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5 DECEMBER 09 www.afterschoool.tk 1 Time & Work & Time & Distance in Quantitative Aptitude by : DR. T.K. JAIN AFTERSCHOOL centre for social entrepreneurship sivakamu veterinary hospital road bikaner 334001 rajasthan, india www.afterschoool.tk mobile : 91+9414430763

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  • Time & Work & Time & Distance in Quantitative Aptitudeby : DR. T.K. JAINAFTERSCHOOL centre for social entrepreneurship sivakamu veterinary hospital roadbikaner 334001 rajasthan, indiawww.afterschoool.tkmobile : 91+9414430763

    AFTERSCHOOOL centre for social entrepreneurship

  • 10 people working 8 hours a day complete a work in 24 days. How many persons will be required to complete the work in 16 days working 10 hours a day? = 10 * 8/10* 24/16=12 persons

    AFTERSCHOOOL centre for social entrepreneurship

  • 10men+6boys=20days, 12m+4boys=18days, in what time will 8m+8b do the work? 12m+4b=1/1810m+6b=1/20solving it we get: m=240, b=720thus 8men + 8boys will do it in 22.5 days

    AFTERSCHOOOL centre for social entrepreneurship

  • 3300 men have provision for 32 days if 850 gram per head. After 7 days X more persons came and now the provision will last for 8days less if given 825 gm per head. What is X?Total = 3300*32*.85=897607 days=19635,left= 70125=70125/(17*.825)=5000X=1700 ans.

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  • A can do in 12 and B in 15 days, if they work together, how many days are required? 1/12+1/15 = 27/180reverse it = 6.67 days.

    AFTERSCHOOOL centre for social entrepreneurship

  • A+B can do a work in 10 days, A can do it in 15 days. In how many days B alone can do the work? 1/10 1/15= 5/150=1/30 or 30 days are required by B

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  • A and B can do a job in X days. A alone take 8 days more than X and B can take 18 days more than X, what is X? Formula = sqrt (8 *18)= 12 Answer

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  • A works twice as fast as B. If B can do it in 12 days, how many days are required by A+B? 1/6 +1/12 = = 4 days

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  • A is thrice as good as B and can do a work in 60 days less than B. In how many days can they do it together? 1/30 + 1/90 = 4/90 = 22.5 days.

    AFTERSCHOOOL centre for social entrepreneurship

  • A can do it in 25 days, B in 20 days. They work together for 5 days. A leaves. How much time more is required? Work done by A = 5/25 = 1/5B has to do 4/5 , 20*4/5 =16B has worked for 5 days, so 11 more days are required.

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  • A moves @ 90 KM per hour from X to Y. Returns from Y to X @ 60 KM per hour. He agains goes to Y @ 30 KM per hour. What is his average speed? 1/3(1/90+1/60+1/30) =49or assume distance between X and Y 180, total time = 2+3+6 = 540/11 = 49

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  • X travels from A to B and Y start from B to A. X travels at 75 km per hour. They finish the remaining journey after cross over in 2.66 and 3 hours respectively. What is the speed of Y? Ratio of speed = opposite ratio of sq. Root of remaining time75:X = sqrt(3): Sqrt(2.66)X = (75 * 1.63) / 1.73) = 70 km

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  • Theif run 50 km from police. Speed of theif is 60 km, what should be the minimum speed of police to catch them before next 120 KM? =(50)/(X-60)=22X-120=50X=170 or X = 85 Ans.

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  • thanks....Join, promote and establish afterschoool [email protected] partners in social entrepreneurship....

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