}

}

printf("\n sorted numbers are:\n");

for(i=0; i<=9; i++)

printf(" %d", a[i]);

printf("\n\n\n\n\n press any key to exit.......");getch();

}

***********************output********************************

enter 10 number:

56 89 25 36 75 32 15 45 65 36

sorted numbers are:

15 25 32 36 36 45 56 65 75 89




/*calculate factorial value of an integer using a function*/

#include<stdio.h>

#include<conio.h>

long fact(int); /*will word upto num=19 only*/

void main()

{

int num;

long factorial;

clrscr();

printf("enter a number:");

scanf("%d", &num);

factorial=fact(num); /*function call*/

printf("\nfactoria; of %d=%1d", num, factorial);


getch() ;

}

long fact(int num)

{

int i;

long factorial=1;

for(i=1; i<=num;i++)

factorial=factorial*i;

return(factorial);

}

*****************************output***************************

enter a number:7

factoria; of 7=5040




/*determine leap or not a leap year*/

#include<stdio.h>

#include<conio.h>

void main()

{ int year;

clrscr();

printf("\n enter year");

scanf("%d", &year);

if(year%400==0|| year % 100 !=0 && year % 4==0)

printf("\n leap year");

else

printf("\n not a leap year");


getch();

}

************************output********************

enter year2008

leap year




/* program to addition two 3*3 matrices */

#include<stdio.h>

#include<conio.h>

void main()

{ int mat1[3][3], mat2[3][3], mat3[3][3], i, j, k, sum;

clrscr();

/* get values for first matrix */

printf("\nenter values for first 3*3 matrix:\n");

for(i=0; i<=2; i++)

{

for(j=0; j<=2; j++)

scanf("%d", &mat1[i][j]);

}

/* get values for second matrix */

printf("\nenter values for second 3*3 matrix:\n");

for(i=0; i<=2; i++)

{

for(j=0; j<=2; j++)


}

/* print the first matrix as entered */

printf("\nthe first 3*3 matrix entered by you is:\n");

for(i=0; i<=2; i++)

{

for(j=0; j<=2; j++)

printf("%d\t", mat1[i][j]);

printf("\n");

}

/* print the second matrix as entered */

printf("\nthe second 3*3 matrix entered by you is:\n");

for(i=0; i<=2; i++)

{

for(j=0; j<=2; j++)


printf("\n");

}

/* calculate the addition of the two matrices */for(i=0; i<=2; i++)

{

for(j=0; j<=2; j++)

mat3[i][j]=mat1[i][j]+mat2[i][j];

}



/* print the new matrix containg the product */

printf("\nthe addition of the above two matrices is:\n");

for(i=0;i<=2;i++)

{

for(j=0; j<=2; j++)printf("%d\t", mat3[i][j]);

printf("\n");

}

printf("\n\npress any key to exit.......");

getch();

}

***************************output**********************

enter values for first 3*3 matrix:

1 2 3 4 5 6 7 8 9

enter values for second 3*3 matrix:

9 8 7 4 5 6 1 2 3

the first 3*3 matrix entered by you is:

1 2 3

4 5 6

7 8 9

the second 3*3 matrix entered by you is:

9 8 7

4 5 61 2 3

the addition of the above two matrices is:

10 10 10

8 10 12

8 10 12




/* program to Addition two 3*3 matrices */

#include<stdio.h>

#include<conio.h>

void main(){

int mat1[3][3], mat2[3][3], mat3[3][3], i, j, k, sum;

clrscr();

/* get values for first matrix */

printf("\nenter values for first 3*3 matrix:\n");

for(i=0; i<=2; i++)

{

for(j=0; j<=2; j++)


}

/* get values for second matrix */

printf("\nenter values for second 3*3 matrix:\n");

for(i=0; i<=2; i++)

{

for(j=0; j<=2; j++)


}

/* print the first matrix as entered */

printf("\nthe first 3*3 matrix entered by you is:\n");

for(i=0; i<=2; i++)

{

for(j=0; j<=2; j++)

printf("%d\t", mat1[i][j]);printf("\n");

}

/* print the second matrix as entered */

printf("\nthe second 3*3 matrix entered by you is:\n");

for(i=0; i<=2; i++)

{

for(j=0; j<=2; j++)


printf("\n");

}/* calculate the product of the two matrices */

for(i=0; i<=2; i++)

{

for(j=0; j<=2; j++)

{

sum=0;

for(k=0; k<=2; k++)



sum=sum+mat1[i][k]*mat2[k][j];

mat3[i][j]=sum;

}

}

/* print the new matrix containg the product */

printf("\nthe product of the above two matrices is:\n");

for(i=0;i<=2;i++)

{

for(j=0; j<=2; j++)


printf("\n");

}

printf("\n\npress any key to exit.......");

getch();

}

*************************************output***********************

******

enter values for first 3*3 matrix:

1 2 3 4 5 6 7 8 9

enter values for second 3*3 matrix:

9 8 7 4 5 6 1 2 3

the first 3*3 matrix entered by you is:

1 2 3

4 5 67 8 9

the second 3*3 matrix entered by you is:

9 8 7

4 5 6

1 2 3

the product of the above two matrices is:

20 24 28

62 69 76

104 114 124




/*program for 1223334444

55555 */

#include"stdio.h"

#include"conio.h"

void main()

{

int i,j,n;

printf(" Enter any number ");

scanf("%d",&n);

for(i=1;i<=n;i++)

{

for(j=1;j<=i;j++)

{

printf("%d",i);

}

printf("\n");

}

getch();

}

**********************************output************************

Enter any number 9

1

22333

4444

55555

666666

7777777

88888888

999999999



/*program for 1121231234

12345 */

#include"stdio.h"

#include"conio.h"

void main()

{

int i,j,n;


scanf("%d",&n);

for(i=1;i<=n;i++)

{

for(j=1;j<=i;j++)

{

printf("%d",j);

}

printf("\n");

}

getch();

}

*******************************output************************

Enter any number 9

1

12123

1234

12345

123456

1234567

12345678

123456789



/*program for 12 34 5 66 8 9 10

11 12 13 14 */

#include"stdio.h"

#include"conio.h"

void main()

{

int i,j,n,a=1;


scanf("%d",&n);

for(i=1;i<=n;i++)

{

for(j=1;j<=i;j++)

{

printf(" %d ",a);

a++;

}

printf("\n");

}

getch();

}

**************output************************

Enter any number 91

2 3

4 5 6

7 8 9 10

11 12 13 14 15

16 17 18 19 20 21

22 23 24 25 26 27 28

29 30 31 32 33 34 35 36

37 38 39 40 41 42 43 44 45



/*program to generate all prime numbers from 1to 300*/

#include<stdio.h>

#include<conio.h>

void main()

{ int i, n=1;

clrscr();

printf("\n prime numbers between 1&300 are: \n1\t");

while(n<=300) /*loop to check numbers upto 300*/

{

i=2;

while(i<n) /*loop starting from 2 to the number*/

{

if(n%i==0)

break; /*takes control out of the inner while as soon

as the number is fully divisible*/

else

i++;

}

if(i==n)

printf("%d\t", n); /*tab is used to print all number in

one screen*/

n++;

}

getch();

}

********************************output**************************

prime numbers between 1&300 are:

1 2 3 5 7 11 13 17 19

23

29 31 37 41 43 47 53 59 61

67

71 73 79 83 89 97 101 103

107 109

113 127 131 137 139 149 151 157

163 167173 179 181 191 193 197 199 211

223 227

229 233 239 241 251 257 263 269

271 277 281 283 293



/*program to produce a typical pattern*/

#include<stdio.h>

#include<conio.h>

void main()

{ int i=1, x=71, blanks=0, j, val, k;

clrscr();

while(i<=7)

{

j=65; /*ascii value of a*/

val=x;

while(j<=val)

{

printf(" %c",j);

j++;

}

if(i==1)

val--;

k=1;

while(k<=blanks)

{

printf(" ");

k++;

}

blanks=2*i-1;

while(val>=65)

{

printf(" %c",val);val--;

}

printf("\n");

x--;

i++;

}

getch();

}

**********************************output**************************

****A B C D E F G F E D C B A

A B C D E F F E D C B A

A B C D E E D C B A

A B C D D C B A

A B C C B A

A B B A

A A



/*program for structure*/

#include"process.h"

#include"stdio.h"

#include"conio.h"

struct record{

char name[10];

int code,rate;

};

void main()

{

int a;

static int i=0;

int c,code;

char ch,ans;

struct record r[100];

while(1)

{

clrscr();

printf("1. Record entry \n\n");

printf("2. List of record \n\n");

printf("3. Delete any record \n\n");

printf("4. Quit \n\n");

printf("enter your choice \t");

scanf("%c",&ch);

switch(ch)

{

case '1':do

{

printf("\n your %d record :",i+1);

printf("\n name\t\t");

scanf("%s",r[i].name);

printf("Code\t\t");

scanf("%d",&r[i].code);

printf("rate : \n\t\t");

scanf("%d",&r[i].rate);

i++;

printf("\n Do you want more");ans=getch();

}while(ans=='Y'||ans=='y');

break;



case '2' : printf("Code\t\t Name\t rate");

for(c=0;c<i;c++)

{

printf("\n %d \t\t %s\t %d",r[c].code,r[c].name,r[c].rate);

}break;

case '3' :printf("enter Code which record you want Delete :");scanf("%d",&code);

for(c=0;c<i;c++)

{

for(c=c;c<i;c++)

{

r[c].code=r[c+1].code;

strcpy(r[c].name,r[c+1].name);

r[c].rate=r[c+1].rate;

}i--;

break;

// }

}break;

case '4' :exit(0);

break;

}

getch();

}

}

***************************OUTPUT********************

1. Record entry

2. List of record

3. Delete any record

4. Quit

enter your choice 2

Code Name rate

22 GFG 89

4 KJ 98

3 67 34



/*program for string ** ** * ** * * * */

#include"stdio.h"#include"conio.h"

void main()

{

int i,j,n;

clrscr();


scanf("%d",&n);

for(i=1;i<=n;i++)

{

for(j=1;j<=i;j++)

{

printf(" * ");

}

printf("\n");

}

getch();

}

*****************OUTPUT********************

Enter any number 9

*

* *

* * ** * * *

* * * * *

* * * * * *

* * * * * * *

* * * * * * * *

* * * * * * * * *



/*program for reverse number */

#include"stdio.h"

#include"conio.h"

void main()

{int n,i=0;

clrscr();


scanf("%d",&n);

printf("Reverse number is:=");

while(n!=0)

{

i=n%10;

printf("%d",i);

n=n/10;

}

getch();

}

*******************************output**************************

Enter any number 12345

Reverse number is:=54321



/*to reverse the digits of a 5 digit number*/

#include<stdio.h>

#include<conio.h>

void main()

{long int n, a,b;

long int revnum=0;

/*intialised otherwise it will contain garbage value. declared as

long as after reversing it may not be in the range*/

clrscr();

printf("\nenter a five digit number:=");

scanf("%ld",&n);

a=n%10; /*last digit*/

n=n/10; /*remaining digits*/

revnum=revnum+a*10000l; /*revnum updated with value of

extracted digit*/

a=n%10; /*4th digit*/


revnum=revnum+a*1000;

a=n%10; /*3rd digits*/


revnum=revnum+a*100;

a=n%10; /*2nd digit*/


revnum=revnum+a*10;

a=n%10; /*1st digit*/

revnum=revnum=revnum+a;

/*specifier %1d is used for printing a long integer*/

printf("\n the reversed number is %ld", revnum);


getch();

}

******************************output****************************

enter a five digit number:=15541

the reversed number is 14551




/*program for ** ** * ** * * ** * * * * */

#include"stdio.h"

#include"conio.h"

void main()

{

int i,j,n=0,s;

clrscr();

printf("\nEnter number : ");

scanf("%d",&n);

for(i=1;i<=n;i++)

{

for(s=1;s<=n-i;s++)

{

printf(" ");

}

for(j=1;j<=i;j++)

{

printf(" *");

}

printf("\n");

}

getch();

}

Enter number : 12

*

* *

* * *

* * * *

* * * * *

* * * * * *

* * * * * * *

* * * * * * * *

* * * * * * * * ** * * * * * * * * *

* * * * * * * * * * *

* * * * * * * * * * * *



/*program for table display*/

#include<stdio.h>

#include<conio.h>

void main()

{ int a,i,x;

clrscr();

printf("enter any number:");

scanf("%d", &a);

printf(" table of enter number is:");

for(i=1;i<=10; i++)

{

x=a*i;

printf("\n%d", x);

}

getch();

}

*************************output************************

enter any number:9

table of enter number is:

9

18

27

36

45

54

6372

81

90

Total Program

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