ADDITIONAL MATHEMATICS3472/1 AND 3472/2

ANSWERING TECHNIQUES

&Paper 1 and Paper 2

If you think it’s hard ….Challenge it !!!

1. Show ……working………….. for questions with 2 or more marks.

2. Copy the formula ………correctly………….……

3. Transfer answer from the working space to the answer space …carefully.………..

4. Write only ……one….. answer in the answer space ( except when ask for more)

5. The final answer, if round off is needed, must be at least

………4 sig. fig.……. or as …stated….. by the question.

6. Attempt every question. If you do not know the answer you may still obtained

……B…….. marks for working.

MMaarrkkiinngg ……

MMaarrkkss wwiillll bbee ggiivveenn ttoo tthhee ccoorrrreecctt AAnnsswweerr:: …………………………………………....

ffiinnaall aannsswweerr,, rreeggaarrddlleessss ooff tthhee wwoorrkkiinngg..

The final answer is the answer written in the answer space.

-- IIff tthhee aannsswweerrss ssppaaccee iiss eemmppttyy,, tthhee llaasstt wwoorrkkiinngg iinn tthheessppaaccee pprroovviiddeedd wwiillll bbee ttaakkeenn aass tthhee ffiinnaall aannsswweerr..

If two non equivalent answers are written in the answer space, thewrong answer will be chosen as the final answer.

For an incorrect answer, B mark will be given for the correctworking.

[4 marks] [3 marks] [2 marks] [1 marks]

B3

B2

B1

B2

B1

B1 no B marks

STUDENT A

Find the distance between A(2, 5) and B(1, – 4).[2 marks]

AB = (2 - 1) 2 + (5 - 4) 2

= 1 2 + 1 2

= 2 2

= 2

Correct answer: 9.06

STUDENT B

The equation x2 – kx + 1 = 0 has only one root.Find the value of k where k > 0.

[3 marks]

b2 – 4ac = 0(-k)2 – 4(1)(1) = 0

k2 = 4k = 2

Answer: k = ………STUDENT C

Solve the quadratic equation 3x2– 5x – 6 = 0 correct to 3decimal places. [3 marks]

3x2– 5x – 6 = 0

Answer: ……………………

STUDENT D

Solve the quadratic equation 3x2– 5x – 6 = 0correct to 3 decimal places.

x =

= 2.74748, –0.80814

Answer: …………

Correct answer : 2.748, –0.808

STUDENT F

Solve x2 – 5x + 6 > 0 [3 marks]

(x – 2)(x – 3) > 0

x > 2 x > 3

Answer: ……………..

STUDENT G

Sketch f(x) = –2(x – 1)2 – 8 for –2 x 2

B0

2.75, –0.81

)3(2

)6)(3(4)5()5( 2

2.

(1, –8)

–6 –

B0

B2

B0

B2

B

B1

………….

[3 marks]

……………..

[3 marks]

shape X

2

75, 0.81

1

1. Show ……… all working……… clearly.

2. Substitute ……. values into formula.

3. The final answer that is rounded off should be at least ……4 sig. fig………………….

4. The final answer must be in the ……simplest………… form.

5. Do not …..round off………. too early in the solution.

6. Build a ………table…………. to draw a graph.

7. Do you need to build table to sketch a graph? ……No………..

8. For sketching, marks are given to the correct …shape … and …3 points … are seen.

9. The least decimal places required in a table is ……3……………

10. Use ruler to sketch or draw a ……straight line graph…………

11. Check answer using other method or use ……calculator..….

12. Use calculator to check on:

i. Quadratic equation : Factorisation / to find the roots.

ii. Simultaneous equations: ……between linear and linear equation……….

iii. Differentiation : ………find dy/dx when x = a ………I…………

iv. Integration : …to find definite integral……………………………

v. Statistics: ……to get mean, standard deviation, and variance ……

13. Always ………remember………… the time frame. Do not spend more than …15…. minutes

to answer a question with 10 marks.

MMaarrkkiinngg ……

TThhee wwoorrkkiinngg wwiillll bbee cchheecckkeedd ffiirrsstt...... TThhee aacccceepptteedd ffiinnaall aannsswweerrss wwiillll ddeeppeenndd oonn tthhee wwoorrkkiinngg.. KK mmaarrkkss wwiillll bbee ggiivveenn ffoorr mmeetthhooddss aanndd NN mmaarrkkss ffoorr ccoorrrreecctt ffiinnaall aannsswweerr..

STUDENT H1. Find . [3 marks]

73.41

499.8

45sin

8

sin

[the exact answer]

STUDENT J

2. Given y = x3 (2x + 1)4 . Finddx

dy . [3 marks]

)3()12()2()12)(4( 2433 xxxxdx

dy

STUDENT K3. Calculate the composite index

Item A B CI 110 108 120W 4 2 1

112

10

1120

I 1

Correct answe

1.11210

1121

STUDENT M

5. Given y = x3 + 2x . If x decreases at the raunit s-1, find the rate of change of y when x =

x = –0.5 and 23 2 xdx

dy

= 14

y dx

dy x 14 0.5 –

Correc

C

B

A

8

45

no working isshown, K0

incomplete answer

= x2 (14x + 3) (2x + 1)3

D1153

[3 marks]

r:

STUDENT L4. Solve log10 x + log10 5 = log10 3

log10 x = log 3 – log 5

log10 x =5log

3log

10

10wrong

concept= 0.4771 – 0.6990 0

X = 0.600

te of 0.52.

(when x=2)

7

t answer: –7

STUDENT N

6. Given that the perimeter of a sector is 12.66. Find thearea of the sector. [3 marks]

Perimeter = 2r+ s2r+ r = 12.66

r = 5.06= 5.1

thus, area = ½ ( 5.1)2 (0.5)= 6.503

Correct answer = 6.411

0.5 rad

round off problem

2