The subsitution Method

34
The subsitution Method Fatema Ahmed Alhajeri 201108382 #19

description

The subsitution Method. Fatema Ahmed Alhajeri 201108382 #19. Previous information. an indefinite integral is a function ∫ f(x)dx= F(x) where F’(x) = f (x) which represents a particular antiderivitive of f, or an entire family of antiderivitives. Example 1. ∫ x √x dx - PowerPoint PPT Presentation

Transcript of The subsitution Method

Page 1: The  subsitution  Method

The subsitution MethodFatema Ahmed Alhajeri

201108382#19

Page 2: The  subsitution  Method

Previous information• an indefinite integral is a function ∫f(x)dx= F(x) where F’(x) = f(x) which represents a particular

antiderivitive of f, or an entire family of antiderivitives.

Page 3: The  subsitution  Method

Example 1

• ∫ x √x dx• = ∫ x x1/2 dx• =∫ x (½ + 1) dx • = ∫x 3/2 dx • Therefore using the intermediate

integration rule:

Page 4: The  subsitution  Method

• We can solve this previous equation:• F(x) = ∫ x3/2 dx• = (x5/2 ) + C

5/2

Therefore,• = F(x) = 2/5 x5/2+C

Page 5: The  subsitution  Method

The Substitution Method• We need to use the substitution method in order

to convert difficult equations, to fit the intermediate general equations in order to solve.

• Example 2• f(x) = ∫ 2x √(1+x2) dx• = ∫ (1+x2 )1/2 2x dx

• Using substituion method we let u = 1+x2 since the derivitive of u (du) is = 2x and is present in the equation

u = 1 +x2

du= 2x dx

Page 6: The  subsitution  Method
Page 7: The  subsitution  Method

• We now change the equation in terms of “u” where it equals to:

• F (x)= ∫ (u)1/2 du• This equation fits the structure of:

• Thus,• ∫ (u)1/2 du • = ∫ (u)3/2 + C

3/2

• = 2/3 u3/2 + C

Page 8: The  subsitution  Method

• Now, replacing the “u” with the variable x to retrieve the final answer:

• = 2/3 √(1+x2)3/2 + C

Page 9: The  subsitution  Method
Page 10: The  subsitution  Method
Page 11: The  subsitution  Method

Math prject - Substitution rule 11

Chapter 5INTEGRALS

THE SUBSITUTION RULE5.5

Somaia Elsherif

Page 12: The  subsitution  Method

Math prject - Substitution rule 12

The Substitution rule

• In general, Notice that each differentiation rule for functions provides a rule to find an antiderivative

• The substitution method is a rewriting method for integrals where we can extend the scope of these rules

• The idea behind substitution rule is to replace a relatively complicated integral by a simpler one

Page 13: The  subsitution  Method

Math prject - Substitution rule 13

• The Chain rule for differentiation

• The chain rule implies the substitution rule

∫f’(g(x))g’(x) = f(g(x)) + C

• Substitution rule (according to text book)

∫ f(g(x))g’(x) dx = ∫ f(u) du

where u = g(x), then du = g’(x)

Summary of the substitution rule proof

Page 14: The  subsitution  Method

Math prject - Substitution rule 14

The Substitution rule• If u=g(x) is a differentiable function whose range is an interval

I and f is continuous on I,Then ∫ f(g(x))g’(x) dx = ∫ f(u) du

• Notice that the rule was proved using the chain rule for differentiationThus, It is easy to remember it ! Only you have to think of dx and du in the previous formula as differentials

Page 15: The  subsitution  Method

Math prject - Substitution rule 15

Example Find ∫ x³ cos (x⁴ + 2) dx.

• We made a substitution u = x⁴ + 2why? Because it’s differentiable function

• it’s differential is du = 4x³ dx, which, apart from the constant factor 4, occurs in the integral.

• Thus, using x³ dx = du/4 and the substitution rule we have

Page 16: The  subsitution  Method

Math prject - Substitution rule 16

∫x³ cos (x⁴ + 2) dx

= ∫cos u . ¼ du

= ¼ ∫ cos u du

= ¼ sin u + C

• Notice that you have to return to the original variable x

= ¼ sin (x⁴ + 2) + C

Page 17: The  subsitution  Method

Math prject - Substitution rule 17

Notice that

• The main challenge in using the Substitution rule is to think of an appropriate substitution

You have 2 ways to do it !• Choose u to be function in the integrand whose differential

occurs ( except for a constant factor )this is similar to the previous example case

Page 18: The  subsitution  Method

Math prject - Substitution rule 18

If the first method didn’t work, Try this• Choose u to be some how complicated part of the integrand

( perhaps the inner function in a composite function )Finally !

• Finding the right substitution is a bit of art• It’s not unusual to guess wrong• If your first guess doesn’t work, just try another substitution

Page 19: The  subsitution  Method

THE SUBSTITUTION RULE FOR DEFINITE INTEGRALS

Done by: Maha Mohd.Ibrahim.ID:201106851

Supervised by: Foud Al-muhannadi

Page 20: The  subsitution  Method

General rule

• If g’ is continuous on [a,b] and f is continuous on the range of u=g(x), then:

=(

Page 21: The  subsitution  Method

Example

• Evaluate:

To find the new limit of the integration we note that:When and when

Page 22: The  subsitution  Method

• Therefore:

Page 23: The  subsitution  Method

• Evaluate:

Method (1):

Page 24: The  subsitution  Method

Method (2): ⇒

The integral now is:

Page 25: The  subsitution  Method

We got the same answer!

Page 26: The  subsitution  Method

Definite integral :symmetry

Gehad desouky 201104686

#26

Page 27: The  subsitution  Method

Definite integral : symmetry

• We use the substitution by U to simplify the calculations of integrals of functions that are symmetric

• Example :

Page 28: The  subsitution  Method

Substitution rule (symmetry)

• The main rule is : • If (F) is continues on [-a,a]

if (f) is even then [f(-x)=f(X)], then

If (F) is odd then [f(-x)=-f(X)], then

a

a

adxxfdxxf

0.)(2)(

a

adxXf 0)(

Page 29: The  subsitution  Method

• Example 1, Evaluate by writing it As a sum of two integrals and interpreting

one of those integrals in terms of an area.

dxxx 2

2

24)3(

2

2

22

2

22

2

2

22

2

22

2

2

4344)3(

)()()()([

)434(4)3(

dxxdxxxdxxx

dxxgdxxfxgxf

dxxxxdxxx

b

a

b

a

b

a

Page 30: The  subsitution  Method

04

0)(

)(4)(

]2,2[

4)(

4

)1

2

2

2

2

2

2

2

2

dxxx

dxxf

xfxxxf

xxxf

dxxx

a

a

Page 31: The  subsitution  Method

2

4

]2,0[4

424

)()()(

4)(

4

)2

22

2

2

2

2

0

22

2

2

2

2

radius

xy

xy

dxxdxx

xsofxfxf

xxf

dxx

Page 32: The  subsitution  Method

64)3(

6)2(304)3(

24

)2(2

)4

(242

)3

2

2

2

2

2

2

2

22

0

2

dxxx

dxxx

then

rdxx

Page 33: The  subsitution  Method

9

18236

72836

172936

1)729(

36

1

)1(36

1)3(

36

16

)(

6

1

)(6

1

6

1

6

21

66

3

1

6

3

1

5

2

2

3

u

duu

dxxdu

dxxdu

xu

dxxx 531

0

2 )21(

Example 2

Page 34: The  subsitution  Method

Thank you for your time