The z-Transform: Introduction Why z-Transform? 1.Many of signals (such as x(n)=u(n), x(n) = (0.5) n...

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The z-Transform: Introduction Why z-Transform? 1. Many of signals (such as x(n)=u(n), x(n) = (0.5) n u(-n), x(n) = sin(nω) etc. ) do not have a DTFT. 2. Advantages like Fourier transform provided: Solution process reduces to a simple algebraic procedures The temporal domain sequence output y(n) = x(n)*h(n) can be represent as Y(z)= X(z)H(z) Properties of systems can easily be studied and characterized in z – domain (such as stability..) Topics: Definition of z –Transform Properties of z- Transform Inverse z- Transform

Transcript of The z-Transform: Introduction Why z-Transform? 1.Many of signals (such as x(n)=u(n), x(n) = (0.5) n...

Page 1: The z-Transform: Introduction Why z-Transform? 1.Many of signals (such as x(n)=u(n), x(n) = (0.5) n u(- n), x(n) = sin(nω) etc. ) do not have a DTFT. 2.Advantages.

The z-Transform: Introduction

• Why z-Transform?1. Many of signals (such as x(n)=u(n), x(n) = (0.5)nu(-

n), x(n) = sin(nω) etc. ) do not have a DTFT.2. Advantages like Fourier transform provided:

• Solution process reduces to a simple algebraic procedures• The temporal domain sequence output y(n) = x(n)*h(n) can

be represent as Y(z)= X(z)H(z)• Properties of systems can easily be studied and

characterized in z – domain (such as stability..)

• Topics:– Definition of z –Transform– Properties of z- Transform– Inverse z- Transform

Page 2: The z-Transform: Introduction Why z-Transform? 1.Many of signals (such as x(n)=u(n), x(n) = (0.5) n u(- n), x(n) = sin(nω) etc. ) do not have a DTFT. 2.Advantages.

Definition of the z-Transform

1. Definition:The z-transform of a discrete-time signal x(n) is defined by

where z = rejw is a complex variable. The values of z for which the sum converges define a region in the z-plane referred to as the region of convergence (ROC).

2. Notationally, if x(n) has a z-transform X(z), we write

3. The z-transform may be viewed as the DTFT or an exponentially weighted sequence. Specifically, note that with z = rejw, X(z) can be looked as the DTFT of the sequence r--nx(n) and ROC is determined by the range of values of r of the following right inequation.

Page 3: The z-Transform: Introduction Why z-Transform? 1.Many of signals (such as x(n)=u(n), x(n) = (0.5) n u(- n), x(n) = sin(nω) etc. ) do not have a DTFT. 2.Advantages.

ROC & z-plane • Complex z-plane

z = Re(z)+jIm(z) = rejw

• Zeros and poles of X(z)Many signals have z-transforms that are rational function of z:

Factorizing it will give:

The roots of the numerator polynomial, βk,are referred to as the zeros (o) and αk are referred to as poles (x). ROC of X(z) will not contain poles.

Page 4: The z-Transform: Introduction Why z-Transform? 1.Many of signals (such as x(n)=u(n), x(n) = (0.5) n u(- n), x(n) = sin(nω) etc. ) do not have a DTFT. 2.Advantages.

ROC properties

• ROC is an annulus or disc in the z-plane centred at the origin. i.e.

• A finite-length sequence has a z-transform with a region of convergence that includes the entire z-plane except, possibly, z = 0 and z = . The point z = will be included if x(n) = 0 for n < 0, and the point z = 0 will be included if x(n) = 0 for n > 0.

• A right-sided sequence has a z-transform with a region of convergence that is the exterior of a circle:

ROC: |z|>α• A left-sided sequence has a z-transform with a region of

convergence that is the interior of a circle:ROC: |z|<β

• The Fourier Transform of x(n) converges absolutely if and only if ROC of z-transform includes the unit circle

Page 5: The z-Transform: Introduction Why z-Transform? 1.Many of signals (such as x(n)=u(n), x(n) = (0.5) n u(- n), x(n) = sin(nω) etc. ) do not have a DTFT. 2.Advantages.
Page 6: The z-Transform: Introduction Why z-Transform? 1.Many of signals (such as x(n)=u(n), x(n) = (0.5) n u(- n), x(n) = sin(nω) etc. ) do not have a DTFT. 2.Advantages.
Page 7: The z-Transform: Introduction Why z-Transform? 1.Many of signals (such as x(n)=u(n), x(n) = (0.5) n u(- n), x(n) = sin(nω) etc. ) do not have a DTFT. 2.Advantages.
Page 8: The z-Transform: Introduction Why z-Transform? 1.Many of signals (such as x(n)=u(n), x(n) = (0.5) n u(- n), x(n) = sin(nω) etc. ) do not have a DTFT. 2.Advantages.
Page 9: The z-Transform: Introduction Why z-Transform? 1.Many of signals (such as x(n)=u(n), x(n) = (0.5) n u(- n), x(n) = sin(nω) etc. ) do not have a DTFT. 2.Advantages.
Page 10: The z-Transform: Introduction Why z-Transform? 1.Many of signals (such as x(n)=u(n), x(n) = (0.5) n u(- n), x(n) = sin(nω) etc. ) do not have a DTFT. 2.Advantages.
Page 11: The z-Transform: Introduction Why z-Transform? 1.Many of signals (such as x(n)=u(n), x(n) = (0.5) n u(- n), x(n) = sin(nω) etc. ) do not have a DTFT. 2.Advantages.
Page 12: The z-Transform: Introduction Why z-Transform? 1.Many of signals (such as x(n)=u(n), x(n) = (0.5) n u(- n), x(n) = sin(nω) etc. ) do not have a DTFT. 2.Advantages.

Properties of Z-Transform • Linearity

If x(n) has a z-transform X(z) with a region of convergence Rx, and if y(n) has a z-transform Y(z) with a region of convergence Ry,

and the ROC of W(z) will include the intersection of Rx and Ry, that is, Rw contains .

• Shifting propertyIf x(n) has a z-transform X(z),

• Time reversalIf x(n) has a z-transform X(z) with a region of convergence Rx that is the annulus , the z-transform of the time-reversed sequence x(-n) is and has a region of convergence , which is denoted by

)()()()()()( zbYzaXzWnbynaxnw Z

yx RR

)()( 00 zXznnx nZ

z

)()( 1 zXnx Z

11 z xR1

Page 13: The z-Transform: Introduction Why z-Transform? 1.Many of signals (such as x(n)=u(n), x(n) = (0.5) n u(- n), x(n) = sin(nω) etc. ) do not have a DTFT. 2.Advantages.

Properties of Z-Transform• Multiplication by an exponential

– If a sequence x(n) is multiplied by a complex exponential αn.

• Convolution theormIf x(n) has a z-transform X(z) with a region of convergence Rx, and if h(n) has a z-transform H(z) with a region of convergence Rh,

The ROC of Y(z) will include the intersection of Rx and Rh, that is, Ry contains Rx ∩ Rh .

With x(n), y(n), and h(n) denoting the input, output, and unit-sample response, respectively, and X(z), Y(x), and H(z) their z-transforms. The z-transform of the unit-sample response is often referred to as the system function.

• ConjugationIf X(z) is the z-transform of x(n), the z-transform of the complex conjugate of x(n) is

)()( 1zXnx Zn

)()()()()()( zHzXzYnhnxny Z

)()( zXnx Z

Page 14: The z-Transform: Introduction Why z-Transform? 1.Many of signals (such as x(n)=u(n), x(n) = (0.5) n u(- n), x(n) = sin(nω) etc. ) do not have a DTFT. 2.Advantages.

Properties of Z-Transform

• Derivative– If X(z) is the z-transform of x(n), the z-

transform of is

• Initial value theoremIf X(z) is the z-transform of x(n) and x(n) is equal to zero for n<0, the initial value, x(0), maybe be found from X(z) as follows:

dz

zdXznnx Z )(

)(

)(lim)0( zXxz

Page 15: The z-Transform: Introduction Why z-Transform? 1.Many of signals (such as x(n)=u(n), x(n) = (0.5) n u(- n), x(n) = sin(nω) etc. ) do not have a DTFT. 2.Advantages.